info from the connection string

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  Hello
  
  I have an Oracle database and its details are configured in LDAP. I have the c# code that I want to connect to Oracle DB using LDAP details. So I wrote the code to connect to the Oracle DB, but not able to connect. Implementation error at the con. Open() statement: "ORA-12154: TNS: could not resolve the connect identifier specified.
  
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  user8786648 wrote:
  Hello

  I have an Oracle database and its details are configured in LDAP. I have the c# code that I want to connect to Oracle DB using LDAP details. So I wrote the code to connect to the Oracle DB, but not able to connect. Implementation error at the con. Open() statement: "ORA-12154: TNS: could not resolve the connect identifier specified.

  Code:
  --------
  String s = "Data Source = @ldap://xyz.us.oracle.com: 11389/xyz_ldap, cn = OracleContext, dc =, dc = oracle, dc = com; User Id = xyz; Password = xyz";

  Con OracleConnection = new OracleConnection (constr.);
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• Display the name of the tag as the column name and the value in the tag as a row of data from the input string.

  Hi Forum members,

  I am looking for a query display the name of the tag as the column name and the value in the tag as a row of data.

  I have to print the values within the tag to a file by choosing the value of the flags. the sequence of the tags will vary each time, as the tag name will change dynamically.

  So here is the example of input data and the expected output. The string in the text column must be separated as the column names and values.

  Input data
  Select 1 as seqno,' < > 0210A 50 4f < / 4f > < 5f20 > TEST CARD 16 < / 5f20 > < 5f2a > < / 5f2a > < 82 > 1 c 00 < / 82 > ' double text

  
  Output:

  Seqno 4f 5f20 5f2a 82
  0210A 50 16 1 00 TEST CARD 1

  Please help me by providing your entries on this.

  We use the version of Oracle 11.2.

  Note: This is not the XML string

  Thank you

  Shree

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  )

  Select d.seqno, x.*

  d the data,

  XMLTable ('/ root')

  by the way xmltransform (xmltype ('': replace (replace (text,'<><>'),)))

  XmlType (q'~http://www.w3.org/1999/XSL/Transform "version ="1.0"> ")

                                                   

                                                     

                                                       

                                                     

                                                   

                                                   

                                                     

                                                       

                                                     

                                                   

  ~'

  )

  )

  path of columns '4f' varchar2 (10) "tag4f."

  path of "5f20' varchar2 (30)"tag5f20. "

  path of '5f2a' varchar2 (10) "tag5f2a."

  path of varchar2 (10) "82" "tag82.

  ) x

  
  

  SEQNO	4f	5f20	5f2a	82
  1	0210A 50	16 TEST CARD	-	1 00
  2	0210A 50	16 TEST CARD	-	1 00
  3	0210A 50	16 TEST CARD	-	1 00
  4	0210A 50	16 TEST CARD	-	1 00

  with

  data in the form of

  (select 1 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2a><82>00 1' text of all the double union)

  Select 2 as seqno,'XYZ<4F>0210 A 50<5f20>TEST CARD 16<5f2a><82>00 1' text of all the double union

  Select 3 as seqno,'<4f>0210 A 50<5f20>TEST CARD 16<5F2A><82>1 00XYZ ' text of all the double union

  Select option 4 as seqno,'<4F>0210 A 50<5F20>TEST CARD 16<5f2A><82>1 00XYZ' double text

  ),

  Chopper (seqno, Key, value, String) as

  (select seqno,

  regexp_substr (text,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (Text,'>(.*?))

  regexp_substr (text,'<.+?>. *? ) (.*) $', 1, 1, null, 1). » <>'

  from the data

  Union of all the

  Select seqno,

  regexp_substr (String,'<(.+?)>', 1, 1, null, 1),

  regexp_substr (String,'>(.*?))

  regexp_substr (String,'<.+?>. *? ) (.*) $', 1, 1, null, 1)

  Chopper

  where regexp_substr (string,'<(.*?)>', 1, 1, null, 1) is not null

  )

  Select '4f', seqno, '5f2a', '82', '5f20.

  of (seqno, lower (key) select key, value)

  Chopper

  )

  Pivot (max (value) for key in ('4f' as '4f', '5f20' as '5f20', '5f2a' as '5f2a', "82" as "82"))

  Concerning

  Etbin
  

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  Published by: Daniel on November 14, 2012 10:01

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