Initialize the string of known length

Similar Questions

• Best practices to declare and initialize the string?

  What is the best practice for the way in which strings are declared in a class?
  
  Should it be
  
  private String chBonjour = "";
  
  or I should have initialization in the constructors?

  The constructor of servlet is usually called only once, when the servlet is first accessed. But then again maybe something happens, google, servlet life cycle if you must know.

  But let's take a step back here. It seems you are trying to put the fields in servlets. Don't, don't. When two users extract URL of the servlet at the same time, the fields are shared between the two shots. If you store something like HTTP settings in the fields, parameters two hits' will get truncated. The hits may eventually see each and other parameter values.

  The best way is not to have fields of servlets. (Except the constant "final static" maybe, sometimes rarely something else). Well the pain of simultaneity go, servlet life cycle concerns go away, builders servlet if go, init() disappears usually.

• Radius of the circle of known length?

  I'm doing a circle with the radius of 200 * sqrt (3).  Is it still possible?  Or illustrator will complete the equation for the thousandths?  If illustrator will round just the equation for the thousandths, I can enter the number myself, but I was hoping that he could find the point.

  AZ,

  We are not just talking about drag of ine point to another with the line Segment tool and then the object > path > add Anchor Points, which will give you the midpoint, and you can remove it again with its path once it has achieved its objectives, are we?

• Length of the string

  Hi all

  I intend to measure the length of the string and the length of the Arc in a gray-scale image. Please advise.

  You need to find to the first circle or outer circle?

  Part of Mathematics:

  The length of the rope of calculation, to find the RADIUS and the angle under which is seen in the center of the rope or perpendicular to the distance between the string and the center of the circle: once you have these settings, you can calculate the length of the rope using formulas:

  Source: http://www.mathopenref.com/chord.html

  Similarly, you can get for the length of the Arc: http://www.mathopenref.com/arclength.html

  Part of image processing:

  -I think that you can get the radius of the internal or external circle based on your requirement, using IMAQ detect forms.

  https://zone.NI.com/reference/en-XX/help/370281M-01/imaqvision/imaq_detect_shapes/

• EXCEL ActiveX + error '-2146827284' (but not the string length limit)

  Hi all

  First of all thanks for your help!

  I have a strange error with excel activeX: "-2146827284!"

  Why strange? Because my export feature works perfectly on a computer but not on another... (both are windows 7 + Excel 2007)

  How my application works:

  I have to read an excel spreadsheet which preserves made with different types of instruments of measures.

  For each type of instrument, I have to create a specific worksheet with its measures.

  For example:

  1 spreadsheet excel with the many measures of 4 different types of instruments

  SHOULD GIVE

  4 excel spreadsheets containing the measures of each instrument (1 worksheet for a type of instrument).

  Hope I am clear...

  Why I do with LV? Because it's fun!

  Now that some snapshoot.

  1 - where the bug appears :

  

  2 - the message I get (translated from french to English):

  

  Additional information:

  -The size of the string I have write in excel cells is 6 characters max. More I put a condition to return an error if the string length is > 900 characters.

  Thanks a lot for your help!

  SO simple...

  It was just the name of the folder...

  I coded the name of the folder as a constant aim dev. And I do not mind that the name of the folder is not the same on both computers!

  "a missing letter = a week closed.

  Arrrgh

  all sorry to bother you

• flatten channel adds the length of the string

  Hi all

  I flatten a cluster chain help to flatten to string.vi. The cluster contains strings and arrays. The flattened string contains the length of the string that is appended to the string.

  So if I have a cluster with only 1 string and a value = "LabVIEW". the flattened string would be "0007LabVIEW". Flatten channel vi has a Boolean entry "add string or array of size? even if I set the Boolean value false, it always adds the length of the string. Is this a bug?

  I think that if you read the detailed help to flatten it to string function you will see this is not a bug.  That boolean applies only to top-level data, once put you something in a cluster or array, the Paris are open.

• Length of the string, excluding the input character/string

  Long story short, I want to replicate the function of the length of the string , but do not include an input the number of characters in string. For example:

  The input string (search) is 'the

  My first string to test is "the big red dog."

  That would mean a 13 string length.

  My second string is "Jumps over the lazy Fox."

  That would mean a length of 21.

  ' Hello World! ' would return 12.

  'The Lion, the Witch and the wardrobe' would return 26.

  I hope that you can see what I want to achieve. How is this possible?

  -James

  (I'm driving Labview 8.5)

  Use the search and replace the string to replace your 'exclusive' with an empty string string.  Use the length of the string on the result string.  Make sure that everything is already set to TRUE.

  

• Doc XML to a string fails when the string length is greater than 512 bytes.

  I have been using the following code to write an XML string.  If the resulting string is lower to ~ 512 bytes, the string will be created, if > ~ 512 bytes, the routine does not create the string.  Assuming that the doc contains an XML document:

  Doc CVIXMLDocument = 0;
  HDoc MSXMLObj_IXMLDOMDocument = 0;

  ...

  cvistatus = CVIXMLSaveDocument (doc, 0, "Test1.xml");
  status = CVIXMLGetDocumentActiveXHandle(doc, &hDoc);)

  hRlt = MSXML_IXMLDOMDocumentGetxml (hDoc, & errInfo & strXml);

  The SaveDocument routine still works, the XML file contains the XML, regardless of their size.

  The Getxml routine creates only the XML string in strXml when the length of the string is lower to ~ 512 bytes.

  Does anyone have an idea of the problem?

  Because the string is very long, the ICB debugger cannot display. That's why I was wondering if you were trying to print using put or printf. Because the return value is 0 and the ERRORINFO is also stating the success, I would recheck the chain by printing it to the console or a file.

• 1st problem = Error 1606% APPDATA % and 2nd problem = WARNING Logger: initialize() is not yet known. The log file may experience corruption...

  1st problem = Error 1606% APPDATA % and 2nd problem = WARNING Logger: initialize() is not yet known. The log file may experience corruption...

  Try this FixIt:

  Code error '0 x 80070646', '646', or '1606 ' when you try to install Office updates

  http://support.Microsoft.com/kb/2258121

  André

  "A programmer is just a tool that converts the caffeine in code" Deputy CLIP - http://www.winvistaside.de/

• How cut the length of the string IE channel name here, if it exceeds 20 characters or letters. The channel name is dynamically analyzed the spreadsheet/xml file.

  How cut the length of the string IE channel name here, if it exceeds 20 characters or letters. The channel name is dynamically analyzed the spreadsheet/xml file.

  My Council of Europe in the .js file is

  function generateHTMLMarkup (i, channel) {}
  Alert ("this is lang" + str);
  var str ="";
  "Str += '.

  ";
  str += "" +
  "" channel ['name'] +.replace("Low",".") + ""+""
  ";
  "Str += '.
  "+ ""+""+"
  ";
  Alert ("this is lang" + str);
  return str;

  }

  nerateHTMLMarkup: function (i, channel) {}
  Alert ("this is lang" + str);
  var str ="";
  "Str += '.

  ";
  str += "" +
  "" +
  "" + channel ['name'] + "" +.
  "" + "
  ";
  "Str += '.
  "+ "" + "
  ";
  Alert ("this is lang" + str);
  return str;

  etc.

  Give mthe rhythm and the exact code where Ihave tio get implemented.

  in the code, replace change

  channelName var = channel ['name'];

  TO

  channelName var = channel ['name'];

• Lesson1 solutions, length of the string, really a God's solution?

  Hello, I was just looking at the solutions proposed for lesson 1 homework and I came on line 65, ex 2 solution where odd length of the string is calculated this way:

  (s.length () & 1) == 1

  Here, we are a group of users of Java for a long time and we still don't completely understand how it really works.

  Do the bitwise AND operation on the length of the string 1 and audit, seems really strange.

  Either way, I suppose it works somehow but is it really a good solution providing a code which may include only a Ninja of Java for the black belt? If you use it in production which will be able to keep it?

  the pit of my ignorance, I wrote this:

  ! (p.length (% 2) == 0)

  Thank you and have a nice day!

  It's probably again my fault.

  I remember presenting examples of lambda at the beginning I used (I % 2 == 0) to test whether a number has been the same. One of our graphics guys chastises me for using rest (%) instead of bits - and ((i & 1) == 0). In C, the remainder operator is usually compiled to some form of a division operation, which is much slower than a - bit operation and exploitation. (An optimizer may be able to replace i with i 2% & 1 but optimizations in c may be quite subtle). In any case, I started to use at the level of the ILO - and in my examples.

  Then I started getting complaints about the use of the bitwise operators because nobody knew how they worked.

  In any case, in Java, the result is well-defined, as a type int is specified as a 32 bit two complement binary number, so I & 1 will tell you if it's odd or even. The force JIT compiler - reduce i % 2 to i & 1, but when the interpreter is running it will go through the slow lane. As someone said, it's a micro-optimisation anyway.

  A ride is what % is the operator remains , not a modulo operator, while for positive numbers, the result is the same. For negative numbers, the result can be negative! So, be sure to not try for an odd number using i % 2 == 1 because it will fail for an odd, negative number, the result will be-1. Test! = 0, or better still simply use at the level of the ILO - and. Of course, the string length is not a problem because it is still not negative, but the problem may occur in other situations, in particular array of indexation.

• How to get the length of the string a vm?

  Hello

  I'm trying to automate some consolidation of virtual machines and would like to add script. I have over 800 virtual machines manually would not work.

  I would like to

  $allVApps = get-CIVApp

  foreach ($CIVm to ($allVApps |)) Get - CIVM)) {}

  find the number of channels and if greater than 8 consolidate them.

  }

  Someone has this practice? or something else?

  I'm in a cloud environment vSphere 5.5, installed latest powercli.

  Thank you

  Don't know why this does not work for others, but what I posted before work for me.  Here is a more complete version of how get the those of VAPP VM.  There are no doubt more direct ways, but that how I made it so far:

  1. get the VAPP

  $vApp = get-CIvApp-name 'Test-VAPP.

  2. get the VMS of vApp

  $VMs = $vApps.ExtensionData.Children.vm

  3. get the ones for the VM first in the list of $VMs:

  $VMs [0]. VCloudExtension.any.VirtualDisksMaxChainLength

  This last command returns 18 for me which is the "Length of the string" value in the properties of the Virtual Machine to the virtual machine in the vCD UI.

  I hope this helps.

• find the length of the string

  Hi all
  
  I have a srting that contains two or more channels as for instance, it's my channel (think of this total string as one string) "Bronson, Ms. Jamie", "elder, Ms. Francis '.
  Now I want to calculate the length of the string of replacement of commas and apostrophes with null.
  
  Can someone pls help me with this?
  
  Thank you

  SQL>
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select * from t;
  
  MYSTRING
  ------------------------------------------
  'Bronson, Ms. Jamie','Elder, Mrs. Francis'  
  
  SQL>
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select replace(replace(mystring, ',', null), '''', null) from t;
  
  REPLACE(REPLACE(MYSTRING,',',NULL),
  -----------------------------------
  Bronson Ms. JamieElder Mrs. Francis
  
  SQL> l
    1  with t as (
    2   select '''Bronson, Ms. Jamie'',''Elder, Mrs. Francis''' as mystring
    3  from dual)
    4  select length(replace(replace(mystring, ',', null), '''', null)) as string_len from t;
  
  STRING_LEN
  ----------
          35  
  

• escape character must be the string of length 1 (error ORA-01425)

  Hi all!
  
  I get this error message (SQL error: ORA-01425: escape character must be the string of length 1) when querying an oracle 9i database with:
  
  SELECT * FROM table WHERE column LIKE '%' ESCAPE ' \';
  
  Bar which makes it a double backslash (included with apostrophes) would solve the problem, however, with this change, the request is more executable in a 10g database.
  
  Is there a way to make the executable SQL above (with a single backslash escape) code in both (and latest) versions, without changing it? Maybe a server definition database that could solve this problem...
  
  Suggestions for the problem described are greatly appreciated!
  
  Thank you

  col2 NVARCHAR2 (100)

  OK, you should have mentioned before using unicode ;)

  However, should not always identical fields be treated identically in any database?...

  Yes, they should :(

  In any case the escape string should obviously be treated as unicode so the right way, I guess, would be

    select * from mytable where col2 like N'%' escape N'\'; 
  

  Note the front N ' \' to make the unicode string.

• Need a bit of help with the string read/write DLL

  I have a DLL that communicates via RS232 with some instruments.

  From 2 numbers (parameter number and a number of processes) the DLL will communicate and extract the values.

  I managed to put in place the DLL to get words, characters, long and floats (single precision).

  Now, it is the documentation that accompanies it for strings:

  

  ReadString asks the DLL to get the data of the instrument, if succesfull I have others on call GetString to get the string memory.

  I have a few questions:

  -The values of her star (*) are pointers; As I understand it that it points to a place of memory where the value is stored, is - that correct?

  -How do I know if I pass the value to the DLL, or read? For example with GetString Im not sure if

  I should pass the length of the string to the DLL or if it is read

  -How to get the character returned in a string; IM assuming I need to find somewhere a byte array.

  Now I can also write strings:

  

  As a matter of f:

  -Should I add NULL at the end of the string, or labview does by default?

  My procedure is now: read the input chain, reduce it to the size of the specified string (this is constant according to the setting of the instrument), converted to a byte array and replace the last element of the array with 0 (Null).

  However, the DLL entry expected a character, that I should get in the DLL?

  _Faust wrote:

  I have a few questions:

  -The values of her star (*) are pointers; As I understand it that it points to a place of memory where the value is stored, is - that correct?

  They can be pointers or buffers. Which of the two is ambiguous in the syntax of C. However, in your case I suppose that piMsgId and pcLen be a pointer to a unique value and pszDest a string buffer.

  -How do I know if I pass the value to the DLL, or read? For example with GetString Im not sure if

  I should pass the length of the string to the DLL or if it is read

  Description is not really clear however most of the C API require today the length of the allocated buffer at the entrance to make sure that they don't overrun the buffer length. They may or may not change this value before returning to indicate the amount of data they actually informed. The pcLen parameter passed by reference probably indicates that this function does this way.

  -How to get the character returned in a string; IM assuming I need to find somewhere a byte array.

  It is not necessary. You can simply set the parameter to a string and must be passed as a C string pointer. In LabVIEW 8.5 or more you can also configure to resize this string for the number of characters as indicates it a different setting of the library to compose the node (CLN), in this case your pcLen. 8.5 you can use a table to explicitedly initialization function create a table Bbyte of the length needed, convert the byte array to string and pass to the CLN parameter. LabVIEW will return automatically only the part of the string up to the NULL character if a CLN is configured as C string pointer

  Now I can also write strings:

  As a matter of f:

  -Should I add NULL at the end of the string, or labview does by default?

  No! If you configure the parameter is a string, passed as a string pointer C, LabVIEW will do it automatically for you.

  My procedure is now: read the input chain, reduce it to the size of the specified string (this is constant according to the setting of the instrument), converted to a byte array and replace the last element of the array with 0 (Null).

  However, the DLL entry expected a character, that I should get in the DLL?