Is possible to use = href and onclick = Ajax.request to track outgoing link?

Hello

I m new in Oracle Apex and I try now to follow outgoing links on my Apex 3.2.1 application.

When the user clicks on a link of my application that redirects to a past site, I want them to be taken on the site (href) and I also want a background script that fit into a table in oracle, this 'click '.

For example, I have this link in a page of the APEX:

When the user cliks in this link, I would like to run a procedure oracle, with a setting in the background. Let´s call this procedure, for example:

SP_REGISTRA_ACESS_LINK(:P19_COD_TOPICO).

This procedure to insert a record into a table called BAC_ACESS, ranger in the SYSDATE and value of ': P19_COD_TOPICO.

Is it possible to link to a new site and call an AJAX request at the same time?

Could someone give me an example of how I can do? How can I implement in my Apex 3.2.1 application?

I m working with Apex 3.2.1 and RDBMS 9i. I can't spend any of these versions, cause Apex is installed in a production database that can be upgraded now to 10g / 11g.

Best regards

Sergio Coutinho

Hello

Ok
One solution could be to make you your own custom County click procedure that you call in the URL.
You go to this external link to procedure and other settings you need.
Procedure to make your custom orders and last stage call owa_util.redirect_url and redirect the user to this external link
http://download.Oracle.com/docs/CD/B13789_01/AppDev.101/b10802/w_util.htm#997457

You create the APA procedure, analysis of schema and grant execute user to DAD.
In addition, you may need change Apex schema function wwv_flow_epg_include_mod_local
http://download.Oracle.com/docs/CD/E17556_01/doc/admin.40/e15521/adm_mg_service_set.htm#AEADM209

Kind regards
Jari

Tags: Database

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