Left outer join query and check the status

Similar Questions

• Help for a LEFT OUTER JOIN query

  Hello, all,.

  I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.

  Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:

  tableA
  blogID        blogTitle       blogBody      dateEntered
  1             This is a test  More text...  2016-05-20 11:11:11
  2             More testing    Still more!   2016-05-19 10:10:10
  3             Third charm!!   Blah, blah.   2016-05-18 09:09:09
  

  tableC
  commID        userID          userText      dateEntered
  10            Bravo           I like it!    2016-05-20 11:21:31
  11            Charlie         I don't!      2016-05-20 11:31:51
  12            Alpha           Do it again!  2016-05-19 10:20:30
  13            Bravo           Still more?   2016-05-19 10:30:50
  14            Charlie         So, what?     2016-05-19 10:35:45
  15            Bravo           Blah, what?   2016-05-18 09:10:11
  16            Alpha           Magic number! 2016-05-18 09:11:13
  

  tableB
  blogID        commID
  1             10
  1             11
  1             12
  2             13
  2             14
  3             15
  3             16
  
  
  
  

  I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry.  But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.

  Here is an example of pseudo-SQL of what I'm trying.

  SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total
  FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID
                LEFT OUTER JOIN tableC c ON c.commID = b.commID
  WHERE a.blogID = '1'
  GROUP BY blogID, blogTitle, blogBody
  ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
  

  I'm sure it's something simple, but I just DO NOT see it.  Can you help me?

  V/r,

  ^_^

  Try:

  GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
  

  See you soon

  Eddie

• Get the error invalid identifier in the left outer join

  I wrote a query and get the invalid identifier error during execution:
  the exact error is: ORA-00904: "D". "" ACCT_NO ": invalid identifier
  This query is not able to access the parent table alias in the subquery of the left outer join.
  
  This is the query:
  SELECT D.PROD_DESC_TX, BASE. ASSET_NUM, BASE. PROD_ID, BASE.NAME
  OF TABLE1 D
  LEFT OUTER JOIN
  (
  SELECT ASSET_NUM, PROD_ID, B.SID
  FROM TABLE2 E
  JOIN IN-HOUSE TABLE3 HAS IT E.PROD_ID = A.ROW_ID
  JOIN INTERNAL TABLE 4 C ON A.PAR_PROD_INT_ID = C.ROW_ID
  INTERNAL TABLE5 JOIN B ON C.ROW_ID = B.PAR_ROW_ID
  AND B.TYPE = 'VALUE '.
  AND B.NAME = 'VALUE '.
  WHERE E.ASSET_NUM = ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO)))
  ) BASE ON ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO))) = BASE. ASSET_NUM
  WHERE D.BANK_NO = 'VALUE '.
  AND D.APPL_CD = 'VALUE '.
  AND D.ACCT_NO = 'VALUE '.
  
  Edited by: user648525 13 Sep, 2011 01:21

  I can easily look at your request at this time (using my iPhone on a train).

  But trying out this line in the WHERE (the one with the invalid reference) clause in the main query.

  Who is... in the view of inline, use only the logic of the join (the clauses).

  Overflow the filtering logic (WHERE clause) to the main request. You may need to select some additional inline view columns to make these references work.

• Left Outer Join help...

  Hello world

  I'm still trying to learn the SQL, and I can not specifically with the left outer join.  I normally join tables using equijoin, but I don't get the right data set returns, and designed with the help of a left or right outer join would solve the problem...

  Here is my SQL that works properly with 1 left outer join.  I build the slow query in the SQL following, you will see where I see the error.  I don't expect you to understand the data and the columns, I'm trying to join, I think the problems I encounter are related to syntax, and I hope that you can find where are my syntax errors.

  Select

  s.Name as "Pseudonym,"

  SV.view_name as "name of the view.

  s_view. Name

  Of

  s s_screen,

  s_screen_view sv

  outer join left s_view

  WE (sv.view_name = s_view.name)

  where

  SV.screen_id = ' 1-866 A - 1X3LU' and

  s.ROW_ID = sv.screen_id and

  s.repository_id = ' 866 A-1-1"and

  s_view.repository_id = ' A-1-1 866 ";

  Here is the SQL code where I encounter the following error...

  Error:

  ORA-00904: "SV". "" View_name ": invalid identifier

  00904, 00000 - '% s: invalid identifier '.

  * Cause:

  * Action:

  Error on line: column 14: 7

  Problematic SQL:

  Select

  s.Name as "Pseudonym,"

  SV.view_name as "name of the view.

  s_view. Name,

  s_applet. Name as Applet

  -b.SID like "name of the cmdlet.

  Of

  s s_screen,

  s_screen_view sv,

  wti s_view_wtmpl_it

  outer join left s_view

  WE (sv.view_name = s_view.name)

  outer join left s_applet

  WE (wti.name = s_applet.name)

  where

  SV.screen_id = ' 1-866 A - 1X3LU' and

  s.ROW_ID = sv.screen_id and

  s.repository_id = ' 866 A-1-1"and

  s_view.repository_id = ' A-1-1 866 ";

  Thanks in advance for your help.

  Chris

  > ORA-00904: "S_VIEW_WEB_TMPL." "" ROW_ID ": invalid identifier

  I don't see this table in your FROM clause.

• Using Left Outer Join with reference

  I have three tables.
  Table 1: BOOK_DETAILS
  Fields: BOOK_ID, BOOK_NAME
  
  Table 2: BOOK_ISSUE_RECORD
  Fields: BOOK_ID, USER_NAME
  
  Table 3: BOOK_AUTHOR
  Fields: BOOK_ID, AUTHOR_NAME
  
  I must link table 1 and table 2 with a left outer join, because even if the book is not the questions to anyone, his name should come.
  I have once again display the name of the author of books for each book.
  I am able to create a query with the left outer join between table 1 and table 2. However, I am not able to give a reference to Table 3.
  Can someone help me with this please.
  
  Concerning
  Hawker

  select  d.book_name,
          a.book_author,
          i.user_name
    from       book_details d
          join
               book_author a
            on (d.book_id = a.book_id)
          left join
               book_issue_recors i
            on (d.book_id = i.book_id)
  /
  

  SY.

• Check the status of voice on the 4.0 unit cards (3)

  Hello

  I would like to know how can I test if the voice cards are correctly installed and setup of the unit has completed the installation of the voice card successfully?

  As far as I know is to open the DCM program and check the status of each voice card. Are there other means or tools to check voice cards in more detail?

  Moreover, I found the in Device Manager, the server could only recognize the cards as the unknown PCI devices. Is this normal?

  Thank you

  ---

  Ray

  DCM confirms that the card has been properly installed.

  Regarding the unknown PCI error, it is normal.

  "Note that if you view a voice card using the Windows Device Manager, the card can be displayed as an unknown device PCI with a warning indicating that the drivers for the device are not installed. A found new hardware wizard may also appear for each card during installation or to restart the computer in Cisco Unity. These conditions are the two expected behavior and do not indicate an error or a condition requiring action. You can disable the hardware detected Wizard to prevent it from appearing at restarting the Cisco Unity computer."

  http://www.Cisco.com/en/us/products/SW/voicesw/ps2237/products_installation_guide_chapter09186a00801ba4b6.html#1505050

  H. M.

• How to check the status of the import in Windows?

  Hello
  
  Import runs in my box of Wndows. The log file is not updated since long. How to check the status of the import job? FYI its oracle 10g.
  
  And I checked the database which.
  
  FYI
  ===
  Select * from DBA_DATAPUMP_SESSIONS;
  
  no selected line.
  
  Select * from DBA_JOBS_RUNNING;
  
  no selected line
  
  
  Select the username, machine, module, sid, State, event, seq #, session seconds_in_wait $ v where type <>'IMPORT' and username = "AUTOTIME";
  
  no selected line
  
  
  
  Please let me know.

  You actually look at the session of $ v and check the status of the session that is created by the import job.

  Sometimes the underlying tablespace is full, so import session just hangs, it must increase the size of the storage space.

  You should also look at alert.log file and see if there is any error message like "cannot extend table space '.

• left outer join and the where clause for the table to the right

  I want to join two tables a and b, where a is a must and b is a result set in option. When I use a left outer join to a to b, I want to achieve:
  
  1. Select a single column, two columns of b (not the join columns)
  2 - even if theres no friendly on the join column does not return data from one.
  3. If there is a match applies when the criteria on column b (table in option)
  
  so, how can I avoid no_data_found in this case? When I apply where criteria for b, so it does not return the data from one, which is a must.

  Sounds like a regular outer join to me...

  select a.col1, b.col2, b.col2
  from   tableA a
         left outer join tableB b
         on (a.id = b.id and b.colX = 'X')
  

• What is the difference between NOT IN and LEFT OUTER JOIN

  Hello
  
  I searched the difference between everywhere. But his powerlessness.
  Please tell me the differences.
  
  Thanks in advance
  KVB

  It's like comparing apples and oranges.

  NOT IN - exclude all lines matching the condition NOT IN (beware of NULL values).

  JOIN EXTERNAL - return of rows from the inner table even if there is no corresponding row in the outer table.

  SQL> -- NOT IN
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  where  col1 not in (1,2);
  
        COL1
  ----------
           3
  
  SQL> -- NOT IN (subquery)
  SQL>
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  where  col1 not in (select col1 from y);
  
        COL1
  ----------
           2
           3
  
  SQL> -- OUTER JOIN
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  left outer join
   10         y
   11  on x.col1 = y.col1;
  
        COL1       COL1
  ---------- ----------
           1          1
           3
           2
  
  SQL> -- Maybe it helps to contrast LOJ with just JOIN?
  SQL> with x as
    2  (select 1 col1 from dual union all
    3   select 2 col1 from dual union all
    4   select 3 col1 from dual)
    5  ,    y as
    6  (select 1 col1 from dual)
    7  select *
    8  from   x
    9  join   y
   10  on x.col1 = y.col1;
  
        COL1       COL1
  ---------- ----------
           1          1
  
  SQL> 
  

• Oracle: Use LEFT OUTER JOIN, but convert the data to an external list

  Hello, all,.

  I know it can be done; I just don't remember how I got it done, oh there are so many years.

  Assumes that the tables exist for groups and individuals.  People can belong to several groups.

  SELECT g.groupName, p.lastName || ', ' || p.firstName as fullName
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON gpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  ORDER BY g.groupName, fullName
  

  This gives us:

  Group One          Alpha, Daniel
  Group One          Bravo, Charles
  Group One          Charlie, Chuck
  Group Two          Beta, Alpha
  Group Two          Delta, Bonnie
  Group Three        Echo, Bunny
  Group Three        Golf, Samuel
  Group Three        November, Stan
  

  How word the SQL to get the data as:

  Group One          Alpha, Daniel | Bravo, Charles | Charlie, Chuck
  Group Two          Beta, Alpha | Delta, Bonnie
  Group Three        Echo, Bunny | Golf, Samuel | November, Stan
  

  V/r,

  ^_^

  I finally thought to it.  I was using incorrect keywords on Google.

  SELECT g.groupName, LISTAGG(p.lastName || ', ' || p.firstName,' | ') WITHIN GROUP (ORDER BY g.groupName) "fullName"
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON ggpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  GROUP BY g.groupName
  ORDER BY g.groupName, fullName  
  

  Just in case someone else is going through this same desire.

  HTH,

  ^_^

• Modeling of the left outer join

  Hello world

  I'm tender hand to you guys for a modeling help

  I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model

  Fact and the client are joined through CUST_ID

  FACT and DATE are joined through DATE_ID

  CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS

  If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.

  Application under
  Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
  Of
  F FACT
  JOIN THE
  CUSTOMER C
  ON C.CUST_ID = F.CUST_ID
  JOIN THE
  DIM_DATE D
  ON F.DATE_ID = D.DATE_ID
  LEFT OUTER JOIN
  CUST_ADDRESS CA
  ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_ID

  Thanks in advance

  When I add the CUSTOMER and in FACT LTS CUST_ADDRESS

  Stop it!

  Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?

  You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.

  So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?

  No problem...

  Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.

  In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.

  Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.

  Give it a try at that.

  But do not add these tables in the LTS, they are logical dimensions.

• Problem with XMLTABLE and LEFT OUTER JOIN

  Hi all.
  
  I have a problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns the correct result, but in 10g it doesn't, it is illustrated as a INNER JOIN.
  

  SELECT * FROM v$version;
  
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
  PL/SQL Release 11.2.0.1.0 - Production
  "CORE     11.2.0.1.0     Production"
  TNS for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  --test for 11g
  
  CREATE TABLE XML_TEST(
       ID NUMBER(2,0),
       XML XMLTYPE
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       1,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g1</id>
                           <dat>data1</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       2,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g2</id>
                           <dat>data2</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       3,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g3</id>
                           <dat>data3</dat>
                      </fields>
                      <fields>
                           <id>g4</id>
                           <dat>data4</dat>
                      </fields>
                      <fields>
                           <dat>data5</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4
  3     data5          

  This is all nice, now the problem:
  

  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
  PL/SQL Release 10.2.0.1.0 - Production
  "CORE     10.2.0.1.0     Production"
  TNS for HPUX: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  --exactly the same environment as 11g (tables and rows)
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4

  As you can see in 10g that I don't have the last row, it seems that Oracle 10 g does not recognize the LEFT OUTER JOIN.
  
  Is this a bug?, Metalink says that sometimes we can have an ORA-0600, but in this case there is no error results returned, just incorrect.
  
  Help, please.
  
  Kind regards.

  What about try the original Oracle method for outer joins? Using (+) without the extra space

  XMLTABLE(...COLUMNS ... id XMLTYPE PATH ... ) x,
  XMLTABLE(... PASSING x.id ...) (+) y
  

• Query of queries: error when you try to fake Left Outer Join

  Hello

  I'm trying to reproduce a left outer join, combining two query of queries using a method I find here

  However, I get an error message...

  Here is the code I use...

  < cfquery dbtype = "query" name = "qry" >
  SELECT *.
  OF returnQry, returnQry2
  WHERE returnQry.mediumImage = returnQry2.mediumImage
  ORDER BY returnQry.name
  < / cfquery >
  
  < name cfquery = "returnQry3", dbtype = "#application.mx #" >
  SELECT *.
  OF trackmeanings t
  < / cfquery >

  < cfquery dbtype = "query" name = "endQry" >
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE qry.name = returnQry3.sNameTrack
  
  UNION
  
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE #qry.name # NOT IN (#QuotedValueList (returnQry3.sNameTrack) #)
  GROUP BY name, nameRcd, mediumImage
  < / cfquery >

  When I try to use the query output in a page, I get the error message "incorrect conditional expression, waiting for an a [as |]» null | between | in | "comparison condition.

  Anyone have any ideas?

  Thank you very much

  The items in the list should be cited.  Since you are using quotedvaluelist, it's weird that they aren't.  However, if you use cfqueryparam, list = Yes, you should have better luck.  Among other things, it will protect you against the apostrophe in names.

• LEFT OUTER JOIN, trigger after QUERY problem

  Hello
  
  Guide to please the following
  
  I wrote under query in QUERY after a BLOCK of TABULAR DATA, not as a single text element, called INVENTORY_ITEM
  
  Select c.cat |' '|| s.SubCat |' '|| L1.lvl1 POINT IN: DATABLOCK. INVENTORY_ITEM
  of itemcat c
  LEFT OUTER JOIN itemsubcat s on (c.catid = s.catid)
  LEFT OUTER JOIN lvl1 l1 on (s.subcatid = l1.subcatid)
  
  When I compile the module an error is generated
  
  «* ' Met the 'LEFT' symbol when waiting for one of the following values for the group with intersect less order start union where connect '.» *
  
  Top query works fine with ORACLE SQL DEVELOPER.
  
  Any solution please.
  
  Kind regards

  Difference

• OUTER JOIN query returns the results of JOIN IN-HOUSE 11.2.0.1.0

  I'm data transfer in 11.2.01.0 (Windows XP 32-bit) and I wanted to compare the sizes of table with the same Table name in two different patterns, ML and SILENT, with a FULL OUTER JOIN (to account for all the tables and NULL values in a diagram).
  
  The scheme of ML has 176 tables: schema TUT a 133 tables. The use of a standard INNER JOIN gives 131 paintings.
  
  I get precisely the results with a FULL OUTER JOIN I get with an INTERNAL JOIN (not the same NULL values so I know they exist).
  
  This happens in SQL-Plus, SQL_Developer and using Oracle Wire pilot of Data_Direct.
  
  Here is the code:
  
  Login: SYS as SYSDBA or SYSTEM (same results for either)
  
  SELECT M.TABLE_NAME, M.NUM_ROWS, T.TABLE_NAME, T.NUM_ROWS
  OF SYS. ALL_TABLES M FULL OUTER JOIN SYS. ALL_TABLES T ON M.TABLE_NAME = T.TABLE_NAME
  WHERE
  M.OWNER = 'ML' AND
  T.OWNER = 'TUT';
  
  Produce the same results with LEFT OUTER joins and RIGHT OUTER joins in ASI and Oracle (+) syntax.
  
  Any thoughts?

  Hello

  If you read what I posted, forget it. MScallion (below) gave the correct answerr.

  If conditions such as

  owner   = 'ML'
  

  in the WHERE clause, and then they will reject the rows of the result set formed by the join condition.

  The inner join returns only 131 lines where the two 'paintings' have the same table_names.
  The outer joins return multiple lines (133, 176 or 178) before the place WHERE the provision is applied , but the WHERE clause eliminates all lines except the 131 found by the inner join.

  Published by: Frank Kulash, July 10, 2010 14:23