logic for this query
Hi friends,I use this logic to get the MEP who's birthday this month...
SELECT *.
WCP
WHERE TO_CHAR (hire_date, "MM") = TO_CHAR (SYSDATE, 'MM')
but I want only these emp which the join date is more than a year...
How to get that
Thanks in advance
Hello
Try this
with datetab as (
select to_date('10-03-2010','dd-mm-rrrr') as hire_dt from dual union
select to_date('10-03-2011','dd-mm-rrrr') as hire_dt from dual union
select to_date('10-03-2009','dd-mm-rrrr') as hire_dt from dual)
select * from datetab where to_char(hire_dt,'MM') = to_char(sysdate,'MM') and (to_char(sysdate,'rrrr') - to_char(hire_dt,'rrrr')) >= 1
see you soon
VT
Tags: Database
Similar Questions
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Why between date is not return data for this query?
Hello
I have a table with this structure and I write this query to retrieve a few lines based on certain conditions, but this query returns no data. Can you please tell why?
ID DT 003 11/8/2011 002 10/8/2011 001 9/8/2011And the execution of the query:
Published by: starting August 13, 2011 07:10SELECT * FROM TABLE_NAME WHERE DT BETWEEN TO_DATE('08/08/2011','dd/mm/yyyy') AND TO_DATE('12/08/2011','dd/mm/yyyy');
>
>
But what is the problem with that, why this date does not match when I'm providing the date format?
What part don't you understand? You have not used TO_DATE when inserting data and default date format is dd/mm/yyyy, right? Same default date format is used if you are running:
SELECT * FROM TABLE_NAME
Original of your post States select returns above:
ID DT 003 11/8/2011 002 10/8/2011 001 9/8/2011So the dates that you inserted are November 8, 2011, October 8, 2011-September 8, 2011. TO_DATE('08/08/2011','dd/mm/yyyy') is now August 8, 2011 and TO_DATE('12/08/2011','dd/mm/yyyy') is August 12, 2011. Then of course:
SELECT * FROM TABLE_NAME WHERE DT BETWEEN TO_DATE('08/08/2011','dd/mm/yyyy') AND TO_DATE('12/08/2011','dd/mm/yyyy').
will return all the lines. Bottome line - never write code that uses the implicit conversions date since your code becomes dependent on the NLS client settings and maybe working for a client and fail or produce erroneous results for other customers.
SY.
-
Hi gurus
need help with this query,
I want to display the records in the table emp
I want just the recordsSQL> Select Deptno,sal,sal/SUMSAL Percent,rn 2 From ( Select emp.*,Sum(Sal) Over() "SUMSAL",Row_number() Over(Order by sal Desc) rn 3 From emp 4 ) 5 / EMPNO DEPTNO SAL PERCENT RN --------- ---------- ---------- ---------- ---------- 7839 10 5000 .172265289 1 7902 20 3000 .103359173 2 7788 20 3000 .103359173 3 7566 20 2975 .102497847 4 7698 30 2850 .098191214 5 7782 10 2450 .084409991 6 7499 30 1600 .055124892 7 7844 30 1500 .051679587 8 7934 10 1300 .044788975 9 7521 30 1250 .043066322 10 7654 30 1250 .043066322 11 7876 20 1100 .037898363 12 7900 30 950 .032730405 13 7369 20 800 .027562446 14 14 rows selected.
Thank youEMPNO DEPTNO SAL PERCENT RN ---------- ---------- ---------- ---------- ---------- 7839 10 5000 .172265289 1 7902 20 3000 .103359173 2 7788 20 3000 .103359173 3 7566 20 2975 .102497847 4 7698 30 2850 .098191214 5 with sum (Percent) of remaing records..... Others .420327304
Published by: SeenuGuddu on February 27, 2011 03:39with a as ( Select Empno, Deptno ,sal, sal/SUMSAL Percent, case when rn<=5 then rn else null end rnm From (Select emp.*, Sum(Sal) Over() "SUMSAL", Row_number() Over(Order by sal Desc) rn From emp) ) select case when max(rnm) is not null then to_char(max(empno)) else 'Others:' end empno, case when max(rnm) is not null then max(deptno) else null end deptno, case when max(rnm) is not null then max(sal) else null end sal, to_char(sum(percent), '90.99') percent, max(rnm) rn from a group by rnm order by rnmEMPNO DEPTNO SAL PERCENT RN ---------------------------------------- ---------------------- ---------------------- ------- ---------------------- 7839 10 5000 0.17 1 7902 20 3000 0.10 2 7788 20 3000 0.10 3 7566 20 2975 0.10 4 7698 30 2850 0.10 5 Others: 0.42 6 rows selected -
Please help get the logic for this
Hello Frs,
I need like if a number is a whole number divide by 100, otherwise if we number integer (for ex 500.23) then leave it as it is how to write a logic to find out if a number is integer or not?
I need to write a function similar to the following
Begin
If invoice_amount = 500 (integer)
then a = invoice_amount/100;
on the other
a = invoice_amount;
end if;
return a;
end;
If anyone has idea pls help
Thank you
MarilouHello
You can do this in SQL by using the CASE statement.
For example:SELECT CASE WHEN invoice_amount = TRUNC (invoice_amount) THEN invloce_amount / 100 ELSE invoice_amount END AS a...
-
Hello
I am getting an error for the below query
"Keyword not found where expected"
I need to use the Banking Code as alias, how do I change the following query?
Select bank_code as rm_nrd_csr Bank CodeHello
Remove the space in the aliasSelect bank_code in the code of rm_nrd_csr
(or)
Use quotesSelect bank_code in the "Bank Code" in rm_nrd_csr
Kind regards
Simma. -
Hi friends,
My requirement is a bit strange
I ' l explain cases...
It's fake
/ * Select
When case months_between(:fut_date,sysdate) > 1
then turn (months_between (: fut_date, sysdate))
on the other
CEIL (MONTHS_BETWEEN (: fut_date, sysdate))
double end * /.
I wrote this one which takes a date parameters and should give me the results as specified below... but does not very well
test conditions are
When the parameter is * 30 - Apr - 2011 * and sysdate is * 23 - Apr - 2011 * should give me * 0 *.
When the parameter is * 31-May-2011 * and sysdate is * 01 - apr - 2011 * should give me * 1 *.
When the parameter is * January 30, 2012 * and sysdate is * 01 - dec - 2011 * should give me * 1 *.
When the parameter is * June 30, 2011 * and sysdate is * 01 - apr - 2011 * should give me * 2 *.
When the parameter is * June 30, 2011 * and sysdate is * 21 - Apr - 2011 * should give me * 2 *.
When the parameter is * August 30, 2011 * and sysdate is * 21 - Apr - 2011 * should give me * 4 *.
When the parameter is * August 30, 2011 * and sysdate is * 01 - apr - 2011 * should give me * 4 *.
When the parameter is * 30 - Apr - 2011 * and sysdate is * 30 - Apr - 2011 * should give me * 4 *.
hope am clear
Thanks in advanceHello
If you want the months between the two dates (an integer), no matter where in the month, those dates are. For example, if fut_dat in the month of August and SYSDATE is in April of the same year, the result should be 4. It does not matter if fut_dat is the beginning, middle or end of the month of August, the result is always exactly 4 and it does not matter if SYSDATE is at the beginning, middle or end of April, the result is always exactly 4.
Is this fair?If so:
MONTHS_BETWEEN ( TRUNC (fut_dat, 'MONTH') , TRUNC (SYSDATE, 'MONTH') )TRUNC (dt, 'MONTH') returns a DATE that is the 1st of the month even as dt.
MONTHS_BETWEEN (T2D, t1d) returns an integer if t1d and T2D are the day of their month (for example, if they are both the 1st of the month).This assumes that the fut_dat data type is date. If: fut_dat is a VARCHAR2, then use TO_DATE (: fut_dat,...) where I used fut_dat.
776317 wrote:
... when the parameter is * 30 - Apr - 2011 * and sysdate is * 30 - Apr - 2011 * should give me * 4 *.It must be a typing mistake. You don't want to 0, not 4?
I hope that answers your question.
If not, post a small example of data (for example, CREATE TABLE, and only relevant columns, INSERT statements), and the results you want from this data.
Explain how you get these results from these data.
Always tell what version of Oracle you are using.Published by: Frank Kulash, April 23, 2011 05:43
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Another approach for this query
Hi all
We can write better than the following query?
SELECT SUBSTR (TO_CHAR (SUM (TO_NUMBER (SUBSTR (12344 / 222 / 333, 1, 8))),))
LENGTH (SUM (TO_NUMBER (SUBSTR (12344 / 222 / 333, 1, 8)))-9)
)
OF THE DOUBLE
Thank you
And demonstrate that with "columns" of data...
SQL > ed
A written file afiedt.buf1 with mytable as (select '12344 ' a, '222' b, 333' double c)
2 --
3 end of table simulated
4 --
5. SELECT floor (mod ((A/B/C) * power (10.7), 10))
6 * from myTable
SQL > /.FLOOR (MOD ((A/B/C) * POWER (10.7), 10))
----------------------------------
7 -
How to use the case for this query.
I got this name from the Employee table.
columns...
EmpId,
EmpType,
Join date,
Date of resignation
Now in EmpType it can be either 'P' OR 'C '.
So I want to check if the EmpTYpe is 'P' then joiningdate must not be null
and if the EmpType is 'C' then resignation date must not be null.
So only want to employee records.
Help, please.Select * from employee
where (employeetype = 'c' and joinngdate is not null)
or (employeetype = 'p' and resigndate is not null) -
How to get the total number of records for this query
SELECT SSN, FIRST, MID, LAST, UCX_UCFE, TRAPOSS, DUAPOSS, CLAIM_SEQ, CLAIM_DT, MAX (INSERT_DT) INSERT_DT.
CLAIM_STAT, ISSUE_CDE, AGENT_ID FROM (SELECT A.SSN, A.FIRST A.MID, A.LAST, B.UCX_UCFE, B.TRAPOSS, B.DUAPOSS,
C.CLAIM_SEQ, C.CLAIM_DT, C.INSERT_DT, C.CLAIM_STAT, C.ISSUE_CDE,
RN C.AGENT_ID, ROWNUM
THE APPLICANT HAS, CLMTELIG B, UICLAIMS C
WHERE A.CLMT_SEQ = B.CLMT_SEQ AND B.CLMT_SEQ = C.CLMT_SEQ AND TRUNC (C.INSERT_DT) BETWEEN 1 JANUARY 09 ' AND 5 JANUARY 09')
GROUP OF NSS, BEGINNING, MIDDLE, LAST, UCX_UCFE, TRAPOSS, DUAPOSS, CLAIM_SEQ, CLAIM_DT, CLAIM_STAT, ISSUE_CDE, AGENT_ID
Thank you all in advance for watching in my post.Select count (*)
Of
(.. .your question here...) ; -
I want to migrate data from DataBase1 base2 which has different structures.
Base2 table has values from several tables from base1. I use IBM Datastage designer for migration.
Can someone help me to write the logic for this. Thanks in advance...
I should pull data base1 to base2 based on Emp_id
DataBase1.Table1:
EmpID EmpName Startdt Traineddt projectdt projectenddt enddt 1 XXX 1-Jan-2013 15-jan-2013 16-jan-2013 1-may-2013 1-Jun-2013 2 YYY 3rd-Jan-2013 6-Jun-2013 (null) (null) 7th-Aug-2013 DataBase1.Table2:
EmpID DeptID DeptName 1 100 HE 2 200 ADMIN DataBase2.Table1 (Target_Table):
Emp_id DeptID DeptName Date_Type Date 1 100 HE Start_dt 1-Jan-2013 1 100 HE Trined_date 15-jan-2013 1 100 HE Project_dt 16-jan-2013 1 100 HE Project_finish_dt 1-may-2013 1 100 HE End_dt 1-Jun-2013 2 200 ADMIN Start_dt 3rd-Jan-2013 2 200 ADMIN Trained_dt 6-Jun-2013 2 200 ADMIN End_dt 7th-Aug-2013 2 200 ADMIN project_dt (null) 2 200 ADMIN project_finish_dt (null) Thank you
Suma
with
emp_table as
(select empid 1, "XXX" empname, to_date('Jan-1-2013','Mon-dd-yyyy') startdt, to_date('Jan-15-2013','Mon-dd-yyyy') traineddt, to_date('Jan-16-2013','Mon-dd-yyyy') projectdt, to_date('May-1-2013','Mon-dd-yyyy') projectenddt, to_date('Jun-1-2013','Mon-dd-yyyy') enddt of all the double union)
Select 2,'YYY',to_date('Jan-3-2013','Mon-dd-yyyy'),to_date('Jun-6-2013','Mon-dd-yyyy'),null,null,to_date('Aug-7-2013','Mon-dd-yyyy ') of double
),
dept_table as
(select empid 1, 100 deptid, deptname Union ' IT' double all the)
Select 2 200, 'ADMIN' of the double
)
Select empid, deptid, deptname, date_type, to_char(date_,'fmMon-ddth-yyyy') date_
from (select d.empid d.deptid, d.deptname, e.startdt, e.traineddt, e.projectdt, e.projectenddt, e.enddt
dept_table d,
e emp_table
where d.empid = e.empid
)
must include null values (date_ for date_type in (startdt as 'Start_dt', traineddt as 'Trained_dt', projectdt as 'Project_dt',
projectenddt as 'Project_finish_dt', enddt as 'End_dt '.
)
)
EMPID DEPTID DEPTNAME DATE_TYPE DATE_ 1 100 HE Start_dt 1-Jan-2013 1 100 HE Trained_dt 15-jan-2013 1 100 HE Project_dt 16-jan-2013 1 100 HE Project_finish_dt 1-may-2013 1 100 HE End_dt 1-Jun-2013 2 200 ADMIN Start_dt 3rd-Jan-2013 2 200 ADMIN Trained_dt 6-Jun-2013 2 200 ADMIN Project_dt - 2 200 ADMIN Project_finish_dt - 2 200 ADMIN End_dt 7th-Aug-2013 Concerning
Etbin
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Logic of SQL query for shipping to calculate prices
Hi Experts,
As I have created a thread already in this regard. You can refer to my previous thread in [previous Thread: http://forums.oracle.com/forums/thread.jspa?threadID=1027799 & tstart = 0]
I'll post my question again in this thread
Records from the tableSHIPMENT_ID SHIPMENT_PRICE SHIPMENT_ADDT_PRICE PRODUCT_ID PRODUCT_QTY VIRTUAL_COLUMN (Just for your Reference) 1000 6.95 2 11 4 1 1000 6.95 2 11 4 2 1000 3.95 1 13 2 3 1000 3.95 1 12 2 4 1001 12.95 2 11 4 5 1001 12.95 1 13 2 6 1001 12.95 2 11 4 7 1001 12.95 1 12 2 8 1002 20.95 1 12 2 9 1002 20.95 2 11 4 10 1002 20.95 2 11 4 11 1002 20.95 1 13 2 12
*Repeated values in table with Maximum Value, SHIPMENT_ID SHIP_PRICE SHIPMENT_ADDT_PRICE PRODUCT_QTY PRODUCT_ID VIRTUAL_COLUMN 1000 6.95 2 4 11 1 1000 6.95 2 4 11 2 1001 12.95 2 4 11 5 1001 12.95 2 4 11 7 1002 20.95 2 4 11 10 1002 20.95 2 4 11 11
In this case, there are two same lines with a maximum value for all shipments of three,
but the need to take a line like maximum and to consider the other as not maximum line to process logic
*
I looked at the folder with the value VIRTUAL_COLUMN 1.5 and 10 as maximum value and other values not maximum
* Note: The virtual column in the data provided is just for the reference and not exists in the tableExpected Result (For Each Row) - Just listed for one shipment_id = 1000 here SHIPMENT_ID SHIP_PRICE CALCULATION STEPS VIRTUAL_COLUMN 1000 41.7 (1*6.95)+((4-1)*2) Maximum ShipPrice + (PRODUCT_QTY-1)*SHIPMENT_ADDT_PRICE 1 1000 8 (4*2) PRODUCT_QTY*SHIPMENT_ADDT_PRICE 2 1000 2 (2*1) PRODUCT_QTY*SHIPMENT_ADDT_PRICE 3 1000 2 (2*1) PRODUCT_QTY*SHIPMENT_ADDT_PRICE 4
Thank you
Dharan VQueries 1 and query 2 are wrong because two of them use the SHIPMENT_PRICE of the line and not the MAXIMUM SHIPMENT_PRICE for this product like you id requested in the original message.
To get the MOST out of SHIPMENT_PRICE, you must use my last request:SQL> with shipment_table as ( 2 select 1000 SHIPMENT_ID, 6.95 SHIPMENT_PRICE, 2 SHIPMENT_ADDT_PRICE, 3 11 PRODUCT_ID, 4 PRODUCT_QTY, 1 VIRTUAL_COLUMN from dual union 4 select 1000,6.95,2,11,4,2 from dual union 5 select 1000,6.95,2,11,4,3 from dual union 6 select 1000,6.95,2,11,4,4 from dual union 7 select 1001,12.95,2,11,4,5 from dual union 8 select 1001,12.95,2,11,4,6 from dual union 9 select 1001,12.95,2,11,4,7 from dual union 10 select 1001,12.95,2,11,4,8 from dual union 11 select 1002,20.95,1,12,2,9 from dual union 12 select 1002,20.95,1,12,2,10 from dual union 13 select 1002,20.95,1,12,2,11 from dual union 14 select 1002,20.95,1,12,2,12 from dual) 15 SELECT shipment_id, 16 shipment_price, 17 shipment_addt_price, 18 product_id, 19 product_qty, 20 CASE 21 WHEN ROW_NUMBER() OVER (PARTITION BY shipment_id 22 ORDER BY shipment_addt_price DESC) = 1 23 THEN 24 (max(shipment_price) over (PARTITION BY shipment_id)) 25 + (product_qty - 1) * shipment_addt_price 26 ELSE 27 product_qty * shipment_addt_price 28 END price 29 FROM shipment_table; SHIPMENT_ID SHIPMENT_PRICE SHIPMENT_ADDT_PRICE PRODUCT_ID PRODUCT_QTY PRICE ----------- -------------- ------------------- ---------- ----------- -------------- 1000 6,95 2 11 4 12.9500 1000 6,95 2 11 4 8.0000 1000 6,95 2 11 4 8.0000 1000 6,95 2 11 4 8.0000 1001 12,95 2 11 4 18.9500 1001 12,95 2 11 4 8.0000 1001 12,95 2 11 4 8.0000 1001 12,95 2 11 4 8.0000 1002 20,95 1 12 2 21.9500 1002 20,95 1 12 2 2.0000 1002 20,95 1 12 2 2.0000 1002 20,95 1 12 2 2.0000 12 rows selected.Look at line 24 of the query and you will see the difference.
On your data, there is no difference because the same product as always the same shipment_price...
We will change a value in the sample data:Query 1
SQL> with shipment_table as ( 2 select 1000 SHIPMENT_ID, 6.95 SHIPMENT_PRICE, 2 SHIPMENT_ADDT_PRICE, 3 11 PRODUCT_ID, 4 PRODUCT_QTY, 1 VIRTUAL_COLUMN from dual union 4 select 1000,6.95,2,11,4,2 from dual union 5 select 1000,100.95,2,11,4,3 from dual union 6 select 1000,6.95,2,11,4,4 from dual union 7 select 1001,12.95,2,11,4,5 from dual union 8 select 1001,12.95,2,11,4,6 from dual union 9 select 1001,12.95,2,11,4,7 from dual union 10 select 1001,12.95,2,11,4,8 from dual union 11 select 1002,20.95,1,12,2,9 from dual union 12 select 1002,20.95,1,12,2,10 from dual union 13 select 1002,20.95,1,12,2,11 from dual union 14 select 1002,20.95,1,12,2,12 from dual) 15 SELECT 16 SHIPMENT_ID, 17 SHIPMENT_PRICE, 18 SHIPMENT_ADDT_PRICE, 19 PRODUCT_ID, 20 PRODUCT_QTY, 21 CASE 22 WHEN ROW_NUMBER() OVER (PARTITION BY SHIPMENT_ID 23 ORDER BY SHIPMENT_ADDT_PRICE DESC) = 1 24 THEN 25 SHIPMENT_PRICE + (PRODUCT_QTY - 1) * SHIPMENT_ADDT_PRICE 26 ELSE 27 PRODUCT_QTY * SHIPMENT_ADDT_PRICE 28 END NEW_SHIP_PRICE 29 FROM shipment_table; SHIPMENT_ID SHIPMENT_PRICE SHIPMENT_ADDT_PRICE PRODUCT_ID PRODUCT_QTY NEW_SHIP_PRICE ----------- -------------- ------------------- ---------- ----------- -------------- 1000 6,95 2 11 4 12,95 1000 6,95 2 11 4 8 1000 6,95 2 11 4 8 1000 100,95 2 11 4 8 1001 12,95 2 11 4 18,95 1001 12,95 2 11 4 8 1001 12,95 2 11 4 8 1001 12,95 2 11 4 8 1002 20,95 1 12 2 21,95 1002 20,95 1 12 2 2 1002 20,95 1 12 2 2 1002 20,95 1 12 2 2 12 rows selected.My query:
SQL> with shipment_table as ( 2 select 1000 SHIPMENT_ID, 6.95 SHIPMENT_PRICE, 2 SHIPMENT_ADDT_PRICE, 3 11 PRODUCT_ID, 4 PRODUCT_QTY, 1 VIRTUAL_COLUMN from dual union 4 select 1000,6.95,2,11,4,2 from dual union 5 select 1000,100.95,2,11,4,3 from dual union 6 select 1000,6.95,2,11,4,4 from dual union 7 select 1001,12.95,2,11,4,5 from dual union 8 select 1001,12.95,2,11,4,6 from dual union 9 select 1001,12.95,2,11,4,7 from dual union 10 select 1001,12.95,2,11,4,8 from dual union 11 select 1002,20.95,1,12,2,9 from dual union 12 select 1002,20.95,1,12,2,10 from dual union 13 select 1002,20.95,1,12,2,11 from dual union 14 select 1002,20.95,1,12,2,12 from dual) 15 SELECT shipment_id, 16 shipment_price, 17 shipment_addt_price, 18 product_id, 19 product_qty, 20 CASE 21 WHEN ROW_NUMBER() OVER (PARTITION BY shipment_id 22 ORDER BY shipment_addt_price DESC) = 1 23 THEN 24 (max(shipment_price) over (PARTITION BY shipment_id)) 25 + (product_qty - 1) * shipment_addt_price 26 ELSE 27 product_qty * shipment_addt_price 28 END price 29 FROM shipment_table; SHIPMENT_ID SHIPMENT_PRICE SHIPMENT_ADDT_PRICE PRODUCT_ID PRODUCT_QTY PRICE ----------- -------------- ------------------- ---------- ----------- -------------- 1000 6,95 2 11 4 106.9500 1000 6,95 2 11 4 8.0000 1000 6,95 2 11 4 8.0000 1000 100,95 2 11 4 8.0000 1001 12,95 2 11 4 18.9500 1001 12,95 2 11 4 8.0000 1001 12,95 2 11 4 8.0000 1001 12,95 2 11 4 8.0000 1002 20,95 1 12 2 21.9500 1002 20,95 1 12 2 2.0000 1002 20,95 1 12 2 2.0000 1002 20,95 1 12 2 2.0000 12 rows selected.Max
http://oracleitalia.WordPress.comPublished by: Massimo Ruocchio, February 12, 2010 15:10
Examples added -
Windows Update driver Fresco Logic USB Hub rot caused the pilot to read device status: the drivers for this device are not installed. (Code 28). The Roll Back button is not active. Where can I get the previous driver that came with my system. ASUS N53S Windows 7. Thank you very much.
Hello
Thanks for posting in the Microsoft Community.
I understand your annoyance that you cannot update the driver hub USB rot. Please follow the steps below to help you to solve the problem.
I would like to inform you that a Code 28 error is caused by a driver missing for that piece of hardware.
There are all sorts of reasons that a driver could not be installed for a device, but your troubleshooting the problem will be the same regardless of the root cause.
- Remove or reconfigure newly installed unit.
- Restore the version before your driver update.
- Use system restore to undo recent changes in Device Manager.
Step 1: Roll back the driver to the version before your update.
If you are having problems with your computer or device after upgrading sound driver, you can restore to an earlier device driver. If you are having problems with your computer or device after upgrading sound driver, you can restore to an earlier device driver. If you are having problems with your computer or device after upgrading sound driver, you can restore to an earlier device driver. If you are having problems with your computer or device after upgrading sound driver, you can restore to an earlier device driver. Check out the link below to make back the driver:
http://Windows.Microsoft.com/en-in/Windows/restore-driver-previous-version#1TC=Windows-7
When Windows 7 starts up again, it will load with the device driver of this material that you had previously installed.
I suggest you to uninstall the driver from hub to rot Fresco Logic USB Device Manager and install the most recent on the manufacturer's Web site.
Tips for solving common driver problems:
http://Windows.Microsoft.com/en-us/Windows7/tips-for-fixing-common-driver-problems
Hope this information is useful. Feel free to get back to us for further questions or problems related to the Windows operating system.
Thank you.
-
Kindly guide me for small query, try to implement the logic of filtering below
Hi all
Ask your kind help in small query below. I need help for Bold Italic clause of the query.
Without bold italics, this query returns 10 records. With below the case diagram, you can understand my concern.
My requirement is to add the three parameters of input as I_PROCESS_ID, I_BASE_CCY, I_SEC_CCY filter. I'm not able to satisfy the CASE 1. Please guide...
If I put all NULL entries, I get no recording while I need to get all THE records with all three input parameter with null value.
CASE I_PROCESS_ID I_BASE_CCY I_SEC_CCY Expected result Comments 1 NULL VALUE NULL VALUE NULL VALUE 10 lines Need help 2 NOT NULL NULL VALUE NULL VALUE Rows filtered on the basis of ID_processus Works well 3 NULL VALUE NOT NULL NOT NULL Rows filtered on the basis of BASE_CCY & SEC_CCY Works well SELECT FT. ID_PROCESSUS,
FT. FEED_DT,
CARD. NORMALIZED_BASE_CCY,
CARD. NORMALIZED_SECONDARY_CCY
OF SAGEDBO. FX_TRANS_REPLICA_90DAYS FT,
(SELECT DISTINCT BASE_CCY, SECONDARY_CCY
OF SAGEDBO. FX_CCY_NORMALIZATION_MAP
) MAP
WHERE PI. BASE_CCY = MAP. BASE_CCY
AND PI. SECONDARY_CCY = MAP. SECONDARY_CCY
AND)
(FT. ID_PROCESSUS = I_PROCESS_ID
OR
(
CARD. BASE_CCY = I_BASE_CCY
AND
CARD. SECONDARY_CCY = I_SEC_CCY
)
)
);
So if the I_... are of non-null values, they should be used to filter the results, but if they are null all results should be returned? Try something like this:
(FT. ID_PROCESSUS = I_PROCESS_ID OR I_PROCESS_ID IS NULL)
AND
((MAP. BASE_CCY = I_BASE_CCY AND MAP. (SECONDARY_CCY = I_SEC_CCY) OR (I_BASE_CCY IS NULL AND I_SEC_CCY IS NULL))
-
Dialog box that says ' Creative Cloud Installer wants to make changes. Type your password for this purpose"- I type my password for Adobe ID (creative cloud), but it will not accept it. who should I go for help with this query?
It does not ask the cloud your computer admin password password!
-
How to make the simple query for this scenario... ?
Hello:
Dummy table provided for simplicity.
It's my database table (Table_A)
Date1 | Plane1 | Category | Duration | Fees
01/01/2011 | A | Gold | 5. 2
01/01/2011 | C | Money | 4. 11
01/01/2011 | B | Gold | 6. 2
01/01/2011 | D | Gold | 2. 4
01/01/2011 | B | Gold | 3. 5
01/01/2011 | A | Money | 4. 8
01/01/2011 | B | Gold | 1. 3
I need to write a query to get the result below:
Date1 | Plane1 | Sum_Duration | Sum_Charge | Sum_Gold_Duration | Sum_Gold_Charge | Sum_Silver_Duration | Sum_Silver_Charge
01/01/2011 | A | 9. 10. 5. 2. 4. 8
01/01/2011 | B | 10. 10. 10. 10. 0 | 0
01/01/2011 | C | 4. 11. 0 | 0 | 4. 11
01/01/2011 | D | 2. 4. 2. 4. 0 | 0
This query will provide the 1st four columns:
SELECT Date1,
base1,
Sum (Duration) Sum_Duration,
Sum (load) Sum_Charge
FROM TABLE_A
GROUP BY date1, rarateplan
But I need to know how to get the rest of the columns (i.e. Summary according to categories; from 5 to 8 columns)? Is this can be done in a single query without writing subqueries?
Please let me know, (with code), the best way.
Thank you-
TanvirUse like this:
SELECT Date1,
base1,
Sum (Duration) Sum_Duration,
Sum (load) Sum_Charge,
SUM (decode(Category,'Gold',duration,0)) Sum_Gold_Duration,
SUM (decode(Category,'Gold',charge,0)) Sum_Gold_charge,
SUM (decode(Category,'Silver',duration,0)) Sum_Silver_Duration,
SUM (decode(Category,'Silver',charge,0)) Sum_Silver_charge
FROM TABLE_A
GROUP BY date1, rarateplanPublished by: SANT007 on August 11, 2011 11:04
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Escalation of the Dispute of Charge
Hello Several counts of Apple a few months old, I noticed on my checking account. I had problems with this before where my child charged in-app purchases, and Apple has been kind enough to help me with these. When I question them last time I asked if
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No sound until what I press turn on/off
I'm having the same issue here: [http://forums.computers.toshiba-europe.com/forums/thread.jspa?threadID=57055] I don't get all the sounds unless I press toggle at the top right of the keyboard. It's nothing to do with windows (windows shows her is pa
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Hello people NOR wise. I am using the below attached text file to control a series of taps. After several tries, I get errors (200524, etc.) and when it runs the sequence is far away. I have an idea were I'm messing things up, but I need some ideas o
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[Aspire One] Tilt screen breaks webcam and USB
I have a netbook Aspire One ZG5 with Windows XP Home edition. If I tilt/adjust the screen at all, I get two problems: (1) I heard the familiar sound of cutting something of a USB port, a USB icon appears in the system tray temporarily. It is said th
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G6-1b23ca: upgrade HDD 1 TB - HP Pavilion g6-1b23ca
I have a HP Pavilion g6-1b23ca (purple) without a HARD drive and was eager to put in a 1 TB HARD drive, but I'm not sure what will be compatible and FAST. . I'm 'hope' to spend less than $100, or even $80 if possible. I use it for most, movies, and g