Kindly guide me for small query, try to implement the logic of filtering below

Similar Questions

• Support for PIVOT query (or advice on the best way to do it)

  Hi gurus of SQL,.
  
  I'd appreciate any help you could provide on this request, I'm assuming that the best way to do this would be by using the PIVOT function. I read through some of the documents and books, and done some research here in the forums, but can't seem to find a way to make it work.
  
  I'm on Oracle 11.1.0.6.0 self.
  
  I have a table like this:
  

  ID     Product          Month_A_Amt Month_B_Amt Month_C_Amt     Month_D_Amt
  
  123     ProductA     3          5          7          9
  123     ProductB     2          4          6          8
  123     ProductC     10          11          12          13
  456     ProductA     1          2          3          4
  456     ProductB     3          4          5          6

  We get this data each month - Month_A is always the most recent month, and so it goes back for this game, Month_A is 09 November, Month_B is October 09, Month_C is Sept 09, etc. I'm OK with Hardcoding this value each month, so for the purposes of this exercise, just assume that Month_A is the 09 November, Month_B is Oct 09, Month_C is Sept 09 and Month_D is Aug 09.
  
  I need essentially "Pivot" in this table, so the end result looks like this:
  

  ID     Month          Product_A_Amt     Product_B_Amt     Product_C_Amt
  
  123     Nov 09          3          2          10
  123     Oct 09          5          4          11
  123     Sep 09          7          6          12
  123     Aug 09          9          8          13
  456     Nov 09          1          3          null
  456     Oct 09          2          4          null
  456     Sep 09          3          5          null
  456     Aug 09          4          6          null

  Here's the SQL code to create the database with test data table. Now that I've typed this explanation, it still seems easier that I had done it to be... but I'm still confused, so any help is greatly appreciated, thank you!
  
  create table test_base_table)
  Identification number,
  Product varchar2 (20).
  Number of Month_a_amt
  Number of Month_b_amt
  Number of Month_c_amt
  Number of Month_d_amt);
  
  insert into test_base_table values (123, "ProductA', 3, 5, 7, 9);
  insert into test_base_table values (123, "ProductB", 2, 4, 6, 8);
  insert into test_base_table values (123, "ProductC", 10, 11, 12, 13);
  insert into test_base_table values (456, 'ProductA", 1, 2, 3, 4);
  insert into test_base_table values (456, 'ProductB', 3, 4, 5, 6);
  
  Published by: TheBlakester on February 10, 2010 19:56

  Hello

  You don't want to make several clauses UNPIVOT and PIVOT; you want to do several sets of columns in a cluase PIVOT and UNPIVOT one clause.

  In the UNPIVOT clause, it's just a matter of replacing the unique "amt" column before the keyword FOR with a list in parentheses '(amt_1, amt_2)' and the replacement of each column in the list (for example, "month_a_amt") with a list of the same length ("(month_a_amt_1, month_a_amt_2)" ").
  In the PIVOT clause, it's just a matter of replacing the unique "SUM (amt)" aggregate function with a list of unparenthesized of functions, each with an alias ("the SUM (amt_1) AS amt_1, SUM (amt_2) AS amt_2'. The alias that will be added at the end of the givien for names output column in the IN clause.

  SELECT       id
  ,       TO_CHAR ( ADD_MONTHS ( TO_DATE ( 'Nov 2009'
                                          , 'Mon YYYY'
                            )
                        , month_num
                        )
              , 'Mon YYYY'
              )          AS month
  ,       product_a_amt_1
  ,       product_a_amt_2
  ,       product_b_amt_1
  ,       product_b_amt_2
  ,       product_c_amt_1
  ,       product_c_amt_2
  FROM       test_base_table
  UNPIVOT       ( (amt_1,         amt_2      )     FOR month_num IN (
           (month_a_amt_1, month_a_amt_2)     AS  0,
           (month_b_amt_1, month_b_amt_2)     AS -1,
           (month_c_amt_1, month_c_amt_2)     AS -3,
           (month_d_amt_1, month_d_amt_2)     AS -4              )
         )
  PIVOT       ( SUM (amt_1) AS amt_1
         , SUM (amt_2) AS amt_2 FOR product IN ( 'ProductA' AS product_a
                                                      , 'ProductB' AS product_b
                                     , 'ProductC' AS product_c
                                     )
         )
  ORDER BY  id
  ,            month_num     DESC
  ;
  

  Output:

  .              PRODUCT  PRODUCT  PRODUCT  PRODUCT  PRODUCT  PRODUCT
    ID MONTH    _A_AMT_1 _A_AMT_2 _B_AMT_1 _B_AMT_2 _C_AMT_1 _C_AMT_2
  ---- -------- -------- -------- -------- -------- -------- --------
   123 Nov 2009        3        9        2        9       10        9
   123 Oct 2009        5        9        4        9       11        9
   123 Aug 2009        7        9        6        9       12        9
   123 Jul 2009        9        9        8        9       13        9
   456 Nov 2009        1        9        3        9
   456 Oct 2009        2        9        4        9
   456 Aug 2009        3        9        5        9
   456 Jul 2009        4        9        6        9
  

  It looks like all the new values of amt2 are 9. Don't you think it's the best test? I think that different numbers, as you used for the examples of previous data, reduce the chances of getting good results purely by chance.

  If you want to experiment with queries like this, I suggest you use "SELECT *" (nothing added) in the SELECT clause. Start with just an UNPIVOT operation. Some examples in the documentation to do a TABLE CREATION AS... to save the results of an UNPIVOT operator and use this table as the base for a PIVOT table. I think it's a good idea to reduce confusion.

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• Rewrite the query, select below or try to get the necessary O/P

  Hello..
  
  My example of data.,.
  
  Create table customer (name varchar2 (10), telephone1 telephone2 number (10), number of phone3 (10), (10) number, bitwisephone number (10));
  
  Insert into customer values('a',23456,67890,null,12345);
  
  Insert into customer values ('b', 67459,89760,null, 37689);
  
  create table do_not_call (dont_call number (10));
  
  insert into do_not_call values (67890);
  
  insert into do_not_call values (37689);
  
  Question: -.
  --------------
  
  Customer 'a' has value of numbers1 as 23456.check if telephone1 exists in the do_not_call table.
  In fact there is no, so set the bit for numbers1 as "o" like wise search telephone2
  & phone3.after update of the bitwisephone for each client should be as the output below.
  
  
  Need to O/P: -.
  -------------------
  
  name bitwisephone
  
  a 010
  b 001
  
  
  For that matter... I use "any" operator...
  
  
  
  SELECT name, case when numbers1 = all (SELECT dont_call FROM do_not_call) and then put an end to '1' other '0'.
  -case when telephone2 = all (SELECT dont_call FROM do_not_call) and then put an end to '1' other '0'.
  -case when phone3 = all (SELECT dont_call FROM do_not_call) then '1' other '0' end 'Bits '.
  OF THE customer;
  
  
  Is there any other way to get the necessary O/P?
  
  
  Thank you!!
  
  Kind regards
  VijayRajaram.

  Looks like one already answered Re: rewrite the query, select below or try to get the necessary O/P

  with
  customer(name,phone1,phone2,phone3,bitwisephone) as
  (select 'a',23456,67890,12345,null from dual union all
   select 'b',67459,89760,37689,null from dual
  ),
  do_not_call(dont_call) as
  (select 67890 from dual union all
   select 23456 from dual union all
   select 37689 from dual
  )
  select name,
         to_char(mod(trunc(sum(weight)/4),2))||
         to_char(mod(trunc(sum(weight)/2),2))||
         to_char(mod(sum(weight),2)) bitwisephone
    from (select name,phone1 phone,4 weight
            from customer
          union all
          select name,phone2,2
            from customer
          union all
          select name,phone3,1
            from customer
         ) c,
         do_not_call d
   where c.phone = d.dont_call(+)
     and d.dont_call is not null
   group by name
  

  Please do not duplicate messages

  Concerning

  Etbin

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