Max and Min value for each column

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• LINES in COLUMNS with different values for each column (after division)

  Hello
  I have a table called summary where I produced, month, value,.
  
  When I used select * tab, I get months jan, Feb, mar, Apr. I wrote a query to get the months(jan,feb,...) columns
  
  SELECTmax (DECODE(ROWNUM,1,month)) Column1
  + Max (decode(rowNum,2,month)) table Column2 +.
  
  as this up to 12 months
  After that, I want to get the NEWVALUE for each month.
  I wrote a query to get the value, but I get the value only for the first month, and for the rest, I get NULL values.
  
  Select max (DECODE(ROWNUM,2,vallue)) Column1, Column2 of max table (DECODE(ROWNUM,3,vallue))
  
  
  
  Is it possible to get the newvalues for each month (in sql only) if so, please help me
  
  Thank you
  Chand
  

• drop the max and min values

  Hi all
  
  I have a table with the following columns that contain the ranks of teams as follows:
  A-B-C-D-E-F
  20-21-22-23-24-20
  21-23-32-25-22-19
  24-23-16-24-24-22
  
  I need a calculation of percentage where I drop the highest and the lowest in each team ranks, then divide the total by 100 remaining.
  
  for the first record:
  20 is the minimum and 24 max would be the percentage (21 + 22 + 23 + 20) / 100
  for the second record:
  percentage = (25 + 21 + 23 + 22) / 100
  the third record:
  percentage = (23 + 24 + 24 + 22) / 100
  
  Thank you
  Sneha

  Like this?

  SQL> WITH t AS (
    2  SELECT 20 a, 21 b, 22 c, 23 d, 24 e, 20 f FROM dual UNION ALL
    3  SELECT 21, 23, 32, 25, 22, 19 FROM dual UNION ALL
    4  SELECT 24, 23, 16, 24, 24, 22 FROM dual)
    5  SELECT ((a + b + c + d + e + f) - GREATEST(a, b, c, d, e, f) - LEAST(a, b, c, d, e, f)) /100 mids
    6  FROM t;
  
        MIDS
  ----------
         .86
         .91
         .93
  

  John

• Determination of running Max and Min values

  Please I need help on getting my minimum value if poster I have it cable like my value max but the min just rest a 0 can someone help me I do not understand what im doing wrong. looking at my drawing, I don't see how it is possible for me to not receive a value in my min indicator, I enclose my vi below

  Add the wire highlighted.

  Two things:

  1. This should work as a subvi if you as useful feedback nodes.
  2. See what you can find on the shift uninitialized registers.  You must initialize the node 'Min' Feedback with the random number (first) or you will get the default value for this type of data - the zero that you saw.

  

• How to find the value max and min for each column in a table 2d?

  How to find the value max and min for each column in a table 2d?

  For example, in the table max/min for the first three columns would be 45/23, 14/10, 80/67.

  Thank you

  Chuck,

  With color on your bars, you should have enough experience to understand this.

  You're a loop in the table already.  Now you just need a function like table Max and min. loop.  And you may need to transpose the table 2D.

• read the max and min of each column value

  Dear qudoe

  I'm doing a program in labview that challenge me to fight with a time.

  Here, I enclose my labview code in which I have a data file, which includes 500 columns that I need to find the values min and max of each column.

  I tried my best, but it takes 30 seconds to find the min and max value of each column.

  I want to do this in less than a second.

  so can anyone suggest me any necessary correction that can stimulate my program.

  You don't have to open and close the file in a loop all the time and also you don't really need some time for this. Check the related code.

  

  Of course, you can still optimize it for best performance, I just did a quick project to show how simple it is.

• Value max and min of partition

  Hello
  I created a table that is partitioned with 8 separations and tables of data exchanged not partitioned 8, now what command do I use to check the min and max values for each partition just to be sure that they contain valid data?
  Any suggestions?
  
  Thank you

  You can use DBA_TAB_PARTITIONS

  You can use the following query will identify the "highest" partition by date range.

  select partition_name, partition_position , high_value, tablespace_name from dba_tab_partitions
  where table_name = ''
  and table_owner = ''
  and partition_position = ( select max(partition_position)
  
                                  from dba_tab_partitions
                                  where table_name = ''
                               and table_owner = '' )
  

• How to find the first max value for each item

  Hello
  
  I have the me_result of the table as below,
  
  SELECT * FROM me_result;
  
  ID     ||| ELITE     ||||||||||| FREQ_ITEM | COMBINED_STR | SUP
  1     ||; 1; 10; 2; 3; 4; 5; 7; 8. 1     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  2     ||; 1; 10; 2; 3; 4; 5; 7; 8. 2     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  3     ||; 1; 10; 2; 3; 4; 5; 7; 8. 3     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  4     ||; 1; 10; 2; 3; 4; 5; 7; 8. 4     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  5     ||; 1; 10; 2; 3; 4; 5; 7; 8. 5     ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
  6     ||; 10; 2; 3; 4; 5; 8; 9. 1     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9; 1 ||| 1
  7     ||; 10; 2; 3; 4; 5; 8; 9. 2     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  8     ||; 10; 2; 3; 4; 5; 8; 9. 3     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  9     ||; 10; 2; 3; 4; 5; 8; 9. 4     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  10     ||; 10; 2; 3; 4; 5; 8; 9. 5     ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
  
  
  I need to find the first COMBINED_STR max for each element of the ELITE,
  I mean, max value is the max REGEXP_COUNT (combined_str,' ;')))
  
  really, I try to write down, but I had a lot of values for each ELITE and I need only the first, that
  SELECT * from me_result
  WHERE (ELITE, REGEXP_COUNT (combined_str,' ;')))) IN
  (SELECT ELITE, MAX (REGEXP_COUNT (combined_str,' ;'))))) ME_RESULT ELITE GROUP);
  
  I need the result to be as below.
  
  1; 1; 10; 2; 3; 4; 5; 7; 8-1; 1; 10; 2; 3; 4; 5; 7; : p
  6; 10; 2; 3; 4; 5; 8; 9 1; 10; 2; 3; 4; 5; 8; 9; 1 1
  
  any help please,.
  
  Published by: user11309581 on July 10, 2011 22:03

  Can be

  with t as
  (select 1     ID, ';1;10;2;3;4;5;7;8'     ELITE, 1     FREQ_ITEM, ';1;10;2;3;4;5;7;8' COMBINED_STR, 2 SUP from dual union all
  select 2     ,';1;10;2;3;4;5;7;8'     ,2     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 3     ,';1;10;2;3;4;5;7;8'     ,3     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 4     ,';1;10;2;3;4;5;7;8'     ,4     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 5     ,';1;10;2;3;4;5;7;8'     ,5     ,';1;10;2;3;4;5;7;8'     ,2 from dual union all
  select 6     ,';10;2;3;4;5;8;9'     ,1     ,';10;2;3;4;5;8;9;1'     ,1 from dual union all
  select 7     ,';10;2;3;4;5;8;9'     ,2     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 8     ,';10;2;3;4;5;8;9'     ,3     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 9     ,';10;2;3;4;5;8;9'      ,4     ,';10;2;3;4;5;8;9'     ,2 from dual union all
  select 10     ,';10;2;3;4;5;8;9'     ,5     ,';10;2;3;4;5;8;9'     ,2 from dual
  )
  select ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP
  from (
    SELECT ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP, ROW_NUMBER() over (PARTITION BY ELITE order by id) RN
    FROM t
    WHERE (ELITE,REGEXP_COUNT(combined_str,';')) IN
      (SELECT ELITE,MAX(REGEXP_COUNT(combined_str,';')) FROM t GROUP BY ELITE)
  ) where RN=1
  order by id
  
  ID                     ELITE             FREQ_ITEM              COMBINED_STR      SUP
  ---------------------- ----------------- ---------------------- ----------------- ----------------------
  1                      ;1;10;2;3;4;5;7;8 1                      ;1;10;2;3;4;5;7;8 2
  6                      ;10;2;3;4;5;8;9   1                      ;10;2;3;4;5;8;9;1 1     
  

• Count values not null for each column in a database

  Hello
  
  I need to write a routine that counts how many values a not null for each column in a database.
  The first idea would be to loop on all_tables / all_tab_cols and write a select statement as

  EXECUTE IMMEDIATE 'SELECT COUNT(*) FROM '||table_name||' WHERE '||column_name||' IS NOT NULL' INTO v_count;

  However, this would mean a complete table for all columns not indexed scan. It's about when I have a maximum of 59 columns for a table with millions of rows.
  
  A better idea? I don't have the exact number. For example, for the number of rows in a table, I just use all_tables.num_rows.
  
  Concerning
  Marcus

  Ask the NUM_NULLS of the ALL_TAB_COLS column (and subtracting the total of the lines).

• Determine the maximum value and the minimum value for each value in the 2D array

  Hello, I need help please. Sorry my English is not very good. I have table 2D in which each value describes a waveform, I needed a time interval to determine the minimum and maximum value of each element of the array.

  
  

• Max and min to find examples of data

  I'm discerning the max and min of cycle data values. We have about 20 data points for each cycle and I need make the max and min out of it. I tried to write a script for this but it takes way to long to run. Do not complete our largest files (over 1 million points of data) with my script and DIAdem crash.  I also tried the peak built by finding functions, but they come with data points that are not max or min. Here is my script below:

  Dim cyclemin
  Dim cyclemax
  Dim cyclecount
  Dim displacementmax, displacementmin
  Dim channelcount
  Dim i, j, k, g, a, m
  cyclemin = CMin ('Cycle Count')
  cyclemax = CMax ('Cycle Count')
  ChannelCount = 0
  Call ChnAlloc ('Single Cycle Count',(cyclemax-cyclemin) + 1, 1, DataTypeFloat64)
  Call ChnAlloc ("pressure min. sample",(cyclemax-cyclemin) + 1, 1, DataTypeFloat64)
  Call ChnAlloc ("Sample pressure Max",(cyclemax-cyclemin) + 1, 1, DataTypeFloat64)
  a = 1
  For cyclecount = cyclemin to cyclemax
  g = 1
  ChannelCount = channelcount + 1
  I = ChnFind ('Ch ()' ' Cycle Count"" "") = "& str (cyclecount)(,a)"
  j = ChnFindReverse ("Ch (" 'Cycle Count) "" ") =" & str (cyclecount), CL ('Cycle Count')) "
  Dial the ChnAlloc ("sample Pressure data retention", (d - i) + 1, 1, DataTypeFloat64 ')
  For k = i j
  ChD (g, "" data keeps the pressure of the sample "") = SMC (k, "Sample pressure")
  g = g + 1
  Next
  Call the ChnCharacter (' "data keeps the pressure of the sample" ")
  ChD (channelcount, ' Single Cycle Count "" ") = cyclecount
  ChD (channelcount, "Max pressure sample") = CMax ("Data Hold sample pressure")
  ChD (channelcount, "pressure min. sample") = CMin ("Data Hold sample pressure")
  Call the ChnDelete (' "data keeps the pressure of the sample" ")
  a = j
  Next

  Can someone please help me find a way to do it quickly? Thank you.

  Hello Steinmeister85

  just in case you are using a newer version of DIAdem, here is an alternative solution.

  Also, I used your example file and it concatenated 50 times to create a file which has about 560,000 values in each channel.

  I run your script from a new one to get a reference number

  Sample file

  Original screenplay: 2.5 seconds

  Optimized script: 0.2 seconds

  50 x example file

  Original screenplay: 111,493 seconds

  Optimized script: 0.25 seconds

  I have to admit that I've sorted the concatenated file. This way I have 216 cycle segments to be analyzed. If I simple concatenate files (without sorting) I get 50 x the number of segments and the new script takes about 9 seconds to execute. The original script doesn't work properly like you woul then have to repeat the cycle count numbers in different areas of the channel...

  I hope that the new versions work for you.

  Andreas

• AVG, max and min calculated from form data

  I have two tables. One with the raw data and the other with summary data. There is a form which the raw data to column came in, and then click submit, I use a cfloop function to get the data in the same column in the table of raw data. I can't find an easy way to calculate the max, min and average values for the data that are in the raw data table that can be put in the summary data table. The data are customized according to the date and place.
  
  This is the code to get the raw data into the table.
  
  < CFLOOP INDEX = "onerow" FROM = "1" TO = "#form.numrows #" >
  < CFQUERY NAME = "insertrawdata" DATASOURCE = 'test' >
  INSERT INTO test.dbo.rawdata (locationid, date, data)
  VALUES (' #form.locaitonid # ', #DateValue #, ' #Form ['data' & onerow] #")
  < / CFQUERY >
  < / CFLOOP >

  OK, well, do it in 2 queries then...

  
  Select max (data) as max, min (data) as min, avg (data) like avg test.dbo.rawdata where locationid = ' #form.locationid # ' and date = #datevalue # group by locationid, date
  

  
  insert into test.dbo.summarydata (locationid, date, max, min, avg)
  values (' #form.locationid #', #datevalue #,)
  (#getSummaryData.max #, #getSummaryData.min #, #getSummaryData.avg #)
  

• 7054 TDS query max and min measure

  I seem to have difficulty querying for minimum and maximum measurements on my o'scope 7054 TDS. I have two meaurements on and if I question MEASU:MEAS1:TYP? He returned to MAX and back MIN for MEAS2. Yet, when I try to question the real value MEASU:MEAS1:MAX? It returns 99.000 + 36, which of course cannot be true. The strange thing is that the code works for the DPO4104. No idea what I am doing wrong? I have attached 2 sets of code, 1, that's how I activate measures on the scope, the other tries to query for max and min.

  You must use ": MEASU:MEAS %dto?" to get your data (put the number in the %d).  You ask in fact that the max best scope value recorded.  It can keep some statistics on measures.  Here are the commands that I use to get the data (even once, replace %d by the number of measure):

  : %D MEASU:MEAS: DAT?
  
  : MEASU:MEAS %d: UNI?

  The first order requested the actual data of the measure as well as the second units of measurement.

• Max and min of the 2d array

  Hello

  can someone show me how to make a max and min of a 2d array

  

  I am oonly watching colum 0,1,2

  the max of 0,1,2

  the min of 0,1,2

  in my example, it would be 13.612 is max and min 10.059

  I think I must make two loop for, but I have not figured out how.

  Thanks in advance.

  super_saiyans wrote:

  Yes. It can

  but I don't want to look at the column 3,4,5

  Subset of the table allows to remove.

• Form - different default value for each new line needed

  Hi all
  
  I'm a newbie in the APEX and now I am struggling with a problem in the form of tables.
  
  On my page, I report master detail, where the detailed part is created in a table form (I used the Wizard).
  
  Now I want to implement the following:
  
  When I click on the button that adds the line of tabular form, I want to assign the default value for the column 'LOGNO' in my tabular form. Value for this column is table extraction and I this value already stored on the page to display one element 'P210_LOGNO_ACT '.
  
  When I click on the button for one second third etc.) times I would like to set the default for the column LOGNO as LOGNO = P210_LOGNO_ACT + 1.
  
  Y at - it something simple, or is - this difficult to attribute the different value to each new row of tabular form?
  
  Version of the apex 4.1.0.00.32
  
  Thanks in advance!
  
  Jiri

  Inspect your column and find out the name of your column attribute, it must be something like fxx (f01, f02, f03... etc) and use this column instead of f11 (in my case, the name attribute is f11)

  Create a JavaScript function in your page header

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  //perform standard addrow
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    //set default value here
  //make sure you replace the P5_X with your page item name
    $s('P5_X',parseInt($v('P5_X'))+1);
    $('input[name="f11"]')[$('input[name="f11"]').length-1].value=$v('P5_X');
  }
  

  Change your button to add a line and call the function above, as shown below

  javascript:myaddRow();
  

  See this example of work http://apex.oracle.com/pls/apex/f?p=46417:5