MI computadora al encenderla join a mi perfil porque me as soon as no pudo tener accesso put archivos y's lights don't con a temporal profile, how I can delivery eso?

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• Problem with join request and left sub ORA-01799

  Hi all

  I am currently working on the following query and I get an error when you use a left join (mandatiry in my case), in good and due place of a join.

  Error message describes the case, but I need to make it work.

  No idea how I can make this one for a left join job?

  Select a.dco, a.agsa, a.agem, a.agde, a.ope, a.eve, a.tpr, a.nat,

  a.Age, a.dev, a.ncp, a.suf, a.sen, a.dva, a.mon, a.lib, c.cli, e.age as kage,

  e.OPE as kope, e.eve as kévé, e.dev as kdev, e.dech, e.ndos, e.tcai3, e.nump, e.natp, e.lib1,

  e.nom2, e.dev2, e.ncp2, e.age1, e.ncp1, e.dev1, e.nom1, e.nomb, e.etab, e.comb,

  e.AGE2, e.nomp, e.lib2, e.lib3, e.lib4, e.lib5, e.lib6, e.lib7, e.lib8, e.lib9, e.dva2,

  e.mht as e.agsa as kagsa, e.mcai3, e.tcai2, e.refdos, e.mnat, d.cur_char, kmht

  of bkmvtg_mi one

  Join bkcom c on a.age = c.age and a.dev = c.dev and a.ncp = c.ncp and a.suf = c.suf

  e left join on (e.age = bkeve_mi

  CASES (select nvl (trim (zon1), 'age') in the cpjoilib where nomtab = 'bkeve' and nat = a.nat and zon2 = 'age')

  WHEN "age" THEN a.age

  WHEN "real" THEN a.agem

  WHEN 'agsa' THEN a.agsa

  WHEN 'agde' THEN a.agde

  Of OTHER a.age

  END

  and a.ope = e.ope and a.eve = e.eve)

  e.CSP4 left join sgsbwb_currency d = d.cur_num

  where exists (select * from sc sgsbwb_client where c.cli = sc.customer_number and ready = 1).

  and exists (select * from sgsbwb_pdt sp where c.cpro = sp.c_pro);

  ORA-01799:

  01799 00000 - "a column cannot be reached outside to a subquery.

  * Cause: < expression > (+) < relop > (< subquery >) is not allowed.

  * Action: Either delete the or make a view of the subquery.

  In V6 and with of the was simply ignored in this case.

  Thanks for your help and valuable advice

  Best regards

  Jérôme

  You must activate the application in that case there in a join.  I used an outer join below because that mimics the effect of your expression, but if you know that there is always a game between bkmvtg_mi and cpjoilib, then it could be a standard join.

  Select a.dco, a.agsa, a.agem, a.agde, a.ope, a.eve, a.tpr, a.nat,

  a.Age, a.dev, a.ncp, a.suf, a.sen, a.dva, a.mon, a.lib, c.cli, e.age as kage,

  e.OPE as kope, e.eve as kévé, e.dev as kdev, e.dech, e.ndos, e.tcai3, e.nump, e.natp, e.lib1,

  e.nom2, e.dev2, e.ncp2, e.age1, e.ncp1, e.dev1, e.nom1, e.nomb, e.etab, e.comb,

  e.AGE2, e.nomp, e.lib2, e.lib3, e.lib4, e.lib5, e.lib6, e.lib7, e.lib8, e.lib9, e.dva2,

  e.mht as e.agsa as kagsa, e.mcai3, e.tcai2, e.refdos, e.mnat, d.cur_char, kmht

  of bkmvtg_mi one

  Join the bkcom c

  On a.age = c.age and

  a.dev = c.dev and

  a.NCP = c.ncp and

  a.SUF = c.suf

  Join cpjoilib l left

  On a.nat = l.nat and

  l.nomtab = "bkeve" and

  l.zon2 = 'age '.

  Join e bkeve_mi left

  on (e.age = nvl (trim (l.zon1), 'age') CASE

  WHEN "age" THEN a.age

  WHEN "real" THEN a.agem

  WHEN 'agsa' THEN a.agsa

  WHEN 'agde' THEN a.agde

  ELSE a.age END and

  a.OPE = e.ope and

  a.Eve = e.eve)

  left join sgsbwb_currency d

  on e.csp4 = d.cur_num

  where exists (select * from sgsbwb_client sc)

  where c.cli = sc.customer_number and

  ready = 1) and

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  where c.cpro = sp.c_pro);

  John

• LEFT JOIN increases the number of lines

  Hi guys,.

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  -1176 lines

  Select count (erg_ID) of

  MySchema. T_STA_ERG sta_erg

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  -252 lines

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  Hello

  I got out of two different select statement with me and these two different tables.

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  -------------- ----------

  1 50

  2 200

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  Hello

  How to get the desired results of your data depends on your data and the results you want.  View the desired results and your data (CREATE TABLE and INSERT for examples of data; instructions lines maybe 5 of each table).

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  (

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  Alpha

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  GROUP BY ar.dist_id

  ar.alpha_count

  ;

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• Effective way to manage multiple outer joins

  I have a large refcursor currently being returned by an oracle 11g stored procedure.  I need to add some addiotional columns to the record set before it is returned.   The logic to include new columns is not simple, and I have to WITH instructions to store the new columns.  In total, I will have to WITH that contains results that are currently returned and 5 additional STATEMENTS that each contain an id column to join to the existing set of records and the new column.  My question is, how I left outer join the Recordset existing (with id column) with each of the 5 WITH statement queries to include the new 5 column in the original dataset?

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  SELECT id,

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  SELECT id,

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  Hello

  what I understand: what about something like:

  WITH original_set AS

  (SELECT LEVEL Id

  OF the double

  CONNECT BY LEVEL<=>

  )

  an ACE

  (SELECT id, "one" |) Col1 to_char (id)

  Of original_set

  WHERE id IN (1, 4)

  )

  two ACEs

  (SELECT id, 'two' |) Col2 to_char (id)

  Of original_set

  WHERE id IN (1, 2)

  )

  three ACEs

  (SELECT id, 'three' |) Col3 to_char (id)

  Of original_set

  WHERE 1 = 2 / * empty * /.

  )

  four ACEs

  (SELECT id, 'four' |) Col4 to_char (id)

  Of original_set

  WHERE id IN (3, 4)

  )

  five ACEs

  (SELECT id, 'five' |) Col5 to_char (id)

  Of original_set

  ID WHERE = 2

  )

  SELECT os.id, o.col1, tw.col2, th.col3, fo.col4, fi.col5

  To original_set os

  A LEFT OUTER JOIN o ON o.id = os.id

  LEFT OUTER JOIN two tw ON os.id = tw.id

  E three LEFT OUTER JOIN ON os.id = th.id

  LEFT OUTER JOIN four fo WE os.id = fo.id

  LEFT OUTER JOIN five fi WE os.id = fi.id

  ORDER BY id

  ;

  ID COL1 COL2 COL3 COL4 COL5

  ---- ------- ------- ------- ------- -------

  1 one1 two1

  2 two2 five2

  3                         four3

  4 one4 four4

  5

  But the same thing can be achieved with:

  WITH original_set AS

  (SELECT LEVEL Id

  OF the double

  CONNECT BY LEVEL<=>

  )

  SELECT os.id

  CASE WHEN os.id IN (1, 4)

  THEN 'a ' | To_char (id)

  END col1

  CASE WHEN os.id IN (1, 2)

  THEN 'two ' | To_char (id)

  END col2

  CASE WHEN 1 = 2

  THEN "three" | To_char (id)

  END col3

  CASE WHEN os.id IN (3, 4)

  THEN "four". To_char (id)

  END col4

  CASE WHEN os.id = 2

  THEN "five" | To_char (id)

  END col5

  To original_set os

  ORDER BY id

  ;

  (I mean: I just do a select on the main table and include the logic of 'creation' of the five 'WITH' tables directly in the select; see how this can be applied to your real situation)

  HTH,

  Bruno Vroman