min and max functions

Similar Questions

• Using the MIN and MAX functions

  Hello
  
  Guide to please the following:
  
  I have a table with records like below:
  
  
  Invoice ID RegistrationNo InvoiceDate
  1 AB-1 JANUARY 1, 10
  2 CB-4 MARCH 23, 10
  3 AB-1 1ST JULY 10
  4 FG-2 AUG 1, 10
  AB - 5 1 7 FEBRUARY 11
  CB - 6 4 FEBRUARY 8, 11
  7 CB-4 12 AUG 11
  
  I want to pass the result of the SQL query, as below
  
  For RegistrationNo = AB-1
  
  Reffacture RegistrationNo InvoiceDate
  3 AB-1 1ST JULY 10
  AB - 5 1 7 FEBRUARY 11
  
  For RegistrationNo = CB-4
  
  Reffacture RegistrationNo InvoiceDate
  CB - 6 4 FEBRUARY 8, 11
  7 CB-4 12 AUG 11
  
  I want to get that two records by RegistrationNo with the previous date of min, whose date max more forward.
  
  
  
  Kind regards

  Something like that?

  WITH A AS (SELECT 1 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JAN-10', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 2 INV_ID, 'CB-4' REG_NO, TO_DATE ('23-mrz-10', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 3 INV_ID, 'AB-1' REG_NO, TO_DATE ('01-JUL-10', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 4 INV_ID, 'FG-2' REG_NO, TO_DATE ('01-AUG-10', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 5 INV_ID, 'AB-1' REG_NO, TO_DATE ('07-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 6 INV_ID, 'CB-4' REG_NO, TO_DATE ('08-FEB-11', 'dd-mon-rr') INV_DATE FROM DUAL
              UNION
             SELECT 7 INV_ID, 'CB-4' REG_NO, TO_DATE ('12-AUG-11', 'dd-mon-rr') INV_DATE FROM DUAL)
  SELECT INV_ID,
         REG_NO,
         INV_DATE
    FROM (SELECT INV_ID,
                 REG_NO,
                 INV_DATE,
                 ROW_NUMBER() OVER (PARTITION BY REG_NO ORDER BY INV_DATE DESC) RN
            FROM A
         )
   WHERE RN<3
  ORDER BY REG_NO,
           INV_DATE DESC
  

• Min and Max on a table

  Hello. I want to make a program where I want to generate a sine and take only the monotonous positive part.

  So I thought to find the min and max of the function index and make a program like the one attached.

  As you can see that if you set the frequency to 10 Hz, it works fine... the problem is when you change the frequency such as 20 or 50 H.. t seems that it is not find the min and max correctly.

  Can you suggest me some tips?

  Thank you

  s.turino84 wrote:

  and take only positive part monotonous.

  This means that the derivative is positive.  So, make a derivative.  If the derivative is greater than 0 keep the present value, or the value 0.

  

• button conrol min and max range option during execution

  Is it possible to change the window button conrol min and max Beach setting during execution?

  Thank you very much Nick.

• the min and MAX values maintain their good values tia sal22

  the min and MAX values maintain their good values tia sal22

  Hi all

  I have problems a little value to stay in their correct min and max values min and max.
  Continue to change their values (up and down) trying to get the max value to only display the maximum value at a given time and the same for the min value.  I looked at the examples max and min and it seems that it should be in a while loop
  http://forums.NI.com/NI/board/message?board.ID=170&thread.ID=359822

  but I would add another while loop and if so put it in the loop for? or is there a better way to do it.

  TIA sal22

  Hi sal22,

  I thought it was just one example you found somewhere, because it is called red rooster. See the attached example.

  Mike

• Delete the min and max labels on chart axis markers

  Hello

  Is it possible to remove the min and max labels on chart axis markers? For example, see the screenshot below. Can I remove the numbers circled in green without changing the range of the axis? In some cases (like this one), the presence of the min and max number of cases other marker values to not be displayed (red line). I am aware that "10" is displayed if I enlarge the graph, but this isn't an option for my application. FYI - the screenshot is from the side before the attached VI.

  Thanks for any help,

  Kind regards

  Stu

  

  You can't delete them because they are the main features to be able to set the max and min on the graph of the Panel before if you use no-AutoScaling.

• Taskbar and min and max do not show on the homepage and e-mail

  When cleaning key board, the taskbar, and the top part of the page containing the min and max symbols disapperared.  How can I restore them?

  Hello

  I suggest you to try the steps below and check if it helps.

  (a) open Internet Explorer by pressing the button of the window of your keyboard, then clicking on Internet Explorer.

  (b) move your cursor to the top right and click the Tools button, and then click file.

  (c) uncheck the option full screen .

  You can also press F11 on your keyboard, which would help you to get to the normal screen.

  Hope this information is useful.

• Min and Max in a row!

  Hi guys,.

  Do you know how I can get the MIN and MAX in a row?

  For example:

  C1 | C2 | C3 | C4 | C5 | C6 | C7 | C8

  10. 50. 70.  5. 90. 135. 4   | 60

  I return 4 and 135.

  I can return it without using the service?

  Thank you

  Eric

  create table t as
  with d as (
    select 1 n from dual
    union all
    select null from dual
  )
  select a.n c1, b.n*2 c2, c.n*3 c3
  from d a, d b, d c;
  
  select c1,c2,c3,
  greatest(
    coalesce(c1,c2,c3),
    coalesce(c2,c3,c1),
    coalesce(c3,c1,c2)
  ) greatest_c,
  least(
    coalesce(c1,c2,c3),
    coalesce(c2,c3,c1),
    coalesce(c3,c1,c2)
  ) least_c
  from t;
  

  C1	C2	C3	GREATEST_C	LEAST_C
  1	2	3	3	1
  1	2		2	1
  1		3	3	1
  1			1	1
  	2	3	3	2
  	2		2	2
  		3	3	3

• Grouping and then find the min and max

  DROP TABLE purge of y;

  CREATE TABLE y
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15)
  );

  INSERT INTO y VALUES (1, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (1, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (1, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (1, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (1, 20140927141944, 20141027142131);
  INSERT INTO y VALUES (2, 20140602164819, 20140606140851);
  INSERT INTO y VALUES (2, 20140827141743, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141744, 20140827141835);
  INSERT INTO y VALUES (2, 20140827141744, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140827142131);
  INSERT INTO y VALUES (2, 20140827141944, 20140924142131);
  INSERT INTO y VALUES (2, 20140927141944, 20141027142131);

  COMMIT;

  Select
  *
  Of
  There
  order by 2, 3;

  out necessary: when the output of the table are sorted by start_date_time and end_date_time in ascending order.
  and when the value of for a particular id start_date_time is located between the
  another set of values start_date_time and end_date_time for the same id then min (start_date_time) and max (end_date_time) is the desired output.

  and if there is no overlap then (start_date_time) min and max (end_date_time) is the output desired.

  and for each line of the output in ascending order of line number order addd;

  Example output is in the output table named

  drop table output is serving;

  create an output table
  (
  ID NUMBER (10),
  START_DATE_TIME NUMBER (15),
  END_DATE_TIME NUMBER (15),
  ROW_NUMBER NUMBER (10)
  );

  
  Values to INSERT OUTPUT (1, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (1, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (1, 20140927141944, 20141027142131, 3);
  Values to INSERT OUTPUT (2, 20140602164819, 20140606140851, 1);
  Values to INSERT OUTPUT (2, 20140827141743, 20140924142131, 2);
  Values to INSERT OUTPUT (2, 20140927141944, 20141027142131, 3);

  COMMIT;

  SELECT
  *
  Of
  output
  ORDER BY 1,2,3,4;

  Thank you

  SQL_Novice

  Hello

  Your postal code.  It is difficult to tell what you're doing wrong without knowing what you are doing.

  user6166680 wrote:

  Hi Frank:

  Max works for ID 3 values only because there is only one group here, as all other values compared, they overlap with max (end_date_time);

  but when I use MAX for ID 1 and 2, the result set is not the same thing as LAG works because there is a GAP...

  Exactly, you have to find the gaps.  If start_date_time is less than or equal to the MAXIMUM of all the end_date_times earlier, then it isn't a gap; Otherwise, there is a gap.

  What is the problem with MAX?

  WITH got_new_group AS

  (

  SELECT id, start_date_time and end_date_time

  CASE

  WHEN start_date_time <= > MAX (end_date_time) OVER (PARTITION BY id )

  ORDER BY start_date_time

  end_date_time

  ROWS BETWEEN UNBOUNDED PRECEDING

  AND 1 PRECEDING

  )

  THEN 0

  1. OTHER

  END AS new_group

  OF y

  )

  got_group_number AS

  (

  SELECT id, start_date_time and end_date_time

  SUM (new_group) OVER (PARTITION BY ID.

  ORDER BY start_date_time

  end_date_time

  ) AS group_number

  OF got_new_group

  )

  SELECT id

  MIN (start_date_time) AS group_start_date_time

  MAX (end_date_time) AS group_end_date_time

  group_number

  OF got_group_number

  GROUP BY id, group_number

  ORDER BY id, group_number

  ;

  You will notice that it is exactly what I posted earlier, in response #5, except that instead of using the OFFSET it uses MAX.

  Output:

  ID GROUP_START_DATE_TIME GROUP_END_DATE_TIME GROUP_NUMBER

  --------------- --------------------- ------------------- ---------------

  1 20140602164819 20140606140851 1

  1 20140827141743 20140924142131 2

  1 20140927141944 20141027142131 3

  2 20140602164819 20140606140851 1

  2 20140827141743 20140924142131 2

  2 20140927141944 20141027142131 3

  3 20140330041350 47121231000000 1

• Help the query to list all the days between MIN and MAX date in a table

  Hello

  Sorry, this may have already responded earlier, but I really struggled to find a previous response with the new provision of the RTO.

  In a DB 11 g, I date MIN and MAX in a table:

  {code}

  SELECT MIN (process_date) start_date, MAX (process_date) end_date FROM my_table;

  {code}

  I would get every day between these 2 dates. I mean even is there is no record in the table for a date.

  Is this possible?

  Thanks in advance,

  Olivier

  Hello

  Do you mean something like this?

  ranit@XE11GR2>> ed
  Wrote file c:\rb\1.sql
  
    1  with xx as
    2  (
    3      select
    4     to_date('05-06-2013','dd-mm-yyyy') min_d,
    5     to_date('20-06-2013','dd-mm-yyyy') max_d
    6      from dual
    7  )
    8  --
    9  -- end of test data
   10  --
   11  select
   12     min_d + level date_x
   13  from xx
   14* connect by level<=(max_d-min_d)
  ranit@XE11GR2>> /
  
  DATE_X
  -------------------
  06-06-2013 00:00:00
  07-06-2013 00:00:00
  08-06-2013 00:00:00
  09-06-2013 00:00:00
  10-06-2013 00:00:00
  11-06-2013 00:00:00
  12-06-2013 00:00:00
  13-06-2013 00:00:00
  14-06-2013 00:00:00
  15-06-2013 00:00:00
  16-06-2013 00:00:00
  17-06-2013 00:00:00
  18-06-2013 00:00:00
  19-06-2013 00:00:00
  20-06-2013 00:00:00
  
  15 rows selected.
  

• Find dates MIN and MAX

  Please, advise how correctly find MIN and MAX dates.
  The XML code:

  <DATES>
  <DT>2011-02-24</DT>
  <DT>2011-02-25</DT>
  <DT>2011-02-26</DT>
  <DT>2011-02-27</DT>
  <DT>2011-02-28</DT>
  </DATES>

  Model:

  <?xdoxslt:minimum(DT)?>
  <?xdoxslt:maximum(DT)?>

  The output:

  0
  20110224

  Expected results:

  2011-02-24
  2011-02-28

  Hello

  If your data is:
  
  
  
  

  2008-10-04
  
  1
  
  
  
  2009-10-21
  
  3
  
  
  
  2009-11-05
  
  4
  
  
  
  2008-11-10
  
  2
  
  

  The maximum is given by: / ROWSET/ROW/DT [.. / DT_RANK = count (//ROW)]
  and the minimum is: / ROWSET/ROW/DT [.. / DT_RANK = 1]

  There may be more effective, but it works.

  concerning

  Jorge

• PanelBox including stretch between min and max height

  Hello

  I use JDeveloper 11.1.1.6 and my customer requests in the application I am developing a PanelBox stretching from its height according to the content inside. There is a minimum height (which may be greater than the height the content) and a maximum height (which, if the content exceeded, should display a scroll bar).

  If you have any suggestions on how I could reach it (including editing the CSS file) please let me know.

  Best regards

  Toma

  Hi Frank,.

  I did this and, in combination with certain CSS styles, I managed to do things. The part that essentially does the work is the property of 'type' equal 'sink '. Styling covered the min-height and max-height, as well as other small visual changes.

  Thank you very much!

• Min and Max of the sequence number

  Hello
  
  I have a table called pins (lot number 4,
  Sequence number (8)
  );
  
  I have data in the table:
  batch sequence
  386 100
  386 101
  386 102
  386 800
  386 801
  1 387
  2 387
  
  I want to know by draw the low values and high for sequence number, is the result, I am looking
  
  batch min (sequence), max (sequence)
  386 100 102
  386 800 801
  387 1 2
  
  Oracle 10g rel2
  
  Thank you

  Hello

  You want something like this:

  WITH       got_grp     AS
  (
       SELECT     lot
       ,     seq_num          -- SEQUENCE is not a good column name
       ,     seq_num - ROW_NUMBER () OVER ( PARTITION BY  lot
                                                    ORDER BY      seq_num
                                        ) AS grp
       FROM    pins
  --     WHERE     ...     -- any filtering goes here
  )
  SELECT       lot
  ,       MIN (seq_num)          AS min_seq_num
  ,       MAX (seq_num)          AS max_seq_num
  FROM       got_grp
  GROUP BY  lot
  ,            grp
  ORDER BY  lot
  ,            min_seq_num
  ;
  

  If I understand the probem, you want to GROUP BY, but many does not define groups by itself: each contiguous set of seq_nums in a batch is a separate group. In each of these groups, the difference between seq_num and a meter which reflects the order of seq_num generated in the query (using ROW_NUMBER) will be constant.

  This assumes that seq_num is an integer, and this (lot, seq_num) is unique.
  If this is not the case, the above query will have a small adjustment.

  If you want to display the INSERT statements for your sample data, then I could test this.

• PowerCLI Script required to identify all clusters in a data center and all hosts within each cluster and calculate it using cpu and ram, avg, min, and max.

  Hi all

  I'm new to powercli and try to create a script to list all clusters in a data center and all hosts in a cluster and calculate min, max and avg cpu usage and ram by the host and cluster. So far, I have tried the below but I can't publish the results of my script.

  $Function = @)
  ForEach ($DataCenter Get-Data Center)
  {
  ForEach ($cluster in ($DataCenter |)) Get - Cluster)) - need help to post the information here and confirm if this is correct or not.
  {
  ForEach ($hosts in ($cluster |)) Get - VMHost))
  {
  ForEach ($vms to ($hosts |)) Get - VM)) - do not know if I called you here functions properly
  {
  $allvms = @)
  $allhosts = @)
  $hosts = get-VMHost
  $vms = get - Vm

  {foreach ($vms in $hosts)
  $hoststat = "" | Select the host name, MemMax, MemAvg, MemMin, CPUMax, CPUAvg, CPUMin
  $hoststat. Host name = $vmHost.name
  
  $statcpu = get-Stat-entity ($vmHost) - start (get-date). AddDays(-30)-Finish (Get-Date) - MaxSamples 10000 - stat cpu.usage.average
  $statmem = get-Stat-entity ($vmHost) - start (get-date). AddDays(-30)-Finish (Get-Date) - MaxSamples 10000 - stat mem.usage.average

  $cpu = $statcpu | Measure-object-property value - average - Maximum - Minimum
  $mem = $statmem | Measure-object-property value - average - Maximum - Minimum
  
  $hoststat. CPUMax = $cpu. Maximum
  $hoststat. CPUAvg = $cpu. Average
  $hoststat. CPUMin = $cpu. Minimum
  $hoststat. MemMax = $mem. Maximum
  $hoststat. MemAvg = $mem. Average
  $hoststat. MemMin = $mem. Minimum
  $allhosts += $hoststat
  }
  }
  }
  }
  }

  $Function | Select the host name, MemMax, MemAvg, MemMin, CPUMax, CPUAvg, CPUMin | Export-Csv "c:\Function.csv" - noTypeInformation

  Any help on this is much appreciated.

  [Ordered] casting was introduced in v3 PowerShell.

  For PowerShell v2, you can use

  $vms = get - VM

  $stat = 'cpu.usage.average ','mem.usage.average '.

  $start = (get-Date). AddDays(-31)

  $report = get-Stat-entity $vms - start $start - Stat $stat - ErrorAction SilentlyContinue |

  Group-object - property {$_.} @entity.name} | %{

  $cpu = $_. Group | where {$_.} MetricId - eq "cpu.usage.average"} | Measure-object-property value - average - Maximum - Minimum

  $mem = $_. Group | where {$_.} MetricId - eq "mem.usage.average"} | Measure-object-property value - average - Maximum - Minimum

  New-object PSObject-property @ {}

  Datacenter = Get-Datacenter - VM $_. Group [0]. Entity | Select the name of ExpandProperty-

  Cluster Cluster Get - VM = $_. Group [0]. Entity | Select the name of ExpandProperty-

  VMHost = $_. Group [0]. Entity.Host.Name

  Name = $_. Group [0]. @entity.name

  CpuMin = $cpu. Minimum

  CpuAvg = $cpu. Average

  CpuMax = $cpu. Maximum

  MemMin = $mem. Minimum

  MemAvg = $mem. Average

  MemMax = $mem. Maximum

  }

  }

  $report | Sort-Object-property Datacenter, Cluster, VMHost name |

  Export Csv report.csv - NoTypeInformation - UseCulture

• Custom fonts: min and max maximum size on the font file?

  Hello

  What is the limit of file size (max and min) on the font file for loading custom fonts?

  I have search the Forum and found a comment by Peter_strange.

  "The documentation says 60 K or 90K depending on how load you, 90 K if you load a an InputStream memory."

  But I want to be sure, share please if someone has the info.

  Thank you.

  Pradeep thanks for your clarification.

  Now, I checked that there is no limit of min file size and maximum file size limit is 90 KB for load of cases and 60 KB in case of direct load flow.

  I also have a resource good sample by peter_strange -.

  http://supportforums.BlackBerry.com/T5/Java-development/font-loader-Manager-utility/m-p/592647#M1223...