Move the schema objects to a different database without data

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• Query where clause of different table without data

  Hello
  
  Oracle 11g.
  
  I have a 'Points' table that stores information point.
  In carts, users can record information on these points.
  Then, the user can some carts he wants to apply to display data in a report.
  
  Here is a minimal example (I hope I didn't too many mistakes):
  

  create table points (
       pt_id integer,
       pt_type varchar2(1),
       pt_accl varchar2(15),
       pt_class varchar2(10),
       pt_status varchar2(1),
       constraint pk_pt_id primary key(pt_id),
       constraint ck_pt_type check(pt_type in ('B','P', 'S', 'T')),
       constraint ck_pt_status check(pt_status in ('A','E'))
  );
  
  create table carts(
       cart_id integer,
       cart_name varchar2(30),
       cart_current varchar2(1),
       constraint pk_cart_id primary key(cart_id),
       constraint ck_cart_current check(cart_current in ('Y','N')) 
  );
  
  create table user_selected_types(
       ust_id integer,
       ust_cart_id integer,
       ust_type varchar2(1),
       constraint pk_ust_id primary key(ust_id),
       constraint fk_ust_cart_id foreign key(ust_cart_id) references carts(cart_id)
  );
  
  create table user_selected_accls(
       usa_id integer,
       usa_cart_id integer,
       usa_accl varchar2(15),
       constraint pk_usa_id primary key(usa_id),
       constraint fk_usa_cart_id foreign key(usa_cart_id) references carts(cart_id)
  );
  
  create table user_selected_classes(
       usc_id integer,
       usc_cart_id integer,
       usc_class varchar2(10),
       constraint pk_usc_id primary key(usc_id),
       constraint fk_usc_cart_id foreign key(usc_cart_id) references carts(cart_id)
  );
  
  create table user_selected_status(
       uss_id integer,
       uss_cart_id integer,
       uss_status varchar2(1),
       constraint pk_uss_id primary key(uss_id),
       constraint fk_uss_cart_id foreign key(uss_cart_id) references carts(cart_id)
  );
  
  insert into carts values (1, 'cart_1', 'N');
  insert into carts values (2, 'cart_2', 'Y');
  insert into carts values (3, 'cart_3', 'Y');
  
  insert into points values (1, 'B', 'AAA', 'AAKCM', 'A');
  insert into points values (2, 'B', 'BIONH1', 'AAKCM', 'A');
  insert into points values (3, 'B', 'BIONH1', 'AAKCM', 'E');
  insert into points values (4, 'B', 'CTF1', 'RF45Q33', 'E');
  insert into points values (5, 'T', 'L4C', 'H4V1', 'A');
  insert into points values (6, 'T', 'L4C', 'H4V1', 'E');
  insert into points values (7, 'S', 'BIONH1', 'RX4', 'A');
  insert into points values (8, 'S', 'L4D', 'L2585', 'A');
  insert into points values (9, 'S', 'L4D', 'L2585', 'E');
  insert into points values (10, 'S', 'CTF1', 'CCMBQX', 'A');
  insert into points values (11, 'S', 'CTF1', 'CCMBQX', 'E');
  insert into points values (12, 'S', 'CTF2', 'CCMBQX', 'A');
  insert into points values (13, 'S', 'CTF2', 'CCMBQX', 'E');
  insert into points values (14, 'P', 'H4', 'L44W', 'A');
  insert into points values (15, 'P', 'H4', 'L44W', 'E');
  insert into points values (16, 'P', null, 'RK', 'E');
  
  insert into user_selected_types values (1, 1, 'B');
  insert into user_selected_types values (2, 1, 'S');
  insert into user_selected_types values (3, 3, 'T'); 
  
  insert into user_selected_accls values (1, 1, 'BIONH1');
  insert into user_selected_accls values (2, 2, 'CTF1');
  insert into user_selected_accls values (3, 2, 'CTF2');
  insert into user_selected_accls values (4, 3, 'L4C');
  
  insert into user_selected_classes values (1, 1, 'AAKCM');
  
  insert into user_selected_status values (1, 3, 'A');

  If a user may for example have the following carts (according to the example above):
  

  cart_1
  Types : 'B', 'S'
  Accls : 'BIONH1'
  Classes : 'AAKCM'
  Status : [All]
  
  cart_2
  Types : [All]
  Accls : 'CTF1', 'CTF2'
  Classes : [All]
  Status : [All]
  
  cart_3
  Types : 'T'
  Accls : 'L4C'
  Classes : [All]
  Status : 'A'

  When no value is selected for an item, it must return all values.
  
  For now, I have the following query:
  

  with t as (select cart_id d from carts where cart_current = 'Y')
  select
       *
  from
       points
  where
       ...
       and (
            pt_type in (select ust_type from user_selected_types where ust_cart_id in (select d from T))
            or not exists (select 1 from user_selected_types where ust_cart_id in (select d from T)))
       and (
            nvl(pt_accl, '' - (null)'') in (select nvl(usa_accl, '' - (null)'') from user_selected_accls where usa_cart_id in (select d from T))
            or not exists (select 1 from user_selected_accls where usa_cart_id in (select d from T)))
       and (
            pt_class in (select usc_class from user_selected_classes where usc_cart_id in (select d from t))
            or not exists (select 1 from user_selected_classes where usc_cart_id in (select d from T)))
       and (
            pt_status in (select uss_status from user_selected_status where uss_cart_id in (select d from T))
            or not exists (select 1 from user_selected_status where uss_cart_id in (select d from T)))

  It works, but the data or mixed...
  If the user apply cart_2 and cart_3, I don't want to for example points to accl "L4C" with status "E", forthcoming.
  I just want to return the union all selected each carts.
  
  Of course I can loop over Cart ID, PL_SQL, and build the query dynamically, as:
  

  for cur_c in (select cart_id d from carts where cart_current = 'Y') loop
       l_query := l_query || 'select ... from ... where ...' || ' union all ';
  end loop;
  l_query := substr(l_query,1,length(l_query)-11);

  But imagine the user ask 500 wagons..., I've reached the limit of varchar2.
  I can't use a CLOB that I use Oracle APEX to view the report, and he expects the query a varchar2.
  
  I don't want to use a temporary table, as it is too slow for the application (I've tested).
  
  You have a solution?
  
  Thank you.
  
  Yann.

  Thanks for create/insert statements - makes it much easier to help :D

  Here's one way:

  SQL> select
    2  c.cart_id,
    3  p.pt_id,
    4  p.pt_type,
    5  p.pt_accl,
    6  p.pt_class,
    7  p.pt_status
    8  from carts c
    9  cross join points p
   10  where c.cart_current = 'Y'
   11  and ( not exists(select null from user_selected_types ust where ust.ust_cart_id = c.cart_id)
   12     or p.pt_type in (select ust.ust_type from user_selected_types ust where ust.ust_cart_id = c.cart_id)
   13      )
   14  and ( not exists(select null from user_selected_accls usa where usa.usa_cart_id = c.cart_id)
   15     or p.pt_accl in (select usa.usa_accl from user_selected_accls usa where usa.usa_cart_id = c.cart_id)
   16      )
   17  and ( not exists(select null from user_selected_classes usc where usc.usc_cart_id = c.cart_id)
   18     or p.pt_class in (select usc.usc_class from user_selected_classes usc where usc.usc_cart_id = c.cart_id)
   19      )
   20  and ( not exists(select null from user_selected_status uss where uss.uss_cart_id = c.cart_id)
   21     or p.pt_status in (select uss.uss_status from user_selected_status uss where uss.uss_cart_id = c.cart_id)
   22      )
   23  order by
   24  c.cart_id,
   25  p.pt_id
   26  ;
  
     CART_ID      PT_ID P PT_ACCL         PT_CLASS   P
  ---------- ---------- - --------------- ---------- -
           2          4 B CTF1            RF45Q33    E
           2         10 S CTF1            CCMBQX     A
           2         11 S CTF1            CCMBQX     E
           2         12 S CTF2            CCMBQX     A
           2         13 S CTF2            CCMBQX     E
           3          5 T L4C             H4V1       A
  
  6 rows selected.
  

  The cross join creates all the possible combinations of carriage/point. Then they are checked for 4 columns according to your rules. I think that the result is correct, if I read your question right?

  If it's the most effective depends a lot on your actual data. Are the usual cases each cart sets a very small subset of points, or each cart will usually define a substantial part of the points. Carts of how are your tables? How many tables of user_selected_? How is the distribution? How many points? Indexes are available?

  If the data are such that it can "pay" to build all of the possible production and "weed" down, then the foregoing can be very effective. If the data is such that the result is usually very small subset then the effectiveness may depend on the index are available.

  Test and see if it works for you ;-)
  If it takes hours, so if please give some information on the quantity and distribution of the data and the expected quantity and size carts etc. Then we could think in a different way...

• How to find these different namespaces in the schema?

  Hello
  
  I heard that this schema contains different namespaces. How to find these different namespaces in the schema?
  
  I checked with this, but it is throwing "table or view does not exist.
  
  Select the namespace of v$ librarycache.
  
  
  Thank you
  Praveen

  Are you referring to this? From the reference manual of the SQL language under the schema object names and qualifiers

  7. part of a namespace, no two objects can have the same name.
  The following schema objects share a namespace:
  Tables
  Display
  Sequences
  Private synonyms
  Autonomous procedures
  Autonomous stored functions
  Packages
  Materialized views
  User-defined types

  Each of the following schema objects has its own namespace:
  Index
  Constraints
  Clusters
  Database triggers
  Private database links
  Dimensions

  Because tables and views are in the same namespace, a table and a view in the same schema cannot have the same name. However, the tables and indexes are in different namespaces. Therefore, a table and an index in the same schema may have the same name.

  Each schema in the database has its own namespaces for objects that it contains. This means, for example, two tables in different schemas are in different namespaces and can have the same name.

  Each of the following schema objects also have its own namespace:
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  Public synonyms
  Links to public database
  Storage spaces
  Profiles of school boards
  The files (PFILEs) settings and server settings (SPFILEs) files

  Because objects in these namespaces do not appear in the drawings, these namespaces cover the entire base.

  That's why you can do:

  SQL> create table t (id number, descr varchar2(10));
  
  Table created.
  
  SQL> alter table t add constraint t check (mod(id,2) = 0);
  
  Table altered.
  
  SQL> create index t on t(id);
  
  Index created.
  
  SQL> create trigger t
    2  before update on t
    3  begin
    4     dbms_output.put_line('T Trigger');
    5  end;
    6  /
  
  Trigger created.
  

  but not:

  SQL> create view t as select * from t;
  create view t as select * from t
              *
  ERROR at line 1:
  ORA-00955: name is already used by an existing object
  

  or

  SQL> create procedure t
    2  begin
    3     null;
    4  end;
    5  /
  create procedure t
  *
  ERROR at line 1:
  ORA-00955: name is already used by an existing object
  

  John

• Privileging the public synonym over schema object

  Hello

  I have a request.

  I logged in a scheme called "SCOTT."

  I have a table called 'EMP '.

  Now, I created a view called "EMP_D" with the addition of more of a few columns.

  Now I create a public synonym 'EMP' pointing to display "EMP_D".

  Now, I'm pulled the query in the schema "SCOTT."

  Select * from EMP

  I want that data to the EMP_D view.

  How to get there?

  Thanks in advance

  S. Jean-Charles

  user629814 wrote:

  My question is

  is it possible to prioritize the resulting public synonym of the same schema?

  Its only for a solution.

  This is called "name resolution" and is documented here: http://docs.oracle.com/cd/B28359_01/server.111/b28310/general008.htm#ADMIN11561

  1 oracle database attempts to qualify the first piece of the name referenced in the SQL statement. For example, in scott.emp , scott is the first piece. If there is only one piece, the piece is considered to be the first piece.

  1. In the current schema, the database looking for an object whose name matches the first part of the name of the object. If it does not find such an object, it continues with step b.
  2. The database looking for a public synonym that matches the first part of the name. If it does not find one, it continues with stepc.
  3. ...
     

  So if you have a schema object with the same name as a public synonym, oracle will always use first the schema object.

  Your only chance would be to rename the schema object or use another schema.

• Does not receive the table name in the list of schema objects creating EO

  Hello

  IAM does not have my name of the table custom in the list of schema objects during the creation of EO.

  I created a custom table and I need to use this table looks for creation EO,

  But while creating the EO, I'm not able to find the table in the schema object list.

  in the connection database, these tables are present, but only in this window (window of creation of Eo) these tables do not come

  can someone please help how to solve this problem.

  Hello

  I found the solution

  in business components that there is another database link that I've changed now, it works fine now