Need help to understand the code
Hi all
I was reading an article related to fill the list item, but I don't get some codes (see the code in red), I really appreciate if someone explain it to me.
Thanks in advance
link real =Oracle application development: how to dynamically populate a Pop list?
Code
DECLARE
group_id RecordGroup;
GroupName varchar2 (10): = 'abc ';
status NUMBER;
BEGIN
group_id: = find_group (group_name);
If not id_null (group_id) then
delete_group (group_id);
end if;
group_id: = Create_Group_From_Query (groupname, 'select DNAME, TO_CHAR (DEPTNO) Department');
/ * Select statement must have two column * /.
status: = Populate_Group (group_id);
Populate_List('DUMMY.) TXT_LIST', group_id);
END;
Concerning
Line
POPULATE_GROUP is a function (not a procedure) and must be called in this way.
State could be verified - see forms help:
"After a successful query, POPULATE_GROUP returns a 0 (zero)."
Kind regards
Zlatko
Tags: Oracle Development
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Need help to understand the query result
Hi gurus
I was reading one of the question here in this forum and its link is below:
I had some confusion related to this code and don't understand the logic of the out put, see query below:
Query
with sub_services as
(
Select su_seq 12323, 'HLR1' so_id, 1 seq Union double all the
Select su_seq 12323, "HLR2' so_id, seq 2 Union double all the
Select su_seq 12323, "A09" so_id, seq 3 of all the double union
Select su_seq 12333, "MO1" so_id, seq 4 Union double all the
Select su_seq 12333, "MO2' so_id, seq 5 Union double all the
Select su_seq 12333, "A09" so_id, 6 seq in union double all the
Select su_seq 12333, 'M0CR' so_id, seq 7 Union double all the
Select su_seq 12999, "LOL1' so_id, seq 8 Union double all the
Select su_seq 12999, "LOL2' so_id, seq 9 double
)
Select *.
of sub_services b
where exists (select 1 from sub_services
where su_seq = b.su_seq
and so_id = 'A09.
)
order by 2;
The query result
12323 A09 3
12333 6 A09
12323 HLR1 1
12323 HLR2 2
12333 M0CR 7
12333 4 MO1
12333 5 MO2
According to my understanding, the above query should return records in red only because of her is below command
It exists (select 1 from sub_services
where su_seq = b.su_seq
and so_id = 'A09.
but don't know why he's back 7 files, can someone help me understand the result...
It is query is functionally identical to the PL/SQL block, but much more effective.
declare
number of l_res;
Start
for line (select *)
sub_services) loop
Start
Select 1 from l_res
of sub_services
where su_seq = row.su_seq and
so_id = "A09" and
rownum = 1;
Essentially every row in the outer query are tested against him exists query. Given the correlation between two requests is based only on su_seq each line with a su_seq value returned by him is returned in the output.
Another way to think he uses instead a join condition. This query is equivalent to the query to exist
Select the main
of main sub_services
Join select (separate su_seq
of sub_services
where so_id = "A09") cond
We main.su_seq = cond.su_seq;
John
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Concerning
Line
Thanks for the explanation, could you please explain what does really to take care of the index as a whole and clause varchar2 and if yes then what condition we use varchar2 index and in which condition we use index as a whole, be we just use index by integer in our daily practice. Really appreciate your response. Thank you
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Loading the kernel symbols
...............................................................
................................................................
........................
Loading user symbols
Loading unloaded module list
.......
*******************************************************************************
* *
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* *
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Could not read the name of the problem driver
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---------0: kd >! analyze - v
*******************************************************************************
* *
* Bugcheck analysis *.
* *
*******************************************************************************PAGE_FAULT_IN_NONPAGED_AREA (50)
Invalid system memory was referenced. This cannot be protected by try-except,
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Arg2: 0000000000000000, value 0 = read operation, 1 = write operation.
Arg3: fffff800036e7f42, if not zero, the address of the instruction that refers to bad memory
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------------------Could not read the name of the problem driver
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fffff6e400084040 non paged poolFAULTING_IP:
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fffff800'036e7f42 498b 00 mov rax, qword ptr [r8]MM_INTERNAL_CODE: 5
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RDX = 0000c 80010808009 rsi = 0000000000000000 rdi = 0000000000000000
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R11 = 000000000000116e r12 = 0000000000000000 r13 = 0000000000000000
R14 = 0000000000000000 r15 = 0000000000000000
iopl = 0 nv in pe of na EI ng nz cy
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Reset the default scopeLAST_CONTROL_TRANSFER: from fffff800037525b3 to fffff800036d5bc0
STACK_TEXT:
"fffff880 '0970b3e8 fffff800' 037525b 3: 00000000'00000050 fffff6e4 ' 00084040 00000000 00000000' fffff880 ' 0970b 550: nt! KeBugCheckEx
fffff880 '0970b3f0 fffff800' 036d3cee: 00000000 00000000' fffff6e4 ' 00084040 fffffa80' 04122600 fffffa80'00000028: nt! : FNODOBFM: 'chain' + 0 x 43801
fffff880 '0970b 550 fffff800' 036e7f42: fffffa80'00000028 00000000'00000000 00000000'00000000 00000000'00000000: nt! KiPageFault + 0x16e
fffff880 '0970b6e0 fffff800' 036f41bd: 00000000' 00000a0f 00000000' 23ba4548 fffff700 ' 01080000 fffff700' 01080000: nt! MiUpdateWsle + 0 x 122
fffff880 '0970b 750 fffff800' 036f39df: 20f00001 '63eb7025 00000001' 63eb7121 fffffa80' 04e10200 00000000' 00000000: nt! MiCompleteProtoPteFault + 0x2cd
fffff880 '0970b7e0 fffff800' 036f24f3: 00000000' 0016bd60 000007fe'fbef34ac fffff683 'ff7df798 fffffa80' 07f6cd08: nt! MiResolveProtoPteFault + 0x1cf
fffff880 '0970b 870 fffff800' 036e2179: 00000001 00000000' 000007fe 'fbef34ac fffffa80' 09a44af0 00000000' 00000000: nt! MiDispatchFault + 0x1c3
"fffff880 '0970b 980 fffff800' 036d3cee: 00000000 ' 00000008 000007fe ' fbef34ac fffff880'00000001 00000000' 0863fe50: nt! MmAccessFault + 0 x 359
fffff880 '0970bae0 000007fe' fbef34ac: 00000000'00000000 00000000'00000000 00000000'00000000 00000000'00000000: nt! KiPageFault + 0x16e
00000000' 0863fb68 00000000'00000000: 00000000'00000000 00000000'00000000 00000000'00000000 00000000'00000000: 0x000007fe'fbef34acSTACK_COMMAND: kb
FOLLOWUP_IP:
NT! MiUpdateWsle + 122
fffff800'036e7f42 498b 00 mov rax, qword ptr [r8]SYMBOL_STACK_INDEX: 3
SYMBOL_NAME: nt! MiUpdateWsle + 122
FOLLOWUP_NAME: MachineOwner
MODULE_NAME: nt
DEBUG_FLR_IMAGE_TIMESTAMP: 531590fb
IMAGE_VERSION: 6.1.7601.18409
Nom_image: memory_corruption
FAILURE_BUCKET_ID: X64_0x50_nt! MiUpdateWsle + 122
BUCKET_ID: X64_0x50_nt! MiUpdateWsle + 122
ANALYSIS_SOURCE: KM
FAILURE_ID_HASH_STRING: km:x64_0x50_nt! miupdatewsle + 122
FAILURE_ID_HASH: {adc90a39-f60f-e57a-aeeb-d2a428d2eb03}
Follow-up: MachineOwner
--------- -
Need help to understand the manifest
Our server:
Service tagComputer modelPowerEdge T610At a 341-8785: PERC 6 / i SAS RAID controller, 2 x 4 connectors, internal, PCIe, 256 MB Cache listed on the manifest. We would like to know if - as embedded (we have not changed hardware from the front desk)-This RAID controller will help readers to all the berries without buying more hardware.
The rest of this topic:
Part numberQuantityDescriptionF609J1MODULE CARD (CIRCUIT), CONTROLLER, PERC6I-JAN NOSLEDJC8811THE ASSEMBLY, CABLE, 5 P, DRUMS, PERC-SASINU2091BATTERY PRIMARY SCHOOL, 7WHR, 1 C, LITHIUM ION, JURČEKPK1651COST OF SERVICE, DRIVER, INT PERC6I SAS RAIDT954J1ASSEMBLY, CARD (CIRCUIT), CONTROLLER, PERC6II, SERIAL ATTACHED SCSI, NOSLDT874M1MODULE, CABLE, SERIAL ATTACHED SCSI, SECONDARY, T6105FM3N1ASSEMBLY, CABLE, SERIAL ATTACHED SCSI, DIS1, T610W116M1MODULE, CABLE, SERIAL ATTACHED SCSI, PRIMARY, T610RM2551ASSEMBLY, CABLE, SERIAL ATTACHED SCSI, PRIMARY, T610Sam - CureSolutions.com
With the material you listed, the T610 and Perc6 / I'd be able to use the remaining locations. It's because you have the SAS0 and cables DIS1 (5FM3N and RM255) that run on both sides of the bottom of basket.
In a brief comment, Perc 6 / I can support much more server can contain, because it supports up to 32 drives per virtual disk and up to 64 virtual disks by Perc 6 / i.
Let me know if it helps.
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Need help to understand the oracle plsql design phase.
I am new user oracle plsql for learning. I wanted to know the following points.
(1) is there any process that we follow before developing procedures for oracle.
(2) is there any algorithm, flowchart, diagrams that we use for the Oracle procedure development.
(3) what I should learn in order to begin to develop procedures for the oracle.
organization charts
data flow diagrams
There any standard used in industry? comments or pointers would be usefuluser507531 wrote:
Meanwhile, I would also like to know if there are any designs / charts, high level design, low level of design, ER diagrams to create before you start any development of Oracle plsql.
It depends on the environment, work in and value standards. Some expect a case of use (UML) before a single line of code is written. At the time of Cobol, an organizational chart was generally expected.
With some new programming approaches, the test cases are often used to define the program (as in turn, which defines the objectives of the program).
ERDs come with database design - with the design of the PL/SQL program. You can use an ERD for a PL/SQL program, but is not part of the design of a PL/SQL program. It describes the database instead.
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