Not getting do not parent group article
Hi all
I need help to select the parent group element by selecting a text within the element of group frame. Here's what I'm trying.
1. the search for a style of paragraph using script (note this paragraph always available within grouped style point)
2. Select the search text
3. with the help of code .parent to go to grouped point
Problem is when I'm targeting .parent point it's going to document instead of the group element. Please help me solve this problem.
Thank you
Shonky
Hello
Everything depends on how you target a parent:
Text.parent (history) .parent ==> document
text.parentTextFrames [0] (textFrame) .parent ==> can be a Group if grouped.
Jarek
Tags: InDesign
Similar Questions
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Listagg function gives ORA-00979: not a GROUP BY expression error
Hello
I have an environment that supports the Listagg function. Suite works perfectly:
Select task_code, LISTAGG(ename||) e ('| role |') (',',') WITHIN GROUP (ORDER BY ename) as employees
team
where task_code = '01.07.05'
Task_code group
However, this is just a test request, the real is a little wider and I can't get the function works, I get ORA-00979: not a GROUP BY expression error.
Here's my query (the column names are in Dutch, but that shouldn't really be a problem):
SELECT distinct op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la,
LISTAGG (op_ploeg.wn_naam |) ' ('| op_ploeg.rol |') (',',') WITHIN GROUP (ORDER BY op_ploeg.wn_naam) as employees.
"Write subtaak/mijlpaal toe."
op_teamplanning.subtaak_mijlpaal as subtaak_of_mijlpaal,
op_teamplanning.subtaak_omschr | -case when op_teamplanning.subtaak_mijlpaal = 'BELMO Mijlpaal' then ' (BRUNO mijlpaalnr: ' | nvl (op_teamplanning.nummer, 0) |) ')' other ' ' end
as subtaak_mijlpaal_omschrijving, op_teamplanning.deadline as date limit, op_teamplanning.status as status,
trim (both
case when op_teamplanning.vlag1 = 'Geen' and op_teamplanning.vlag2 = 'Geen' and op_teamplanning.vlag3 = 'Geen' and op_teamplanning.vlag4 = 'Geen'
and op_teamplanning.vlag5 = 'Geen' or op_teamplanning.vlag1 is null and op_teamplanning.vlag2 is null and op_teamplanning.vlag3 is null
op_teamplanning.vlag5 is null and op_teamplanning.vlag4 is null then 'Geen '.
Another pad (both case when op_teamplanning.vlag1 = 'Geen' then "else trim (both from op_teamplanning.vlag1) end) |
trim (both case when op_teamplanning.vlag2 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag2) end) |
trim (both case when op_teamplanning.vlag3 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag3) end) |
trim (both case when op_teamplanning.vlag4 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag4) end) |
trim (both case when op_teamplanning.vlag5 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag5) end) end) as Beleidsvlaggen,
op_teamplanning.naam_verantw as quotation, op_teamplanning.subtaak_id as subtaak_id, nvl (op_teamplanning.nummer, 0) as Nummer, nvl (op_teamplanning.regelgevingsagenda, 'Nee') as
Regelgeving, op_teamplan_subsubtaak.subsubtaak_submijlpaal as subsubtaak_submijlpaal, op_teamplan_subsubtaak.subsubtaak_id as subsubtaak_id, op_teamplan_subsubtaak.subsubtaak_omschr
like subsubtaak_omschr, op_teamplan_subsubtaak.deadline, sub_deadline, op_teamplan_subsubtaak.status as sub_status, op_teamplan_subsubtaak.naam_verantw as naam_verantw
Of...
WHERE THE...
Group of op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la
Can someone tell me the reason for this error?
Thanks in advance!
Kind regards
NDG
NDG123 wrote:
I don't really understand your other question:
Is below for example, a group of expression?
op_teamplanning.subtaak_mijlpaal
After some additional research:
The group by mistake is not appear anymore when I delete all fields after the listagg field, that might be a clue to the solution.
It is not difficult to understand. You can have other columns not aggregated in your projection on the side of those listed in the group by expression.
The reason for ORA-01489 is that the resulting string will become long and exceeds 4000 bytes.
You will find several solution in this forum.
For example
-
error: not a GROUP BY expression
Hello world
Looks like I need some help here... :) don't know what that means, but im getting this message
00979 00000 - "not a GROUP BY expression"
* Cause:
* Action:
Error on line: column 137: 36
It's the function:
function get_path (materialID in number, materialTypeID number, inTopFolderID number default null, inMaterialFolderID in the number default null, webMode in default number 1 in)
return varchar2;
and im using it on my query
, (select material_util.get_path (m.material_id, 8, 1021695, min (mf.)) (IP_MATERIALFOLDERID), 1).
material m, materialfolder mf
where mf.nfx_link = m.MATERIAL_ID
and t.template_id = m.template_id) as path
It seems that min (mf. IP_MATERIALFOLDERID) is having some problems here... don't know why...
Let me know guys...
Thank you...
JRead below for informative post from Frank Kulash on ABC in the group by clause
{message: id = 9969583} -
Hi all
Can someone tell me what is wrong with the query below? I get an exception is NOT a GROUP OF CLAUSE:
SELECT LAST_DAY((xxx.timevalue)) as SUMMARYDATE , xxx.acct AS ACCTNUM , xxx.referenceid AS SEARCHTYPE , CASE WHEN NVL(xxx.PRIMARYSRCH_IND,'N') = 'Y' THEN COUNT(xxx.searchid) ELSE 0 END Cnt_PrimarySearches , CASE WHEN NVL(xxx.primarysrch_ind,'N') = 'N' THEN COUNT(xxx.Searchid) ELSE 0 END Cnt_SecondarySearches FROM XXX_Tablename xxx WHERE xxx.referenceid NOT IN ('Alert','Search','Collection') GROUP BY LAST_DAY((xxx.timevalue)) , xxx.acctnum , xxx.referenceidHello
Try this
SELECT LAST_DAY((xxx.timevalue)) as SUMMARYDATE , xxx.acct AS ACCTNUM , xxx.referenceid AS SEARCHTYPE ,COUNT( CASE WHEN NVL(xxx.PRIMARYSRCH_IND,'N') = 'Y' THEN (xxx.searchid) ELSE 0 END Cnt_PrimarySearches) , COUNT(CASE WHEN NVL(xxx.primarysrch_ind,'N') = 'N' THEN (xxx.Searchid) ELSE 0 END) Cnt_SecondarySearches FROM XXX_Tablename xxx WHERE xxx.referenceid NOT IN ('Alert','Search','Collection') GROUP BY LAST_DAY((xxx.timevalue)) , xxx.acctnum , xxx.referenceidNot tested
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I can receive all messages from whatsapp on my Apple Watch, but not the Group whatsapp messages, don't know why... Help, please.
Besides, my watch is custom in Spanish, but only answer messages Whatsapp understands English... anyone know why? Thanks to you all!
Hello
To change the language for a response on your watch: Press answer > firmly press the screen > press on choose language > select Spanish.
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In Outlook Express, how can I send the same message to the large group (already in the address book), but have to each recipient can only see his name (not the Group)?
To use the functionality of the BCC (Blind Carbon Copy), in a new message window, click View | All headers and type the addresses separated by a; Or: Click the button to. You will see your list of contacts and the choice to put them in the To, CC, or BCC field. Click on an address, and then click BCC to add it. Repeat for all of the contacts you want. (Note: most of the providers have limits as to how many messages you can send both a. 25 is common, but it varies).
Put your own address in the box to. That's the only name/address that any recipient will see. If you leave the field empty, some people may not receive e-mail because of message rules they put in place, or restrictions imposed by their ISP.
You can also make an entry in the address book using your e-mail address, but put something like the mailing list in the area of the display.
*********************
You can also create groups if you send e-mail to the same people often.
To create a group of contacts:
You can create a single group name (or alias) to use when sending a message to several contacts at the same time. Just create a group name and add individual contacts to the group. Then just type the name of the group in the box for when you send mail.
1. in the address book, select the folder in which you want to create a group. Click New in the toolbar, and then click New Group.
2. the Properties dialog box opens. In the group name box, type the name of the group.
3. There are several ways to add people to the Group:
a. to add a person from your address book list, click Select members, and then click a name in the address book list.
(b) to add a person directly to the group without adding the name to your address book, type the person's name and e-mail address at the bottom of the Properties dialog box and then click Add.
to add a person to both the Group and your address book, click New Contact and enter the appropriate information.
(d) to use a directory service, click Select members, and then click search. Select a directory service in the drop-down list at the end of the text box. After finding and selecting an address, it is automatically added to your address book.
4. Repeat for each addition until your group is defined.Note
a. to view a list of your groups separately from the list of address book in the address book on the view menu, make sure that folders and groups is selected.
b. you can create multiple groups, and contacts can belong to several groups.If you want to send to a group without addresses are displayed for each recipient, open the address book and make a new entry. Enter the name of the group in the area of the display, but use your address. (Some Internet service providers require a legitimate address in the line to and recipients will know it's from the Group).
Click on the button to. Enter the name of the group using your address. Enter the group in the BCC field.
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The message below appears, after having tried and do not access the Article, release press, or Social Bookmarking sites; Since the software newly installed.
((Accès àle chemin c:\Program Files (x86) Dotcom Marketing / Auto System X references xml traffic is denied.))
Does anyone know how to overcome this problem.
Original title: Error Message
"since the newly installed software? What software? Have you checked the manufacturer's website to see if they have a solution?
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SQL error: ORA-00979: not a GROUP BY
Hi team,
I am trying to execute the query
SELECT DISTINCT comp.company_name |' -' || COMP.contract_number AS 'company_name '.
, UPPER (bh.first_name) AS 'budget_holder '.
, INITCAP (sup.first_name) |' -' || SUP. Surname AS 'supervisor '.
, INITCAP (emp.status) AS "Department".
, INITCAP (emp.first_name |) » '|| EMP. Surname) AS "employee."
r.employee_id
, emp.paaf_number AS 'paaf_num '.
, emp.employee_payroll_number AS 'payroll_num '.
, emp.discipline AS 'discipline '.
, NVL (SUM (tg.week_day1), 0) AS "day 1".
, NVL (SUM (tg.week_day2), 0) AS "day 2".
, NVL (SUM (tg.week_day3), 0) AS day '3 '.
, NVL (SUM (tg.week_day4), 0) AS "day4.
, NVL (SUM (tg.week_day5), 0) AS "day5".
, NVL (SUM (tg.week_day6), 0) AS "day6.
, NVL (SUM (tg.week_day7), 0) AS "day 7".
r.valid_from
r.valid_to
Tw_roster_data r
JOIN tw_employee emp
ON emp.employee_id = r.employee_id
JOIN tg tw_timesheet_stage
ON tg.employee_id = r.employee_id
AND tg.week_commencing = r.valid_from
JOIN the tw_contracting_company comp
ON comp.contracting_company_id = r.contracting_company_id
JOIN tw_supervisor sup
ON sup.supervisor_id = tg.supervisor_id
JOIN tw_budget_holder bh
ON bh.budget_holder_id = sup.budget_holder_id
WHERE r.contracting_company_id = 101
AND r.VALID_FROM = January 31, 2015.
AND r.VALID_TO = February 6, 2015"
Group of r.employee_id, comp.company_name, bh.first_name,
EMP.paaf_number, emp.employee_payroll_number, emp.discipline,
r.valid_from, r.valid_to;
But still the error below
Error in the command line: 1 column: 17
Error report-
SQL error: ORA-00979: not a GROUP BY expression
00979 00000 - "not a GROUP BY expression"
Can help.
Hello
When to use analytical function oracle other columns used based on the analysis, must be included in the GROUP BY Clause
SELECT expression1, expression2, ... expression_n, aggregate_function (expression) FROM tables WHERE conditions GROUP BY expression1, expression2, ... expression_n;
SQL 101: Seen are medium and other aggregate data
SELECT DISTINCT comp.company_name || ' - ' || comp.contract_number AS "company_name", UPPER (bh.first_name) AS "budget_holder", INITCAP (sup.first_name) || ' - ' || sup.surname AS "supervisor", INITCAP (emp.status) AS "department", INITCAP (emp.first_name || ' ' || emp.surname) AS "employee", r.employee_id, emp.paaf_number AS "paaf_num", emp.employee_payroll_number AS "payroll_num", emp.discipline AS "discipline", NVL (SUM (tg.week_day1), 0) AS "day1", NVL (SUM (tg.week_day2), 0) AS "day2", NVL (SUM (tg.week_day3), 0) AS "day3", NVL (SUM (tg.week_day4), 0) AS "day4", NVL (SUM (tg.week_day5), 0) AS "day5", NVL (SUM (tg.week_day6), 0) AS "day6", NVL (SUM (tg.week_day7), 0) AS "day7", r.valid_from, r.valid_to FROM tw_roster_data r JOIN tw_employee emp ON emp.employee_id = r.employee_id JOIN tw_timesheet_stage tg ON tg.employee_id = r.employee_id AND tg.week_commencing = r.valid_from JOIN tw_contracting_company comp ON comp.contracting_company_id = r.contracting_company_id JOIN tw_supervisor sup ON sup.supervisor_id = tg.supervisor_id JOIN tw_budget_holder bh ON bh.budget_holder_id = sup.budget_holder_id WHERE r.contracting_company_id = 101 AND r.VALID_FROM = '31-JAN-2015' AND r.VALID_TO = '06-FEB-2015' GROUP BY comp.contract_number ,comp.company_name ,bh.first_name ,sup.first_name ,sup.surname , emp.status ,emp.first_name ,emp.surname r.employee_id, emp.paaf_number, emp.employee_payroll_number, emp.discipline, r.valid_from, r.valid_to; -
SQL - ORA-00979: not a GROUP BY expression
Hi Expert,
I received the error message: ORA-00979: not a GROUP BY expression at the bottom of the sql statement
Please advise - display total number of point of sale and the total amount of all items. Only display results when the total quantity is greater than 2.
SELECT o.Qty, sum(o.Qty*o.salesprice) AS TOTALDOLLARS, description and i.Itemcode
OF ORDERLINE o
INNER JOIN POINT I
ON o.itemcode = i.itemcode
GROUP BY i.Itemcode
After having o.qty > 2
> > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > >
Create table ORDERLINE
(
Qty number 4,
Salesprice Number (6.2),
OrderNo Number (3).
ItemCode Varchar2 (6).
Primary key (OrderNo, Itemcode)
Foreign Key (Itemcode) refers to POINT.
Foreign Key (OrderNo) made reference SALESORDER
Create table POINT
(
ItemCode Varchar2 (6).
Description Varchar2 (50).
Retailprice Number (6.2),
Number of weight (4.1),
Purchaseprice Number (6.2),
Category Varchar2 (20).
Primary Key (Itemcode)
);Hi 845720,
Based on the sql code, the sum must be grouped itemcodewise, descriptionwise, qtywise.
This means that you have all these in a group by clause too with sum().eg : group by i.Itemcode, i.Description, o.QtyIs this wise sum qty is logical? I do not know...
It will be useful,
CKLPPublished by: CKLP April 14, 2011 22:10
-
Subquery in the select clause and not "a group by expression" error.
Hi all
I hope someone out there can help me out with this one. I have a sql query that performs a subquery in the select case combined with an aggregate function and gives me a "not a group by expression.
I created a simplified example
I'm sure he expected me to add the po_number to the group by clause, but this does not work and gives the error "invalid identifier".SELECT COUNT(*) , ai.invoice_num invoice_number , ai.description invoice_description , (SELECT poh.po_header_id FROM po_headers poh , po_distributions pod WHERE pod.po_distribution_id = aid.po_distribution_id AND pod.po_header_id = poh.po_header_id ) po_number FROM ap_invoice_distributions aid , ap_invoices ai WHERE ai.invoice_id = 1476932 AND aid.project_id = 8608 AND aid.task_id = 462202 AND ai.invoice_id = aid.invoice_id GROUP BY ai.invoice_num, ai.description;
Can someone suggest a way for a new concert the query so that I can add po_number to my education by clause.
KrisYou should try either:
SELECT COUNT (*),
AI.invoice_num invoice_number,
have. Description invoice_description,
(SELECT poh.po_header_id
OF po_headers poh,.
pod po_distributions
WHERE pod.po_distribution_id = aid.po_distribution_id
AND pod.po_header_id = poh.po_header_id
) po_number
HELP ap_invoice_distributions.
ap_invoices AI
WHERE ai.invoice_id = 1476932
AND aid.project_id = 8608
AND aid.task_id = 462202
AND ai.invoice_id = aid.invoice_id
Ai.invoice_num GROUP,
have. Description, aid.po_distribution_id;or
SELECT COUNT (*),
AI.invoice_num invoice_number,
have. Description invoice_description,
MAX ((SELECT poh.po_header_id
OF po_headers poh,.
pod po_distributions
WHERE pod.po_distribution_id = aid.po_distribution_id
AND pod.po_header_id = poh.po_header_id
po_number))
HELP ap_invoice_distributions.
ap_invoices AI
WHERE ai.invoice_id = 1476932
AND aid.project_id = 8608
AND aid.task_id = 462202
AND ai.invoice_id = aid.invoice_id
Ai.invoice_num GROUP,
have. Description; -
Get rid of Parental control on my guest account
Why can't get rid of parental control on my guest account! It is said you can not set up parental controls for the guest account and yet when I try to connect it throws up of all these parental controls! I watched & tried and tried again to fix it. Very frustrated here, especially with guests coming for the holidays! I just set up a password for the guest account...
Hello
See this and the 'related links' here and I hope that you find the answer. You may need to remove
all parental controls and try again. You have Ultimate or business where group policies would come
in game (GPEdit)?How to install and use Parental controls in Vista
http://www.Vistax64.com/tutorials/95139-parental-controls-Setup-use.htmland these:
Setting up Windows Vista's Parental control
http://www.bleepingcomputer.com/tutorials/tutorial139.htmlSet up Parental controls
http://Windows.Microsoft.com/en-us/Windows-Vista/set-up-parental-controlsI hope this helps.
Rob - bicycle - Mark Twain said it is good. -
Microsoft support see my installed OS windows XP. When, in fact, I have Vista for businesses. So that when I click on an article I get a message that the article does not apply to me and that I should see windows xp support
If you don't mind, double check what Windows do you really.
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t-4-2
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How to get rid of repeat groups using the query? Its my sql script.
Mr President.
worm of Oracle's 10g express edition
I want to get rid of repeating groups and wants to get result like
If my table script is as below
BEGIN -- drop tables EXECUTE IMMEDIATE 'DROP TABLE CUSTOMER'; EXECUTE IMMEDIATE 'DROP TABLE PRODUCT'; EXECUTE IMMEDIATE 'DROP TABLE SUPPLIER'; EXECUTE IMMEDIATE 'DROP TABLE PURCHASE'; EXECUTE IMMEDIATE 'DROP TABLE PURCHASELINE'; EXECUTE IMMEDIATE 'DROP TABLE SALES'; EXECUTE IMMEDIATE 'DROP TABLE SALESLINE'; EXECUTE IMMEDIATE 'DROP TABLE STOCK'; EXCEPTION WHEN OTHERS THEN DBMS_OUTPUT.PUT_LINE(''); END; / CREATE TABLE CUSTOMER ( cust_id NUMBER NOT NULL , name VARCHAR2(50) NOT NULL , address VARCHAR2(100) DEFAULT NULL , contactno VARCHAR2(20) DEFAULT NULL , CONSTRAINT CUSTOMER_PK PRIMARY KEY ( cust_id ) ENABLE ); CREATE TABLE PRODUCT ( prod_id NUMBER NOT NULL , name VARCHAR2(50) NOT NULL , description VARCHAR2(50) DEFAULT NULL , CONSTRAINT PRODUCT_PK PRIMARY KEY ( prod_id ) ENABLE ); CREATE TABLE SUPPLIER ( suplr_id NUMBER NOT NULL , name VARCHAR2(50) NOT NULL , address VARCHAR2(100) DEFAULT NULL , contactno VARCHAR2(20) DEFAULT NULL , CONSTRAINT SUPPLIER_PK PRIMARY KEY ( suplr_id ) ENABLE ); CREATE TABLE PURCHASE ( pur_id NUMBER NOT NULL , pur_date DATE NOT NULL , suplr_id NUMBER DEFAULT '0' , CONSTRAINT PUR_SUPLR_FK FOREIGN KEY ( suplr_id ) REFERENCES SUPPLIER ( suplr_id ) , CONSTRAINT PURCHASE_PK PRIMARY KEY ( pur_id ) ENABLE ); CREATE TABLE PURCHASELINE ( pur_id NUMBER DEFAULT '0' NOT NULL , prod_id NUMBER DEFAULT '0' NOT NULL , pur_qty NUMBER DEFAULT '0' NOT NULL , unit_pur_price NUMBER DEFAULT '0' NOT NULL , CONSTRAINT PUR_LINE_PUR_FK FOREIGN KEY ( pur_id ) REFERENCES PURCHASE ( pur_id ) , CONSTRAINT PUR_LINE_POD_FK FOREIGN KEY ( prod_id ) REFERENCES PRODUCT ( prod_id ) , CONSTRAINT PUR_LINE_PK PRIMARY KEY ( pur_id,prod_id ) ENABLE ); CREATE TABLE SALES ( sal_id NUMBER NOT NULL , sal_date DATE DEFAULT NULL , cust_id NUMBER DEFAULT '0' , CONSTRAINT PUR_CUSTR_FK FOREIGN KEY ( cust_id ) REFERENCES CUSTOMER ( cust_id ) , CONSTRAINT SALES_PK PRIMARY KEY ( sal_id ) ENABLE ); CREATE TABLE SALESLINE ( sal_id NUMBER DEFAULT '0' NOT NULL , prod_id NUMBER DEFAULT '0' NOT NULL , sal_qty NUMBER DEFAULT '0' NOT NULL , unit_sal_price NUMBER DEFAULT '0' NOT NULL , CONSTRAINT SAL_LINE_SAL_FK FOREIGN KEY ( sal_id ) REFERENCES SALES ( sal_id ) , CONSTRAINT SAL_LINE_POD_FK FOREIGN KEY ( prod_id ) REFERENCES PRODUCT ( prod_id ) , CONSTRAINT SAL_LINE_PK PRIMARY KEY ( sal_id,prod_id ) ENABLE ); CREATE TABLE STOCK ( prod_id NUMBER NOT NULL , prod_qty NUMBER DEFAULT '0' NOT NULL , re_ord_level NUMBER DEFAULT '0' NOT NULL , CONSTRAINT STOCK_POD_FK FOREIGN KEY ( prod_id ) REFERENCES PRODUCT ( prod_id ) , CONSTRAINT STOCK_PK PRIMARY KEY ( prod_id ) ENABLE ); SET DEFINE OFF; -- ***** Populate Tables ***** --CUSTOMER table data INSERT INTO CUSTOMER VALUES(1,'Kamrul Hasan','Moghbazar, Dhaka','0456789123'); INSERT INTO CUSTOMER VALUES(2,'Rabiul Alam','Motijheel, Dhaka','0567891234'); INSERT INTO CUSTOMER VALUES(3,'Shahed Hasan','2-G/1,2-2,Mirpur, Dhaka','0678912345'); --PRODUCT table data INSERT INTO PRODUCT VALUES(1,'RAM',NULL); INSERT INTO PRODUCT VALUES(2,'DVD Drive',NULL); INSERT INTO PRODUCT VALUES(3,'HDD','160 GB Satta'); INSERT INTO PRODUCT VALUES(4,'Monitor','LCD 19\"'); INSERT INTO PRODUCT VALUES(5,'Printer','HP Color'); INSERT INTO PRODUCT VALUES(6,'Keyboard','Multimedia Keyborad (Customised)'); INSERT INTO PRODUCT VALUES(7,'Mouse','Customised Mouse'); -- SUPPLIER table data INSERT INTO SUPPLIER VALUES(1,'Salam Enterprise','2-H/1-10, Mirpur, Dhaka, Bangladesh','0123456789'); INSERT INTO SUPPLIER VALUES(2,'ABC Supplies','Dhanmondi, Dhaka','0234567891'); INSERT INTO SUPPLIER VALUES(3,'XYZ Company','52 Gabtali, Dhaka','0345678912'); --PURCHASE table data INSERT INTO PURCHASE VALUES(1,TO_DATE('12-12-2007','dd-mm-yyyy'),1); INSERT INTO PURCHASE VALUES(2,TO_DATE('13-12-2007','dd-mm-yyyy'),2); INSERT INTO PURCHASE VALUES(3,TO_DATE('13-12-2007','dd-mm-yyyy'),1); INSERT INTO PURCHASE VALUES(4,TO_DATE('14-12-2007','dd-mm-yyyy'),1); INSERT INTO PURCHASE VALUES(5,TO_DATE('15-12-2007','dd-mm-yyyy'),2); INSERT INTO PURCHASE VALUES(6,TO_DATE('20-12-2007','dd-mm-yyyy'),3); INSERT INTO PURCHASE VALUES(7,TO_DATE('05-01-2007','dd-mm-yyyy'),2); INSERT INTO PURCHASE VALUES(8,TO_DATE('06-05-2007','dd-mm-yyyy'),3); INSERT INTO PURCHASE VALUES(9,TO_DATE('15-07-2008','dd-mm-yyyy'),1); --PURCHASELINE table data INSERT INTO PURCHASELINE VALUES(1,1,25,900); INSERT INTO PURCHASELINE VALUES(1,2,10,1700); INSERT INTO PURCHASELINE VALUES(1,3,10,5000); INSERT INTO PURCHASELINE VALUES(1,4,9,5500); INSERT INTO PURCHASELINE VALUES(1,7,100,250); INSERT INTO PURCHASELINE VALUES(2,3,15,5000); INSERT INTO PURCHASELINE VALUES(2,6,20,500); INSERT INTO PURCHASELINE VALUES(3,6,25,450); INSERT INTO PURCHASELINE VALUES(4,7,100,200); INSERT INTO PURCHASELINE VALUES(5,5,10,3450); INSERT INTO PURCHASELINE VALUES(5,6,10,180); INSERT INTO PURCHASELINE VALUES(6,1,15,900); --SALES table data INSERT INTO SALES VALUES(1,TO_DATE('12-12-2007','dd-mm-yyyy'),2); INSERT INTO SALES VALUES(2,TO_DATE('15-12-2007','dd-mm-yyyy'),3); INSERT INTO SALES VALUES(3,TO_DATE('20-12-2007','dd-mm-yyyy'),2); INSERT INTO SALES VALUES(4,TO_DATE('28-12-2007','dd-mm-yyyy'),3); INSERT INTO SALES VALUES(5,TO_DATE('05-01-2008','dd-mm-yyyy'),1); INSERT INTO SALES VALUES(6,TO_DATE('12-01-2008','dd-mm-yyyy'),3); INSERT INTO SALES VALUES(7,TO_DATE('12-02-2008','dd-mm-yyyy'),1); INSERT INTO SALES VALUES(8,TO_DATE('12-02-2008','dd-mm-yyyy'),2); INSERT INTO SALES VALUES(9,TO_DATE('12-02-2008','dd-mm-yyyy'),3); --SALESLINE table data INSERT INTO SALESLINE VALUES(1,1,3,1000); INSERT INTO SALESLINE VALUES(1,3,1,5500); INSERT INTO SALESLINE VALUES(1,4,1,6000); INSERT INTO SALESLINE VALUES(1,6,2,500); INSERT INTO SALESLINE VALUES(1,7,2,200); INSERT INTO SALESLINE VALUES(2,2,2,1900); INSERT INTO SALESLINE VALUES(2,7,2,200); INSERT INTO SALESLINE VALUES(3,4,1,5500); INSERT INTO SALESLINE VALUES(4,2,1,2200); INSERT INTO SALESLINE VALUES(5,6,1,300); INSERT INTO SALESLINE VALUES(5,7,2,250); INSERT INTO SALESLINE VALUES(6,6,1,300); INSERT INTO SALESLINE VALUES(6,7,3,180); INSERT INTO SALESLINE VALUES(7,1,2,1000); INSERT INTO SALESLINE VALUES(7,2,1,1900); INSERT INTO SALESLINE VALUES(7,3,2,5500); INSERT INTO SALESLINE VALUES(8,4,1,5500); INSERT INTO SALESLINE VALUES(8,6,2,300); INSERT INTO SALESLINE VALUES(8,7,1,200); INSERT INTO SALESLINE VALUES(9,1,3,1000); INSERT INTO SALESLINE VALUES(9,3,2,5500); INSERT INTO SALESLINE VALUES(9,5,2,1000); --STOCK table data INSERT INTO STOCK VALUES(1,200,15); INSERT INTO STOCK VALUES(2,25,10); INSERT INTO STOCK VALUES(3,40,10); INSERT INTO STOCK VALUES(4,20,10); INSERT INTO STOCK VALUES(5,10,10); INSERT INTO STOCK VALUES(6,50,20); INSERT INTO STOCK VALUES(7,150,20); COMMIT;Concerning
I could not figure out how you pulled your expected results, especially the last column. I guess that your problem I have several prod_id table productline / salesline. If a group of prod_id in these table should solve your problem. Something like that
SQL> select p.prod_id as product_prod_id 2 , p.name as product_name 3 , p.description as product_description 4 , s.prod_qty as stock_prod_qty 5 , s.re_ord_level as stock_re_ord_level 6 , pl.pur_qty as purchaseline_pur_qty 7 , pl.unit_pur_price as purchaseline_unit_pur_price 8 , sl.sal_qty as salesline_sal_qty 9 , sl.unit_sal_price as salesline_unit_sal_price 10 from product p 11 join stock s 12 on p.prod_id = s.prod_id 13 join ( 14 select prod_id 15 , sum(pur_qty) pur_qty 16 , sum(unit_pur_price) unit_pur_price 17 from purchaseline 18 group 19 by prod_id 20 ) pl 21 on p.prod_id = pl.prod_id 22 join ( 23 select prod_id 24 , sum(sal_qty) sal_qty 25 , sum(unit_sal_price) unit_sal_price 26 from salesline 27 group 28 by prod_id 29 ) sl 30 on p.prod_id = sl.prod_id 31 order 32 by p.prod_id; PRODUCT_PROD_ID PRODUCT_NAME PRODUCT_DESCRIPTION STOCK_PROD_QTY STOCK_RE_ORD_LEVEL PURCHASELINE_PUR_QTY PURCHASELINE_UNIT_PUR_PRICE SALESLINE_SAL_QTY SALESLINE_UNIT_SAL_PRICE --------------- -------------------- ---------------------------------------- -------------- ------------------ -------------------- --------------------------- ----------------- ------------------------ 1 RAM 200 15 40 1800 8 3000 2 DVD Drive 25 10 10 1700 4 6000 3 HDD 160 GB Satta 40 10 25 10000 5 16500 4 Monitor LCD 19\" 20 10 9 5500 3 17000 5 Printer HP Color 10 10 10 3450 2 1000 6 Keyboard Multimedia Keyborad (Customised) 50 20 55 1130 6 1400 7 Mouse Customised Mouse 150 20 200 450 10 1030 7 rows selected. -
Thunderbird does not recognize groups of outlook express news. What can I do to fix?
Years, I had no problem emailing messages to my Outlook Express news groups. Now, when I try to do, I get a message saying that the news group "is not a valid email address because it is not of the form user@host.» Thanks for your help.
See the bug:
Please register and add comments stating what OS you are using and what version of thunderbird. then Vote for the bug - this at the top:
- Importance:-normal (vote)
(Vote) is a link: click on it. Select the check box for the bug and click the button "change my voice."
Workaround solution:
Comment of Fabian Rodriguez 2014-09-04 06:19:15 PDT
Confirmed workaround solutions:
- All by composing an email open the address book and select the list you want to send, to highlight all the names in the list and drag them to the To: box. This example uses your existing data without changing it.
- Replace white "" between the words in the descriptions of these lists with an underscore "_". This requires modification of your descriptions of mailing list (s).
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Article not available - this article cannot be read
With the exception of free U2 songs, my playlist everything is grey and when you try to play a song I get the message "not available article - this article cannot be read. Same problem when I connect my phone to my laptop and access iTunes. I see the reading list, but can't play the songs. Not exactly how long it has been like this that I had not used for a while. Any help would be appreciated. I don't know that I'm missing something simple. I have an iPhone 6 and I am up to date with all updates.
Hey there,
I had this problem two minutes ago, but I managed to fix it. During the synchronization of your iPhone to iTunes, your phone is unlocked? Mine was and the music was grayed out, I tried the lock phone and disconnect it from the computer and then plug it back again. The music is fine and everything is back to normal.
I hope this works,
Miomo
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