Options of mutually exclusive in a function of the Option

Similar Questions

• Class BOM with mutually exclusive components option: box is protected from update

  Hi all

  Please refer to the following Nomenclature-

  Article A- User item Type: class of Option ATO

  BOM item type: Option class

  Item B- Finished product

  Section C- Finished product

  Nomenclature of point A is twofold - point B and C article.

  Box each other is protected against editing.

  Please let know if BOM above is properly created. If not, please explain how to create a BOM with mutually exclusive elements.

  Kind regards

  Abhishek

  Hi Abhishek,

  This is a planned feature.

  Mutually Exclusive is set to 'class point Option' in the model bill ATO/PTO.

  Extend your example - if you have a point D, as the model which included the Option class point has... then in the Bill to point D, against article A, we would be setting up the "Mutually exclusive" indicator to "Y" to indicate the system to choose the point B or C of the agenda during the configuration of the model.

  I hope this helps.

  Thank you and best regards,

  REDA

• Application of mutually exclusive

  Hi all

  Could you please help me in this problem.

  CREATE TABLE TEST_VERSION (VERSION_ID NUMBER, SUBVERSION VARCHAR2 (100));

  insert into TEST_VERSION VALUES(1,null);

  insert into TEST_VERSION VALUES(1,'Alpha');

  insert into TEST_VERSION VALUES(1,'Internal Beta');

  insert into TEST_VERSION VALUES(1,'Technical Preview');

  insert into TEST_VERSION VALUES(1,'RTM');

  insert into TEST_VERSION VALUES(2,null);

  insert into TEST_VERSION VALUES(2,'Alpha');

  insert into TEST_VERSION VALUES(3,'Internal Beta');

  insert into TEST_VERSION VALUES(4,'Technical Preview');

  SELECT * FROM TEST_VERSION;

  Select rules:

  for given version_id:

  (1) if there is a SUBVERSION = 'RTM' or the lines in the game and also a line with SUBVERSION = NULL ignore the

  line with SUBVERSION = NULL, and then select all of the other lines, including RTM

  (2) if there is a SUBVERSION row = NULL and there is no line with SUBVERSION = "RTM" then select all the

  lines, including SUBVERSION = NULL

  In essence, row with SUBVERSION = NULL cannot coexist with SUBVERSION = "RTM" for the same

  version_id. They are mutually exclusive. RTM has a higher priority.

  873797 wrote:

  Ramin thanks for your response.

  Your answer works partially.

  For a = 1, it returns the correct values, removed B = NULL row

  For the test of the ranks, he returned only a single line for a = 2. Rest of the lines for a = 3 and a = 4 has disappeared.

  Hello. Okay, I think that now I understand you. Try

  t (a, b) as)

  Select 1, null of union double all the

  Select 1, 'Alpha' from dual union all

  Select 1, 'Internal Beta' dual Union all

  Select 1, 'Technical Preview' from dual union all

  Select 1, 'RTM' from dual union all

  Select 2, union null value double all the

  Select 2, 'Alpha' from dual union all

  Select 3, 'Internal Beta' dual Union all

  Select option 4, "Technical Preview" of double)

  Select * from)

  Select t.*,

  sum (case when b is null then 1 when b = "RTM" then 1 end) on (partition one) c

  t

  )

  where nvl(b,'-1')! = (case when c = 2 then '-1' another '1' end ')

  ----

  Ramin Hashimzade

• Drop-down menus are mutually exclusive

  Hi all:

  I am working on a form in which I need to have a user rates four items 1 to 4 compared to the other. Initially, we were going to use 4 drop downs each menu containing four options allowing the user to choose. The problem is, of course, that the user could choose option 1 four times in a row. So I need a way to allow the user to assess these four points 1 to 4, but in a mutually exclusive way. the image below shows the problem (they are in Spanish, but the text is not important). Here point 1 and section 4 have been selected both as 1, which is what we want to avoid. Any suggestions would be greatly appreciated. Thank you.

  

  Hello

  You could have a script of the event preOpen all of the four drop-down menus that would set the display settings, based on the previous selections in the other drop-down menus.

  There is an example here to populate the drop-down menus: http://assure.ly/jcTahK.

  Try this in the DropDownList1 preOpen event:

  Remove the previously selected items

  this.deleteItem (DropDownList2.selectedIndex);

  this.deleteItem (DropDownList3.selectedIndex);

  this.deleteItem (DropDownList4.selectedIndex);

  Hope that helps,

  Niall

• Patch S8C2 is mutually exclusive and can not coexist with the patches: ZLNA, EJUW

  Hi all

  I tried to apply the patch from Jan 2016 to the Weblogic Server that runs the RMS Application.

  The version of the Weblogic Server is 10.3.6

  The version of RMS App is 13.2.6

  While applying the patch that has a PATCH-LIST of S8C2 on the Weblogic Server, I encountered the following error:

  [oracle@test-rms-app bsu] $. /BSU.sh - prod_dir = $WLS_HOME / wlserver_10.3 - patch_download_dir = / home/oracle/2016_JAN_CPU_SPU - patchlist = S8C2-verbose - install

  Checking for conflicts...

  Detected A - conflict to solve and run the installation of the patch again

  Conflict condition details below:

  Patch S8C2 is mutually exclusive and can not coexist with the patches: ZLNA, EJUW

  After reading the forums, I followed the suggestion to delete the previous patch: EJUW and who has obtained successfully removed as shown below, when I tried to install the Patch Jan complained conflict ZLNA patch and when trying to remove the ZLNA encountered unrecognized patch ID patch: ZLNA.

  [oracle@test-rms-app bsu] $. /BSU.sh - delete - patchlist = EJUW-prod_dir = $WLS_HOME/wlserver_10.3

  Checking for conflicts...

  No conflict detected

  Removal of the Patch ID: EJUW...

  Result: success

  [oracle@test-rms-app bsu] $. /BSU.sh - prod_dir = $WLS_HOME / wlserver_10.3 - patch_download_dir = / home/oracle/2016_JAN_CPU_SPU - patchlist = S8C2-verbose - install

  Checking for conflicts...

  Detected A - conflict to solve and run the installation of the patch again

  Conflict condition details below:

  Patch S8C2 is mutually exclusive and can not coexist with the patches: ZLNA

  [oracle@test-rms-app bsu] $. /BSU.sh - delete - patchlist = ZLNA-prod_dir = $WLS_HOME/wlserver_10.3

  Encountered unrecognized patch ID: ZLNA

  Any suggestions how to solve and apply the fix successfully Jan would be useful.

  Thank you.

  Hello

  Can you please set the download directory of the fix for MW_HOME/utils/bsu/cache_dir/with the help of Smart updated interface and test again.

  To designate a directory to download the hotfix, follow these steps:

  Start the smart update.

  On the Smart Update main window, choose file > Preferences.

  The Preferences dialog box appears.

  In the section Patch download directory of the Preferences dialog box, specify the path to the download patch directory.

  https://docs.Oracle.com/CD/E14759_01/doc.32/e14143/start.htm

  Thank you

  Aishwarya

• Using SQL to ensure the matching records are mutually exclusive.

  There are two tables defined in the following way:

  Table A

  Number 1

  Number 2

  Date

  ROWID

  Table B

  Number 1

  Number 2

  Date

  Identifier of the line

  Each table stores a call between number 1 and 2 on a specific date. The goal is to map exactly one entry of table A with exactly the record in table B

  in a mutually exclusive way. So a single call to a table must be associated with exactly one call the other table (the key is here

  A.Number1 is B.Number1 and A.Number2 = B.Number2). Because it is a relationship is many to many (the number of source and destination may be paired multiple)

  (time), I'm not able to build a series of sql statements that will allow me to get a relationship one between pairs of telephone numbers.

  I'm not allowed to develop a PL/SQL procedure, which would easily solve this problem.

  I was able to find a solution using MIN(Number 1) KEEP (DENSE_RANK FIRST ORDER BY Date) to THE (PARTITION BY x) the form x

  using temporary tables, which allows me to reach a breaking successively much many relationships (i.e. three broken bones in a 01:58 after

  an iteration, and after one iteration, I arrive at a one to one relationship). However, I can't break these relations some n number of times because it requires number n

  hard curls. Therefore, I need a sophisticated solution that will allow me to achieve a relationship one by one.

  Example of

  Table A

  Record 1

  Number 1:451923456789

  Number 2:541969432045

  Date: 29/07/2015-09:01

  Worksheet 2

  Number 1: 451923456789

  Number 2: 541969432045

  Date: 29/07/2015-09:03

  Table B

  Record 1

  Number 1: 451923456789

  Number 2: 541969432045

  Date: 29/07/2015-09:04

  Worksheet 2

  Number 1: 451923456789

  Number 2: 541969432045

  Date: 29/07/2015-09:05

  If we unite our table A and B by A.Number1 = B.Number1 and A.Number2 = B.Number2, we have 4 records. I'm looking for exactly two records.

  The criteria is to associate by the minimum of the sum of the date of the table A table B date. Therefore, the final result should match:

  (1) record 1 of table A with record 1 of table B.

  sheet 2) 2 table A with 2 record in table B.

  So we must do something to reduce the 4 records resulting from the join of two records describe as we see above.

  The result of the join:

  1st row: TableA.Record1 with TableB.Record1

  2nd place: TableA.Record1 with TableB.Record2

  Rank 3: TableA.Record2 with TableB.Record1

  4th place: TableA.Record2 with TableB.Record2

  What I'm looking for, which is easily achievable with a slider, but not with SQL:

  1st row: TableA.Record1 with TableB.Record1

  4th place: TableA.Record2 with TableB.Record2

  Note that if the minimum date condition allows us to select the necessary records, we won't get the expected results. In other words, using the minimum date.

  the results will be:

  1st row: TableA.Record1 with TableB.Record1

  Rank 3: TableA.Record2 with TableB.Record1

  (criteria - table a minimum date)

  or

  1st row: TableA.Record1 with TableB.Record1

  2nd place: TableA.Record1 with TableB.Record2

  (criteria - date minimum table B)

  Two of these results to break the rule are mutually exclusive.

  Post edited by: 3000640

  If I understand correctly, something like:

  SQL > with tableA (id, telephone1, telephone2, call_date) as)

  2. Select 1, ' 451923456789 ', ' 541969432045',

  3 to_date (July 29, 2015 09:01 ', 'dd.mm.yyyy hh24')

  4 union double all the

  5. Select 2, ' 451923456789 ', ' 541969432045',

  6 to_date (July 29, 2015 09:03 ', 'dd.mm.yyyy hh24')

  double 7),

  TableB 8 (id, telephone1, telephone2, call_date) as)

  9. Select 1, ' 451923456789 ', ' 541969432045',

  10 to_date (July 29, 2015 09:04 ', 'dd.mm.yyyy hh24')

  11 double Union all the

  12. Select 2, ' 451923456789 ', ' 541969432045',

  13 to_date (July 29, 2015 09:05 ', 'dd.mm.yyyy hh24')

  14 double)

  15 select a.id help, a.phone1 aphone1, a.phone2 aphone2,

  16 a.call_date acall_date, b.id offer, b.phone1 bphone1,

  17 b.phone2 bphone2, b.call_date bcall_date

  18 (select id, telephone1, telephone2, call_date,

  19 row_number() over (partition by numbers1, telephone2

  RN 20 order by call_date)

  tablea 21) a

  22 join (select id, telephone1, telephone2, call_date,

  23 row_number() over (partition by numbers1, telephone2

  RN 24 order by call_date)

  tableb 25) b

  26 on a.phone1 = b.phone1 and

  27 a.phone2 = b.phone2 and

  28 a.rn = b.rn;

  HELP APHONE1 APHONE2 ACALL_DATE BPHONE1 BPHONE2 BCALL_DATE OFFERS

  ---------- ------------ ------------ -------------------- ---------- ------------ ------------ --------------------

  1 451923456789 541969432045 July 29, 2015 09:01 1 451923456789 541969432045 July 29, 2015 09:04

  2 451923456789 541969432045 July 29, 2015 09:03 2 451923456789 541969432045 July 29, 2015 09:05

  John

• Why do I not see megasign as an option under "Additional functions" in the dashboard?

  I need to send the same document to more than 100 people for individual signatures and megasign seems the best option.  However, I didn't like an option under additional functions in the dashboard.  I currently have the individual account.

  Thank you

  Tom

  Hello Tom,

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  Kind regards

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• I have lightroom 5 and I'm trying to merge some pictures to make a panorama, I saw on the tutorial there is a function under the photos to merge into panorama. I do not see this option in my lightroom 5, it is something new in Lightroom 6?

  I have lightroom 5 and I'm trying to merge some pictures to make a panorama, I saw on the tutorial there is a function under the photos to merge into panorama. I do not see this option in my lightroom 5, it is something new in Lightroom 6? I don't have photoshop.

  Hi santanu_rudra,

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  Kind regards

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• A license is required at the VASA? A license is required for each copy? VSI is necessary to have the VASA? They are mutually exclusive? VSI need NOTTM?

  A license is required at the VASA? A license is required for each copy? VSI is necessary to have the VASA? They are mutually exclusive? VSI need NOTTM?

  Thanks in advance.

  Assuming that you are referring to EMC arrays.

  License to the VASA: No.

  VSI required at the VASA: No. they work very well together, but does require that the other.

  VSI allowing VAAI: No. VAAI is active with or without the VSI.

• report based on elements are mutually exclusive:

  Hi guys,.
  I am creating a parameterized report based on elements are mutually exclusive:
  
  I have a list select 'P1_Property_type' element that has these values (office, apartment)
  If you choose "desktop" then the report should ONLY the value of the selection list element 'P1_beds '.
  If you choose 'apartment' then the report should be considered AS the value of the selection list "P1_size."
  ----------
  I used this query, but it does not seem to contribute:
  

  Select * from realestate where
  unit_type = decode (: P1_PROPERTY_TYPE, 'null', unit_type,: P1_property_type)
  and
  (br = decode (: P1_beds, "null", br,: P1_beds) or size = decode (: P1_size, 'null', size,: P1_size))

  ----------------
  I hope my question is clear
  
  Kind regards
  Fateh

  Assuming you are using the literal string "null" instead of NULL.

  "it doesn't seem to work" because of this:

  (br = decode (: P1_beds, "null", br,: P1_beds) or size = decode (: P1_size, 'null', size,: P1_size))

  Assuming you choose 'office' and: has the value p1_beds and: p1_size is "null", you end up with a statement that is the equivalent of:

  select * from realesate
  where unit_type = 'office'
  and (br = :p1_beds
  or size=size)    <--------------problem
  

  and your: p1_beds restriction is so inefficient.

  I'm not a fan of decode for this logic.
  I prefer a clear statement of the exclusive predicates that the optimizer can sometimes deal more effectively.

  for example, assuming that it is irrelevant, if you choose office or apartment because the relevant parameter: p1_beds or: p1_size will have the appropriate value:

  select * from realestate
  where
        (:p1.property_type is null / = 'null'
  or    (:p1.property_type is not null / != 'null'
  and    unit_type          = :p1_property_type))
  and   (:p1_beds          is null / = 'null'
  or    (:p1_beds          is not null / != 'null'
  and    br                 = :p1_beds))
  and   (:p1_size          is null / = 'null'
  or    (:p1_size          is not null / != 'null'
  and    size               = :p1_size))
  

  Note that I have provided alternatives depending on whether you are actually the NULL or a magic string.

• County of mutually exclusive

  Here's 4 query, I need mutually exclusive number. I mean all data included in the first query in the second query and the two sets of data excluded in third query and so on... I will be very thank full.
  
  I need heads of accusation against each query, but mutually exclusive
  

  SELECT count(*)
    FROM cbainfo.ip_with_employer a
   WHERE (LENGTH (TRIM (a.old_nic_no)) = 13
          OR (LENGTH (TRIM (a.new_nic_no)) = 15
              AND SUBSTR (a.new_nic_no, 1, 5) <> 'DUMMY'))
         AND a.first_name IS NOT NULL
         AND A.EMP_AREA_CODE <> 'ZZZ'
         AND a.date_of_birth IS NOT NULL
         AND A.PRESENT_ADDRESS IS NOT NULL
         AND A.GENDER IS NOT NULL
         AND A.DATE_OF_JOINING_EOBI IS NOT NULL
         AND A.RELATIVE_NAME IS NOT NULL

  SELECT count(*)
    FROM cbainfo.ip_with_employer a
   WHERE (LENGTH (TRIM (a.old_nic_no)) = 13
          OR (LENGTH (TRIM (a.new_nic_no)) = 15
              AND SUBSTR (a.new_nic_no, 1, 5) <> 'DUMMY'))
         AND a.first_name IS NOT NULL
         AND A.EMP_AREA_CODE <> 'ZZZ'
         AND a.date_of_birth IS NOT NULL
         AND A.GENDER IS NOT NULL
         AND A.DATE_OF_JOINING_EOBI IS NOT NULL
         AND A.RELATIVE_NAME IS NOT NULL

  SELECT count(*)
    FROM cbainfo.ip_with_employer a
   WHERE (LENGTH (TRIM (a.old_nic_no)) = 13
          OR (LENGTH (TRIM (a.new_nic_no)) = 15
              AND SUBSTR (a.new_nic_no, 1, 5) <> 'DUMMY'))
         AND a.first_name IS NOT NULL
         AND A.EMP_AREA_CODE <> 'ZZZ'

  SELECT count(*)
    FROM cbainfo.ip_with_employer a
   WHERE A.EMP_AREA_CODE <> 'ZZZ'

  Published by: malhi on May 12, 2011 02:08

  Hi malhi,.

  I do not have your tables, so this is obviously not tested. But I'm sure you get the idea

  SELECT qry, count(*) qry_count
  FROM (
          SELECT CASE
                   WHEN (LENGTH (TRIM (a.old_nic_no)) = 13
                             OR (LENGTH (TRIM (a.new_nic_no)) = 15
                                 AND SUBSTR (a.new_nic_no,1,5) != 'DUMMY'))
                        AND a.first_name IS NOT NULL
                        AND a.date_of_birth IS NOT NULL
                        AND a.present_address IS NOT NULL
                        AND a.gender IS NOT NULL
                        AND a.date_of_joining_eobi IS NOT NULL
                        AND a.relative_name IS NOT NULL
                    THEN
                       'Q1'
                   WHEN (LENGTH (TRIM (a.old_nic_no)) = 13
                             OR (LENGTH (TRIM (a.new_nic_no)) = 15
                                 AND SUBSTR (a.new_nic_no,1,5) != 'DUMMY'))
                        AND a.first_name IS NOT NULL
                        AND a.date_of_birth IS NOT NULL
                        AND a.gender IS NOT NULL
                        AND a.date_of_joining_eobi IS NOT NULL
                        AND a.relative_name IS NOT NULL
                   THEN
                      'Q2'
                   WHEN (LENGTH (TRIM (a.old_nic_no)) = 13
                             OR (LENGTH (TRIM (a.new_nic_no)) = 15
                                 AND SUBSTR (a.new_nic_no,1,5) != 'DUMMY'))
                        AND a.first_name IS NOT NULL
                   THEN
                      'Q3'
                   ELSE
                      'Q4'
                 END
                   qry
          FROM   cbainfo.ip_with_employer a
          WHERE  A.EMP_AREA_CODE != 'ZZZ')
  GROUP BY qry;
  

  Or, using nested CASE

  SELECT qry, count(*) qry_count
  FROM (
          SELECT CASE
                   WHEN (LENGTH (TRIM (a.old_nic_no)) = 13
                             OR (LENGTH (TRIM (a.new_nic_no)) = 15
                                 AND SUBSTR (a.new_nic_no,1,5) != 'DUMMY'))
                        AND a.first_name IS NOT NULL
                   THEN
                      CASE
                         WHEN   a.date_of_birth IS NOT NULL
                            AND a.present_address IS NOT NULL
                            AND a.gender IS NOT NULL
                            AND a.date_of_joining_eobi IS NOT NULL
                            AND a.relative_name IS NOT NULL
                         THEN
                            'Q1'
                         WHEN   a.date_of_birth IS NOT NULL
                            AND a.gender IS NOT NULL
                            AND a.date_of_joining_eobi IS NOT NULL
                            AND a.relative_name IS NOT NULL
                        THEN
                           'Q2'
                        ELSE
                           'Q3'
                        END
                   ELSE
                      'Q4'
                 END
                   qry
          FROM   cbainfo.ip_with_employer a
          WHERE  A.EMP_AREA_CODE != 'ZZZ')
  GROUP BY qry;
  

  Or, even more fit

  SELECT qry, count(*) qry_count
  FROM (
          SELECT CASE
                   WHEN (LENGTH (TRIM (a.old_nic_no)) = 13
                             OR (LENGTH (TRIM (a.new_nic_no)) = 15
                                 AND SUBSTR (a.new_nic_no,1,5) != 'DUMMY'))
                        AND a.first_name IS NOT NULL
                   THEN
                      CASE
                         WHEN   a.date_of_birth IS NOT NULL
                            AND a.gender IS NOT NULL
                            AND a.date_of_joining_eobi IS NOT NULL
                            AND a.relative_name IS NOT NULL
                         THEN
                            CASE
                               WHEN a.present_address IS NOT NULL
                                  THEN
                                    'Q1'
                                  ELSE
                                    'Q2'
                            END
                        ELSE
                           'Q3'
                        END
                   ELSE
                      'Q4'
                 END
                   qry
          FROM   cbainfo.ip_with_employer a
          WHERE  A.EMP_AREA_CODE != 'ZZZ')
  GROUP BY qry;
  

  Concerning
  Peter

• Mutually exclusive check boxes

  I know that this question is asked a lot and I read through the other posts. My code still does not work. I tried all the variations I've seen here, using null instead of 0, using quotation marks, do not use quotes, double equal signs, no double equal signs... What am I doing wrong? I'm really new to JavaScript, so I'm not sure on the syntax stuff yet.

  assessment. Questions.Questionset.Questiondetail.TFdetail.False_check::click - (JavaScript, client)

  If (this.) RawValue is "1")
  {
  xfa.form.assessment.Questions.Questionset.Questiondetail.TFdetail.True_check.rawValue = 'no l';
  }

  assessment. Questions.Questionset.Questiondetail.TFdetail.True_check::click - (JavaScript, client)

  If (this.) RawValue is "1")
  {
  xfa.form.assessment.Questions.Questionset.Questiondetail.TFdetail.False_check.rawValue = 'he's naked'.
  }

  OK if you check the correct value. Checkboxes are not mutually exclusive... .radioButtons are. You can move these objects to radio buttons and change the appearance of the radio button for a place to make it look like a checkbox, but behave like a radiobutton.

  You can share your form it would make it easier to debug.

  Paul

• Change the function of the shortcut key of media on the laptop itself player

  Hey everybody,

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  I'm almost certain that there is a way, but I can't seem to find, if someone can help me, then I would be really happy,

  See you soon.

  Hello

  I remember that it was possible to attribute the different functions of the control buttons on several units.
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  I put t know what BIOS you have, but generally you can activate or deactivate this option in the BIOS.

• G8D94PA #ACJ: is it possible to change the function of the FN keys?

  Hello

  I sometimes use windows 7 32-bit due to my software dependency. in some software I have to use fn keys (F1 to F12) frequently with the combination of other keys. It is possible to enable the functionality of the fn keys as from now on if I have to use F5, so I use FN + F5 combination. So in this software I have to use F2 to F7 & I have to press CTRL + ALT + FN + F2 to F7.

  Please share any solution...

  Hello

  Shut down the laptop.  Tap away at the esc you key start Notepad to open the Start Menu.  Select the Bios ( f10 ) option, and then change the figure in the document at the following link.

  http://support.HP.com/us-en/document/c02035108

  Kind regards

  DP - K