ORCL:lookup - table problem

Similar Questions

• API: get the contents of a lookup table?

  Hello

  I have a small application that automates the deployment of applications. He, among others, should be able to make calls in VSM.

  I used a previous version of the API with infraEnterpriseAPI.asmx as an entry point, so I'm not totally familiar with that.

  Now, to make a call, the user of my application needs to fill out some information:

  -Call description

  Status - IPK

  -The group in support of the appeal must be sent to

  And that's all. There is another piece of information that is too full, but I put all those automatically.

  Now, I want to give my menus drop down users about the status of the IPK and the "Forward To" field, because I want to choose what type of call, it should be and who to send it to. They don't know the names or the refs of the IPK statutes or support groups, and they shouldn't have to.

  Problem is that I have no idea how to do to get the content of the API lookup tables. Is it possible to do? Or should I (as I did for the previous version) that information straight out of the database?

  Best regards

  Kris

  I think I'll just query the database directly... which seems quite a lot easier.

• View object database lookup Table

  Hello

  I use JDeveloper 11.1.1.6.0.

  Reading Guide of Fusion Developer's for ADF on the sharing of the application module, I found the following note in Section 10.3.1

  Note:

  While the view read-only objects that you create to access lookup tables are ideal for inclusion in a module of the shared application, if you want to share the view object in an instance of shared application module, you must create the view object in the same package as the module of the shared application.

  My question is, why the view object must be in the same package as the module of the shared application? What are the consequences if it is not respected?

  Thank you.

  Kind regards

  Tim

  Hello

  to me, this looks like a bug in the documentation. I think that its meant to say that both, I and VO must be in the same project structure (the application package should not serious). However, I haven't run a physical test, so do not know if there would be a class path search problem (but why should there be). Probably best for you just run a test.

  Frank

• How to create the formula with the lookup table

  Hi, I would like to convert formula in the below format of labview, no idea how this could be done more easy way?

  I intend to use the node form, but I'm not sure how to use the table of choice within the formula not or is that even possible?

  BR, Jani

  Dim dblLookUp (-) As Double = New Double (3, 1) {{4, 4}, {10, 200}, {60, 3000}, {100, 7000}}
     
  If dblAbsValue > = 0 and dblAbsValue<= dbllookup(0,="" 0)="">
  USB = dblLookUp (0, 1) / dblLookUp (0, 0)
  dblAbsValue = dblValue * USB
  ' lblMode.Text = 1
  ElseIf dblAbsValue > dblLookUp (0, 0) and dblAbsValue<= dbllookup(1,="" 0)="">
  USB = (dblLookUp (1, 1) dblLookUp (0, 1)) / ((1, 0) - dblLookUp dblLookUp (0, 0))
  dblValue = USB * dblAbsValue - USB * dblLookUp (0, 0) + dblLookUp (0, 1)
  ' lblMode.Text = 2
  ElseIf dblAbsValue > dblLookUp (1, 0) and dblAbsValue<= dbllookup(2,="" 0)="">
  USB = (dblLookUp (2, 1) dblLookUp (1, 1)) / (dblLookUp (2, 0) - dblLookUp (1, 0))
  dblValue = USB * dblAbsValue - USB * dblLookUp (1, 0) + dblLookUp (1, 1)
  ' lblMode.Text = 3
  ElseIf dblAbsValue > dblLookUp (2, 0) and dblAbsValue<= dbllookup(3,="" 0)="">
  USB = (dblLookUp (3, 1) dblLookUp (2, 1)) / (dblLookUp (3, 0) dblLookUp (2, 0))
  dblValue = USB * dblAbsValue - USB * dblLookUp (2, 0) + dblLookUp (2, 1)
  ' lblMode.Text = 4
  On the other
  dblValue = dblLookUp (3, 1) ' * Math.Sign (dblValue)
  ' lblMode.Text = 5
  End If

  Return dblValue * intSign

  Hello janijt,

  You can certainly use formula node for it. What you would do is to create a constant for the lookup table.

  Here is an implementation in MathScript node

  

• Best way to parse a string for use in a lookup table?

  I am trying to create a system by which users can create a premade simulation and store simulations in order to easily load at their convenience. The way it works now is that when the user creates a simulation, information on the characteristics of the simulation are condensed down to a 12 string, which is written in a text file with the same name as its content. This string is then read, and ideally, I would have some sort of lookup table to convert characters in the information they have been condensed to. For example, a variable X can have possible values {650,720,851} who gets the mapping to {A, B, C} during the creation process. When loading, I would be able to send in a Sub C - VI and took her out in 851, group in a cluster. How can I perfectly realize this in LV? So far the best I have is this messy thing:

  

  Basically, who runs the string character by character and includes the appropriate value for the character at the given offset.

  You want to use the configuration VI palette.

  These screws makes it stupid simple save and load the values in the file by using Sections and keys.

  You can use the keys 'A', 'B' or 'C' and section 'X' to complete your example.

• Where we use lookup table?

  Hello

  Where we use lookup table?

  Thank you

  POOJA

  Hi Pooja,

  Look up table stores data. Look up table data is automatically updated with other data.

  It is used in the "update rule". Look up table has two columns, one for the original values for the changed values.

  Here is a link where you can get more help on implementing of lookup table:

  "If this, then that"-a Guide to create Lookup Tables in Eloqua

  The link "update rule:

  How to run an update rule set with a Table of choice on a shared list

  I hope this helps.

  Kind regards

  Eloqua Experts Edynamic

• Field in a lookup table values

  Hello

  A lookup table must contain all the values in a field, or can he communicate with a small selection you want to normalize.

  I want to test a small set of data before starting a washing machine coordinate complete, mainly to prove the simplicity for power.

  Thank you

  Hi James,

  You can include values as little or as much as you want in the Lookup Table. You have the complete control on which you will find the values and what the replacement values will be.

  Brad

• Date of max from the entire lookup table

  Hello people:

  I hope that this discussion finds you well.  I have 2 tables (MED_IMMUNO and LU_MED_IMMUNO).  "MED_IIMMUNO" is the base table, and "LU_MED_IMMUNO" is the lookup table for the column 'IMM_REC '.  Please see CFDS below:

  TABLE: MED_IMMUNO

  CREATE TABLE 'MED_IMMUNO' ('ID', 'EMP_ID' NUMBER, NUMBER OF "IMM_REC", "IMM_DATE" DATE, VARCHAR2 (255) 'IMM_NOTES', 'IMM_APPLICABLE' NUMBER, NUMBER OF "IMM_REFUSED")

  /

  INSERTION of REM in MED_IMMUNO

  TOGETHER TO DEFINE

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (55,8474,5,to_date('12-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (56,8474,6,to_date('26-JUN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (57,8474,8,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (58,8474,9,to_date('13-FEB-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (59,8474,10,to_date('26-JUN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (60,8474,22,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (61,8474,4,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (62,8474,16,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (63,8474,17,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (64,8474,11,to_date('10-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (65,5900,1,to_date('19-JUN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (66,5900,2,to_date('17-JUL-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (67,5900,3,to_date('20-DEC-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (68,5900,22,to_date('19-JAN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (69,5900,4,to_date('19-JAN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (70,5900,14,to_date('19-JAN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (71,5900,17,to_date('19-JAN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (72,5900,16,to_date('19-JAN-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (73,10069,5,to_date('16-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (74,10069,6,to_date('24-FEB-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (75,10069,8,to_date('16-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (76,10069,9,to_date('24-FEB-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (77,10069,22,to_date('05-DEC-11','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (78,10069,4,to_date('02-JAN-12','DD-MON-RR'),null,null,null);

  Insert into MED_IMMUNO (ID, EMP_ID, IMM_REC, IMM_DATE, IMM_NOTES, IMM_APPLICABLE, IMM_REFUSED) values (79,10069,16, null, null, null, null);

  Try this:

  WITH max_date AS

  (

  SELECT emp_id, imm_rec, max (imm_date) imm_date

  OF MED_IMMUNO M

  GROUP BY emp_id, imm_rec

  )

  DIS_MED_IMMUNO AS

  (

  SELECT DISTINCT M.emp_id

  OF MED_IMMUNO M

  )

  tmp AS

  (

  SELECT *.

  OF DIS_MED_IMMUNO

  CROSS JOIN LU_MED_IMMUNO

  )

  Tmp.emp_id SELECT emp_id, tmp.ID, tmp. IMM_DESC, M.imm_date

  OF tmp LEFT OUTER JOIN max_date M

  ON tmp.emp_id = M.emp_id

  AND tmp.ID = M.IMM_REC

  ORDER BY tmp.emp_id, tmp.ord

• Tree of the University campus solutions 9.0 organization and Lookup Table question

  People,

  Hello. I'm creating 9.0 Solution Campus of a college. I confront the issue as below:

  Implement AWAR > Foundation Table > academic Structure > academic organization

  I implemented the academic organization of these data Table: in addition to academic departments, I also type in academic institutions and academic groups.

  Then I create academic organization tree using the tree Manager. The tree is verified and valid a date of entry into force.

  Then I put in place the 2 tables below:

  Implemented AWAR > Foundation Table > academic Structure > program academic table

  Implemented AWAR > Foundation Table > academic Structure > Table of different disciplines

  Table of research of the academic organization developed in the 2 above table successfully. But when I put in place the other 2 tables below, search for academic organisation table does:

  Implement > AWAR > Security > secure Administration of the student > user ID > Security academic organization

  Curriculum management > Catalogue > Catalogue courses > tab offer

  I understand that the 2 tables above are based on the tree of academic organizations and not on the academic organization Table. I see no error in the tree.

  Because the search for academic organisation table can't happen in the tab 'Offers' course catalogue, the course cannot be saved.

  My question is:

  Any folk can help resolve the issue of the "academic organization lookup table cannot mount security academic organization and in the tab catalog of courses'? Or any suggestion on the tree of the academic organizations?

  Thanks in advance.

  Perform the following procedure:

  Home > ACSS configuration > Security > secure Administration student > process > security update - Acad Orgs

  After the execution of the process, check the lookup tables.

• Lookup tables

  I'm new to BC.  I use the CRM Web Service API.  The OrderList_Retrieve method returns data contains it statusTypeID and orderType.  Y at - it any documentation that contains the possible values for these fields or all the other lookup tables that uses BC?

  My eyes meet right now with all the documentation I read so I hope that's not look me in the face.  Any help finding this information is greatly appreciated.

  I found this thread.  It seems the status and StatusTypeID list is different for each site.  I have to write a quick and dirty program see the codes associated with the status text.

  What are the values and the meaning of PaymentStatusID and statusTypeId of the API

• level of access to the lookup table

  I use Dreamweaver CS4. It seems that access levels can if apply (at least through server behaviors) to a field in the same table that host users and their associated passwords. I adopted a database that contains a table that contains the users and their passwords and access levels are stored in a lookup table. Outside hand coding this or the change in the structure of the table to include levels of access, users and passwords in the same table, can anyone provide an overview on how to handle this?

  > I do not understand the recordset has to do with the newspaper to the user.

  Yes, I have just answered the same time-I got deceived to have first to create the Recordset. Your version of MySQL does support the views?

• Changing aid necessary table problem

  Hello. I hope someone can help me with this problem.
  
  I have two tables, an and mv. Create the following script:
  
  create table (mv)
  the moduleId Char (2) CONSTRAINT ck_moduleId CHECK (moduleId in ("M1", "M2", "M3", "M4', 'M5', 'M6', 'M7', 'M8'")).
  credit ck_credits Number (2) CONSTRAINT CHECK (credits (10, 20, 40));
  constraint pk_mv primary key (moduleId)
  );
  
  create table (its)
  stuId Char (2) CONSTRAINT ck_stuId CHECK (stuId ('S1', 'S2', 'S3', 'S4', 'S5')),
  moduleId tank (2),
  primary key constraint (stuId, moduleId) pk_sa,
  constraint fk_moduleid foreign key (moduleId) references (moduleId) mv
  );
  
  And the scripts below is to insert data into the two:
  
  insert into VALUES mv ("M1", 20)
  /
  insert into VALUES mv ("M2", 20)
  /
  insert into VALUES mv ("M3", 20)
  /
  insert into VALUES mv ("M4", 20)
  /
  Insert in mv VALUES ('M5', 40)
  /
  insert into VALUES mv ("M6", 10)
  /
  insert into VALUES mv ("M7", 10)
  /
  Insert in mv VALUES ('M8', 20)
  /
  
  
  insert into a VALUES ('S1', 'M1')
  /
  insert into a VALUES ('S1', 'M2')
  /
  insert into a VALUES ('S1', 'M3')
  /
  insert into a VALUES ('S2', 'M2')
  /
  insert into a VALUES ('S2', 'M4')
  /
  insert into a VALUES ('S2', 'M5')
  /
  insert into a VALUES ('S3', 'M1')
  /
  insert into a VALUES ('S3', 'M6')
  /
  
  Now for the real problems.
  
  First of all, I need to try to overcome the problem of table mutation ensure that stuid = S1 in table its can not take the two moduleId M5 and M6.
  
  Just one or the other. I created a single trigger, but runs aground because of the changing table problem.
  
  The second problem that I need to overcome is that none of the stuids can have the ModuleID where total value of more than 120 credit credits. Credit value is stored in the table of mv.
  
  Thank you very much in advance for any help.

  Use a statement-level trigger:

  First of all, I need to try to overcome the problem of table mutation ensure that stuid = S1 in table its can not take the two moduleId M5 and M6.

  SQL> create or replace trigger sa_trg
    2  after insert or update on sa
    3  declare
    4  c number;
    5  begin
    6    select count(distinct moduleId) into c
    7    from sa
    8    where stuid = 'S1'
    9    and moduleId in ('M5','M6');
   10    if c > 1 then
   11       raise_application_error(-20001,'S1 on both M5 and M6!!');
   12    end if;
   13  end;
   14  /
  
  Trigger created.
  
  SQL> select * from sa;
  
  ST MO
  -- --
  S1 M1
  S1 M2
  S1 M3
  S2 M2
  S2 M4
  S2 M5
  S3 M1
  S3 M6
  
  8 rows selected.
  
  SQL> insert into sa values ('S1','M5');
  
  1 row created.
  
  SQL> insert into sa values ('S1','M6');
  insert into sa values ('S1','M6')
  *
  ERROR at line 1:
  ORA-20001: S1 on both M5 and M6!!
  ORA-06512: at "SCOTT.SA_TRG", line 9
  ORA-04088: error during execution of trigger 'SCOTT.SA_TRG'
  

  The second problem that I need to overcome is that none of the stuids can have the ModuleID where total value of more than 120 credit credits. Credit value is stored in the table of mv

  SQL> create or replace trigger sa_trg
    2  after insert or update on sa
    3  declare
    4  c number;
    5  begin
    6    select count(distinct moduleId) into c
    7    from sa
    8    where stuid = 'S1'
    9    and moduleId in ('M5','M6');
   10    if c > 1 then
   11       raise_application_error(-20001,'S1 on both M5 and M6!!');
   12    end if;
   13
   14    select count(*) into c from (
   15    select stuid
   16    from mv, sa
   17    where sa.moduleid=mv.moduleid
   18    group by stuid
   19    having sum(credits)>120);
   20
   21    if c > 0 then
   22       raise_application_error(-20002,'A student cannot have more than 120 credits!!');
   23    end if;
   24
   25  end;
   26  /
  
  Trigger created.
  
  SQL>   select stuid, sum(credits)
    2  from mv, sa
    3  where sa.moduleid=mv.moduleid
    4  group by stuid;
  
  ST SUM(CREDITS)
  -- ------------
  S3           30
  S2           80
  S1          100
  
  SQL> insert into sa
    2  values ('S1','M4');
  
  1 row created.
  
  SQL>   select stuid, sum(credits)
    2  from mv, sa
    3  where sa.moduleid=mv.moduleid
    4  group by stuid;
  
  ST SUM(CREDITS)
  -- ------------
  S3           30
  S2           80
  S1          120
  
  SQL> insert into sa
    2  values ('S1','M7');
  insert into sa
  *
  ERROR at line 1:
  ORA-20002: A student cannot have more than 120 credits!!
  ORA-06512: at "SCOTT.SA_TRG", line 20
  ORA-04088: error during execution of trigger 'SCOTT.SA_TRG'
  

  Max
  http://oracleitalia.WordPress.com

• Workshop SQL-&gt; Tables-&gt; create the Lookup Table

  It is perhaps a SQL issue rather than an issue of Apex, but...
  
  With my experience of amateur to create database tables, I usually start with a parent table and create children and link them.
  
  While playing with Apex, I have the ability to create a Lookup Table of in any table.
  
  And, what is created is a new table that is, indeed, a parent.
  So I have been working from the bottom to the top.
  
  I understand that correctly?
  
  Thank you-
  Marion

  Marion...

  Yes...

  Lookup tables store data from reference and a link to your main table with a standard primary/foreign key relationship.

  This feature is particularly useful if you are creating your tables of data in the worksheet and you want to standardize it.
  Gus...

• separate account using the lookup table

  How can I get a separate count of column values by using another table?
  
  Let's say I want to get a separate account of all 'company_name' files in the 'emp' table that corespond (soccer match) with table of 'research', 'State' category.
  
  What I want is to find charges for all businesses that have a value of 'california' in the 'Status' column of the 'search' Table. I want the output to look like:
  
  Sears 17
  Pennys 22
  Marshalls 6
  Macys 9
  
  I want the result to show me the company names dynamically as I don't know what they are, just that they are part of the group 'State' in the lookup Table object. Does make sense?
  
  M

  If you want a counter for each value of rfs_category, but instead of rfs_category you want to display, it's translated value lookup_value_desc.

  This should do it for you:

  select lookup_value_desc, the_count
    from lookup
    join (select rfs_category, count(*) the_count
            from RFS group by rfs_category)
      on rfs_category = lookup_type;
  

• manipulation of the table problem

  I'm using Labview 2009 and I have a problem with windows... I have to implement the following code in Labview (X and digital input boards):

  for (i = 0 to MAX (X)) {}

  If (X [i] > (X [i-1] + 1)) {}

  X.Add (X [i], X [i-1] + 1) / / add the value X [i-1] + 1 x [i] position of the X table

  Y [i] = 0

  }

  on the other

  Y [i] = Y [i]

  }

  If I try to add items in the original array Y with the function 'Replace subset of table', the output array is not changed by the VI. If I try to initialize and to build a new table, I get a matrix of zeros. Can someone help me?

  If you want to just add 0 to the index that does not exist in X [] then try this.