order for the calculation of the difference between the points of channel

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   11  /
  

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  Published by: XIC on 6 April 2013 20:25

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• The order of the points in a sort pathPoints array

  Well, why would I do that? Well, I have areaText the rectangles that have been created by various means, and index 0 is sometimes high on the left, other times the bottom right. I need to do a lot of resizing, alignment, spacing, sizing. To describe the movement of the top left point of each (or anywhere else), I'm trying to clean up the sequence of points in each table pathPoints objects in order to move the pathPoint [0] .anchor for each rectangle and make sure that the upper left corner moves, not another random corner.

  Then, test only one script, and I came up with the following (don't laugh about how I called the table), which works very well in extendScript:

  var testArray = new Array;

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  testArray.push ({xVal: 0, yVal:-2});

  testArray.push ({xVal: 5, yVal:-2});

  testArray.push ({xVal: 0, yVal:0});})

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  function secondarySort() {}

  reorganize the first pair of xVal-based points

  If (Number(testArray[0].xVal) > Number(testArray[1].xVal)) {}

  Sensors = testArray [1];

  testArray.splice (1,1);

  testArray.unshift (moveMe) ;}

  reorganize the second pair of points based on xVal

  If (Number(testArray[2].xVal) < Number(testArray[3].xVal)) {}

  Sensors = testArray [2];

  testArray.splice (2.1);

  testArray.push (moveMe) ;}    }
  

  function printArray() {}

  for (i = 0; i < testArray.length; i ++) {}

  var writeMe is testArray [i].xVal.toString () + ', ' + testArray [i].yVal.toString ();.

  $.writeln (writeMe);  }}

  
  

  primarySort();

  printArray();

  $.writeln ('... ») ;

  secondarySort();

  printArray();

  So then I tried to do the same thing for Illustrator:

  var ObjArr = app.activeDocument.textFrames;

  var objPoints = new Array;

  for (i = 0; i < objArray.length; i ++) {}

  var pathObj = .textPath ObjArr [i];

  objPoints = pathObj.pathPoints;

  XYpairSort() ;}

  function XYpairSort() {}

  writes the current sequence of anchor pathPoint y coordinate x in the console

  for (i = 0; i < objPoints.length; i ++) {}

  writeMe var = objPoints [i] .anchor [0] m:System.NET.SocketAddress.ToString () + ', ' + objPoints [i] .anchor [1] m:System.NET.SocketAddress.ToString () + "," + i;

  $.writeln (writeMe) ;}

  Sort the four points at the top and at the bottom of the pairs

  objPoints.sort (function (a, b) {return b.anchor [1]-a.anchor [1]});

  reorganize the first pair of xVal-based points

  If (Number(objPoints[0].anchor[0]) > Number(objPoints[1].anchor[0])) {}

  Sensors = objPoints [1];

  objPoints.splice (1,1);

  objPoints.unshift (moveMe) ;}

  reorganize the second pair of points based on xVal

  If (Number(objPoints[2].anchor[0]) < Number(objPoints[3].anchor[0])) {}

  Sensors = objPoints [2];

  objPoints.splice (2.1);

  objPoints.push (moveMe) ;}

  writing the new sequence of pathPoint anchor y coordinate x in the console

  for (i = 0; i < objPoints.length; i ++) {}

  writeMe var = objPoints [i] .anchor [0] m:System.NET.SocketAddress.ToString () + ', ' + objPoints [i] .anchor [1] m:System.NET.SocketAddress.ToString () + "," + i;

  $.writeln (writeMe) ;}

  }

  Who raises an error "objPoints.sort is not a function".

  Unlike the single version JS, my script HERE trying to sort all the points of all of the textAreas, which I will fix shortly so it sorts the 4 points for each object. The problem is that the script is not sorting points, but providing a helpful error instead.

  Any ideas? Research on the Internet for this error does not explain why it happens, just in other ways to do the kinds.

  Well, if you did this time to the discussion, the approach I took is completely unnecessary.

  You see, I knew .top, .the .width and .height rectangles properties, and if you changed the width of a textFrame, he would scale the text that it contains:

  var obj = app.activeDocument.textFrames [0] / / guess that's narrower than the 2 inches

  obj. Width = 144; will scale the width of the block and its content also.

  Thus, to avoid the problem of scaling that I had to make sure that the textPaths of what I had selected was the same index order for I can enter each item individually and always take the same point for each textFrame. I was changing the height and width of each textFrame by assigning new XY coordinates at each angle of the trajectory. Good to know how to do this, but not necessary, because the attributes .top, .the, .width and .height are available for the textPath object.

  What I do not know (and do now), is that you can change the path without scaling the content:

  var obj = app.activeDocument.textFrames [0] / / guess that's narrower than the 2 inches

  var objPath = obj.textPath;

  objPath.width = 144;  is not at the scale of the text inside the frame.

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  What do you think of this approach?

  

  We subtract just the mouse coordinates in the coordinated range 2D (Array stores the coordinates of the points on the image), the absolute value and look for the minimum. X and y the selected point index is returned in minutes or the index. You can replicate the fuction "in range" by ensuring min value is not too high.

  With regard to:

  Andrew Valko

  NOR Hungary