Partition on a column for the number interval

Similar Questions

• How to add a 0 in a column for the number

  Hai All
  
  I have my table, I had three columns
  
  Respondent, declared as date
  
  Outime date and Working_time are declared under the number
  
  
  So while subtracting respondent and outtime I got a result in three digits
  
  
  For example
  
  outtime is 1715 and intimate is 0815, then working_time is 0900 I need result like this, but I had 900
  
  
  Even if I added lpad inside... My update statement is
  
  
  Update dail_att set wtime = lpad ((to_number (to_char(outtime,'hh24mi')-to_char(intime,'hh24mi'))), 4, 0);
  
  Concerning
  
  srikkanth. M

  Or simply use

  SELECT TO_CHAR (  TO_DATE ('00:00:00', 'HH24:MI:SS')
                  + (TO_DATE (:outtime, 'hh24mi')
                  - TO_DATE (:intime, 'hh24mi')),
                  'HH24SS'
                 ) hm
    FROM DUAL;
  
  HM
  ------
  0900
  

  * 009 *.

• How to get the timestamp per minute for the given interval

  Hello

  I have a table with a date of beginning and end of time columns. I need to divide the date given in one minute interval and post the results.

  create table min_data(objectid varchar2(20),starttime timestamp,endtime timestamp,duration number);
  
  
  SET DEFINE OFF;
  Insert into MIN_DATA Values ('U1_B011_P006_InvA', TO_DATE('06/23/2015 02:42:00', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('06/23/2015 02:46:00', 'MM/DD/YYYY HH24:MI:SS'), 5);
  Insert into MIN_DATA Values ('U1_B011_P006_InvA', TO_DATE('06/23/2015 12:43:00', 'MM/DD/YYYY HH24:MI:SS'), TO_DATE('06/23/2015 12:44:00', 'MM/DD/YYYY HH24:MI:SS'), 2);
  COMMIT;
  
  
  
  
  

  My expected output should be something like this. INT_TIMESTAMP is the timestamp calculated for the given interval (time of start and end times)

  INT_TIMESTAMP	OBJECTID	STARTTIME	END TIME
  23/06/2015-02:42	U1_B011_P006_InvA	23/06/2015-02:42	23/06/2015-02:46
  23/06/2015-02:43	U1_B011_P006_InvA	23/06/2015-02:42	23/06/2015-02:46
  23/06/2015-02:44	U1_B011_P006_InvA	23/06/2015-02:42	23/06/2015-02:46
  23/06/2015-02:45	U1_B011_P006_InvA	23/06/2015-02:42	23/06/2015-02:46
  23/06/2015-02:46	U1_B011_P006_InvA	23/06/2015-02:42	23/06/2015-02:46
  23/06/2015 12:43	U1_B011_P006_InvA	23/06/2015 12:43	23/06/2015 12:44
  23/06/2015 12:44	U1_B011_P006_InvA	23/06/2015 12:43	23/06/2015 12:44

  I wrote a query that works for one set of intervals.

  With get_data AS(
  SELECT   a.*,
           starttime -1/1440 v_s_date,
           endtime v_e_date
  FROM min_data a
  where duration=5)
  SELECT v_s_date + ((1 / 1440) * DECODE(LEVEL, 1, 1, LEVEL)) int_timestamp, objectid,starttime,endtime
            FROM get_data d
           WHERE MOD(LEVEL, 1) = 0
              OR LEVEL = 1
          CONNECT BY LEVEL <= (v_e_date - v_s_date) * 1440;
  
  

  Please send me a SQL query that gives me the timestamps of minutes between intervals.

  Hello

  The following query works for any number of intervals

  SELECT STARTTIME + ((LVL-1) / 1440) INT_TIMESTAMP, OBJECTID, STARTTIME, ENDTIME

  Of

  (SELECT LEVEL LVL FROM DUAL CONNECT BY LEVEL< 10)="">

  (SELECT * FROM MIN_DATA)

  WHERE STARTTIME + ((LVL-1) / 1440) BETWEEN STARTTIME AND ENDTIME ORDER BY, STARTTIME, ENDTIME LVL;

  Concerning

  Salim

• Procedure for the number of working days per month when the user enters to and from everyday

  Hi all

  Can provide you a solution to this - procedure for the number of working days per month when the user enters and days.

  Suppose that the user enters November 18, 2014 start date and date as November 23, 2014.

  The output should display

  Count: 4

  November 18, 2014 Mar

  Sea 19 November 2014

  November 20, 2014 game

  Fri November 21, 2014

  It will exclude Saturday and Sunday.

  Hello

  Here is an example of removing dates Saturday and Sunday:

  with days as(
       select (trunc(sysdate, 'YEAR') + level) as col from dual
       connect by level < 365
  )
  select * from days
  where trim(to_char(col, 'DAY', 'NLS_DATE_LANGUAGE=ENGLISH')) not in ('SATURDAY', 'SUNDAY')
        and col between to_date('18.11.2014', 'DD.MM.YYYY') and to_date('30.11.2014', 'DD.MM.YYYY')
  order by col;
  

  Cheerz,

  Stako

• While trying to see Planner installation and operation, the test in local mode, the EXECUTION fails with message "Waiting for the number of virtual machines to register.

  While trying to see installation and operation Planner, the test in local mode with only 1 VM the EXECUTION fails with message "Waiting for the number of virtual machines to register.

  There may be a lot of problems in the desktop VM. Agent service see Planner is not running in VM Office. You can check in the event viewer to see what kind of error occurs. The most usual error missing file IP.txt c; drive or harness IP in the IP.txt produce if there is.

• Problems with sorting of columns and the number of lines in the report

  Hello
  
  I'm having a problem with sorting of columns and the number of lines displayed in a report.
  
  This report displays the data correct, but if I try to sort on a column when I click on the column heading in the report returns no line... I need to click on the "go" button to refresh the report (with the column sorted now) in to display the data.
  
  Similarly, I display only 15 lines per page. If I try to view the lines 16-30, 31-45, etc., that it returns no line until I click on the 'go' button to refresh again.
  
  Has anyone else had (and overcome) the same problem?
  
  Thank you
  
  Joseph

  Joseph,

  2 questions:

  1) are you using the elements referenced by the report page to filter etc.. ? If so, you're failing values of these when the loading of the page?
  (2) are you using PPR page through the results?

  If so, it could be a problem with the different types of session state, as Anton Nielsen blogged about here:
  http://c2anton.blogspot.com/2008/12/Oracle-Application-Express-Apex-three.html

  If so, you can use calculations or processes to set element values in session state persistent during page rendering, as Anton mentions. In this way, when you use PPR page values will be available in session state and your report should work fine.

  Anthony.

• Column with the number of Partition lines or program group?

  Hi all
  
  I wish I had a column in my query that indicates how many rows in each partition/group. I hope that my code is clear. Everyone would be Kow how do I do this? I'm pretty eager to avoid nesting if I can because it is already part of a larger and more complex query.
  
  Be grateful for any help, I'm a little confused!
  
  Thank you
  
  Jon
  
  Select
  d.deal_id,
  c.class_id,
  c.Seniority,
  ROW_NUMBER () OVER (PARTITION BY d.deal_id ORDER BY c.seniority ASC, ASC c.class_id) DealClassCount,.
  -I want the number of Classes per case here, max DealClassCount (the value is the same on all rows of the agreement).
  decode (ROW_NUMBER () OVER (PARTITION BY d.deal_id ORDER BY c.seniority ASC, asc c.class_id), 1,1,0) DealSum
  global_sf.deal d, global_sf.class c
  where d.deal_id = c.deal_id
  
  and d.deal_id in
  (
  '87354694'
  '87355187'
  )
  
  order of d.deal_id, c.class_id, c.seniority

  Hi, Jon,

  It would really help, whenever you have any questions, post a few examples of data (CREATE TABLE and INSERT statements) and the results desired from these data. This makes it much more clearly what you want to do.
  If you don't want to show all the data, use the tables commonly available (like those of the scott schema) of your DIF,.

  I think you want to use the COUNT function Analytics (without ORDER BY clause) instead of ROW_NUMBER.

  SELECT    deptno
  ,         ename
  ,         COUNT (*) OVER (PARTITION BY deptno)  AS dept_total
  FROM      scott.emp
  ORDER BY  deptno
  ;
  

  Output:

  `   DEPTNO ENAME      DEPT_TOTAL
  ---------- ---------- ----------
          10 CLARK               3
          10 KING                3
          10 MILLER              3
  
          20 JONES               5
          20 FORD                5
          20 ADAMS               5
          20 SMITH               5
          20 SCOTT               5
  
          30 WARD                6
          30 TURNER              6
          30 ALLEN               6
          30 JAMES               6
          30 BLAKE               6
          30 MARTIN              6
  

• change the column size for the number

  Hello

  I created a table with a primary key declared under the (default specification) NUMBER column.

  Create table T

  (

  Number of key primary col1,.

  col2 varchar2 (10)

  );

  Then, I filled this table using the sequence. Now, I want to change the size of the primary key to the number (15) column.

  Is this possible without emptying the primary key column?

  You can't reduce the length of a column that has already given. But you can work around it like that.

  SQL> create table t  2  (  3  col1 number primary key,  4  col2 varchar2(10)  5  );
  Table created.
  SQL> insert into t  2  select level, 'a'  3    from dual  4  connect by level <= 10;
  10 rows created.
  SQL> desc t Name          Null?    Type -------------- -------- ------------------------------ COL1          NOT NULL NUMBER COL2                    VARCHAR2(10)
  SQL> select * from t;
        COL1 COL2---------- ----------        1 a        2 a        3 a        4 a        5 a        6 a        7 a        8 a        9 a        10 a
  10 rows selected.
  SQL> alter table t modify col1 number(15);alter table t modify col1 number(15)                    *ERROR at line 1:ORA-01440: column to be modified must be empty to decrease precision or scale
  
  SQL> alter table t add col_temp number(15);
  Table altered.
  SQL> update t set col_temp = col1;
  10 rows updated.
  SQL> commit;
  Commit complete.
  SQL> alter table t drop column col1;
  Table altered.
  SQL> alter table t rename column col_temp to col1;
  Table altered.
  SQL> alter table t add constraint t_pk primary key (col1);
  Table altered.
  SQL> desc t Name            Null?    Type --------------- -------- ------------------------------ COL2                    VARCHAR2(10) COL1            NOT NULL NUMBER(15)
  SQL> select * from t;
  COL2            COL1---------- ----------a                  1a                  2a                  3a                  4a                  5a                  6a                  7a                  8a                  9a                  10
  10 rows selected.
  SQL>
  

• Largest number of digits for the NUMBER data type?

  What length more of a NUMBER that Oracle will "support"?

  The documentation says the following:

  Limitations of the data type says:

  «Can be represented in a comprehensive precision 38 digits»

  NUMBER of Data Types says:

  "Oracle guarantees portability of numbers with precision of up to 20 digits of base-100, which equals 39 or 40 decimal digits according to the position of the decimal point."

  I realize account that if I define a column as simply NUMBER, I can insert numbers with a size up to 126 characters.  However, Oracle seems to maintain only the first 40 digits in MOST cases.  The largest number of digits, it seems to allow is 40 before it begins to be replaced by 0.

  With numbers that have more than 40 figures, Oracle will sometimes replace all numbers according to the 38th numbers with a 0 and sometimes replace 0 after the digit 39th or 40th.

  Therefore, what is the largest number of digits, can be trusted to safely store Oracle?

  This is the code I used for this testing process.

  create the table max_num (num number);

  declare

  number of l_x;

  Start

  for x in 1.200

  loop

  l_x: = x;

  insert into max_num values (rpad (1, x, 1));

  end loop;

  exception

  while others then

  dbms_output.put_line ('STOP: ' | l_x);

  dbms_output.put_line (SQLERRM);

  end;

  /

  Select num, length (replace (num, 0)) of max_num;

  What length more of a NUMBER that Oracle will "support"?

  You have already given your own answer. If 'length': the maximum number of digits is written the doc gives you the answer:

  999... (38 9's) x 10 value maximum¹²⁵

  The 38/39/40, hereinafter referred to as the doc means "significant digits". This is why rounding or truncation occurs if you provide more significant digits of 38/39/40.

  Oracle stores the numbers internally in a binary format 21 bytes using a documented structure in the doc of the OIC in the section 'NUMBER'.

  http://docs.Oracle.com/CD/E11882_01/AppDev.112/e10646/oci03typ.htm#i423684

  Oracle database stores the values of the NUMBER data type in a variable length format. The first byte is the exponent and is followed by 1 to 20 mantissa bytes. The high bit of the exponent byte is the sign bit; It is defined for positive numbers, and it is cleared for negative numbers. The lower 7 bits represent the exponent, which is a number of base-100 with an offset of 65.

  This article from doc continues to show you how to convert the internal format to the real value.

  An additional byte of 1 is used for all types of data to store the length; That's why you often see docs saying numbers can take 22 bytes.

• Impossible to delete the partitions of a table with the number of rows is zero

  Hi all
  
  I want to delete all partitions on all the tables in a schema having the number of lines equal to zero.
  
  I use the queries below to get a solution.
  
  Select 'EDIT '. '' || 'TABLE ' | TABLE_NAME | 'DROP '. 'PARTITION | Nom_partition from dba_tab_partitions where TABLE_OWNER = "xyz";
  
  Select count (*) in the table table_name partition (nom_partition).
  
  Edited by: 887563 October 17, 2011 13:39

  If you trust your statistics, you can simply use the stat num_rows in dba_tab_partitions:

  select *
  from dba_tab_partitions
  where table_owner = 'MY_SCHEMA'
  and num_rows = 0;
  

  But I think what you try to get some code like this:

  declare
    v_rows number;
    v_statement varchar2(500);
  begin
    for c in (select *
              from dba_tab_partitions
              where table_owner = 'MY_SCHEMA') loop
      v_statement := 'select count(*) from '||c.table_name||
                     ' partition ('||c.partition_name||') where rownum=1';
      --dbms_output.put_line(v_statement);  --for debugging
      execute immediate(v_statement)
      into v_rows;
      --dbms_output.put_line(c.table_name||' '||c.partition_name||' '||v_rows);  --for debugging
      if v_rows = 0 then
        v_statement := 'ALTER TABLE '||c.TABLE_NAME||' DROP PARTITION ' || c.PARTITION_NAME;
        dbms_output.put_line(v_statement); --shows the drop statements
        --execute immediate(v_statement); --remove comment to execute
      end if;
    end loop;
  end;
  

• Use the 2nd column for the label data

  This should be easy. Online help for the numbers shows an example under Add graphics > adjust figure brands and labels.  My table is a simple 2-d column chart. In a single column, I have the weight in pounds, and in the second column, I have a date. When I have only the weight column selected in the form of data, I get a graph that is almost perfect, but there is no date label. When I try to include date data, I have a reverse relationship X and Y. Once I selected a cell as reference data, it doesn't have any way to deselect. What I want to do is chart weight against date and have the date appear as a label.

  Any advice is welcome.

  Hi innerserenity,

  I swapped the order of the columns. Column A is a column header.

  

  Kind regards

  Ian.

• Satellite C55 - A - 1 K 6 - Partition which is Important for the recovery of Toshiba?

  My laptop is Satellite C55 - A - 1 K 6

  In the past, I have deleted Toshiba System Recovery Partition by mistake when I install the new OS for my laptop so I sent my laptop to Toshiba Service and they recreate standard scores and send back me my laptop.

  I need to ask this question to you now;

  When I opened the disk management in the computer management, I see two partition named Recovery. One of them is the beginning of the disc and it is 1 GB, another 11FR and at the and of the disc. What is the Toshiba system recovery?

  On the other hand I just created 3 * 4, 5 GB Toshiba System Recovery DVD by Toshiba Recovery Media Creator. Instead of I have those DVD am I still need the recovery Partition for recovery of my laptop in the future?

  Now, if I delete all the partitions on the hard drive now, can I still use Toshiba Recovery with these 3 * 4, 5 GB DVD?

  Thank you...

  Original recovery image contains the operating system, all necessary drivers, tools specific to Toshiba and utility and sure some additional software so it may not be only 1 GB. 11 GB partition is for the recovery image.

  > On the other hand I just created 3 * 4, 5 GB Toshiba System Recovery DVD by Toshiba > Recovery Media Creator. Instead of I have those DVD am I still need the recovery recovery Partition > my cell phone in the future?
  In general you don't need it more. With the help of your created recovery DVD you will be able to install the original recovery image whenever you want. In case that the HARD drive will be effective and exchanged with a new one, you can use these discs to install the original recovery image.

  Many people do not read manuals s and does not create a recovery media. After a few experiences, they are surprised why HARD recovery disk image installation doesn't work anymore.

  I hope that some other Toshiba laptop owners will read this so here are original recovery Toshiba recall info:

  + Important INFORMATION +.

  + your system is equipped with a hard drive recovery system. If you need repair your computer in the restaurant to original factory State, you can do so directly from the hard disk (press F8 when you start your computer, choose "Repair your computer" and follow the instructions in the menu) or create a media drive bootable recovery to that end. +.

  + Toshiba recommends you create recovery disk medium using the "Toshiba Recovery Disc Creator' to ensure that you are able to restore your computer to the original state factory-installed, +.
  + even if your computer is seriously damaged. +

• Satellite C55A - 1 K 6 - partition which is necessary for the Toshiba system recovery?

  I have a laptop that Toshiba Satellite C55A - 1 K 6.

  In the past, I deleted the Partition Recovery Toshiba by mistake and now I want to ask the cause of the thing of this...

  When I go to disk management in Windows 8 (which preinstalled by Toshiba on my laptop) I see four partitions...

  The first partition is close to 1 GB and I think his need for Windows 8, then I see C and D for my Windows 8 and at the end there is a 11 GB partition and it is hidden and it does not appear in my computer in Windows...

  I just created 3 * 4.5 GB defined via Rescue Media Creator Toshiba Recovery DVD and now if I delete all the partitions on the hard drive, can I use these DVD media to restore my laptop to its original state, when I bought it or that I still need the recovery Partition on the HARD drive instead of using recovery DVd media?

  If I delete all the partitions on the hard drive now, are these DVD media are enough to return to the first State independent or not?

  Sorry for my bad English and I hope to describe things in my head... :)

  Sincerely...

  > in the past, I have deleted the error Toshiba Recovery Partition
  It was really bad move since the recovery partition is necessary in order to create the recovery disk or recover the laptop with HARD drive recovery option.

  > The first partition is close to 1 GB and I think that his need of Windows 8.
  That s right.

  > then I see C and D for my Windows 8
  That s right

  > and at the end there is a 11 GB partition and it is hidden and it does not appear in my computer in Windows.
  It looks like the recovery partition. But I put t understand why you said earlier that you deleted the Toshiba recovery partition. Could you please clarify this statement?

  > I just created 3 * 4.5 GB defined via Rescue Media Creator Toshiba Recovery DVD and now if I delete all the partitions on the hard drive, can I use these DVD media to restore my laptop to its first State

  The recovery DVD set would be to format the HARD drive and would recreate once more all partitions.
  The answer is: Yes, it will restore the laptop to the State as on the first day of purchase.

  By the way: I found another thread that you created on the same theme:
  http://forums.computers.Toshiba-Europe.com/forums/thread.jspa?threadID=76203
  Please follow a thread to avoid misunderstandings.

• Installed Windows on the bad disk partition (C :) and meant for the recovery disc (e :)))

  Hello world

  My question is that I installed windows vista on the wrong partition. When I tried to do a re-install for partition recovery (e), I saw that the drive (C :) local was still installed with my last error when I first installed it on drive C: (OS) that is full. I didn't want to do, that I was going for the recovery disk (E :).

  If I re - install windows on the recovery disk now, he will have to complete partitions. I'm just completely start over as if I first had an empty space to install an OS right the first time around when choosing the right partition.

  It is on a latitude D630, where the BONE was full and the Data 2 which is the recovery disk (e) has free space that should have (c).

  Any help is grateful, thank you.

  Make sure that the important data that you have on the drive is backed up.

  Boot from the Windows DVD

  To learn how to change your BIOS options to boot from the DVD drive, the following tutorial:

  http://notebooks.com/2011/05/05/How-to-load-BIOS-and-change-boot-configuration/

  Click Install now

  Accept the license agreement

  When the option is displayed to select a type of installation, click (Custom advanced)

  Click on drive Options

  Select the disc/s click on Delete

  Click new

  Click on apply

  Click OK

  Click Format, and then click next to proceed with the installation

• How Oracle 'row_limiting_clause' for the number of lines. percent for HUNDRED lines works in Oracle 12 c?

  Platform: Windows 7 x 64 database: Oracle Database Enterprise Edition Release 12.1.0.2.0 12 c - 64 bit.

  How row_limiting_clause Oracle to rowcount. percent for HUNDRED lines works in Oracle 12 c?

  Row_limiting_clause Oracle is acting funny. In the code below, the 'fetch_test' table has 10 rows

  Case 1 When using row_limiting_clause with first extract 0.5 lines only I get, no line selected

  Case 2 When use the row_limiting_clause with the first rows only 5 percent clause I get,1 row as output.

  This means case 1! = 2 cases [0.5! = 0.5 (5 percent of 10 lines)]

  SQL > select * from fetch_test;

  COL1 COL2

  ---- ----

  1A

  2B

  3 C

  4 D

  5 E

  6 F

  8: 00

  5%

  : j

  10 J

  10 selected lines.

  case 1:

  SQL > select col1 from fetch_test

  2 first extract 0.5 lines only;

  no selected line

  case 2:

  SQL > select col1 from fetch_test

  2 extract the first rows of 5 percent;

  COL1

  ----

  1

  1 selected line

  What Oracle Documentation has to say,

  https://docs.Oracle.com/database/121/SQLRF/statements_10002.htm

  If the number of lines has a fraction, then the fractional part is truncated. If the number of rows is NULL, 0 rows are then returned.

  This explains the case 1, but I can't find any possible explanation in case 2 in my example above. and there is no mention on percentage clause in the Oracle Documentation.

  Already asked on stack - overflow.but I got the answer regarding "assumes percent Gets the cycle of 5% to 10%.

  No idea why Oracle doing what they do on the documentation!  I hope that now you have the answer: a rest (when you use percent in the line limiter) will ALWAYS return a number integer, rounded upward.