Password encrypted ticket to principal-protected or is security authorization simply in function?

Result, the safety of this new feature of file system permissions, or are password encrypted notes?

I think that it has encrypted - Security iCloud and overview of privacy - Apple Support

Similar Questions

problem during decryption of password encrypted

Hello to all that I am saving the password encrypted in the database. And decrypting the password attached to the url. But while I'm decrypting it gives me the Exception BadPadding exception. I used this class to encrypt and decrypt the password.

public class CryptAes {

    // First create the AES key based on the bytes in secretKey using  keyLength bits as the length
    static AESKey keydec = new AESKey("A3$1E*81234567891111111111111111".getBytes() );
    static AESKey keyenc = new AESKey("A3$1E*81234567891111111111111111".getBytes() );
    static AESKey keyenc128 = new AESKey("A3Q1EF8123456789".getBytes());
    static AESKey keydec128 = new AESKey("A3Q1EF8123456789".getBytes());

    private static byte[] iv = { 0x0a, 0x01, 0x02, 0x03, 0x04, 0x0b, 0x0c,
        0x0d, 0x0a, 0x01, 0x02, 0x03, 0x04, 0x0b, 0x0c, 0x0d };

    public static byte[] plainText= new byte[10000];

 public static String AESEncryption(byte[] plainText) {

        String resultString = null;

        try {

             AESEncryptorEngine engine = new AESEncryptorEngine( keyenc128 );

             CBCEncryptorEngine cengine=new CBCEncryptorEngine(engine, new InitializationVector(iv));
                PKCS5FormatterEngine fengine = new PKCS5FormatterEngine( engine );
                ByteArrayOutputStream output = new ByteArrayOutputStream();
                BlockEncryptor encryptor = new BlockEncryptor( fengine, output );

                encryptor.write(plainText);
                encryptor.close();
                byte[] encryptedData = output.toByteArray(); output.close();
                String st=new String(encryptedData);

                byte[] base64 = Base64OutputStream.encode(encryptedData, 0, encryptedData.length, false, false);

                      //Base64Coder.encodeString(Byte.toString(plainText));
                      resultString = new String(base64);

        } catch (CryptoException cryptoException) {
            // TODO: handle exception
            System.out.println("Exception is "+cryptoException.getMessage()+"And the exception is"+cryptoException.toString());
        }
        catch (CryptoTokenException e) {
            // TODO: handle exception
            System.out.println("Exception is "+e.getMessage()+"And the exception is"+e.toString());
        }catch (CryptoUnsupportedOperationException e) {
            // TODO: handle exception
            System.out.println("Exception is "+e.getMessage()+"And the exception is"+e.toString());
        }catch (IOException e) {
            // TODO: handle exception
            System.out.println("Exception is "+e.getMessage()+"And the exception is"+e.toString());
        }
        return resultString;
  }

    public static String AESDecryption(byte[] cipherText, int dataLength ) /*throws CryptoException, IOException, CryptoTokenException, CryptoUnsupportedOperationException*/ {      

        String reString = null;
        try {

            ByteArrayInputStream in = new ByteArrayInputStream( cipherText, 0, dataLength );

            // Now create the block decryptor and pass in a new instance
            // of an AES decryptor engine with the specified block length
            BlockDecryptor cryptoStream = new BlockDecryptor(new AESDecryptorEngine( keydec128 ), in );
            byte[] T = new byte[dataLength];

            // Read the decrypted text from the AES decryptor stream and
            // return the actual length read        

            int length = cryptoStream.read( T ); //Here i am getting exception BadPadding
            reString = new String(T);
            int i=reString.indexOf("");
            reString = reString.substring(0,i+6);      

        } catch (CryptoException e) {
            // TODO: handle exception
            System.out.println("Exception is ="+e.getMessage());
        }catch (CryptoTokenException e) {
            // TODO: handle exception
            System.out.println("Exception is ="+e.getMessage());
        }catch (CryptoUnsupportedOperationException e) {
            // TODO: handle exception
            System.out.println("Exception is ="+e.getMessage());
        }catch (IOException e) {
            // TODO: handle exception
            System.out.println("Exception is ="+e.getMessage()+"333333333333"+e.toString());
        }
        // Create the input stream based on the ciphertext        

        return reString;

    }

Help me with this.

I was trying to encrypt and decipher passing on it but only has failed, so I just change how to encrypt or to decrypt the password. I had just use Base64Coder class to achieve this. And thank you for your concern. And here is the Base64Coder class, if someone needs it.

//Copyright 2003-2009 Christian d'Heureuse, Inventec Informatik AG, Zurich, Switzerland
//www.source-code.biz, www.inventec.ch/chdh
//
//This module is multi-licensed and may be used under the terms
//of any of the following licenses:
//
//EPL, Eclipse Public License, http://www.eclipse.org/legal
//LGPL, GNU Lesser General Public License, http://www.gnu.org/licenses/lgpl.html
//AL, Apache License, http://www.apache.org/licenses
//BSD, BSD License, http://www.opensource.org/licenses/bsd-license.php
//
//Please contact the author if you need another license.
//This module is provided "as is", without warranties of any kind.

/**
* A Base64
* r/Decoder.
*
* 
* This class is used to encode and decode data in Base64 format as described in RFC 1521.
*
* 

* Home page: http://www.source-code.biz">www.source-code.biz

* Author: Christian d'Heureuse, Inventec Informatik AG, Zurich, Switzerland

* Multi-licensed: EPL/LGPL/AL/BSD.
*
* 

* Version history:

* 2003-07-22 Christian d'Heureuse (chdh): Module created.

* 2005-08-11 chdh: Lincense changed from GPL to LGPL.

* 2006-11-21 chdh:

*    Method encode(String) renamed to encodeString(String).

*    Method decode(String) renamed to decodeString(String).

*    New method encode(byte[],int) added.

*    New method decode(String) added.

* 2009-07-16: Additional licenses (EPL/AL) added.

* 2009-09-16: Additional license (BSD) added.

*/

public class Base64Coder {

    //Mapping table from 6-bit nibbles to Base64 characters.

    private static char[]    map1 = new char[64];

    static {

        int i=0;
        for (char c='A'; c<='Z'; c++) map1[i++] = c;
        for (char c='a'; c<='z'; c++) map1[i++] = c;
        for (char c='0'; c<='9'; c++) map1[i++] = c;
        map1[i++] = '+'; map1[i++] = '/';
    }
    //Mapping table from Base64 characters to 6-bit nibbles.

    private static byte[]    map2 = new byte[128];

    static {
        for (int i=0; iin.
     * @return     A character array with the Base64 encoded data.
     */

    public static char[] encode (byte[] in, int iLen) {

        int oDataLen = (iLen*4+2)/3;       // output length without padding
        int oLen = ((iLen+2)/3)*4;         // output length including padding
        char[] out = new char[oLen];
        int ip = 0;
        int op = 0;

        while (ip < iLen) {
            int i0 = in[ip++] & 0xff;
            int i1 = ip < iLen ? in[ip++] & 0xff : 0;
            int i2 = ip < iLen ? in[ip++] & 0xff : 0;
            int o0 = i0 >>> 2;
            int o1 = ((i0 &   3) << 4) | (i1 >>> 4);
            int o2 = ((i1 & 0xf) << 2) | (i2 >>> 6);
            int o3 = i2 & 0x3F;

            out[op++] = map1[o0];
            out[op++] = map1[o1];
            out[op] = op < oDataLen ? map1[o2] : '='; op++;
            out[op] = op < oDataLen ? map1[o3] : '='; op++;
        }

        return out;
    }

    /**
     * Decodes a string from Base64 format.
     * @param s  a Base64 String to be decoded.
     * @return   A String containing the decoded data.
     * @throws   IllegalArgumentException if the input is not valid Base64 encoded data.
     */

    public static String decodeString (String s) {
        return new String(decode(s));
    }

    /**
     * Decodes a byte array from Base64 format.
     * @param a Base64 String to be decoded.
     * @return   An array containing the decoded data bytes.
     * @throws   IllegalArgumentException if the input is not valid Base64 encoded data.
     */

    public static byte[] decode (String s) {
        return decode(s.toCharArray());
    }

    /**
     * Decodes a byte array from Base64 format.
     * No blanks or line breaks are allowed within the Base64 encoded data.
     * @param in  a character array containing the Base64 encoded data.
     * @return    An array containing the decoded data bytes.
     * @throws    IllegalArgumentException if the input is not valid Base64 encoded data.
     */

    public static byte[] decode (char[] in) {

        int iLen = in.length;

        if (iLen%4 != 0) throw new IllegalArgumentException ("Length of Base64 encoded input string is not a multiple of 4.");

        while (iLen > 0 && in[iLen-1] == '=') iLen--;

        int oLen = (iLen*3) / 4;

        byte[] out = new byte[oLen];

        int ip = 0;

        int op = 0;

        while (ip < iLen) {

            int i0 = in[ip++];

            int i1 = in[ip++];

            int i2 = ip < iLen ? in[ip++] : 'A';

            int i3 = ip < iLen ? in[ip++] : 'A';

            if (i0 > 127 || i1 > 127 || i2 > 127 || i3 > 127)

                throw new IllegalArgumentException ("Illegal character in Base64 encoded data.");

            int b0 = map2[i0];

            int b1 = map2[i1];

            int b2 = map2[i2];

            int b3 = map2[i3];

            if (b0 < 0 || b1 < 0 || b2 < 0 || b3 < 0)

                throw new IllegalArgumentException ("Illegal character in Base64 encoded data.");

            int o0 = ( b0       <<2) | (b1>>>4);

            int o1 = ((b1 & 0xf)<<4) | (b2>>>2);

            int o2 = ((b2 &   3)<<6) |  b3;

            out[op++] = (byte)o0;

            if (op

Hidekeys with password encryption Service

Hello

I'm reviewing my companies switch check-in facility and I noticed was the lack of the "hidekeys" command in the configuration of archive. I wonder if this is really necessary when the service password encryption is enabled as surely all passwords would be encrypted anyway?

Thank you!

"the password encryption service" is a very weak security measure because it is reversible. The algorithm is documented and anyone sniffing the transfer can restore passwords. Thereby, these passwords must be viewed in plain text. Now you have to decide if this is a problem for your environment.

Best practice is to move the hashed passwords, where possible. For the fair user accounts move to the 'secret' of the configuration form. But for all types of routing-protocol-passwords which is not possible.

password encryption when the value is not in TB

In the settings of POP3 e-mail, transmit precarious pw works together and pop3. I get smtp on the sending of error message indicating a password encrypted tent to serve and is rejected by the smtp server. I don't see a separate setting for the security of password in the smtp settings.

Go down to the very last account in the list, "outgoing (SMTP) server. You'll find all of your smtp settings there.

How to compare the current password encrypted pasword enter APEX4.1

Hi all
In my application uses the following package

create or replace PACKAGE BODY app_security_pkg
AS
PROCEDURE login 
          (
           p_uname IN VARCHAR2
          ,p_password IN VARCHAR2
          ,p_session_id IN VARCHAR2
          ,p_flow_page IN VARCHAR2
          )
IS
 lv_goto_page NUMBER DEFAULT 1;
BEGIN
 
 -- This logic is a demonstration of how to redirect 
 -- to different pages depending on who successfully 
 -- authenticates. In my example, it simply demonstrates 
 -- the ADMIN user going to page 1 and all other users going
 -- to page 2. Add you own logic here to detrmin which page 
 -- a user should be directed to post authentication.
 IF UPPER(p_uname) = 'ADMIN'
 THEN
  lv_goto_page := 1;
 ELSE
  lv_goto_page := 2;
 END IF;

APEX_UTIL.SET_SESSION_STATE('FSP_AFTER_LOGIN_URL');

 wwv_flow_custom_auth_std.login 
 (
  p_uname => p_uname,
  p_password => p_password,
  p_session_id => p_session_id,
  p_flow_page => p_flow_page || ':' || lv_goto_page
  );

EXCEPTION
WHEN OTHERS
THEN 
 RAISE;
END login;

PROCEDURE add_user 
(
 p_username IN VARCHAR2
,p_password IN VARCHAR2
)
AS
BEGIN
INSERT INTO app_users (username, PASSWORD)
    VALUES (UPPER (p_username),
        get_hash (TRIM (p_username), p_password));

COMMIT;

EXCEPTION
WHEN OTHERS
THEN 
 ROLLBACK; 
 RAISE;
END add_user;

-- Function to Perform a oneway hash of the users 
-- passwords. This cannot be reversed. This exmaple 
-- is a very week hash and if been used on a production 
-- system, you may want to use a stronger hash algorithm.
-- Read the Documentation for more info on DBMS_CRYPTO as 
-- this is the supported package from Oracle and 
-- DBMS_OBFUSCATION_TOOLKIT is now depricated.
FUNCTION get_hash (p_username IN VARCHAR2, p_password IN VARCHAR2)
RETURN VARCHAR2
AS
BEGIN
RETURN DBMS_OBFUSCATION_TOOLKIT.md5 (
input_string => UPPER (p_username) 
                || '/' 
                || UPPER (p_password));
END get_hash;

PROCEDURE valid_user2 (p_username IN VARCHAR2, p_password IN VARCHAR2)
AS
v_dummy VARCHAR2 (1);
BEGIN
SELECT '1'
INTO v_dummy
FROM app_users
WHERE UPPER (username) = UPPER (p_username)
AND PASSWORD = get_hash (p_username, p_password);
EXCEPTION
WHEN NO_DATA_FOUND
THEN raise_application_error (-20000, 'Invalid username / password.');
END valid_user2;

FUNCTION valid_user (p_username IN VARCHAR2, p_password IN VARCHAR2)
RETURN BOOLEAN
AS
BEGIN
valid_user2 (UPPER (p_username), p_password);
RETURN TRUE;
EXCEPTION
WHEN OTHERS
THEN RETURN FALSE;
END valid_user;

END app_security_pkg;

Here the ADD_USER procedure will convert the password and stores in the Table app_users in encrypted form.

In my application, users can change their password,
So I need to compare the password entering the Current_password field with the password encrypted in the app_users table.
So I used the following code,

declare
  l_x varchar2(30);
begin
  select username into l_x
        from app_users
    where upper(username) = upper(:P7_USERNAME)
      and password = :P7_CURRENT_PASSWORD;
  return (true);
exception
  when no_data_found then
    return (false);
end;

This code works fine when the password is stored without encryption, but it displays error, after encryption

because the password entered is simply password and not encrypted if the two are different even if the user enters the correct password.

Please tel me how encrypt the entered password to compare with the encrypted password.

Thank you
Kind regards
gurujothi.

Hi guru,.

When you say comparing it is obvious that both must be in the same format, so either you have to compare both encrypted or not encrypted.

Do you have an example on apex.oracle.com?

Thank you

I need the Md5 algorithm for password encryption adf
Can someone provide pointer how to use the algorithm Md5 password encryption for the adf
Ah, database 11g is great.
But it does not help you. In middleware, alias in a managed Bean of ADF you must use the Oracle Security Development Toolkit libraries to encrypt the password before storing it in the database. Traffic between the middleware and database is not normally encrypted and readable for all network sniffer.
When the user connects, you can use a similar mechanism to compare the encrypted password.
The other solution would be to use an LDAP server for the user/password information (WebLogic has a built-in and very good for small environments). No encryption necessary, as does the LDAP protocol.
Since you don't mention the middleware you use, here is the link to 11g of BCI for the tool box: http://download.oracle.com/docs/cd/E14571_01/apirefs.1111/e10668/toc.htm

HTH,
-olaf

Password encrypt a PDF file. (security lost)

Hello
I use the following piece of code password encrypt a PDF file
However. When I copy this PDF file to another machine. the PDF is not secure
Help, please... It is very important to me.
char * errorBuf;

DURING THE
CString strPassword = "123456789";
PDDocSetNewCryptHandler (pdDoc, ASAtomFromString ("Standard"));
StdSecurityData securityData = (StdSecurityData) PDDocNewSecurityData (pdDoc);
securityData-> format = sizeof (StdSecurityDataRec);
securityData-> hasUserPW = false;
securityData-> newOwnerPW = false;
securityData-> hasOwnerPW = true;
securityData-> newOwnerPW = true;
strcpy_s (securityData-> ownerPW, strPassword);
strcpy_s (securityData-> userPW, strPassword);
securityData-> perms = pdPermPrint;
securityData-> keyLength = 16;
PDDocSetNewSecurityData (pdDoc, securityData (void *));
PDDocSetFlags (pdDoc, PDDocRequiresFullSave);
HANDLER
ASGetErrorString (ASGetExceptionErrorCode(), errorBuf, 255);
AVAlertNote (errorBuf);
END_HANDLER

Have you thought to save the PDF file after execution of this? This gives him only to be guaranteed - you still need to save it.

On the remote host MySQL database: password encryption?

Hello
I discovered the world of PHP and MySQL in the last days. I didn't get all the intricacies still but nevertheless I managed to set up a server "localhost" on my computer, create a MySQL database and display correctly information in this database in HTML using PHP pages.
I am now at the stage of transferring it to the remote host where the site will happen: I exported my database, imported these information in the database on the server host and I n unexpectedily even just to get my PHP/HTML pages to connect to this database. It's great.
I have one question. I've read a lot of thread in this forum about this, but haven't seen an answer: must the password encryption? I mean, when I connect to a database using DW CS4, the software creates for me a connections folder in my Web site root folder and stores inside a little PHP to the folder with the server name, database name, user name and password which are necessary to allow PHP to connect to the MySQL database. It is all printed clearly in there. Once which is transferred to the remote host, it is always accessible to anyone? Should I not worry and try to hide the password?
Any thoughts on this would be greatly appreciated.
Emilie

Thread moved to Dreamweaver application development forum, which addresses other issues aside and PHP/MySQL server.

As long as the server is enabled in PHP, put the connection details in a PHP file like this is not a problem. PHP code is processed on the server. Only its output is sent to the browser. Even if someone guesses the name of your connection file, they won't see anything if they try to load the page in a browser. The only way they can see it is to hack into the server. It is important to have passwords on your FTP account.

Insert the password encrypted in the table user = > ORA-01861

Hello

I have a little problem, I try to save a password encrypted in the user's my table:

It works well:

declare
test VARCHAR2(40);
begin
select RAWTOHEX(dbms_crypto.hash(utl_raw.cast_to_raw('yyyyyyy'), dbms_crypto.hash_sh1)) into test from dual;
DBMS_OUTPUT.PUT_LINE(test);
end;
/

But when I try to integrate it into a procedure to insert in my table of the user, it shows me an error ORA-01861:

create or replace procedure inserer_utilisateur(v_nom in varchar2, v_prenom in varchar2, v_adresse in varchar2, v_mail in varchar2, v_login in varchar2, v_password in varchar2, v_dateNaissance in date) as
    id_uti integer;
    id_duti integer;
begin
    select seq_Utilisateur.nextval into id_uti from dual;
    insert into Utilisateur values (id_uti,v_nom,v_prenom,v_adresse,v_mail,v_login,RAWTOHEX(dbms_crypto.hash(utl_raw.cast_to_raw(v_password), dbms_crypto.hash_sh1)),to_date(v_dateNaissance,'DD-MM-YYYY'));
    select seq_Droit_Utilisateur.nextval into id_duti from dual;
    insert into Droit_Utilisateur values (id_duti,id_uti,1); 
end;

The procedure is called from my APEX application, it works when I don't encrypt the password.

I forgot something?

Thank you.

Yann.

The problem has nothing to do with encryption

The v_dateNaissance parameter is a date, remove the TO_DATE at all:

insert into Utilisateur values (id_uti,v_nom,v_prenom,v_adresse,v_mail,v_login,RAWTOHEX(dbms_crypto.hash(utl_raw.cast_to_raw(v_password), dbms_crypto.hash_sh1)),v_dateNaissance);

Max
http://oracleitalia.WordPress.com

Published by: Massimo Ruocchio, February 16, 2010 18:43

Who holds the keys for encryption AES mentioned in the table under "security and features iCloud?

Who holds the keys for encryption AES mentioned in the table under "security and features iCloud?

Article

Security and privacy - Apple Support Overview iCloud

has a useful table in the section entitled Security and features iCloud.

The table shows the types of keys used to secure the different types of data.

Apple holds these keys as it may be requested of Apple by third parties?

Hmmm... You definitely raise a good and valid question to which I don't know the answer to, but if I had to guess, I would say that no one. Would this be possible? I know I've heard Cook mention that they "don't hold the keys" but does the same thing, it refers? It would make a very interesting topic of discussion.

Then the password standard open mobile application protected AES256 encrypted files (not Livecycle) made by XI Acrobat adobe reader software?

I downloaded the Adobe reader mobile for iOS at the time and tried to open a PDF created by Acrobat XI and optimized (no error reported) for the web and mobile devices, the file has been encrypted password (* not livecycle *) using 256AES, acrobat X compatibility restrictions allow: no, authorized printing low ground.
at the spearhead of mobile pdf Acrobat had a password and even with the password that is used to change the failed to open security settings.
How people can secure pdf editing their XI Acrobat using (compatibility Acrobat X) unauthorized work, protection of password using AES256 bit encryption standard and opened using adobe reader mobile app?

You can open the file with Adobe Reader.

How can I retrieve or reset my password encryption for backup of iTunes to a new phone?

I just bought an iPhone 6 and that it replaces an iPhone 5. I want to transfer my data in iTunes but don't remember my password for encryption. Is there a way to recover the password or change it?

It is not recoverable.

On safeguards encrypted in iTunes - Apple Support

Cisco IPS 6.1 Auto Update password encryption

I have recently set up the automatic update via Cisco. I entered my CCO username and password via the GUI. As I entered the password, the characters were displayed in the form of points. A little later, I was in the EPI CLI. I noticed in the "show config" my CCO username and password are in the clear. Is there a way to encrypt my password? I assume developers Cisco intended for me to use my ORC. Should I use a different id EAC? Maybe a generic company userid has only IPS signature update capabilities.

Unaware, but they work.

See http://tools.cisco.com/Support/BugToolKit/search/getBugDetails.do?method=fetchBugDetails&bugId=CSCsh61309

I opened a case of TAC as if you installed a blocking device it stores also your credentials and the enable plaintext password if the configuration file is encrypted on disk.

User name and password, encryption

Hello..

My client wants the username and password to be encypted in the application. I see that there is some encryption methods to use in android and iOS. Do we have something like this in BB10? I really need it soon...

the sandbox of the PPA is inaccessible, it is unnecessary to quantify, it is course design.

If you want to encrypt in any case you can use the Cryptography API that supports a large number of common algorithms:
https://developer.BlackBerry.com/native/reference/BB10/crypto_libref/topic/intro.html

just be warned, they are not as easy to use as QML and Qt.

How to save the password encrypted in the database using database authentication (weblogic server)

Hi Experts,
JDEV version 11.1.1.7.0
I have a usecase where I use database authentication in my Application.
However if I save the module to record user password. Its economy without encryption. Can U suggest how can I do this
Thank you
Roy

Please see

https://docs.Oracle.com/CD/E16162_01/user.1112/e17455/dev_secure_apps.htm#OJDUG1168

Password encrypted ticket to principal-protected or is security authorization simply in function?

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