Please, help me to by merging the same id assining people
Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit ProductionPlease help me
We_addr_id defines the Address.
We_pid Defines the Person.
i am planning to merge the same person together by assigining the same we_pid.WITH merge_names AS (SELECT 1000 We_pid,
999898989 We_addr_id,
'DONALD' first_name,
'BOATRIGHT' last_name,
'L' middle_name,
NULL Suffix FROM DUAL
UNION ALL
SELECT 1001 We_pid,
999898989 We_addr_id,
'DONALD' first_name,
'BOATRIGHT' last_name,
'LARRY' middle_name,
NULL Suffix
FROM DUAL
UNION ALL
SELECT 1002 We_pid,
999898989 We_addr_id,
'DONALD' first_name,
'BOATRIGHT' last_name,
NULL middle_name,
NULL Suffix
FROM DUAL
UNION ALL
SELECT 33065 WE_PID,
99000000 We_addr_id,
'LUNA' First_name,
'JOSE' last_name,
NULL middle_name,
NULL suffix
FROM DUAL
UNION ALL
SELECT 8450527 WE_PID_LINK,
99000000 We_addr_id,
'LUNA' First_name,
'JOSE' last_name,
'A' middle_name,
NULL suffix
FROM DUAL
UNION ALL
SELECT 373453429 WE_PID_LINK,
99000000 We_addr_id,
'LUNA' First_name,
'JOSE' last_name,
NULL middle_name,
NULL suffix
FROM DUAL
UNION ALL
SELECT 442303062 WE_PID,
99000000 We_addr_id,
'LUNA' First_name,
'JOSE' last_name,
'S' middle_name,
NULL suffix
FROM DUAL
UNION ALL
SELECT 30088775765 WE_PID,
990000878 We_addr_id,
'BILL' last_name,
'RAY' first_name,
'M' middle_name,
NULL SUFFIX
FROM DUAL
UNION ALL
SELECT 30088775766 WE_PID,
990000878 We_addr_id,
'RAY' first_name,
'BILL' last_name,
NULL middle_name,
NULL SUFFIX
FROM DUAL
UNION ALL
SELECT 30088775767 WE_PID,
990000878 We_addr_id,
'RAY' first_name,
'BILL' last_name,
'MAX' middle_name,
NULL SUFFIX
FROM DUAL
UNION ALL
SELECT 30088775768 WE_PID,
990000878 We_addr_id,
'RAY' first_name,
'BILL' last_name,
'MICHEL' middle_name,
NULL SUffix
FROM DUAL
UNION ALL
SELECT 399998776 WE_PID,
9901111 We_addr_id,
'ELLISON' first_name,
'LAWRANCE' last_name,
NULL middle_name,
NULL SUFFIX
FROM DUAL
UNION ALL
SELECT 399998777 WE_PID,
9901111 We_addr_id,
'ELLISON' first_name,
'LAWRANCE' last_name,
'J' middle_name,
'JR' SUFFIX
FROM DUAL
UNION ALL
SELECT 399998778 WE_PID,
9901111 We_addr_id,
'ELLISON' first_name,
'LAWRANCE' last_name,
'JAMES' middle_name,
'SR' SUFFIX
FROM DUAL
UNION ALL
SELECT 399998779 WE_PID,
9901111 We_addr_id,
'ELLISON' first_name,
'LAWRANCE' last_name,
'JACK' middle_name,
'JR' SUFFIX
FROM DUAL)
SELECT *
FROM merge_names o/p Required
WE_PID WE_ADDR_ID FIRST_NAME LAST_NAME MIDDLE_NAME SUFFIX MERGE_WEPID
1000 999898989 DONALD BOATRIGHT L 1000
1001 999898989 DONALD BOATRIGHT LARRY 1000
1002 999898989 DONALD BOATRIGHT 1000
33065 99000000 LUNA JOSE 33065
8450527 99000000 LUNA JOSE A 8450527
373453429 99000000 LUNA JOSE 33065
442303062 99000000 LUNA JOSE S 442303062
30088775765 990000878 BILL RAY M 30088775765
30088775766 990000878 RAY BILL 30088775766
30088775767 990000878 RAY BILL MAX 30088775767
30088775768 990000878 RAY BILL MICHEL 30088775768
399998776 9901111 ELLISON LAWRANCE 399998776
399998777 9901111 ELLISON LAWRANCE J JR 399998777
399998778 9901111 ELLISON LAWRANCE JAMES SR 399998778
399998779 9901111 ELLISON LAWRANCE JACK JR 399998777Hello
Interesting problem!
That's what you asked for:
WITH got_min_we_pid AS
(
SELECT merge_names.*
, MIN (we_pid) OVER ( PARTITION BY first_name
, last_name
, middle_name
, suffix
) AS min_we_pid
FROM merge_names
)
, possible_matches AS
(
SELECT CONNECT_BY_ROOT min_we_pid AS min_we_pid
, we_pid AS leaf_we_pid
FROM got_min_we_pid
WHERE CONNECT_BY_ISLEAF = 1
START WITH we_pid = min_we_pid
CONNECT BY first_name = PRIOR first_name
AND last_name = PRIOR last_name
AND SUBSTR ( 'x' || middle_name
, 1
, LENGTH ('x' || PRIOR middle_name)
) = 'x' || PRIOR middle_name
AND 'x' || middle_name > 'x' || PRIOR middle_name
AND 'x' || suffix = 'x' || PRIOR suffix
)
, got_match_cnt AS
(
SELECT DISTINCT
min_we_pid
, leaf_we_pid
, COUNT (DISTINCT leaf_we_pid) OVER (PARTITION BY min_we_pid) AS match_cnt
FROM possible_matches
)
SELECT c.*
, NVL (p.leaf_we_pid, c.min_we_pid) AS merge_wepid
FROM GOT_MIN_we_pid c
LEFT OUTER JOIN got_match_cnt p ON p.min_we_pid = c.min_we_pid
AND p.match_cnt = 1
ORDER BY c.last_name
, c.first_name
, c.middle_name
;
Here's how it works:
First of all, we take care of the exact replica, by finding the we_pid lowest for each group defined by (first_name, last_name, middle_name, suffix). For example, the two lines for Jose Luna (no middle name) are assigned to the min_we_pid = 33065. It is this min_we_pid, not the original we_pid, that is used in all future operations.
Then we are all names other names that are similar, but more comprehensive, using a CONNECT BY (subquery possible_matches) query. The parents in this query are stored with short middle_names, and children are lines that have first_name, last_name identical and suffix, but middle_names longer. I concatenated the x at the beginning of all middle_names for comparisons, to treat the NULL as being less at, but similar to something else. Is so, that we had a group of lines with identical names (and suffixes) with the exception of the middle_names, then
NULL middle_name might be a parent got ', "DEB" and "DEBORAH",.
A ' would be a parent of "DEB" and "DEBORAH", and
"DEB" would be a parent of 'DEBORAH '.
By following this chart until we find the lines that have no children, we may associate each short middle_name with the similar longer middle_name, or names. At this point, we will have "BILL RAY" as the ancestor of 'RAY MAX BILL' as well as "RAY MICHEL BILL". Here comes the following subquery, got_match_cnt. If notes how many descendants are associated with each ancesotor, in other words, how much longer names might match a name more runs. If this number is greater than 1, we do not consider one of the matches. That is why match_cnt = 1 is one of the join conditions in the main query, where each row in the theoriginale table is related to its more relative, when it exists, and if it is unique.
Tags: Database
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