Please help me to set a query that was so irritating... (test 2)
I thank in advance for any help, you can provide or you the light can shineon that. I tried to work this problem for a few days
and continue to run into a wall, so any help is appreciated more.
Overview-
We have a collection of sites. At each location, users can create
checklists and assign ratings to the elements.
Database model:
CREATE TABLE RATINGS_DETAIL
(
RATING_ID NUMBER(5),
RATING_DESCRIPTION VARCHAR2(30 BYTE)
);
CREATE TABLE ITEMS
(
ITEM_ID NUMBER(5),
ITEM_DESCRIPTION VARCHAR2(1000 BYTE)
);
CREATE TABLE CHECKLIST_USERS
(
USER_ID NUMBER(5),
USER_NAME VARCHAR2(32 BYTE)
);
CREATE TABLE CHECKLIST
(
CHECKLIST_ID NUMBER(5),
LOCATION_ID NUMBER(5),
CHECKLIST_DESCRIPTION VARCHAR2(1000 BYTE),
CHECKLIST_DATE DATE,
CHECKLIST_EXTERNAL CHAR(1 BYTE)
);
CREATE TABLE CHECKLIST_ITEMS
(
ITEM_ID NUMBER(5),
CHECKLIST_ID NUMBER(5),
RATING_ID NUMBER(5),
RATING_USER_ID NUMBER(5)
);
ALTER TABLE RATINGS_DETAIL ADD (CONSTRAINT RATINGS_DETAIL_PK PRIMARY KEY (RATING_ID));
ALTER TABLE ITEMS ADD (CONSTRAINT ITEMS_PK PRIMARY KEY (ITEM_ID));
ALTER TABLE CHECKLIST_USERS ADD (CONSTRAINT CHECKLIST_USERS_PK PRIMARY KEY (USER_ID));
ALTER TABLE CHECKLIST ADD (CONSTRAINT CHECKLIST_PK PRIMARY KEY (CHECKLIST_ID));
ALTER TABLE CHECKLIST_ITEMS ADD (CONSTRAINT CHECKLIST_ITEMS_PK PRIMARY KEY (ITEM_ID, CHECKLIST_ID));
ALTER TABLE CHECKLIST_ITEMS ADD (
CONSTRAINT CHLIST_ITEM_RATING_FK FOREIGN KEY (RATING_ID) REFERENCES RATINGS_DETAIL (RATING_ID),
CONSTRAINT CHLIST_ITEM_USER_FK FOREIGN KEY (RATING_USER_ID) REFERENCES CHECKLIST_USERS (USER_ID),
CONSTRAINT CHLIST_ITEMS_LIST_FK FOREIGN KEY (CHECKLIST_ID) REFERENCES CHECKLIST (CHECKLIST_ID),
CONSTRAINT CHLIST_ITEMS_ITEM_FK FOREIGN KEY (ITEM_ID) REFERENCES ITEMS (ITEM_ID));Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (1, 1, 'Internal List 1', TO_DATE('09/01/2011', 'MM/DD/YYYY'), 'N');
Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (2, 1, 'External List 1', TO_DATE('05/01/2011', 'MM/DD/YYYY'), 'Y');
Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (3, 1, 'External List 2', NULL, 'Y');
Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (4, 1, 'External List 3', TO_DATE('08/01/2011', 'MM/DD/YYYY'), 'Y');
Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (5, 1, 'External List 4', NULL, 'Y');
Insert into CHECKLIST
(checklist_id, location_id, checklist_description, checklist_date, checklist_external)
Values (6, 2, 'Internal List 1 (loc 2)', TO_DATE('08/01/2011', 'MM/DD/YYYY'), 'N');
COMMIT;
Insert into ITEMS (item_id, item_description) Values (1, 'Item 1');
Insert into ITEMS (item_id, item_description) Values (2, 'Item 2');
Insert into ITEMS (item_id, item_description) Values (3, 'Item 3');
Insert into ITEMS (item_id, item_description) Values (4, 'Item 4');
Insert into ITEMS (item_id, item_description) Values (5, 'Item 5');
Insert into ITEMS (item_id, item_description) Values (6, 'Item 6');
Insert into ITEMS (item_id, item_description) Values (7, 'Item 7');
Insert into ITEMS (item_id, item_description) Values (8, 'Item 8');
Insert into ITEMS (item_id, item_description) Values (9, 'Item 9');
Insert into ITEMS (item_id, item_description) Values (10, 'Item 10');
COMMIT;
Insert into RATINGS_DETAIL (rating_id, rating_description) Values (1, 'Low');
Insert into RATINGS_DETAIL (rating_id, rating_description) Values (2, 'Med');
Insert into RATINGS_DETAIL (rating_id, rating_description) Values (3, 'High');
COMMIT;
Insert into CHECKLIST_USERS (user_id, user_name) Values (1, 'Internal User');
Insert into CHECKLIST_USERS (user_id, user_name) Values (2, 'External User');
COMMIT;
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (1, 1, 1, 1);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (2, 1, NULL, NULL);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (3, 1, 1, NULL);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (4, 1, 3, 1);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (5, 1, 3, 1);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (8, 1, 2, 1);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (1, 2, NULL, NULL);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (2, 2, NULL, NULL);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (6, 2, 2, 2);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (7, 2, 1, 2);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (1, 3, NULL, NULL);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (8, 3, 2, 2);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (1, 4, 3, 2);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (6, 4, 1, 2);
Insert into CHECKLIST_ITEMS (item_id, checklist_id, rating_id, rating_user_id)
Values (8, 4, NULL, NULL);
COMMIT; 1 SELECT CC.checklist_id, II.item_id, CHI.rating_id, RR.rating_description
2 FROM checklist CC
3 LEFT JOIN checklist_items CHI ON CC.checklist_id =CHI.checklist_id
4 LEFT JOIN items II ON CHI.item_id =II.item_id
5 LEFT JOIN ratings_detail RR ON CHI.rating_id =RR.rating_id
6* WHERE CC.checklist_id =1
SQL> /
CHECKLIST_ID ITEM_ID RATING_ID RATING_DESCRIPTION
------------ ---------- ---------- ------------------
1 3 1 Low
1 1 1 Low
1 8 2 Med
1 5 3 High
1 4 3 High
1 2
1 SELECT CC.checklist_id, II.item_id, CHI.rating_id, RR.rating_description
2 FROM checklist CC
3 LEFT JOIN checklist_items CHI ON CC.checklist_id =CHI.checklist_id
4 LEFT JOIN items II ON CHI.item_id =II.item_id
5 LEFT JOIN ratings_detail RR ON CHI.rating_id =RR.rating_id
6* WHERE CC.checklist_id =4
SQL> /
CHECKLIST_ID ITEM_ID RATING_ID RATING_DESCRIPTION
------------ ---------- ---------- ------------------------------
4 1 3 High
4 6 1 Low
4 8
For a given location, there may be multiple lists - 1 list of audit 'Internal' and any number of checklists "External" (including 0). They may, but have not, share items.
It should pull up a query that joins the list of internal control with the most recent list of external audit. And there manage if there is no list of external control.
So far, the best I've been able to understand is to make each separate list and then try to merge the results later, but it's not effective for hundreds of possible objects we need to "Preview" in several places and find all their results which would be thousands of results.
So, I want a single query to retrieve the data if possible. I can make a separate request for internal identification numbers and a list of corresponding external audit.
I need to produce something like this:
1 SELECT checklist_id AS INTERNAL_ID FROM checklist
2* WHERE checklist_external ='N' AND location_id =1
SQL> /
INTERNAL_ID
-----------
1
1 SELECT EE.checklist_id AS EXTERNAL_ID
2 FROM checklist EE
3 WHERE EE.checklist_external ='Y'
4 AND EE.checklist_date =(SELECT max(EE2.checklist_date)
5 FROM checklist EE2
6 WHERE EE2.checklist_external ='Y'
7 AND EE2.location_id =EE.location_id)
8* AND EE.location_id =1
SQL> /
EXTERNAL_ID
-----------
4INTER EXTER ITEM_ID I_RATING E_RATING
----- ------ -------- ---------- ---------
1 4 1 Low High
1 2
1 3 Low
1 4 High
1 5 High
4 6 Low
1 4 8 Med
1 SELECT CC1.checklist_id AS INTER,
2 CC2.checklist_id AS EXTER,
3 II.item_id,
4 RD1.rating_description AS I_rating,
5 RD2.rating_description AS E_rating
6 FROM items II
7 JOIN checklist_items CHI1 ON II.item_id =CHI1.item_id
8 JOIN ratings_detail RD1 ON CHI1.rating_id =RD1.rating_id
9 JOIN checklist CC1 ON CHI1.checklist_id =CC1.checklist_id
10 AND CHI1.checklist_id =1
11 JOIN checklist_items CHI2 ON II.item_id =CHI2.item_id
12 JOIN ratings_detail RD2 ON CHI2.rating_id =RD2.rating_id
13 JOIN checklist CC2 ON CHI2.checklist_id =CC2.checklist_id
14* AND CHI2.checklist_id =4
15 /
INTER EXTER ITEM_ID I_RATING E_RATING
---------- ---------- ---------- ------------- --------------
1 4 1 Low High
Tags: Database
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DEPTNO DNAME LOC
--------------------------------------------------------------------------------
--------------
--------------------------------------------------------------------------------
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Sum (volume15),
Sum (volume16),
Sum (volume17),
Sum (Volume18),
Sum (volume19),
Sum (volume20),
Sum (rate1),
Sum (rate2),
Sum (rate3),
Sum (rate4),
Sum (rate5),
Sum (rate6),
Sum (rate7),
Sum (rate8),
Sum (rate9),
Sum (rate10),
Sum (rate11),
Sum (rate12),
Sum (rate13),
Sum (rate14),
Sum (rate15),
Sum (rate16),
Sum (rate17),
Sum (rate18)
Sum (rate19),
Sum (rate20)
Of
Table 1 - 13, 25, 99, 400 records
Table2 - 13, 45, 1000 records
Table 3 - 4, 50, 000 records
Table 4 - 1,00,000 records
table5 - 30 000 records
where tabl1.col1 = table2.col2,
Table1.Col1 = table3.col1.
table2.col2 = table3.col2...
Group
Sum (volume1),
Sum (volume2),
Sum (volume3),
Sum (volume4),
Sum (volume5),
Sum (volume6),
Sum (volume7),
Sum (volume8),
Sum (volume9),
Sum (volume10),
Sum (volume11),
Sum (volume12),
Sum (volume13),
Sum (volume14),
Sum (volume15),
Sum (volume16),
Sum (volume17),
Sum (Volume18),
Sum (volume19),
Sum (volume20),
Sum (rate1),
Sum (rate2),
Sum (rate3),
Sum (rate4),
Sum (rate5),
Sum (rate6),
Sum (rate7),
Sum (rate8),
Sum (rate9),
Sum (rate10),
Sum (rate11),
Sum (rate12),
Sum (rate13),
Sum (rate14),
Sum (rate15),
Sum (rate16),
Sum (rate17),
Sum (rate18)
Sum (rate19),
Sum (rate20)
Thank you
Prasad.
> Could someone please help how to tune the query as its takes a long time to retrieve the results.
The query you posted is obviously fake.
If you ask to give us a request that you do not post and we cannot see.
For real?
-
I bought Photoshop and elements of order #AD003212006UK. When I try to download I am informed that the software is not suitable for my system (new iMac, retina) Please help
You are 100% sure that you are clicking to download the Mac version and not the version of Windows?
Since this is an open forum, not Adobe support... you must contact Adobe personnel to help
Chat/phone: Mon - Fri 05:00-19:00 (US Pacific time) <===> NOTE DAYS AND TIME
Don't forget to stay signed with your Adobe ID before accessing the link belowCreative cloud support (all creative cloud customer service problems)
http://helpx.Adobe.com/x-productkb/global/service-CCM.html
-or by phone http://helpx.adobe.com/x-productkb/global/phone-support-orders.html -
Hello
I need help to form a query. I have two tables Support_issues and Support_comments with the information below.
I want to create a query to view the account of the situation for the last 15 days until today.
Sample Input data support_issues: ISSUE_ID ISSUE_DESC CREATION_DATE STATUS 1 AAA 01/NOV/2011 Open 2 BBB 02/NOV/2011 Closed 3 CCC 02/NOV/2011 Open 4 DDD 03/NOV/2011 Reopened 5 EEE 03/NOV/2011 Reopened support_comments: COMMENT_ID ISSUE_ID COMMENT_DESC STATUS UPDATE_TIME 101 1 aaa Open 01/NOV/2011 102 2 bbb Open 02/NOV/2011 103 2 bbbbbb Closed 03/NOV/2011 104 2 bbbb11 Reopened 03/NOV/2011 105 3 ccc Open 02/NOV/2011 106 2 bbbbb Closed 03/NOV/2011 107 4 ddddd Open 03/Nov/2011 108 5 eeeee Open 03/NOV/2011 109 4 343434 Closed 06/NOV/2011 110 4 dfdf Reopened 07/NOV/2011 111 5 dfdfdf Closed 08/NOV/2011 112 5 udehjk Reopened 10/NOV/2011
For "Created" count of status must be taken Support_issues table, for others it must be taken from table Support_comments.Sample output: DATE Created Reopened Closed 28/OCT/2011 0 0 0 29/OCT/2011 0 0 0 30/OCT/2011 0 0 0 31/OCT/2011 0 0 0 01/NOV/2011 1 0 0 02/NOV/2011 2 0 0 03/NOV/2011 2 1 2 04/NOV/2011 0 0 0 05/NOV/2011 0 0 0 06/NOV/2011 0 0 1 07/NOV/2011 0 1 0 08/NOV/2011 0 0 1 09/NOV/2011 0 0 0 10/NOV/2011 0 1 0 11/NOV/2011 0 0 0
Please help me to form a query for this!
Thank you
MukeshHello
Try the following query
with t1 as ( select to_char(sysdate-level+1,'dd-mm-yyyy') as date_range from dual where level<16 connect by sysdate-16Cannot test because I did not create, insert commands...
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