Problem with REGEXP_SUBSTR

Similar Questions

• Problem with REGEXP_SUBSTR related query.

  I'm having a problem with this query:

  SELECT *.

  FROM (SELECT REGEXP_SUBSTR ('{SUMMER} |)) {} POINT OF SALE}',

  '({)([A-Z]+ *[A-Z]*)(})',

  1,

  LEVEL,

  'I,

  2)

  Val

  OF THE DOUBLE

  CONNECT BY LEVEL < =.

  REGEXP_COUNT ('{SUMMER} |) {} POINT OF SALE} ',' |') + 1)

  WHERE val IS NOT NULL

  I need the output in 2 rows in this format:

  VAL

  ====

  SUMMER

  POINT OF SALE

  But I'm not able to get the "POINT OF SALE" in the output due to space, or perhaps another reason. Anyone can correct my query?

  So, you want something like that?

  SQL > ed
  A written file afiedt.buf

  1. SELECT *.
  2 (SELECT REGEXP_SUBSTR ('{SUMMER} |)) {} POS} ',' [^ {|}] + ", LEVEL, 1, 'i') val"
  3 FROM TWO
  4. CONNECT BY LEVEL<>
  5 REGEXP_COUNT ('{SUMMER} |) {} POINT OF SALE} ',' [^ |] +'))
  6 * val WHERE IS NOT NULL
  SQL > /.

  VAL
  ------------------------
  SUMMER
  POINT OF SALE

  SQL >

• Problem with regexp_substr if the string with null values between commas.

  Hi all
  
  My version of DB is 10.1.0.5.0
  I want to extract the string values using query below, but I am unable to provide the correct result.
  

  WITH t  AS ( select '123,1,3,22' col FROM DUAL
          UNION ALL
          SELECT '123,,2,1' FROM DUAL
          UNION ALL
          SELECT '5,1,2,,' FROM DUAL
          ) 
  SELECT regexp_substr(t.col,'[^,]*',1,1)
        ,regexp_substr(t.col,'[^,]*',1,2)
        ,regexp_substr(t.col,'[^,]*',1,3)
        ,regexp_substr(t.col,'[^,]*',1,4) FROM DUAL,t   ;

  My required result as below.

  123     1      3      22
  123            2       1
  5       1      2        

  Please help me to get the required result by using regular expressions.
  Thanks, Ram

  Hello

  In Oracle 10, you can do so by combining REGEXP_SUBSTR with something else like RTRIM:

  SELECT     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 1), ',')     AS part_1
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 2), ',')     AS part_2
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 3), ',')     AS part_3
  ,     RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 4), ',')     AS part_4
  FROM     t
  ;
  

  Starting Oracle 11 REGEXP_SUBSTR alone can do.

  But look at the first response; regular expressions will be probably less effective than less powerful features, especially when all channels have the same number of separators.

  Published by: Frank Kulash on 29 December 2012 08:36

• Problem with subquery

  Dear all,

  Hope that your door

  I'm having a problem with the sub query. I have to pass several ID for my sub query... but with my request, I only get the correct result...

  Here is the my sample data and my table structure...

  Employee table:

  ------------------------

  EMPLOYEE_ID	NOT NULL	NUMBER (16)
  EXTERNAL_ID_1		VARCHAR2 (200)
  EXTERNAL_ID_2		VARCHAR2 (200)
  JOB_PROFILE_TYPE		VARCHAR2 (4)
  FIRST NAME	NOT NULL	VARCHAR2 (200)
  MIDDLE_NAME		VARCHAR2 (200)

  Table alignment:

  -------------------------

  ALIGNMENT_ID	NOT NULL	NUMBER (16)
  TEAM_ID	NOT NULL	NUMBER (16)
  EMPLOYEE_ID		NUMBER (16)
  ALIGNMENT_NAME	NOT NULL	VARCHAR2 (200)
  EXTERNAL_ID_1		VARCHAR2 (200)
  STATUS	NOT NULL	VARCHAR2 (4)
  STATUS_CHANGE_DATE	NOT NULL	DATE
  MANAGER_ALIGNMENT_ID		NUMBER (16)

  
  

  Event table:

  -------------------

  EVENT_ID	NOT NULL	NUMBER (16)
  EMPLOYEE_ID	NOT NULL	NUMBER (16)
  AFFILIATION_ID		NUMBER (16)
  CUSTOMER_ID		NUMBER (16)
  EXTERNAL_ID_1		VARCHAR2 (200)

  Sample data:

  ALIGNMENT_ID

  ALIGNMENT_NAME

  EMPLOYEE_ID

  ROLE

  MANAGER_ALIGNMENT_ID

  1006034672	SII-KRN-BANG-A01	17452000001661	REP	1006034513
  1006034673	SII-KRN-BANG-A02	18910000219453	REP	1006034513
  1006034674	SII-KRN-BANG-A03	60000001963804	REP	1006034513
  1006034675	SII-KRN-BANG-A05	60000001963706	REP	1006034514
  1006034676	SII-KRN-BANG-A06	18910000081856	REP	1006034514
  1006034677	SII-KRN-BANG-B01	60000001963699	REP	1006034513

  My query:

  [code]

  SELECT *.

  Ev EVENT

  INNER JOIN employee e ON e.employee_id = ev.employee_id

  INNER JOIN alignment one ON e.employee_id = a.employee_id AND alignment_id in(:alignment_id)

  [/ code]

  Description:

  I have the data stored in the table in the alignment with the child records and parent records... in the table of alignment, I have the id of the alignment_id alignment and data manager.

  Each rep there would be a single Manager. (manager_alignment_id).

  I have to integrate this query at the front end. .

  At the end I drop down values and will select more than one pass to this request...

  If the selection for alignment_id (rep) then no prob... If they select manager_alignemnt_id then how to pass this value to the query of mu...

  Thanks a lot for your help.

  I'm using the version of oracle 11g.

  Sihem...

  Ideally, the front-end server would be best to store the values in a table (global temporary) and then the request would just join this table to limit the records returned.

  If, for some reason, you can do that, and him are spent as a delimited string (not ideal according to the standards of most of the people), then you have to splits the string to provide the individual values for example

  SQL > ed
  A written file afiedt.buf

  1 Select
  2 of PEM
  3 where empno in)
  4 with t as (select '& input_string' as double txt)
  5 Select REGEXP_SUBSTR (txt, ' [^,] +', 1, level)
  6 t
  7. connect by level<=>
  8*   )
  SQL > /.
  Enter the value of input_string: 7369,7844,7788
  4 old: with t as (select '& input_string' as double txt)
  4 new: with t as (select ' 7369,7844,7788' as double txt)

  EMPNO, ENAME, JOB HIREDATE DEPTNO COMM SAL MGR
  ---------- ---------- --------- ---------- -------------------- ---------- ---------- ----------
  7369 SMITH CLERK 7902 DECEMBER 17, 1980 00:00:00 800 20
  7844 TURNER SALESMAN 7698 1981 - SEP - 08 00:00:00 1500 0 30
  7788, SCOTT, ANALYST, 7566 19 APRIL 1987 00:00:00 3000 20

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