Q How Merge Elements 9 elements 14 catalogue?

Recently downloaded 14 items and you want to merge it with 9 elements catalog. Help please.

Carrie

roberts72691463 wrote:

Recently downloaded 14 items and you want to merge it with 9 elements catalog. Help please.

Carrie

There is no command integrated to 'merge' catalogues (such a command is available in Lightroom).

See:

http://www.johnrellis.com/psedbtool/Photoshop-elements-FAQ.htm#_Splitting_and_rearranging

The usual to migrate your catalog to a more recent version is simple to use menu file > manage catalogs, then use the button "Convert", which will create a new catalog with the same organization in the new format. Then, you use the new catalog of the new version. The old catalog (renamed with a suffix-1) is always available for the old version of elements. Remember that what is happening in a catalog is completely ignored by the other; That is why it is strongly recommended to use a single catalog.

Tags: Photoshop

Similar Questions

  • I have two libraries 'photos' and only want one. How Merge/consolidate their?

    I have two libraries 'photos' and only want one. How Merge/consolidate their?

    Photos has no tool to merge two libraries by importing each other.

    • You can export the photos of the smallest library and import them into the largest library,
    • or merge libraries in iCloud, if you sign up for enough storage iCloud accommodate the merged libraries.  To merge in iCloud activate one of your photo libraries as the photo library iCloud and wait for the pictures to download on iCloud, then proceed to the second library, enable this as the iCloud photo library, wait for the pictures to download. iCloud will download the pictures of the first library to the second, and you'll have a library merged in the second library.

    Or buy PowerPhotos.  This tool allows you to move photos between libraries and can help you merge some libraries. You can buy it here:

  • How "merge" several duplicate layers together to make a single image?

    How "merge" several duplicate layers in the same image, (each of them with a number painted on it) in an image, which shows all the numbers separated, that is are coalition? Believe me, I tried all means to do, but nothing helps, I just can't 'merge' into a single image. Help, please! I use Photoshop cc with windows 7.

    Select all layers, and then press ctrl-alt-shift-e. This will create a composite of all layers, leaving your only originals.

    Each layer must have a mask or pixels removed to create a transparent box that allows to display the image in the next layer below and so on. This must be done before you create the composite.

  • How to merge elements of two tables (defined as local types)

    Hello

    How can he get the elements in array 'a' and 'b' in table 'c '. I could write a loop, but I don't know if there is a smarter option:

    DECLARE
      TYPE t IS TABLE OF NUMBER;
      a t;
      b t;
      c t;
    BEGIN
      a := t(1,2,3);
      b := t(3,4,5);
      c := ...  -- c {1, 2, 3, 3, 4, 5}     
    END;
    
    

    I could use something like that, but I prefer to define the type of table in a package:

    CREATE OR REPLACE TYPE t AS TABLE OF NUMBER;
    
    SELECT a MULTISET UNION b INTO c FROM dual;
    
    
    

    Thanks in advance

    Try this:

    DECLARE

    TYPE T IS TABLE OF NUMBER;

    A T;

    b T;

    c T;

    BEGIN

    A: = T (1,2,3);

    b: = T (3,4,5);

    --c: =...--c {1, 2, 3, 3, 4, 5}

    c: = A MULTISET UNION B;

    END;

    /

  • How insert elements into a table after each iteration of a for loop

    I'm new to labview and work on an application where I'm supposed to store an element in an array (without crushing) after each iteration in a loop for. I tried using function Array build, keeping the flag outside the loop for and played with indexing, but did not work. Please suggest me an idea how to do it.

    Thank you

    It would be better if you attached the real VI.

    None of your images show an operation 'insert into array.

  • How the elements tag with two tags?

    With the following function I can tag with bold and italic tags xml elements. The problem is, I also need '< b > < i >' for example. Now my question is, how is that possible?

    function tagStyles (myXmlElement) {}

    app.findTextPreferences = app.changeTextPreferences = NothingEnum.nothing;

    app.findChangeTextOptions.caseSensitive = false;

    app.findChangeTextOptions.includeFootnotes = app.findChangeGrepOptions.includeFootnotes = false;

    app.findChangeTextOptions.includeHiddenLayers = false;

    app.findChangeTextOptions.includeLockedLayersForFind = false;

    app.findChangeTextOptions.includeLockedStoriesForFind = false;

    app.findChangeTextOptions.includeMasterPages = false;

    app.findChangeTextOptions.wholeWord = false;

    objectToTag = myXmlElement;

    italic conversion

    need to be developed for other styles

    attention to the problems of nested xml tags

    app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.nothing;

    app.findGrepPreferences.findWhat = '. '. + » ;

    app.findGrepPreferences.fontStyle = "italic";

    var myFindTexts = myXmlElement.findGrep ();

    If (myFindTexts.length > 0) {}

    for (var j = 0; j < myFindTexts.length; j ++) {}

    var myText = myFindTexts [j];

    var myStartIndex = myText.characters [0] .index;

    var = myText.characters [-1] .index myEndIndex;

    objectToTag = objectToTag.xmlElements.add ({markupTag: "i", xmlContent:myText});})

    myShift += 2;

    }

    }

    conversion "BOLD"

    need to be developed for other styles

    attention to the problems of nested xml tags

    app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.nothing;

    app.findGrepPreferences.findWhat = '. '. + » ;

    app.findGrepPreferences.fontStyle = "Bold";

    var myFindTexts = myXmlElement.findGrep ();

    If (myFindTexts.length > 0) {}

    for (var j = 0; j < myFindTexts.length; j ++) {}

    var myText = myFindTexts [j];

    var myStartIndex = myText.characters [0] .index;

    var = myText.characters [-1] .index myEndIndex;

    objectToTag = objectToTag.xmlElements.add ({markupTag: "b", xmlContent:myText});})

    }

    }

    bold italics conversion

    need to be developed for other styles

    attention to the problems of nested xml tags

    app.findGrepPreferences = app.changeGrepPreferences = NothingEnum.nothing;

    app.findGrepPreferences.findWhat = '. '. + » ;

    app.findGrepPreferences.fontStyle = "Bold Italic";

    var myFindTexts = myXmlElement.findGrep ();

    If (myFindTexts.length > 0) {}

    for (var j = 0; j < myFindTexts.length; j ++) {}

    var myText = myFindTexts [j];

    var myStartIndex = myText.characters [0] .index;

    var = myText.characters [-1] .index myEndIndex;

    objectToTag = objectToTag.xmlElements.add ({markupTag: "b", xmlContent:myText});})

    }

    objectToTag = myXmlElement;

    for (var j = 0; j < myFindTexts.length; j ++) {}

    var myText = myFindTexts [j];

    var myStartIndex = myText.characters [0] .index;

    var = myText.characters [-1] .index myEndIndex;

    objectToTag = objectToTag.xmlElements.add ({markupTag: "i", xmlContent:myText});})

    }

    }

    }

    When there is an element with the "Bold Italic" style it looks like this: 'my element with < b > < /b > < i > "BOLD" and the italic text < /i > '. There it looks like this: ' my element with < b > < i > bold and italic < /i > < / b > text.

    Does anyone have an idea on this?

    Thanks in advance!

    Dear Stamm,

    Try this...

    objectToTag = objectToTag.xmlElements.add ({markupTag: "b", xmlContent:myText});})

    App.Select (objectToTag.texts);

    App.Selection [0] .associatedXMLElements [0].xmlElements.Add ("i", app.selection [0]);

    Kind regards

    Bala

  • How the elements of knot delete\retract?

    Hello

    I want to delete\retract node using my server (c#) elements, as in the Console of the room (see picture to attach it)lccs.JPG

    How can I do this?

    Thank you

    Eyal.

    With the latest version of the SDK, available at DevPortal, we have added operations node to the server API, so now you can call retractItem and removeNode of a server environment.

  • How do elements in a word in the list to wrap as necessary and be of variable height

    I am trying to build an itemrenderer for the list control.  The elements of the list of variable lengths of text, some of the text elements will be different colors determined during execution based on certain criteria (it works fine now with my custom itemrenderer).  What I need is for the items back to the line, and so for the list view items in different heights.  Is this possible to do?  All my attempts appear to have failed.  If I can't do that with a converter part of the suggestions on how to do?  Thank you very much in advance to one of you gurus who are able to help me.

    I would not expect this example works.  Width of the text is not always related to the canvas explicitWidth.  You'd probably have to substitute Measure [] like this:

    override protected function measure (): void

    {

    txt.explicitWidth = explicitWidth;

    Super.Measure ();

    }

    ]]>

    Alex Harui

    Flex SDK Developer

    Adobe Systems Inc..

    Blog: http://blogs.adobe.com/aharui

  • Merge elements of form script possible?

    When I have a pathItem in my doc with several subPathItems how can I access the ability to activate the "form components merge"?

    Is it possible by script?

    I tried listener script with no luck.

    pathsComp.jpg

    Record fine for me. (Edit: the path must be selected.)

    // =======================================================

    var idcombine is stringIDToTypeID ("combine");.

    var desc2 = new ActionDescriptor();

    var idnull = charIDToTypeID ("null");

    var ref1 = new ActionReference();

    var idPath = charIDToTypeID ('Path');

    var idOrdn = charIDToTypeID ('Ordn');

    var idTrgt = charIDToTypeID ("Trgt");

    Ref1.putEnumerated (idPath, idOrdn, idTrgt);

    desc2.putReference (idnull, ref1);

    executeAction (idcombine, desc2, DialogModes.NO);

  • insert/update - merge elements of apex

    Hello =)

    I want to insert data into a table, and if the table already has the "List_id' I want to update the values:

    Start
    BECAUSE me IN 1.APEX_APPLICATION. G_F01. COUNTING LOOP
    MERGE INTO list_values
    With the HELP of double
    WE (list_values.list_id = to_number (APEX_APPLICATION. G_F02 (i))
    WHEN MATCHED THEN
    UPDATE
    SET
    list_values.product_fk =: P900_PRODUCT_NAME.
    ist_values. Attribute = APEX_APPLICATION. G_F04 (i),
    list_values. Value = APEX_APPLICATION. G_F05 (i)
    WHEN NOT MATCHED THEN
    INSERT
    *(*
    list_values.product_fk, list_values. Attribute, list_values. Value
    *)*
    VALUES
    *(*
    *: P900_PRODUCT_NAME, APEX_APPLICATION. G_F04 (i), APEX_APPLICATION. G_F05 (i) *.
    *);*
    end loop;
    end;

    you have a lot of errors in sql...
    + 1 + error has occurred

    ORA - 06550:line 6, column 65: PL/SQL: ORA-00907: missing parenthesis ORA-06550: line 4, column 1: PL/SQL: statement ignored SQL

    Maybe someone can help me with the syntax of the merge statement or perhaps merging does not work in this case. because of the apex_items.


    also got separated insert/update process. they work perfect, if I use the process individually:
    Begin
    BECAUSE me IN 1.APEX_APPLICATION. G_F01. COUNTING LOOP

    insert into List_values (product_fk, attribute, value)
    values (: P900_PRODUCT_NAME, APEX_APPLICATION.) G_F04 (i), APEX_APPLICATION. G_F05 (i));
    END LOOP;
    end;

    Start
    BECAUSE me IN 1.APEX_APPLICATION. G_F01. COUNTING LOOP

    List_values update
    set
    product_fk =: P900_PRODUCT_NAME.
    attribute = APEX_APPLICATION. G_F04 (i),
    value = APEX_APPLICATION. G_F05 (i)
    where list_id = to_number (APEX_APPLICATION. G_F02 (i));
    END LOOP;
    end;

    Maybe someone can help me to combine.
    Thank you =)

    Name of the table on line 12 was also misspelled.

    BEGIN
       FOR i IN 1 .. APEX_APPLICATION.g_f01.COUNT
       LOOP
          MERGE INTO LIST_VALUES
               USING DUAL
                  ON (LIST_VALUES.list_id =
                         TO_NUMBER (APEX_APPLICATION.g_f02 (i)))
          WHEN MATCHED
          THEN
             UPDATE SET
                LIST_VALUES.product_fk = :p900_product_name,
                LIST_VALUES.attribute = APEX_APPLICATION.g_f04 (i),
                LIST_VALUES.VALUE = APEX_APPLICATION.g_f05 (i)
          WHEN NOT MATCHED
          THEN
             INSERT     (LIST_VALUES.product_fk,
                         LIST_VALUES.attribute,
                         LIST_VALUES.VALUE)
                 VALUES (
                           :p900_product_name,
                           APEX_APPLICATION.g_f04 (i),
                           APEX_APPLICATION.g_f05 (i));
       END LOOP;
    END;
    

    Jeff

  • How messageTextInput element readonly on loading the page dynamically?

    Hi all
    This is my requirement. I have a point message text entry populated on load of the page attributeX of the VO. I need to check the condition of attributeY! = pageContext.getUserName () and if he is convinced that I have to make the item messageTextInput as read only when the page is loaded. To do this, I wrote the following code in the form request process.


    vo.executeQuery ();
    If (VO. GetCurrentRow.GetAttribute ("attributeY")! = pageContext.getUserName ())
    {
    OAMessageTextInputBean bean = (OAMessageTextInputBean) webBean.findChildRecursive ("txtItem");
    bean.setReadOnly (Boolean.FALSE);
    }

    Copy the following code throws exceptions. Also if I don't give the if condition and just trying to make the point to read only the loading of the page, it does not take exception, but does not in read-only mode.


    Please let me know how to solve this problem.

    Thank you
    Sunny

    Sunny,

    Can you check after the vo run the query, your VO have rows by
    vo.getFetchedRowCount (),

    And then do vo.first () and then only the if condition,

    Inside the if condition add some diagnostic message to check, your state of health is coming inside.
    print the values for vo.getCurrentRow.getAttribute ("attributeY"), pageContext.getUserName)

    And if you compare the string, you must use api .equals
    If (!) (vo.getCurrentRow.getAttribute("attributeY").equals (pageContext.getUserName ())))

    Thank you.

    With respect,
    Kali.
    OSSI.

  • How an element of the specific instance of control/get "from outside"?

    Hello

    I use a function in my script object to control my subforms flowed and reproducible.

    Each subform contains a checkbox

    structure of the form:

    Page 1

    mysubform 1 (subform flowed, repeatable)

    Checkbox

    mysubform 2 (instance number "2")

    Checkbox

    mysubform 3 (instance number '3')

    Checkbox

    ...

    mysubform n (instance number "n")

    Checkbox

    // click event on CheckBox
         doProcessOnSubForm(this):
    
    
    
    
    // scripting object
    function doProcessOnSubForm(CheckBox){
         var InstanceOfMysuborm = CheckBox.parent._mysubform;
    
         console.println(InstanceOfMysuborm.count); // Outupt = 3, so I have 3 mysubforms
         
         // make only instance number 2 invisible
         InstanceOfMysuborm.SOMEmagicCODEtoGETitemNUMBER2.presence = "hidden";
    
    
    }
    

    Anyone have an idea how I can get the number of 'point' 2 of mysubform?

    p.s. I'm not removeInstance; )

    Thank you

    solved by myself

    xfa.resolveNode ("... pathToSubform...") [ » + 2 + «] ") .its presence is hidden;.

  • How "inspect element" arrived on my right click menu?

    I have installed several addons when it appeared. Anyone know where this right click menu item came? My research has suggested "firebug" - whatever that is. This isn't on my XP but it's on my Vista and both have the same addons.
    Thank you

    Hello

    It's a new tool in Firefox which is also accessible via Tools ("Alt + T") > Web Developer > inspect. Pressing ESC will close it. See also this.

  • How the elements of provision correctly

    I am struggling to align 2 imagebuttons vertically and horizontally on the dev c alpha and z10, regardless of orientation.

    Without defining preferredHeight of containers that I'm now trying the container on the alpha c dev does not fill the whole screen vertically so I don't get a full black background - only about 2/3 of the full black screen vertically, but it works well on Z10.

    So now, I try to get the background black everything at the bottom of the screen on the dev c alpha using preferredHeight but then items start at the top of the screen rather than centered vertically.

    What is the right way to do it?

    Container* container = Container::create().background(Color::Black)
                                   .layout(DockLayout::create())
                                   .add(Container::create().background(Color::Black)
                                   .preferredHeight(display.pixelSize().height())
                                   .horizontal(HorizontalAlignment::Center)
                                   .vertical(VerticalAlignment::Center)
                                   .layout(StackLayout::create()
                               .orientation(LayoutOrientation::TopToBottom))
                                   .add(imageButton1)
                                   .add(imageButton2));
    

    Try this:

    Container* container = Container::create().background(Color::Black)
        .layout(DockLayout::create())
        .vertical(VerticalAlignment::Fill)
        .add(Container::create()
            .horizontal(HorizontalAlignment::Center)
            .vertical(VerticalAlignment::Center)
            .layout(StackLayout::create())
            .add(imageButton1)
            .add(imageButton2));
    

    Orientation for the StackLayout TopToBottom is by default, so you don't need to specify it. Also, one thing you pouvez have to do is give the internal container a "setMinHeight '... I'm not entirely sure at this moment if the two ImageButtons displayed correctly...

  • How deactiveat elements 9 when he stopped not working, no error code.

    My 9 items stopped not working, no error code.  I am trying to disable and uninstall, however, it seems to turn off I have to be able to get the program to open.

    Thank you Jeff Wright, the third time that I chatted they disabled the program for me and I was able to uninstall and reinstall the program works now.  I had two applications on my lap top and the other on my computer when they disabled it.

    W

Maybe you are looking for

  • What ink needs to be replaced

    Despite several questions by seeing on the same topic, I see no answers. So I put again. I have HP Photosmart 5520. When the ink becomes low I have no warning notice given, it displays just in any old color. Yes, I press the icon on the front and he

  • How to record on an output table iterated data

    I want to save modified data (individual channels of data) in a table or an indicator that shows the ropes of checksums. As you can see from my attached code that each value is to be replaced by the following. I want to save all the iterations and no

  • Restart Skype anywhere from 3% to 50%, does not download, what can I do here?

    Skype keeps restarting installation regardless of redownloading or reboot.  SkypeSetupFull.exe won't download at all.

  • Precision imaging 7710 with MDT 2013 U1

    All right, so my company has a try to buy 7710 we think make our standard high-end. This unit is fitted with 2 x PCIe M.2 discs inside. I joined the fix in our installation wim for Windows 7 (not necessary in starting up wim, since its 10 WinPE): All

  • How to stop spam

    Original title: junk mail I get spam from a site that I continually delete and block. They just continue to send with the name of a different person. I went to what I thought was originally and asked them to stop, but to no avail. How can I stop it p