Question formula numbers

= IF ("J" = B8, C8, "No") that's the formula that I use and say that its location is D300.  Is it possible to have the entire column 'B' instead of just B8 or a beach like B1 to B290 for the letter 'J' reference and output then the content of the column "C"? For example if:

B2 = C2 = 'truck' and 'J' and

B3 = 'R' and C2 = 'car' and

B3 = C3 = 'bike' and 'J' and

B4 = 'J' and C3 = "flat" and

B5 = C3 = 'bus' and 'R'

Then the output to the D300 (or a range of rows) would be

truck

bike

plane

I created a list of 300 lines and throughout the list, the first letter of 4 different names is in column b.  Basically, I would like the output of the corresponding 'C' column appear.  In this way, the list is specific responsibilities for this person?  Thanks in advance for any help.

Rick

Hi rmac,.

" is there a way to have the entire column 'B' instead of just B8 or a beach like B1 to B290 for the letter 'J' for reference"

You can use the MATCH or a SEARCH, VLOOKUP to search the entire column 'J', but these will be pick up only the first occurrence of 'J' in the column. It's is not, in my opinion, what you want.

Here is what I understand of your table:

You have a list of acronyms, all repeated several times in column B, from B2.

Next to each initial, in column C, is an item associated with this individual.

For each trip, you want to generate a list of all items related to that person.

This seems doable. Assuming that the elements are distributed between four individuals, 300 lines would mean an average 75 per person elements.

Here is an example using fewer lines (so it fits on the screen). I also placed the initials in column A and the elements in column B, to reduce the space required for the images. Double click to zoom.

Table 1, the left is the data table and did most of the calculations.

The initials are in column A, the elements in column B.

Columns C, D, E and F are used to construct the list for each individual, using the formula below.

Note that the table contains 2 lines header and that the cells of the row 2 are empty. This allows labeling the columns in row 1 and using the same formula in all cells below these lines, which allows to automatically fill the formula in the new lines when they are added to the bottom of the table.

A single formula, entered in cell C3, then right to full F3 and up to the last line in the four columns in the table.

C3: = C2 & IF ($A = CAN$ 1, $B & ",","")

The formula gets the contents of the cell above (C2), then IF the first column A corresponds to the first tier 1 of the column that contains the formula, adds the contents of 'the line' in column B, followed by a comma and a space, OR the initials do not match, which adds a string NULL ("").

Table 2 shows a formula, entered in cell B2, and then filled up to B5.

B2: INDEX (table 1: $A:$ F, LINES (1::A, table headers), MATCH ($A2, table 1: $1: $1.0))

The INDEX function returns the contents of the cell to a range of cells, located at the intersection of the row and column specified by the row index and column index.

The range of cells is columns A to F of table 1 (ie. table 1)

The row index is LINES (1::A, table headers) that always points to the last row of the table.

The column index ($A2, table 1: $1: $1.0). This returns the position in the list of values in line 1 of table 1 of the initial report in A2 "this table." "A" is the third element in this list, until the column index points to the third column, column C.

The index function returns the string of the cell in the last row in column C of table 1.

Kind regards

Barry

Tags: iWork

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