Question of VARRAY

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• PLSQL - varray in doubt/question varray

  Hello
  
  My version of Oracle:
  Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64 bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  "CORE 11.2.0.1.0 Production."
  AMT for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  Please find the code below:
  --------------------------------------------------------------------------------------------------------------------------------
  create or replace
  procedure p_varray_test
  AS
  t_va_emp_group_sal type is varray (10) number (9);
  
  t_2d_VA type is varray (2) of t_va_emp_group_sal;
  L2DVAv_test t_2d_VA: = t_2d_VA (t_va_emp_group_sal (11,12,13,14,15,16,17,18,19));
  
  Start
  L2DVAv_test.extend;
  L2DVAv_test (2) (1): = 21;
  dbms_output.put_line (L2DVAv_test (2) (1));
  end;
  --------------------------------------------------------------------------------------------------------------------------------
  
  its getting compiled but when I try to run it, I get the following error:
  ORA-06532: index outside the boundary
  
  Please help me with this problem.
  
  Now, if I change the code something like this:
  --------------------------------------------------------------------------------------------------------------------------------
  create or replace
  procedure p_varray_test
  AS
  t_va_emp_group_sal type is varray (10) number (9);
  
  t_2d_VA type is varray (2) of t_va_emp_group_sal;
  L2DVAv_test t_2d_VA: = t_2d_VA (t_va_emp_group_sal (11,12,13,14,15,16,17,18,19), t_va_emp_group_sal (11,12,13,14,15,16,17,18,19));
  
  Start
  L2DVAv_test.extend;
  L2DVAv_test (2) (1): = 21;
  dbms_output.put_line (L2DVAv_test (2) (1));
  end;
  --------------------------------------------------------------------------------------------------------------------------------
  This code works perfectly fine for me, but I'd like to understand why I get the above error.
  
  Concerning
  Rahul

  First of all let's start your second example (work):

  L2DVAv_test t_2d_VA := t_2d_VA(t_va_emp_group_sal(11,12,13,14,15,16,17,18,19),t_va_emp_group_sal(11,12,13,14,15,16,17,18,19));
  

  Now you have an "outside" varray initialized with two elements. Each of these two elements are initialized with an 'inner' varray each with 9 elements.

  L2DVAv_test.extend;
  

  The varray "outside" has now been extended with a third element. This third element is not yet initialized.

  L2DVAv_test(2)(1) := 21;
  

  The value of the first element of the varray 'internal' in the second element of the 'outside' varray is changed to 21.
  So "11" in your second term t_va_emp_group_sal is changed to 21.

  ----------------------

  Now your first example:

  L2DVAv_test t_2d_VA := t_2d_VA(t_va_emp_group_sal(11,12,13,14,15,16,17,18,19));
  

  Now you have an "outside" varray initialized with a single element. This single element is initialized with an 'internal' varray each with 9 elements.

  L2DVAv_test.extend;
  

  The varray "outside" has now been extended with a second element. This second component is not yet initialized.

  L2DVAv_test(2)(1) := 21;
  

  L2DVAv_test (2) you will get the second element of the varray 'outside '.
  But this element is not yet initialized, then you cannot reference "the first element of the inner varray" here.
  But it should work after your extension:

  L2DVAv_test(2) := t_va_emp_group_sal(21);
  

  Now, you initialize an 'internal' varray with a single element and affecting who recently initialized varray to become the second element of the varray 'outside '.

• Retrieve by using the TYPE attribute of the element type VArray

  I want to recover the varray stores through the type attribute type or no matter WHAT work-around.
  
  for example, our type is defined as SUCH CREATE "READS" AS VARRAY (200) OF NUMBER (21: 6); (reading is with elements of number type varray (21.6))
  
  READING is a column in a table of INTERVALS. INTERVALS is a central table and we batch on the INTERVALS that are running sql store procedures. In the stored procedure we have hardcoded the declarations of variables mapping to the element type of type VArray of READING which is NUMBER (21: 6); for example, the stored procedure has declarations of variables such as
  
  NUMBER OF CONSUMPTION (21: 6);
  
  each Varray definition is changed or varray is deleted and recreated with precision and of different size, ex on number (21.6) past to number (25.9), we need declarations of variables to change in our store to batch process procedures. I am looking for is CONSUMPTION variable declaration, refer to item VArray type. I want something like that
  
  INTERVALS OF CONSUMPTION. READINGS. COLUMN_TYPE % TYPE; (I want something like this, identify the type of the items stored by varray)

  No problem. Discussions forum flags viewers have read so you don't need to keep posting.

  In response to your question I don't know of a direct method, but it doesn't seem to be syntactically possible to anchor via a SLIDER instead diverted the road % TYPE and % ROWTYPE.

  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bit Production
  With the Partitioning, OLAP, Data Mining and Real Application Testing options
  
  SQL> CREATE OR REPLACE TYPE type_name
    2  AS
    3     VARRAY (200) OF VARCHAR2 (3);
    4  /
  
  Type created.
  
  SQL>
  SQL> DECLARE
    2     CURSOR cursor_name
    3     IS
    4        SELECT COLUMN_VALUE column_name
    5        FROM   TABLE (type_name ());
    6
    7     record_name cursor_name%ROWTYPE;
    8
    9     variable_name record_name.column_name%TYPE := 'AAAA';
   10  BEGIN
   11     NULL;
   12  END;
   13  /
  DECLARE
  *
  ERROR at line 1:
  ORA-06502: PL/SQL: numeric or value error: character string buffer too small
  ORA-06512: at line 9
  
  SQL>
  

  However, if you try this with a digital item type precision and scale are not kept and you will end up with a NUMBER.

  I said just a subtype corresponding to the same place, declaring variables, on this basis and do with it.

• can we use rowtype in varray?

  I try to use a rowtype as content of the varray, I go for collecting information of employees collect table using the majority and trying to assign to a variable created by the data varray type, but I get this error?
  
  error:
  ORA-06532: index outside the boundary
  
  Code:
  
  declare
  abc type is varray (400) employees % rowtype;
  v_emp abc;
  number x: = 1;
  Start
  v_emp:=ABC();
  Select * bulk collect into v_emp of employees;
  loop
  v_emp.extend ();
  dbms_output.put_line (v_emp (x) .employee_id);
  x: = v_emp. Next (x);
  output when x is null;
  end loop;
  end;
  /
  
  help me with this solution to the question above?
  
  also tell me
  1. the question of whether we can able to store several values of the column to a variable using varray

  declare
  abc type is varray (400) employees % rowtype;
  v_emp abc;
  number x: = 1;
  Start
  v_emp:=ABC();
  Select * bulk collect into v_emp of employees where rownum<>
  for x in 1.v_emp.count
  loop
  dbms_output.put_line (v_emp (x). (Name)
  end loop;
  end;
  /

• VARRAY

  HII all
  
  I created a varray like this
  
  SQL > desc v_array
  v_array VARRAY (5) OF VARCHAR2 (20)
  
  
  n, then I created a table
  SQL > desc vir
  Name Null? Type
  ----------------------------------------- -------- ---------------------
  
  NO NUMBER OF
  NAME V_ARRAY
  
  
  given that v_array column
  
  My question is that I thought that I could insert only 5 a particular name field name values have number = 1 (say) but I keep on inserting n he crossed the limit of 5 I don't know ny hpnd y 1 explain
  
  saying that I was
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  Insert in the vir values (1, V_ARRAY ('a '));
  
  
  as I thought that I could insert only 5 values but I can easily insert these values in this
  
  NY bdy can it be this hpnd

  SQL> INSERT INTO test_varray VALUES(2,v_array('P','Q','R','S','T'));
  
  1 row created.
  
  SQL> SELECT * FROM test_varray;
  
       EMPNO
  ----------
  ENAME
  --------------------------------------------------------------------------------
           2
  V_ARRAY('P', 'Q', 'R', 'S', 'T')
  
  SQL> /* So it is empno 2 with 5 names in the array. One row in the table*/
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> INSERT INTO test_varray VALUES(1,v_array('A'));
  
  1 row created.
  
  SQL> SELECT * FROM test_varray;
  
       EMPNO
  ----------
  ENAME
  --------------------------------------------------------------------------------
           2
  V_ARRAY('P', 'Q', 'R', 'S', 'T')
  
           1
  V_ARRAY('A')
  
           1
  V_ARRAY('A')
  
       EMPNO
  ----------
  ENAME
  --------------------------------------------------------------------------------
           1
  V_ARRAY('A')
  
           1
  V_ARRAY('A')
  
           1
  V_ARRAY('A')
  
       EMPNO
  ----------
  ENAME
  --------------------------------------------------------------------------------
           1
  V_ARRAY('A')
  
  7 rows selected.
  
  SQL> /* So it is 6 rows with empno as 1 and only one item 'A' in the array in each row*/
  SQL> 
  

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  Hi JohnP007,

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  If you forgot the answers to your questions of security of Apple ID - Apple Support

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  Hello

  You will need to contact the Apple Support.

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  I accidentally deleted one of my iPhone SMS 6 Plus.  They always show on my iMac and iPad but I fear when an AutoSave occurs, it will back up the iPhone and remove them to two other devices. What will happen?  I use iCloud if that makes a difference.

  Hi melissahh625,

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