Queue time UCCX 9 Script'

Similar Questions

• Is it possible to control the opening and the closing time of a script by an officer being connected?

  Hi Experts,

  We currently use scripts UCCX 7.0 with opening and closing hours of CSQ controlled via defined under the time of day in the script.

  I would like to know if it is possible to control the opening and the closing time of a script based on an agent is connected or not?

  So basically, the office is deemed open when an agent is connected and deemed closed when there is no connected agents regardless of the time.

  If possible, can you kindly point me in the right sense of how implement this corresponds to the script.

  Kind regards

  THERE.

  Hello

  Sure... in short:

  -Use a step "to obtain the statistical report" to see how many officers is connected, or "ready" (your choice) and store that in an int variable

  -If this > 0 then 'goto' your behavior variable open.

  -If it is 0 or - 1, then goto closed.

  Aaron

• (Reference #7231113) Loop to control phase a queue time

  (Reference #7231113) Loop to control phase a queue time

  
  

• Database queue time calculation.

  Hi, I use 10.2.0.4.0 oracle version.
  
  I need to find the queue time total for each day for each WAIT_CLASS and need to trace trends in the last days. I use the application below to get the details, but my results do not match with the ones I get in the AWR report. In my daily report AWR, "USER i/o" is coming in higher class waiting times, where as in my query, I get 'Application' on the highest expectation section. Total wait time is also different. Can you please help me to understand, what don't understand me in the query?
  

  SELECT  wait_class, 
       TO_CHAR (MIN (s.end_interval_time), 'DD-MON-YYYY DY HH24:MI')
           sample_end,
          SUM (WAIT_TIME + time_waited)  waittime
   FROM dba_hist_active_sess_history q, dba_hist_snapshot s
  WHERE   s.snap_id = q.snap_id
        AND s.dbid = q.dbid
        AND s.instance_number = q.instance_number
        AND s.end_interval_time >=
               TO_DATE (TRIM ('16-Oct-2012 '), 'dd-mon-yyyy hh24:mi:ss')
        AND s.begin_interval_time <=
               TO_DATE (TRIM ('18-nov-2012 '), 'dd-mon-yyyy hh24:mi:ss')
       AND wait_class in ('User I/O','System I/O','Concurrency','Commit','Other','Configuration','Network','Application','Administrative')
   GROUP BY trunc(s.end_interval_time),wait_class
  ORDER BY trunc(s.end_interval_time),waittime desc

  SELECT Trunc(end_interval_time),
         wait_class,
         SUM(time_waited)
  FROM   dba_hist_service_wait_class
         join dba_hist_snapshot USING(snap_id)
  GROUP  BY Trunc(end_interval_time),
            wait_class
  ORDER  BY Trunc(end_interval_time),
            wait_class; 
  

  Published by: JohnWatson on 7 November 2012 16:34
  Formatting.

• Queue time Total STATSPACK

  HI -.
  with the keys v 9.2
  
  I wonder about the queue time Total (s) waiting for the Top 5 list of events.
  I took a snapshot of 10.55 (min) but time to other (s) exceeds this, so I'm clearly interpreted something wrong:
  

  Top 5 Timed Events
  ~~~~~~~~~~~~~~~~~~                                                     % Total
  Event                                               Waits    Time (s) Ela Time
  -------------------------------------------- ------------ ----------- --------
  db file scattered read                            587,895       1,464    37.24
  CPU time                                                        1,205    30.66
  SQL*Net message from dblink                        22,597         609    15.49
  db file sequential read                           478,006         554    14.11
  log file parallel write                             6,335          28      .72
            -------------------------------------------------------------

  For example, reading of files scattered db is 1 464 (s) that is more than the 10.55 (min) of the snapshot.
  
  How to establish a correlation between this time in the clock?
  My hypothesis is that several sessions are added, and this number may exceed the time of the snapshot?
  
  Published by: stg on October 17, 2008 09:50

  rocr wrote:
  the time is per processor, so if you have 8 processors and the clock of the report time is 6 minutes but 5 CPU use 3 minutes of treatment each then the total time is 15 minutes.

  rocr,

  You consider the "CPU time" component only.
  The timeout can be much more than "snapshot interval * CPU_count". "" It can be bigger than "snapshot interval * number of sessions'." "

  For example:
  I lock a table in exclusive mode for 15 minutes.
  100 other users try to update this table and must wait to release my lock.

  Elapsed time = 15 minutes
  Wait time = 100 * 15 minutes = 1 500 minutes.

  Concerning
  Jonathan Lewis
  http://jonathanlewis.WordPress.com
  http://www.jlcomp.demon.co.UK

  "The greatest enemy of knowledge is not ignorance, it is the illusion of knowledge." Stephen Hawking.

• How to launch two executable files (excel file & a .exe file) at the same time using VB Script?

  Hello

  I need vb Script code to run exe files at the same time.

  I hope someone will help me!

  This issue is beyond the scope of this site and must be placed on Technet or MSDN
  http://social.technet.Microsoft.com/forums/en-us/home

  http://social.msdn.Microsoft.com/forums/en-us/home

• UCCX. Script editor. Conversion of the string.

  Colleagues, good day!

  Please tell me such a simple thing: how, in the script editor UCCX convert a string like:

  "User [type = Call Manager user, id = aa.ivanov, authenticated = true].

  in the following string:

  'aa.ivanov '.

  I'm not familiar with the Java programming language, and I have some difficulty with this.

  Thanks in advance!

  Hello

  You can use the step to read the information of the user. Map the identifier a string variable field.

  G.

• Launch of the VI Client on XP SP3 after VMware data Recovery installation call 10 times a Microsoft Script Editor!

  Hello

  I give a try to VMware Data Recovery. So I installed the plugin on my XP SP3 computer.

  But since then, everytime I lauch VI client to step «Discover plugins...» ', it asks me to choose a debugger (with a unique choice of Microsoft Script Editor) and I must decline 10 times before it will work eventually. VMware support told me to install or reinstall my computer, but I'd rather have it run without a reinstall.

  Someone at - it an idea on how to solve this problem?

  Any help will be greatly appreciated.

  PJ: the window first, and what I get, if I click on 'Yes' (yes).

  Hello once more,.

  I got a solution for this, and it works with me;

  • Make a right click my computer / properties.

  • Click on Advanced tab

  • Under performance, click settings

  • Click the data execution prevention tab

  • Select turn on DEP for Windows programs and services only

  • Restart Windows

  Also, this will help you;

  • Internet Explorer / Tools

  • Internet Options

  • Advanced

  • • Disable Script debugging (Internet Explorer)

    • Disable Script debugging (other)

  Best regards

  Hussain Al Sayed

  If you find this information useful, please give points to "correct" or "useful".

• How can I control whether or not an audio queues times at the start of a slide?

  I am putting together a course and I have an audio welcome that plays automatically when the user starts the course. Since this slide contains a list of the modules that will be ongoing, I would also like to the use it as a navigation option - click on the link 'Menu' on any slide and return to this page.

  The problem: whenever the page is hit the audio playback.

  The question: How can I set the audio to only run the first time the page is entered but not yet?

  I created a variable called "PlayWelcomeAudio" and set it on 'Y' at the beginning, can have an advanced action script that modifies the variable "N" when selected (progress throughout are linear, so there is only one option available to the user at this point.) By clicking on this link opens the next page and sets the "PlayWelcomeAudio" "N".

  I see that the variable has been set correctly (when I start it up is "O" and when I come back, it's "N"), but I don't see any place where I can put the audio file so it does not play.

  I tried setting on '1' cpCmndMute but that has not worked because it apparently is a global setting and I don't no audio playing anywhere after that.

  I don't have to pause the timeline or something like that. I just want the audio to play first, but not the second and the following page is hit.

  Thoughts? Suggestions?

  Thank you.

  Michael

  Set your audio welcome to an object that is not seen (e.g. a highlight area set to 0%) and use your stocks advanced and variable to HIDE this object ON SLIDE ENTER if the user comes back in the same Menu slide at a later stage in the course module.

  This should mean that the first time that the user gets to this slide, the audio will play.  But every subsequent hour, they come back on this slide, the object will be hidden immediately on entering the slide, which means that the audion does not play and sees all users are the menu options.

  Your alternative strategy would be to have two slides that look almost the same.  The first has the audio, and the other does not.  Your TOC for Menu item and all other links in the project that point to the Menu, go to the second slide without audio.  The user no longer wise will also be long as you train to navigation.

• How to create queues for JMS using Scripts

  Hi all
  
  I want to create the JMS queue in weblogic server 8.1 running scripts.
  Can someone give me scripts and how to run the scripts...
  
  I have the WLshell scripts to create the JNDI and JMS queues, but I don't know how to run the scripts.
  Please help me on the same.
  
  Thank you
  Amandine

  http://eDOCS.BEA.com/WLS/docs91/config_scripting/using_WLST.html#1078952

• a queue time

  Hello, I have a code in labview that generates a signal like this:

  

  and I would like to stop the execution of the code when the execution time is equal to the duration of settling of the signal, is there a way to do this?

  I need a command that calculates this running-in of the signal that I'm generating

  Thank you

  
  

• Movie offer, before their download queue time

  The waiting time for movies free offer to download

  Contact your local Sony

  http://www.sonymobile.com/global-en/support/contact-us/

• I tried to write code to a timer in action script 3... I have the...

  I wrote this code and I don't know how to finish it... any help would be great.

  var targetDate:Date = new Date (2012, 3, 5);

  addEventListener (Event.ENTER_FRAME, loop);

  function loop(e:Event):void

  {

  var nowDate:Date = new Date (2012,00,24);

  Ms: Number var = targetDate.getTime () - nowDate.getTime ();

  var sec: Number = Math.floor(6220800000/1000);

  var min:Number = Math.floor(6220800/60);

  var hr:Number = Math.floor(103680/60);

  var day: Number = Math.floor(4320/24);

  s = s % 60;

  min = min % 60;

  HR = % 24 hr;

  daytxt. Text = day.toString ();

  hrtxt. Text = (< 10 hr)? "0" + hr.toString (): hr.toString (); "."

  mintxt. Text = (< 10 min)? "0" + min.toString (): min.toString (); "."

  sectxt. Text = (s < 10)? "0" + sec.toString (): sec.toString (); "."

  }

  :

  var targetDate:Date = new Date (2012, 3, 5);

  var s:Number = (targetDate.getTime () - Date () .getTime (new)) / 1000;

  var t:Timer = new Timer (1000,0);

  t.addEventListener (TimerEvent.TIMER, loop);

  t.Start ();

  function loop(e:Event):void {}

  s-- ;

  var day: Number = Math.floor (s /(60*60*24));

  var hr:Number = Math.floor (s /(60*60)-day * 24);

  var min:Number = Math.floor(s/60-hr*60-day*24*60);

  var sec: Number = Math.floor(s-min*60-hr*60*60-day*24*60*60);

  your_tf. Text = formatF (day) + ":" + formatF (hr) + ":" + formatF (min) + ":" + formatF (sec);

  }

  function formatF(n:Number):String {}

  var s:String = n.toString ();

  While (s.length<>

  s = « 0 » + s ;

  }

  return s;

  }

• JS CS3: Help reduce the execution time of my script

  Hello

  We have developed a script to find the words/characters similar to the beginning/end of continuous lines 3 or more. The script was developed by following the steps:

  1. get all the lines of the document;

  2. get the first 2 characters of the first line and to compare with the first 2 characters of the two lines.

  3. If the matches, then don't give a no pause after the word to flow.

  The same procedure to search for characters from end of lines.

  Our documents with more than 300 pages, the script runs too long (about 15 minutes) per document.

  Might suggest to shorten the script running?

  My sript base is:

  for (k = 0; k < myStory.paragraphs.item (i).lines.length; k ++) {}

  var myParaText = myStory.paragraphs.item (i);

  var myChar2Fa = myParaText.lines [k].characters.itemByRange (0.1) .texts [0] .silence;
  var myChar2Fb = myParaText.lines [k + 1].characters.itemByRange (0.1) .texts [0] .silence;
  var myChar2Fc = myParaText.lines [k + 2].characters.itemByRange (0.1) .texts [0] .silence;

  If (myChar2Fa == myChar2Fb & & myChar2Fa == myChar2Fc) {}
  myParaText.lines [k + 2] .characters [-1] .noBreak = true;
  }

  Please suggest.

  concerning

  Lionel Messi

  Every interaction with the costs of model object - in this case, request ID paragraphs.item (i) .line, itemByrange(), etc. Avoid this problem by storing as much as possible directly referred to in variables.

  Every interaction with the text of the document itself costs too - you will see that the script runs a lot faster if you only account the number of occurrences. (But this cannot be avoided).

  That said, your way to recover the first 2 characters per line is rather clumsy... My version still takes the odd minute or two, for a 300-page test document, but I think it's mainly because ID must re - flow each paragraph that it changes.

  myStory = app.selection[0].parentStory;
  ln = myStory.lines;
  n_ln = ln.length;
  for (i=0; i 1 &&
    ln[i].contents.substring(0,2) == ln[i+1].contents.substring(0,2) &&
    ln[i].contents.substring(0,2) == ln[i+2].contents.substring(0,2))
   {
    ln[i+2].characters[-1].noBreak=true;
   }
  }
  

  I am not convinced that is what you intend: avoiding three consecutive lines to begin with the same two characters. First, of course you will have to run again, as reinvesting the text can move another word on the front of the line with these same characters.

  Second:-[1] is a special index in InDesign. It does not point to the point before the current (as it would if - 1 was treated the same as 0, 1, and 100), but instead it counts backward from the end of the indexed item - in this case, No Break is applied to the last character of line 3. I bet you have to apply to the last character in the 2nd line (which, if so, is easy fixed).

• Queue time Long in Windows Explorer

  I did an upgrade from Vista to Win 7 Home Premium 32 bit.

  Everytime I open windows Explorer and go to any folder that has a large number of files it contains, the address bar of windows explore turns into a bar green thermometer that takes forever to fill. Then, if you want to sort the results of this long waiting to something as updated or something, it does all of the process even more.

  Is there a way to disable this painful process or speed it up significantly?

  Thanks for your help.

  Hi dblbogey1,

  Thank you for visiting Microsoft Answers.

  I have a few steps that might help you solve the problem.

  1 put the computer to boot and check if the problem persists.

  2. scan your computer of viruses or malware.

  Run Analyzer online to check any malware or virus activity. Link below will help you launch the free scan on the computer.

  http://OneCare.live.com/site/en-us/default.htm

  To perform a clean boot on a computer that is running Windows Vista, follow these steps.

  1. click on Start, type msconfig in the Search box and press ENTER. If you are prompted for an administrator password or a confirmation, type the password, or click continue.

  2. in the general tab, click Selective startup.

  3. under Selective startup, clear the Load Startup items check box.

  4. click on the Services tab, select the hide all Microsoft Services check box, and then click disable all.

  5. click on OK.

  6. When you are prompted, click restart.

  7. after the computer starts, check if the problem persists.

  If not, then follow the steps mentioned in the article: http://support.microsoft.com/kb/331796

  To restore your computer to a Normal startup mode, follow these steps.

  In the box to start the search , click Start .

  1. type msconfigand press ENTER. If you are prompted for an administrator password or a confirmation, type the password, or click continue.

  2. click on the general tab.

  3. click on Normal Startup - load all drivers of devices and services, and then click OK.

  4. When you are prompted, click restart to restart the computer.

  Swati K - Microsoft support technician

  Visit our Microsoft answers feedback Forum and let us know what you think.