Random generator No.

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• draw the histogram of the random generator of > > >

  Hello

  I have a bulit a random generator by using + 1 D Cellular Autómata LFSR

  I need to draw the histogram of the system to check the shape of the distribution

  I have the vision of labview

  help me draw

  I thank you in advace

  concerning

  Mathematics-> probability and statistics, below a histogram express vi that will help you.

  

• Randomly generate the special characters

  I want to generate random password which should include at least one special character that could be any special character except @. dbms_random. String ('p', 1) will give 1 printable character that could be all in uppercase or lowercase, or any numeric value too. But how can I generate just 1 special character (with the exception of the @)?
  
  
  Thank you
  
  Published by: user5406804 on November 4, 2009 05:50

  Hello

  Welcome to the forum!

  You can do something like this:

  SELECT     SUBSTR ( '!#$%^*:;,.'               -- list all special characters here
                 , dbms_random.value (1, 11)     -- 11 = 1 + number of special characters
              , 1
              )     AS special_char
  FROM     scott.emp
  ;
  

• Number of random generator help

  I created a generator of random numbers with this code. The idea is that a number is introduced into the EntryText and a random number is chosen between 1 and the value of EntryText.
  
  "" ResponseString =:
  TempString: = LowerCase (EntryText)
  ResponseString: = (number: = Random (1, TempString, 1)) ^ return
  
  Is it possible that I can improve it so that:
  a. once a number has been selected, it will not take again?
  b. instead of display an imbue at one time, a whole list of numbers appears in the range between 1 and the value of EntryText. For example, if the value of EntryText was 5, the list might be:
  3
  1
  4
  5
  2
  

  Given that the space varies in fact (i.e. for a given result, there may be
  groups of different sizes), it is probably better to specify the number of
  groups instead, then maybe something like:

  TempString: = "15".
  numgroups: = 5

  t: = Number (TempString)
  [randomlist: =]
  Repeat with j: = 1 to t
  AddLinear (randomlist, j, Random(1,j,1))
  end repeat

  "" ResponseString =:
  a: = 0
  b: = t
  Repeat with j: = 1 to t
  ResponseString: = ResponseString ^ randomlist [j]
  a: = a + numgroups
  If a > = b then
  ResponseString: = ResponseString ^ return
  b: = b + t
  on the other
  "" ResponseString: = ResponseString ^ ' "
  end if
  end repeat

  Chris Forecast

• We can implement random generator lv in hardware?

  Salvation or

  I've been using the lv randomly in my project and now I want to set up my project in hardware

  can I implement this Randomizer LV in the material?

  If not then why?

  Please I need some details if you can

  Best regards

  Magnin

  The random numbers function is not available on FPGA. Good algorithms for random generation numbers are complex. I guess that the LabVIEW function calls one or more functions in the operating system that are not available on FPGA. Also the output random number is a floating-point, which was not taken in charge on FPGA, until recently (and I do know that if it is fully supported now, I have not yet tried).

• Randomly generate movieClips from the library onto the stage

  Hello

  I'm calling the objects from the library for a collection set.

  Major problems with how best to attribute the good and bad objects update later a score.

  Can anyone help me how can I first assign the clips in the library in an array of good and bad and then after randomally fill the stage with them.

  Concerning

  James

  see you never fake in your output panel, when using:

  public void placeWords() {}

  random location

  var x: Number = Math.floor (Math.random () * mapRect.width) + mapRect.x;

  var y: Number = Math.floor (Math.random () * mapRect.height) + mapRect.y;

  check all blocks to see if it's over everything

  var isOnBlock:Boolean = false;

  for (var j: int = 0; j

  If (blocks [j].hitTestPoint(x+gamesprite.x,y+gamesprite.y)) {}

  isOnBlock = true;

  break;

  }

  }

  not on everything, so use location

  trace (isOnBlock);

  If (! isOnBlock)

  {

  var goodObjects:Array = ["WordObject1"];

  var badObjects:Array = ["WordObject2"];

  If (Math.Random)<>

  {

  var r: int = Math.floor (Math.random () * goodObjects.length);

  var classRef: Class = getDefinitionByName (goodObjects [r]) in class;

  var newObject:MovieClip = new classRef();

  newObject.typestr = "good";

  } else

  {

  r = Math.floor (Math.random () * badObjects.length);

  classRef = getDefinitionByName(badObjects[r]) in class;

  newObject = new classRef();

  newObject.typestr = "bad";

  }

  gamesprite.addChild (newObject);

  newObject.x = Math.floor (Math.random () * stage.stageWidth);

  newObject.y = Math.floor (Math.random () * stage.stageHeight);

  break;

  }

  }

• slide show code generating random images with clickable links

  I make a slide show with images that occur randomly wch hav clickable links, OK it works but sometimes, the transition is very fast instead of the 8 s interval I expected, when I discovered the exit trace(), I noticed that sometimes the timer is triggered two times or more at the same time... my code is below... What perhaps may cause well u want to help

  I have 21 pictures with 21 images

  Import fl.transitions.Tween;

  Fl.transitions.easing import. *;

  Import fl.transitions.TweenEvent;

  import flash.events.MouseEvent;

  Stop();   slide stops

  var total_images:Number = 21;

  var my_playback_counter:Number = 0;

  showslide();     call to the showslide function

  defination function with the timer event

  function showslide (): void {}

  var myTimer:Timer = new Timer (8000);

  myTimer.addEventListener (TimerEvent.TIMER, timerListener);

  myTimer.start ();

  }

  / * function timelistener

  After 8 s, meter reading in increments of 1.

  Then reset to 0 playbckcounter if it is equal to total images

  */

  function timerListener (e:TimerEvent): void {}

  my_playback_counter = my_playback_counter + 1;

  If (my_playback_counter == total_images) {}

  my_playback_counter = 0;

  }

  trace ("Timer is triggered"); trace when the timer goes off

  NextImage();

  }

  function NextImage (): void {}

  var pic_number:Number = 21;

  var randomframe:Number = Math.ceil (Math.random () * pic_number) ;// randomly generates betwwen number 1 and 5

  trace (randomframe);

  gotoAndStop (randomframe); display a random image

  }

  Button1.addEventListener (MouseEvent.CLICK, onMouseClickB1);

  function onMouseClickB1(e:MouseEvent):void {}

  var request: URLRequest = new URLRequest ("http://www.aginternetwork.org/en/");

  navigateToURL (request, "_blank");

  }

  new Tween(btn1,"alpha",None.easeOut,0,1,1,true);

  Each time the playhead returns to frame where this code is another instance of Timer will be created.  Try to put a conditional on the showslide function call so that he will not repeat...

  var showStarted:Boolean; by assigning not it is null or false

  {if(!showStarted)}

  showslide()

  showStarted = true; but once they assign remains true

  }

• Generate a random number with a decimal point

  I searched all over the internet and cannot find how to generate a random number that had a decimal.

  I'm trying to randomly generate numbers between 12.0 and 13.0.

  Here is my code... I know its bad because of Math.round and Math.random, but I can't seem to find something that deals with a decimal...

  addEventListener (Event.ENTER_FRAME, fl_EnterFrameHandler_1);

  function fl_EnterFrameHandler_1(event:Event):void
  {
  Volt.Text = Math.round (Math.random () * (1) + 12) m:System.NET.SocketAddress.ToString ();
  }

  Any suggestions?

  -Pat

  Try this,

  addEventListener(Event.ENTER_FRAME, fl_EnterFrameHandler_1);
  
  function fl_EnterFrameHandler_1(event:Event):void
  {
  
       var rndNum:Number = int(Math.random()*10)/10; // Generate random num with 1 decimal place
       var newVal:Number = newVal + 12;
       volt.text = newVal.toString();
  }
  

  If you want 2 decimal places then replace the 10 per 100.

• Keep suggesting to randomly connect credentials

  Hi all

  For some time (but definitely starting with one of the latest Safari, OS X, or the two major updates), whenever I can connect on any Safari Web site displays the user name field already filled in with a randomly generated user name. I always which will remove and type in my credentials (and, if they are saved, the password will automatically follow) but this has become a real nuisance. I searched this random username suggest Safari, which has remained the same over time, among those who are registered under Preferences > passwords, to make sure that I had never used the user/PW suggested on any Web site. But it is not found, and it's pretty clear that it's just something that Safari feels that it must offer whenever I connect. Again, this applies to all windows login on ALL Web sites. I imagine that this is linked to a function of bunch, but I couldn't find a solution myself.

  Is there a way to stop it?

  Thank you!

  Have you checked the Applications/Utilities/Keychain Access to see if the name of user and password is stored in memory?

• MacPrO _ randomly typing in capital letters...

  Help! My keyboard randomly generates capital letters. The keys are all move freely, no friction. Ideas?

  You have restarted your computer?

• Generation of random values

  There is a bug in the continuous Random.vi for the generation of random in a khi-two distribution and Chi-squared Centre-no? When I draw the histogram with high resolution (numerous ferries) successively the h does not vary around the theoretical value as expected for some values of x.

  I posted a note therebug.

  Here is a comparison between the use of tools OR against my own normal random generator (based on Box Muller). As you can see, NEITHER has much more noise with peaks that are always in the same place. That noise is NOT random!

  

• framed color box color changes randomly - with red, blue and yellow

  Hello

  I want the user to do something when the color box changes from black (ready) to green (together), then red, yellow or blue (go). The user wil know what colors come to them.

  The user will will push a specific sequence of buttons depending on the color.

  Success will push the sequence of buttons assigned to a specific color. There are 16 push buttons. (this is to recall and response time)

  In any case, I can write the program without problem.

  The user can test red (push a specific sequence of buttons according to red), then blue and yellow. I can get to repeat a color so they will make four tests.

  Sorry for being long-winded.

  My question is how I randomly generates a color to begin a trial.

  If this set of tests is unclear by the subject on go the color was presented randomly as a guest.

  Any help would be greatly appreciated!

  Thanking you in advance,

  NK

  If you have a fixed set of colors, put them in a table and generate a random number between 0 (Array Size-1) and an element of the matrix of the index. Multiply the random number (0-1), multiply by the rounded and maximum value at most closely to get your index.

  If you want to generate a truly random color, use the RGB color VI and wire 3 random numbers between 0 and 255 to generate a random red, green and blue component like this:

  

• How to create random file names

  I have a folder containing 600 JPEG files. I want to replace the current file with those randomly generated names. So instead of files names IMG_11.jpg, IMG_12.jpg, IMG_13.jpg, I don't want to see something like 342.jpg, 8.jpg 107.jpg.

  Could someone smart give me a code that would do this. I want to change ONLY the names of files in this folder.

  I need simple instructions and comprehensive on how to run the code, suitable for a young man is no longer in the brain.

  I DON'T want TO change the name of each file by hand. I CERTAINLY DON'T want TO cut-and - paste or other references to Movie Maker or any other manufacturer of trade show.

  Please read each question carefully before answering. I tried to ask before and gotten completely irrelevant responses that make me tired.

  Hi David,

  Thanks for posting the question in the Microsoft Community.

  Unfortunately, you will not be able to run a code to change the names of files in bulk. However, you can try to look for a third-party software that might help.

  Note: using third-party software or a link, including hardware drivers can cause serious problems that may prevent your computer from starting properly. Microsoft cannot guarantee that problems resulting from the use of third party software or link can be resolved. Using third-party software or a link is at your own risk.

  Thank you.

• JVM error 104 Eception: IllegalStateException - random usage

  HFM = new HorizontalFieldManager();

  Random generator = new Random();

  bF_ # = ButtonField< of="" said="">

  If (field is bf_rearrange)

  {

  hfm.deleteAll ();

  RND = generator.nextInt (5);

  previous int = 0;

  do

  {

  If (rnd == 0)

  {

  HFM. Add (bf_6);

  HFM. Add (bf_5);

  HFM. Add (bf_4);

  HFM. Add (bf_3);

  HFM. Add (bf_2);

  HFM. Add (bf_1);

  }

  another (rnd == 1)

  {

  HFM. Add (bf_1);

  HFM. Add (bf_2);

  HFM. Add (bf_3);

  HFM. Add (bf_4);

  HFM. Add (bf_5);

  HFM. Add (bf_6);

  }

  } While (rnd == previous);

  previous = rnd;

  }

  It is a small snipper of the code that caused the error, as I am creating an algorithm to completely randomize the order of the 6 numbers while removing and adding the horizontal buttons they represent.  Please let me know if anyone has a good algorithm for this operation. The fastest algorithm that I could do would be great series of nested loops, but I think that the hfm gives error so I won't attempt it until I know.  Thank you in advance.

  Problem solved, figured it got the random job well enough I'll show you how I did it.

  ElseIf (field == bf_rearrange)

  {

  Vector temp = new Vector();

  temp.addElement (bf_1.getLabel ());

  temp.addElement (bf_2.getLabel ());

  temp.addElement (bf_3.getLabel ());

  temp.addElement (bf_4.getLabel ());

  temp.addElement (bf_5.getLabel ());

  temp.addElement (bf_6.getLabel ());

  RND = generator.nextInt (5);

  If (rnd == 0)

  {

  bf_1.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  ElseIf (rnd == 1)

  {

  bf_1.setLabel ((String) temp.elementAt (1));

  temp.removeElementAt (1);

  }

  ElseIf (rnd == 2)

  {

  bf_1.setLabel ((String) temp.elementAt (2));

  temp.removeElementAt (2);

  }

  ElseIf (rnd == 3)

  {

  bf_1.setLabel ((String) temp.elementAt (3));

  temp.removeElementAt (3);

  }

  ElseIf (rnd == 4)

  {

  bf_1.setLabel ((String) temp.elementAt (4));

  temp.removeElementAt (4);

  }

  ElseIf (rnd == 5)

  {

  bf_1.setLabel ((String) temp.elementAt (5));

  temp.removeElementAt (5);

  }

  RND = generator.nextInt (4);

  If (rnd == 0)

  {

  bf_2.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  ElseIf (rnd == 1)

  {

  bf_2.setLabel ((String) temp.elementAt (1));

  temp.removeElementAt (1);

  }

  ElseIf (rnd == 2)

  {

  bf_2.setLabel ((String) temp.elementAt (2));

  temp.removeElementAt (2);

  }

  ElseIf (rnd == 3)

  {

  bf_2.setLabel ((String) temp.elementAt (3));

  temp.removeElementAt (3);

  }

  ElseIf (rnd == 4)

  {

  bf_2.setLabel ((String) temp.elementAt (4));

  temp.removeElementAt (4);

  }

  RND = generator.nextInt (3);

  If (rnd == 0)

  {

  bf_6.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  ElseIf (rnd == 1)

  {

  bf_6.setLabel ((String) temp.elementAt (1));

  temp.removeElementAt (1);

  }

  ElseIf (rnd == 2)

  {

  bf_6.setLabel ((String) temp.elementAt (2));

  temp.removeElementAt (2);

  }

  ElseIf (rnd == 3)

  {

  bf_6.setLabel ((String) temp.elementAt (3));

  temp.removeElementAt (3);

  }

  RND = generator.nextInt (2);

  If (rnd == 0)

  {

  bf_4.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  ElseIf (rnd == 1)

  {

  bf_4.setLabel ((String) temp.elementAt (1));

  temp.removeElementAt (1);

  }

  ElseIf (rnd == 2)

  {

  bf_4.setLabel ((String) temp.elementAt (2));

  temp.removeElementAt (2);

  }

  RND = generator.nextInt (1);

  If (rnd == 0)

  {

  bf_5.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  ElseIf (rnd == 1)

  {

  bf_5.setLabel ((String) temp.elementAt (1));

  temp.removeElementAt (1);

  }

  bf_3.setLabel ((String) temp.elementAt (0));

  temp.removeElementAt (0);

  }

  Huzzah! The captain we have lift, I noticed this page get a number of veiws during my efforts and my bad questions, I am purchase a web domain and set up a large number of my works, c#, java and blackberry free.  I will publish on this site page, if anyone wants to see which machine this part belongs.  This is my first BlackBerry app it's a game scramble I think naming words FUBAR.  We never learned of vectors of class CS but I don't see how they are very powerful when you use this type of algorithm.

• AS5300 connection with any random userid and password

  Hello

  A bit of an odd request, I know, but is it possible to get an AS5300 to enter a user name and password for dial access but to accept random data that are entered in these areas. This should allow any user to connect if they have a valid user name or password.

  I entered in what follows.

  AAA to local USERS & TUNNELS ppp authentication no

  If I use a local user name, it works very well but a random generates the following text.

  Harbour_Ex_as01 #.

  * Jun 16 02:45:39.092 TSB: % ISDN-6-CONNECT: Serial1:30 of the Interface is connected to n/a n/a

  * 02:45:58.661 June 16 TSB: % LINK-3-UPDOWN: Interface Async126, changed State to

  * Jun 16 02:45:58.661 EST: As126 PPP: treatment of connection as a dedicated line

  * Jun 16 02:46:00.429 EST: As126 PAP: I AUTH-REQ id 29 len 30 'richarddfsdfsdf '.

  * Jun 16 02:46:00.429 EST: As126 PAP: authenticate peer richarddfsdfsdf

  * 02:46:00.429 June 16 TSB: AAA: analyze name = Async126 BID type = 10 ATS = 126

  * Jun 16 02:46:00.429 TSB: AAA: name = Async126 flags = 0 x 11 type = 4 shelf = 0 = 0 = 0 = 126 = 0 channel port adapter slot

  * 02:46:00.429 June 16 TSB: AAA: analyze name = Serial1:30 BID type = 13 = - 1 ATS

  * 02:46:00.429 June 16 TSB: AAA: name = Serial1:30 flags = 0 x 51 type = 1 shelf = 0 = 0 = 0 = 1 = 30 channel port adapter slot

  * 02:46:00.429 June 16 TSB: AAA/MEMORY: create_user (0x6242F3E0) user = "richarddfsdfsdf" ruser = "port ="Async126"rem_addr =" async/08453500050 ' authen_type = service PAP = PPP priv = 1 ".

  * Jun 16 02:46:00.429 TSB: AAA/AUTHENTIC/START (116733842): port = list "Async126" = "USERS & TUNNELS" action = LOGIN service = PPP

  * 02:46:00.429 June 16 TSB: AAA/AUTHENTIC/START (116733842): found list USERS & TUNNELS

  * 02:46:00.429 June 16 TSB: AAA/AUTHENTIC/START (116733842): method = LOCAL

  * 02:46:00.429 June 16 TSB: AAA/AUTHENTIC (116733842): status = ERROR

  * 02:46:00.429 June 16 TSB: AAA/AUTHENTIC/START (116733842): method = NONE

  * 02:46:00.433 June 16 TSB: AAA/AUTHENTIC (116733842): status = PASS

  * Jun 16 02:46:00.433 EST: As126 PAP: O AUTH-NAK id 29 len 28 msg is '% authorization has failed."

  * 02:46:00.433 June 16 TSB: AAA/MEMORY: free_user (0x6242F3E0) user = "richarddfsdfsdf" ruser = "port ="Async126"rem_addr =" async/08453500050 ' authen_type = service PAP = PPP priv = 1 ".

  * 02:46:01.197 June 16 TSB: % ISDN-6-DISCONNECT: Interface Serial1:30 disconnected from the unknown, call lasted 22 seconds

  * 02:46:03.677 June 16 TSB: % LINK-5-CHANGED: Interface Async126, changed State to reset

  * 02:46:08.685 June 16 TSB: % LINK-3-UPDOWN: Interface Async126, changed State to down

  Any help much appreciated.

  Thank you

  Richard

  I see at least two ways to allow anyone on the 5300 router any username and/or password.

  The first and easiest is to remove the telephone line ppp authentication command. This will allow anyone to dial on the machine without checking the ID and password. I believe that this will allow them in without the router generates a demand for ID, but that wasn't a big problem because most of the time invites it is generated by the PC before dialing in any case. It may matter is the user using the terminal window after dial where the prompt IS generated by the router.

  The second and more complicated are based on the fact that there are several methods of authentication that can be specified for ppp, including Ganymede +, radius, local and no. You can configure the authentication of ppp with Ganymede + or RADIUS as the main method and 'none' as the backup and run the Ganymede + or RADIUS to a non-existent server. This would cause the 5300 attempt to authenticate on the Ganymede + or RADIUS and when that got no response, he would let the user. I can't guarantee that this would generate a command prompt, but the same remarks apply as in the previous paragraph on why he cannot question.