Random Number Generator, throwing error

Similar Questions

• How can I create a random number generator, protected by password and username?

  I have attached a VI that is a random number generator. I want to just be prompted for the name of user and password when I start this generator. There should be three names of users and passwords found in three different files. I would like to know how to link the code username/password for the code generator and how do the program to know that there are three txt files in my computer with usernames and passowrds.

  
  

• Smartphones from blackBerry Desktop Manager software - random number generator

  Hello

  I have a blackberry that I configured to synchronize with an outlook account. The other day when it is plugged, I received a message that pops up saying something about a "random number generator '. When I searched the problem of people said to uninstall/reinstall the Desktop Manager software with the latest version. So I downloaded the latest version of the software, and when I ran everything has been disabled. When I uninstall/reinstall the version that we used before the same thing, everything has been disabled. This could be the cause of this problem? I guess it must be a hardware problem.

  Thank you for your time.

  Reid

  Hi and welcome to the forums!

  I recommend you to perform the following procedure

  to ensure that you have removed all the system

  the files and registry entries made by previous installations.

  Make sure that all antivirus and firewalls are down when you install

  The other two links will help check connection problems.

  Bifocals

  Don't forget to adjust your thread.

  Put the check mark in the green box containing your answer! Thank you

  Own installation procedure;

  http://www.BlackBerry.com/BTSC/search.do?cmd=displayKC&docType=kc&externalId=KB02206&sliceId=SAL_Pub...

  Assistance Fund

  http://www.BlackBerry.com/BTSC/search.do?cmd=displayKC&docType=kc&externalId=KB00125&sliceId=SAL_Pub...

  Troubleshooting USB connection:

  http://www.BlackBerry.com/BTSC/search.do?cmd=displayKC&docType=kc&externalId=KB02640&sliceId=SAL_Pub...

• Random number generator. Even and odd numbers

  I have a problem.

  I have a generator of random numbers, it goes from 0 to 20, I need to have two indicators, we show you how many numbers are pairs, and how much isn't.

  I tried to table D use the decimated 1, but as these numbers are random, it doesn´t works for me. I m new with LabView and I Don t know if there is another way to make it work, I need help, especially with a few examples.

  Thank you very much.

  
  

• How to generate a random number within a specified tolerance and control than tolerance.

  I am trying to simulate data without using a data acquisition device using a random number generator and I want to be able to control the "range" the random number generated well.  On the front panel, the user can enter a nominal number, and the random number generator would generate numbers more or less disponibles.003 this number nominal.  The data would be delayed on a chart.  Someone knows how to do this?  Or if it is still possible?

  Just for the sake of information, the random number is supposed to resemble thickness measures, that's why I want to simulate more and less disponibles.003 because the data might be thinner or thicker than the nominal value.

  Thanks in advance!

  Two ways of approaching the issue.  First of all, for even distribution, you can 'Roll the dice', which is the (0,1) random number function, multiply the result by 0.06 and then add Mean - 0.03 to center around average distribution.  If you simulate a real process, my initial guess would be that the results would follow a normal distribution.  In this case, you can use the VI of white noise Gaussian of the palette of generation of signals with a standard deviation of 0.015 if you wanted 0.03 to be the point of 2 sigma, then add average results.

• How to build a VI that generates a random number between 1 and 80... Help!

  Generate a VI that generates a random number between 1 and 80

  Divide the random number by a number specified in the front panel.

  If the number of seizures is zero, the VI program should light a LED in the face to indicate a divide by zero error.

  Hai edwardty2009,

  Welcome to the forum.

  Thanks for the congratulations.

  Your problem is solved? If so can you please mark as solution what post help better to solve your problem.

  Thank you

  Mathan

• How can I generate a single random number on a button for use in a VI?

  I'm creating a new VI and need a new random number every time that I hit a button... it will eventually be replaced by externally triggered en boolean, but for now, I would like to just press a button, get a new number, use this number, click the button, get a new number (previous deletion), etc etc.

  Thank you

  -Steve

  Just to add to what SAM has shown you can generate in a different ranges without limit it... It's just a very simple logic... Try this...

• Generating unique random number with a Boolean signal on an RT target

  Hello, this is my first time asking your question. I apologize if I post this question in the wrong Council.

  [What I'm trying to do]

  I am stable heating and cooling in an experimental space that I (with cRio9024).

  And I'm putting a different experimental condition in space based on the function 'random number '.

  'Different experimental conditions' sense different combinations of Tind, Twat_s and mdot (refer to the attached VI).

  For example, if I get the Boolean TRUE signal.

  I should have a set of [Tind, Twat_s, mdot] = [21,14,0.05], and IS this set of numbers until this Boolean signal goes to FALSE.

  And when the signal passes to the TRUE once again.

  I should have a different set of [Tind, Twat_s, mdot] = [24,16,0.15] for example.

  [I]

  Problem I am with my code is that,

  When the VI is running, the random number remains the same as the Boolean signal is set to TRUE.

  From what I tried so far for the last couple days, using 'the event structure' was the message more concerned that I found,

  However, LabView help tells me that "structure of the event" on the objectives of the RT do not support the events associated with the user interface such as the façade of VI or controls panels.

  I would therefore ask a quick help, since my knowledge of LabView is exhausted at this point.

  

  This is so the part where I want to generate random numbers, WHEN this structure case is TRUE.

  convert whole numbers, random numbers

  Use them as a table index,

  while I can choose conditions from radom to the given set of conditions.

  Once more, I want to do is,

  generate a SINGLE random number series when the structure above is TRUE.

  Hope I have developed quite clear.

  I'm appreciated for any kind of advice.

  Thank you!

  You just need to store the Boolean from the previous run. Then the logic would be (I'll call her Boolean previous B_prevand current boolean B):

  If B AND B_prev > don't generate new values

  otherwise if B > generate new values

  Edit: to store your Boolean value, you can use a feedback node, or a loop with N = 1 and a registry change.

• Error message: "the temp"e:\random number\cygwin\tmp\"directory is not a valid directory. Cannot install Visual C++ express 2010.

  Original title: cannot install visual c++ express 2010.

  When I ran vc_web.exe, I got this error message: "the temp"e:\random number\cygwin\tmp\"directory is not a valid directory. Implementation cannot continue. "Can help to solve this problem? Thank you.

  Hi moyeh,

  The question you have posted is better suited to the MSDN forums. You can ask your question in the help link.

  http://social.msdn.Microsoft.com/forums/en/Vsexpressvc/threads

  Hope the helps of information.
  Please post back and we do know.

• Generate a random number

  I have this function to generate a random number

  RandNum = genRand();

  public function genRand (): int
  {
  Return (Math.Random ());
  }

  but he seemed to generate the number is 0

  any1 have more luck with this?

  Hey,.

  According to the range of numbers you're trying to get it, you must either change the type returned or modfiy before he returned. What happens is the number that you generate is probably something like 0.9393 (example) and his cutting the comma because you return a value type int value (no decimals).

  try to modify the function to do this:

  public function genRand():int
          {
              return(Math.random() * 10);
          }
  

  and you will get a number from 0 to 10. If you want a number from 0 to 100, you can use 100 instead of ten, and so on. This will give you back not decimal numbers. If you want decimal numbers simply change the type of data returned to the number instead. hope that helps. Good luck!

• Need help with a JavaScript to generate random number

  Hello

  First things first. I don't know the JavaScript J.

  When I thought about a ready to use solution to generate a random number in Captivate, I found this on a forum of LinkedIn.

  (1) add a user to your project variable, called "NombrAl". Its value can be zero.

  (2) add a text caption with ' $$randomNumber$ $"inside, to check if your script works.

  (3) add a button to the slide. Give him one on success Action to run JavaScript. Clear the check box 'continue playing the Project '.

  (4) add the following text in the button Script_Window:

  var objCP = document. Captivate;

  var rand = 1 + Math.floor (Math.random () * 10);

  onButtonClick() {} function

  objCP.cpEISetValue ('NombrAl', rand);

  }

  onButtonClick();

  However, it is (as the poster in the forum warned) for 7 Captivate does not. Can someone please help?

  I am open to all other methods to achieve the same result.

  Thanks in advance,

  Anthony

  Hi Anthony,.

  During the test, make sure that you are testing from a web server where the web address starts with http or https.  When you set the captivate variable "NombrAl" try this instead:

  objCP.cpEISetValue ('m_VarHandle.randomNumber', rand);

  This will work for the SWF output.  If you want to work for the release of HTML5 and SWF, try this code:

  window.onButtonClick = function(){
            var rand = generateRandomNumber(1, 10);
            setCpVariable('randomNumber', rand);
  
  };
  
  window.generateRandomNumber = function(min, max){
            var randomNum = 0;
  
            if(!isNaN(parseFloat(min)) && !isNaN(parseFloat(max))){
                      min = Number(min);
                      max = Number(max);
                randomNum = Math.floor(Math.random() * (max - min + 1)) + min;
            }
  
            return randomNum;
  };
  
  window.setCpVariable = function (cpUserVariableName, variableValue) {
            /* Check for HTML5 vs. SWF output */
            if (typeof window.cp === 'undefined') {
                      /* We have SWF output, so Get the Captivate Object */
                      var objCp = document.getElementById('Captivate');
  
                      if (objCp && objCp.cpEISetValue) {
                                /* Set the Captivate User variable with the JavaScript variable, variableValue */
                                objCp.cpEISetValue('m_VarHandle.' + cpUserVariableName, variableValue);
                      }
            } else {
                      /* We have HTML5 output */
                      /*If variable does not exist off of the window object, then use the variables manager*/
                      if (typeof window[cpUserVariableName] === 'undefined') {
                                if (cp.vm && cp.vm.setVariableValue) {
                                          cp.vm.setVariableValue(cpUserVariableName, variableValue);
                                }
                      } else {
                                window[cpUserVariableName] = variableValue;
                      }
            }
  };
  
  window.onButtonClick();
  

  Don't forget to test this situation from a web server either local security prevents the javascript code for execution.

  Best,

  Jim Leichliter

• generate a random number between 1 and 10

  Dear All;
  
  I have an insert... Select and in one of the columns, I would like to generate a random number from 1 to 10, how is this possible. Thank you.

  Select round (dbms_random.value (1,10)) double;

  http://download.Oracle.com/docs/CD/B28359_01/AppDev.111/b28419/d_random.htm#CDEJAHCB

• Generate a random number with a decimal point

  I searched all over the internet and cannot find how to generate a random number that had a decimal.

  I'm trying to randomly generate numbers between 12.0 and 13.0.

  Here is my code... I know its bad because of Math.round and Math.random, but I can't seem to find something that deals with a decimal...

  addEventListener (Event.ENTER_FRAME, fl_EnterFrameHandler_1);

  function fl_EnterFrameHandler_1(event:Event):void
  {
  Volt.Text = Math.round (Math.random () * (1) + 12) m:System.NET.SocketAddress.ToString ();
  }

  Any suggestions?

  -Pat

  Try this,

  addEventListener(Event.ENTER_FRAME, fl_EnterFrameHandler_1);
  
  function fl_EnterFrameHandler_1(event:Event):void
  {
  
       var rndNum:Number = int(Math.random()*10)/10; // Generate random num with 1 decimal place
       var newVal:Number = newVal + 12;
       volt.text = newVal.toString();
  }
  

  If you want 2 decimal places then replace the 10 per 100.

• A random number in the range generator please help!

  Hey hope someone can help out me, im sure its a easy:

  var tstArray:Array = new Array (1,2,3);

  for (var a: uint = 0; has < tstArray.length; a ++)

  {

  var x: Number = Math.floor ((Math.random () * tstArray [a]));

  trace (x);

  tstArray.splice (a, 1);

  }

  I have this code but it does not exectply what I want it to do. Im trying to generate a random number of signle click between 1 and 3, and when all numbers have been used upwards, remove this click listener.

  If you can help it will be much appriciated

  THX pavel

  use:

  var fp1:farm_part1 = new farm_part1();

  and when you want to randomize a table use:

  var tstArray:Array = fp1.randomizeF ([1,2,3]);

  package

  {

  * / import flash.utils.Timer;

  import flash.display.Sprite;

  import flash.events.MouseEvent;

  import flash.display.MovieClip;

  import flash.events.Event;

  import flash.events. *;

  import flash.media.Sound;

  import flash.events.TimerEvent;

  import flash.media.SoundChannel;

  import flash.media.SoundTransform;*/

  public class farm_Part1

  {

  public void randomizeF(a:Array):Array

  {

  a.shuffle ();
  return a;
  }

  ///////////////////////////// change nothing below /////////////////////////////////////////

  function shuffle(a:Array)

  {

  var p:int;

  var t: *;

  var ivar:int;

  for (ivar =. Length-1; Ivar > = 0; Ivar-)

  {

  p = Math.Floor ((Ivar+1) * Math.Random ());

  t = a [ivar];

  a [ivar] = a [p];

  a [p] = t;

  }

  }

  } //randomAnimal

  } //class

  } //package

• generate a random number in a range of duplication no

  Good day people,

  I need help once again. I want to animate an image inside a movieclip with frame label animate1, animate2, animate3 and animate4.

  I managed to generate random numbers, but my concern is I want my animation not animate same image twice, here is my code.

  = main time line code =.

  function randRange(min:Number,_max:Number):Number {}
  Generate a number between and including min - max
  var randomNum:Number = Math.floor (Math.random () *(max-min)) + min;
  Return randomNum;
  }

  
  

  build table to hold the frame label names
  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";
  
  Get created random number
  var n: Number = plageAleatoire (0, frameArray.length);

  
  

  trace ("n": + n);

  
  

  Stop Frame label name
  This.img_ani.gotoAndStop (frameArray [n]);

  
  

  trace ("frameArray:" + frameArray [n])

  = label code and frame inside a clip with 4 frames containing different pictures =.

  as layer: stop();

  image tag: animate1, animate2, animate3, animate4

  Any help is greatly appreciated. Thanks in advance.

  It is not a routine of brewing, integrated, but there is a pretty standard shuffle function that was happening around...

  var frameArray:Array = new Array();
  frameArray [0] = "animate1";
  frameArray [1] = "animate2";
  frameArray [2] = "animate3";
  frameArray [3] = "animate4";

  function shuffle (a) {}
  var p;
  var t;
  Ivar var;
  for (ivar =. Length-1; Ivar > = 0; Ivar-) {}
  p = Math.Floor ((Ivar+1) * Math.Random ());
  t = a [ivar];
  a [ivar] = a [p];
  a [p] = t;
  }
  }

  trace (frameArray);  See the property before shuffle

  Use:
  Shuffle (frameArray);

  trace (frameArray);  Show after shuffle