Record in the table don't is not updated correctly after sail of detail page

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• How to find inserted last record in the table.

  Version: Oracle 10g
  
  I have a table called 'Manufacturing' and 3 columns as mfno, itemname, quantity.
  How to find inserted last record in the table 'manufacturing '.
  
  As I got to know that the Rowid is not a result perfect result. Please provide your inputs.

  user13416294 wrote:
  Version: Oracle 10g

  This is not a version. It's a product name. A version is 10.1.0.2 or 10.2.0.4, etc.

  I have a table called 'Manufacturing' and 3 columns as mfno, itemname, quantity.
  How to find inserted last record in the table 'manufacturing '.

  Not possible as your data model do not answer for him. As simple as that.

  If there is a need to determine an order or associate some time to an entity, then that should be part of the data model - and a relationship, or one or several attributes are necessary to represent this information. Your data model in this case is therefore unable to meet your requirements.

  If the requirements are valid, set the data model. In other words - your question has nothing to do with Oracle and nothing to do with the other pseudo columns in Oracle, the rowscn or the rowid. It is a question of pure data modeling. Nothing more.

• Not able to read the values in group by, when no records in the table

  Hi all, I have this query

  Select p.header_id,

  Type "some_constant."

  sum (nvl (p.total_amount, 0)) sum_of

  from table_name p

  P.header_id group

  When there is record in the table, it works fine, but I want to if there is no any folder that it returns as below,

  header_id type sum_of

  some_constant 0 0

  How to...?

  Help, please.

  Kind regards

  SELECT * FROM (select p.header_id,

  Type "some_constant."

  sum (nvl (p.total_amount, 0)) sum_of

  from table_name p

  P.header_id group

  UNION ALL

  SELECT 0,

  BOX WHEN (SELECT COUNT (*) FROM table_name) = 0 THEN type of 'some_constant',

  ANOTHER NULL

  END type as,

  0

  THE DOUBLE)

  WHERE type IS NOT NULL;
  

  Post edited by: 000000

• Create record in the Table of results gives error

  Hi all
  
  Update page there is a table of results with the Add button to create a new line.
  
  Everything by creating a new record on the table of results gives an error
  
  The attributes defined for AccessId in the view object xxlcupdvariablesvo1 failed
  
  I checked the EO and VO attributes, everything seems to be good.
  Updatable also has the value "Always".
  
  
  Still don't know why this error is coming.
  
  Please help resolve this error.
  
  
  Thank you
  SK

  SK

  Don't forget that your AO made correctly and you do your from VO of the two OS after this AO. If possible, allow Jdev to create your AO. Try to create is not in manuallly

  Hope it solves your problem

  Thank you
  AJ

• Name of the table list ALL_TABLES but not in TABS

  Hello
  
  I was trying to programatically check if a table is exist or not and insert the records if exist (via Java). I see a weired behaviour where when I check the metadata through my connection, I see this table_name in it (don't think there is an error in the logic), but when I try to insert a record after that, he lifts - java.sql.SQLException: ORA-00942: table or view does not exist.
  
  When I manually check the DB, I see this table to table ALL_TABLES but not in TABS (not sure what is the same difference between those two, and that is the right place to check), desc < table_name > is also a failure...
  
  I'm really confused if the table is exist or not...
  
  Any help is really appreciated.
  
  Thank you
  Rajiv

  SHOW USER
  Select owner, table_name from ALL_TABLES where table_name = 'PROPDB_VIEW_MAP ';

  probably, 'you' (USER) are not the owner of this table

• I have a table of the adf, I added a column that contains a button that I created, when I click it must remove this row in the table, but it is not, please help

  I have a table of the adf, I added a column that contains a button that I created, when I click it must remove this row in the table, but it is not, please help

  I don't understand. You use vo and eo for you to use business components.

  Again, this kind of code call in trouble.

  You must post the changes to make them visible to the eo find vo. You must then run the query for the changes in the business layer strips then you must update the iterator he table is based on.

  In your code I see that happen, hooch maybe because it is more often than not formatted and undocumented.

  My advice is to do a small test case that you can manage with easy sql. Once you get it to run transfer you the results to the actual application.

  Timo

• Total number of records in the table read

  Here is the procedure to read total no of record in the table specified by the user during execution. But it still gives the same answer for all the table. Can someone help me?
  
  create or replace procedure p3 (varchar2, not on the number tab)
  as
  Start
  Select count (*) from no tab;
  end;

  You need dynamic SQL statements.

  Or:
  http://laurentschneider.com/wordpress/2007/04/how-do-i-store-the-counts-of-all-tables.html
  To get the name of the Table and no lines
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:1725645184471282:P11_QUESTION_ID:1660875645686

  Or simply use the data dictionary, collect statistics of the table, then:
  Select table_name, num_rows from user_tables;

• Validate values inserted into a table against an another record in the table.

  Hi, I have this two tables on my Oracle Database 10g:

          Status                                    
  
  Id_Status | Description        
  --------------------------------       
    102     |   Ok                 
    123     |   Damaged 
    345     |   Broken
  
  Cars
  
  Car_ID|  wheel  |  hood  |  bumper  |  radiator
  -------------------------------------------------
    1   |   1     |     2  |     2    |   3

  and what I have to do is to make sure that you can only insert a record if the [wheel, hood, bumper, radiator etc...] values are values that already exist in the State of the table, but I do not know if you add FK as:
  

  ALTER TABLE "RCVRY"."COMPANY" 
      ADD (CONSTRAINT "CITY_ID" FOREIGN KEY("STATE") 
      REFERENCES "RCVRY"."CITIES"("STATE")

  is the right way to do it.
  
  If anyone can help by providing code samples or pointing to the right place in the documentation to look out it will be greatly appreciated.
  Concerning
  
  JMHP

  Hello

  José M. Hurtado says:
  Hi, I have this two tables on my Oracle Database 10g:

  Status                                    
  
  Id_Status | Description
  --------------------------------
  102     |   Ok
  123     |   Damaged
  345     |   Broken
  
  Cars
  
  Car_ID|  wheel  |  hood  |  bumper  |  radiator
  -------------------------------------------------
  1   |   1     |     2  |     2    |   3
  

  and what I have to do is to make sure that you can only insert a record if the [wheel, hood, bumper, radiator etc...] values are values that already exist in the State of the table, but I do not know if you add FK as:

  ALTER TABLE "RCVRY"."COMPANY"
  ADD (CONSTRAINT "CITY_ID" FOREIGN KEY("STATE")
  REFERENCES "RCVRY"."CITIES"("STATE")
  

  is the right way to do it.

  Yes, foreign keys are the right way to do it.
  Make sure that first of all, there is a constraint of PRIMARY KEY (or UNIQUE) on status.id_status.

  If anyone can help by providing code samples or pointing to the right place in the documentation to look out it will be greatly appreciated.

  The code you have posted has an imbalance ' (' between ADD and CONSTRAINT.) Lose that ' (' and you have the right syntax.)
  Double quotes are necessary only if you use non-standard names. Do not.
  The schema name (RCVRY in the above example) is optional.

  So, you could say:

  ALTER TABLE     cars
  ADD CONSTRAINT     cars_wheel_fk
  FOREIGN KEY     (wheel)
  REFERENCES     status (id_status)
  ;
  

  I hope that answers your question.
  If this is not the case, after a test script.
  Publish instructions CREATE TABLE for tables and ALTER TABLE instructions for constraints (if they are not part of the CREATE TABLE statements).
  Let's just do the constraint on wheel first. Once you know how to do this, add similar constraints for the other columns (radiator, hood, bumper,) will be easy.
  After a series of INSERT statements (and update, if you want) for the two tables, which must be executed in order.
  Say if you want as each INSERT (or UPDATE) statement of work or not. (Include a few of them).

  Published by: Frank Kulash, December 7, 2010 19:15

• Add new records to the table of the ADF

  Hello
  
  I use Jdev 11.1.1.3.0.
  I have a Page of the ADF with detail Table of form - master, I want to add new records to the table reflecting in DB. Is it possible to do? pointers or demo?
  
  
  Thank you
  MB

  What are the components are used in your table? When you created the table originally, you specified as a table read-only? If your table contains components of af: outputText, then you will need either manually change components entry way, or remove the table and re-drop-the-in the form of table (not read-only)

  John

• Form check synchronize on Popup to the selected record from the table

  I'm trying to recreate what I did on the portals of the OAS in Weblogic/ADF. I have JDeveloper 11.1.1.2.0. What I do seems to be a little different than the tutorials: I need something like the tutorial master-detail, but instead the details appearing on the same page, it should appear in a popup. I managed to build the part table/popup. But when the popup appears, it displays the wrong record. Here are the steps I used to create this page:
  
  After you create the ADF Fusion Middleware project:
  
  1 create templates for the tables I need.
  2. create the JSF Page.
  3 drop panelCollection on the page.
  4. remove my data to see in panelCollection control and choose the Table read-only ADF. Select the sorting and selection options.
  5 change table properties: selected = DisplayRow, EditingMode = clickToEdit
  6 drag the Popup on the page.
  7. remove my data from view in popup control and choose the form of the ADF. Select the send option.
  8 drop showPopupBehavior on the page. Name of the popup. The value triggerType to the 'selection '. (triggerType "click" works, too)
  9 deploy.
  
  The table is displayed. I click on a line. The pop-up window appears. The form of popup displays the first record in the table. I click on any line.
  
  I just bought the merger Oracle 11g Developer Guide, but were not able to answer this question yet.
  
  Any ideas?
  
  Thank you.

  See this video for how it works for me:
  http://www.ScreenToaster.com/watch/stWUtcRkVLQ1BcSV1aX15Q

• After updating my iPhone 6 (9.3.4) the WiFi signal becomes very low! I did everything, but the problem does not stop! I don't a not update my other devices &amp; their very good WiFi signals. Please help me solve this terrible problem...

  After updating my iPhone 6 (9.3.4) the WiFi signal becomes very low! I did everything, but the problem does not stop! I don't a not update my other devices & their very good WiFi signals. Please help me solve this terrible problem...

  Here's a tip for the user on the problems of Wi - Fi. Suggest from the top and bottom. Maybe one of them will help you.

  (1) restart you device.

  (2) resetting the network settings: settings > general > reset > reset network settings. Join the network again.

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  (4) change of Google DNS: settings > Wi - Fi > click the network, delete all the numbers under DNS and enter 8.8.8.8 or otherwise 8.8.4.4

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  (6) determine if other wireless network devices work well (other iOS devices, Mac, PC).

  (7) try the device on another network, i.e., neighbors, the public coffee house, etc.

  (8) backup and restore the device using iTunes. Try to restore as New first and test it. If ok try to restore the backup (the backup may be corrupted).

  https://support.Apple.com/en-us/HT201252

  (9) go to the Apple store for the evaluation of the material. The Wi - Fi chip or the antenna could be faulty.

  Council: https://discussions.apple.com/docs/DOC-9892

• OK, I changed my hard reversing in car and the windows don't will not activate because of it, how or who should I call to fix this *... once again!

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  Have you tried to restart by phone?

  How to activate Windows 7 manually (activate by phone)
   
  1) click Start and in the search for box type: slui.exe 4
   
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  http://support.Microsoft.com/kb/950929/en-us
  ----------------------

• How can I recover only odd or even number of records in the table?

  Hello

  How can I recover only odd or even number of records in the table?

  Thank you
  

  Hi IndiMinds,

  Alternatively, you can use in queries. :

  Odd:

  SELECT *.

  Of

  (SELECT rownum row_count, id, name FROM bigemp

  )

  WHERE mod (row_count, 2) = 1;

  Still:

  SELECT *.

  Of

  (SELECT rownum row_count, id, name FROM bigemp

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  WHERE mod (row_count, 2) = 0;

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• The left join - no data in the table don't want to display the data from the table one

  Hello
  
  I'm writing a query. Here is my scenario, I have two tables EMP and EMP_TYPE. I want to join both the table and even if there is no matching record in the table for EMP EMP_TYPE, I want to return the record to the EMP table and empty values of EMP_TYPE.
  

  create table EMP
  
  (
  
    EMPID   NUMBER(10,2),
  
    EMPNAME VARCHAR2(100)
  
  );
  
   
  
  INSERT INTO emp (empid,empname) values (1, 'abc');
  
  INSERT INTO emp (empid,empname) values (2, 'xyz');
  
  INSERT INTO emp (empid,empname) values (3, 'UNJ');
  
   
  
  create table EMP_Type
  
  (
  
    ID          NUMBER(10,2),
  
    EMPID       NUMBER(10,2),
  
    TYPE_ID     NUMBER(10,2),
  
    END_DATE    DATE
  
  );
  
   
  
  INSERT INTO EMP_Type(id, empid, TYPE_ID, END_DATE) values (100, 2, 1, SYSDATE);
  
   
  
  select *
  
    from emp e
  
    left outer join emp_Type t
  
      on e.empid = t.empid
  
   and t.type_id = 1
  
  
  
  returns.
  
  
  
          EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
  
       2.00             xyz            100.00     2.00             1.00             10/9/2012 5:18:59 PM
  
       3.00             UNJ                    
  
       1.00             abc                    
  
  
  
  
  
  select *
  
    from emp e
  
    left outer join emp_Type t
  
      on e.empid = t.empid
  
   and t.type_id = 1
  
   and t.empid = 3
  
  
  
  returns
  
  
  
          EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
  
       2.00             xyz                 
  
       3.00             UNJ                    
  
       1.00             abc          
  
  
  
  but instead I want
  
  
  
          EMPID     EMPNAME     ID             EMPID     TYPE_ID     END_DATE
  
       3.00             UNJ                    

  Your conditions of conflict
  >
  and t.type_id = 1
  and t.empid = 3
  >
  There is a record with t.empid 3

  select *
    from empx e, empx_Type t
  where e.empid = 3
    and e.empid = t.empid (+)
  
  EMPID,EMPNAME,ID,EMPID_1,TYPE_ID,END_DATE
  3,UNJ,,,,
  

• Table of contents, do not update when the project is saved

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  I'm sorry, so sorry. I forgot to add that my esteemed colleague and fellow Adobe Community Expert Peter Grainge has some fabulous on its site information if you go with merged WebHelp.

  Click here to see

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  Useful and practical links Wish to RoboHelp form/Bug report form Begin to learn RoboHelp HTML 7 or 8 days - $24.95! Adobe Certified RoboHelp HTML Training SorcerStone blog RoboHelp EBooks