Regarding comparisons of neighborhood in two tables
I was wondering if there is no effective way to do it.
Let's say I have two text files that are 1 d arrays:
Table1: Table2:
0 0
0 0
0 0
0 100
100 0
0 100
0 0
100 0
0 0
Basically, I want something that runs through each value in the array array1, and if he sees a number exceeding a certain threshold (in this case, 100), it checks the entry of array2, so that n-1 n and n + 1. If there are numbers greater than a threshold in n - 1, n or n + 1, then add one to a counter variable. Otherwise do nothing.
So in my two paintings, there should be 1 County. Array1 and array2 will have always the same number of rows.
Something like this would be trivial with Java or Matlab using a loop for, but I don't know how to do it with LabVIEW. I can manage the FI, but I do not know how to represent "n-1" or "n + 1".
LabVIEW is also loops.
Tags: NI Software
Similar Questions
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Hello
I have two tables USERS and LISTS:
And I want that there is a comparison between these two tables executed when user table USERS connect to the application.
They must compare the columns between the SEXES and AGE and if some users have the same attributes in its ranks as in a line in the table LISTS (here is unique each line) so that the user gets in his line in the column 'LIST_ID' the ID of the line with which attributes between GENDER and AGE.
Example:
USERS TABLE: exampleuser | Boby | McGrahem | Male | 18. -------
LISTS OF TABLE: 28 | examplelist | Male | 18
Once the Login of the user Boby gets in its ranks the ID = 28 because the SEX and AGE corresponds to the row of table LIST:
Result:
USERS TABLE: exampleuser | Boby | McGrahem | Male | 18. 28
CREATE TABLE "USERS" ( "USERNAME" VARCHAR2(15) NOT NULL ENABLE, "FORRNAME" VARCHAR2(15) NOT NULL ENABLE, "SURNAME" VARCHAR2(15) NOT NULL ENABLE, "GENDER" VARCHAR2(10) NOT NULL ENABLE, "AGE" NUMBER, "LIST_ID" NUMBER, CONSTRAINT " USERS_PK" PRIMARY KEY ("USERNAME") USING INDEX ENABLE
CREATE TABLE "LISTS" ( " LIST_ID" NUMBER NOT NULL ENABLE, " LISTNAME" VARCHAR2(50) NOT NULL ENABLE, "GENDER" VARCHAR2(10) NOT NULL ENABLE, "AGE" VARCHAR2(3) NOT NULL ENABLE, CONSTRAINT " LISTS_PK" PRIMARY KEY ("LIST_ID") USING INDEX ENABLE
I need help for coding this, if someone be so good.
This is my essay:
DECLARE v_listid varchar2(100); BEGIN SELECT LIST_ID into v_listgid FROM LISTS WHERE GENDER = (SELECT GENDER FROM USERS WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER))) AND AGE = (SELECT AGE FROM USERS WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER))); UPDATE USERS SET LIST_ID = v_listid WHERE UPPER(TRIM(USERNAME)) = UPPER(TRIM(:APP_USER)); END;
I'd like to REALLY shy away using the USER name as the primary key, because the fact that users can create duplicate user names... YOU should NEVER base a PK on the entry of user, the better to let the database create and maintain this element of date...
FIX:
UPDATE to users U
SET List_Id = (SELECT List_Id OF lists L WHERE L.Gender = U.Gender and L.SOMENUMBER = U.SOMENUMBER) AND
Upper (U.UserName) = UPPER(:APP_USER);
Don't really want to cut the strings, Oracle which will do since they are of type varchar2 columns...
Thank you
Tony Miller
Software LuvMuffin
Ruckersville, WILL -
Hello
I have a question about the merger of the two 2D arrays. I have a program that generates two tables different interms of binary digits (attached file) and I wanted to arrange them as below.
The first generation of table: 1110
1101
1011
0111
Second generated table: 0001
0010
0100
1000
Output should be: 1110
0001
1101
0010
1011
0100
0111
1000
Thank you.
Hello
Order the attached VI
Kind regards
Amine31
(Give congratulations to good answers and Mark as a Solution If your problem is resolved)
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I want to compare two tables and out a boolean
This should be simple. I want to compare two tables (5 items) and return a single Boolean value (T/F), not an array of Boolean.
Thank you
Kevin
Right click on the comparison, the comparison mode, select compare the aggregates.
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Question: two tables in a pool, load balancing, etc.
Hello
So I'm sort of confused about how it works. I know I can put two tables that are part of the same group in the same pool, and I know I can create a volume that spans the two tables and the EQL will spread the volume also between two boxes, etc etc.
My question, I guess that is the reliability... Have I missed something or that seems like a "RAID 0" type thing between two EQLs? I mean, if the volume is divided between the two boxes, how can I ever do a reset on a box? What happens if one of the EQL breaks down? What I lose this entire volume?
What Miss me? Or is it how it really works?
I'm kind of fear put anything in production where a failure on a device would kill everything like that.
Any explanation would be appreciated.
The button is named "restart" and launch of a failover of the MC Eve always. Yes, there is no complete reboot option or task.
Well... is the same "risk" to have a storage with multiple heads and a few shelves of extension. If storage with Betclic or groups on disc on shelves and you lose a comprehensive shelf, you're in trouble.
In theory the risk increases if you put more members to a pool, because a volume divided on 3 volume by default. But it is a softlimit and you can adjust the distribution of volume more or less members. If you have a volume that is large and 3 members cannot provide this ability, he can go 4 or more members. The largest volume spreads i never saw in all 8 members. Spread of the volumes between the members, that's how EQL scales on.
If you do not as you turn this option off or copy your data with SyncRep option.
Kind regards
Joerg
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Hello experts...
I'm new to this forum and Oracle coding complex.
I have a task in which I want to compare two tables with the same structure, same columns. My Oracle database is 11g Release 2. I want this column-by-column comparison and save the result in a separate table. (say result_table)
The structure of the table would be as follows:
SQL > desc emp;
Name Null? Type
----------------------------------------- -------- ----------------------------
EMPNO NOT NULL NUMBER 4
ENAME VARCHAR2 (10)
JOB VARCHAR2(9)
MGR NUMBER(4)
HIREDATE DATE
SAL NUMBER(7,2)
COMM NUMBER(7,2)
DEPTNO NUMBER (2)
SQL > emp_comp desc;
Name Null? Type
----------------------------------------- -------- ----------------------------
EMPNO NOT NULL NUMBER 4
ENAME VARCHAR2 (10)
JOB VARCHAR2(9)
MGR NUMBER(4)
HIREDATE DATE
SAL NUMBER(7,2)
COMM NUMBER(7,2)
DEPTNO NUMBER (2)
Both of the tables EMPNO is the primary key.
I want to compare these two tables based on the EMPNO (EMPNO even is both tables).
The result log table would be as follows:
SQL > create table result_table
2 (check_sr_no, number (5),)
table_name 3 varchar2 (30),
ROW_ID 4 varchar2 (20).
column_name 5 varchar2 (20).
6 column_data varchar2 (1000).
compared_by 7 varchar2 (10));
Table created.
SQL > alter table result_table
2 Add the constraint result_table_pk
3 primary key (check_sr_no);
Modified table.
The name of the table and the name of the column will not be hardcoded (based parameter by user)
I tried to use the dbms_comparison package, but do not find comparison of column to column.
I also used by using the query operator LESS. It's showing the difference in rank.
I also went to https://asktom.oracle.com/pls/apex/f?p=100:11:0:P11_QUESTION_ID:2151582681236
Your help will be very appreciated.
Thank you
DK
Tom Kyte has answered this question MANY times over the years. Here are links for its solution
https://asktom.Oracle.com/pls/Apex/f?p=100:11:0:P11_QUESTION_ID:4934799800346640847
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Take the difference of two tables
Hello
I have two tables where in I need to take the difference between the two columns of different tables and show as decimal below:
Table A
Name, salary
x 10.5
y - 10.32
z 5
Table B
Name, salary
x 10.5
y - 10.32
z 3
a 12
Output:
Name_A, Name_B, salary, remarks
x, x, 0, no diff
y, y, 0, no diff
z, z, 2 Diff is here
, one, no data, no data from the previous
Hello
Try ythis:
with table_a as
(
SELECT 'X' NAME, SALARY, 10.5 DUAL UNION ALL
SELECT THE NAME OF 'Y',-10.32 SALARY OF DOUBLE UNION ALL
SELECT THE NAME OF 'Z', 5 DOUBLE SALARY
)
table_B as
(
SELECT 'X' NAME, SALARY, 10.5 DUAL UNION ALL
SELECT THE NAME OF 'Y',-10.32 SALARY OF DOUBLE UNION ALL
SELECT THE NAME OF 'Z', 3 DOUBLE UNION ALL SALARIES
SELECT 'A' NAME, SALARY 12 DUAL FROM
)
SELECT
COALESCE(A.NAME,B.NAME) NAME
, NVL (TO_CHAR (A.SALARY - B.SALARY), 'NO DATA') SALARY
, CASE WHEN A.SALARY - B.SALARY = 0 THEN 'NO DIFFERENCE '.
WHEN B.SID IS NULL, "NO DATA OF THE PREVIOUS.
WHERE B.NAME IS NULL, "NO DATA FROM NEXT.
ANOTHER 'DIFFERENCE IS THERE.
END NOTEOf
TABLE_A HAS
TABLE_B FULL OUTER JOIN B ON (B.SID = B.NAME)
;NAME SALARY NOTE
---- ---------------------------------------- ---------------------
X 0 NO DIFFERENCE
Y 0 NO DIFFERENCE
Z 2 THE DIFFERENCE IS THERE
A NUMBER OF DATA NO DATA FROM THE PREVIOUSKind regards
Peter
-
How to link two tables with form
Hello
Here's what I want to do
I have a table-> Student (rollno, name)
I also have these two tables (rollno, marks) Math Physics (rollno, marks)
now, I want to have a form in my page (in which I can navigate school records) and two tables in the adf (Math, physical). When selecting a certain record of the form, I want to see data associated with these two tables.
I try to make the link display but works for me...
Please help me on this.
-Usman
-Open the module of the application
-Go to the model data tab
-You will see all the your available on the left and your already added to the AM to the right
-For the your who are 'master' for others your (in your case, student VO's master VO of Math and physics VO), you will see a (+) monkey behind it
-Expand this node and you will see the math and physics your.
-Math VO on the left and the VO student on the right then click on the button (>) to shuttle Math VO VO of the student child and give it a name
-Repeat step for physics VO
After completing the above steps and save, go back to your jsf (or jspx or...) and in the data tab control you will see this student VO is now two children, Math and physics. Use WHAT YOUR theses to create your tables for details.
Kind regards.
-
How to update these two tables
Hello
I have two tables (in Oracle 11 g R2) and need to lock some lines in each of them for the update...
Here is the sample data and the result after update, please help me for update instructions.
Thanks in advance!
drop table t1; drop table t2; create table t1( t1_id number(5) primary key, t1_col2 varchar2(20), t1_col3 varchar2(10), t2_id varchar2(5)); create table t2( t2_id varchar2(5) primary key, t2_col2 varchar2(10), t2_col3 number(2), t1_id number); insert into t1 values(1, '1 - col2', 'AB', null); insert into t1 values(2, '2 - col2', 'AB', null); insert into t1 values(3, '3 - col2', 'AB', null); insert into t1 values(4, '4 - col2', 'AC', null); insert into t1 values(5, '5 - col2', 'AC', null); insert into t1 values(6, '6 - col2', 'AC', null); insert into t1 values(7, '7 - col2', 'AC', null); insert into t1 values(8, '8 - col2', 'AC', null); insert into t1 values(9, '9 - col2', 'AC', null); insert into t1 values(10, '10 - col2', 'AC', null); commit; insert into t2 values('11001', 'ABC', 12, null); insert into t2 values('11021', 'ABC', 12, null); insert into t2 values('11022', 'ABC', 12, null); insert into t2 values('11023', 'ABC', 12, null); insert into t2 values('11024', 'ABC', 12, null); insert into t2 values('11025', 'ABC', 12, null); insert into t2 values('11030', 'ABC', 12, null); insert into t2 values('11035', 'ABC', 12, null); insert into t2 values('11051', 'ABC', 12, null); insert into t2 values('11061', 'ABC', 12, null); insert into t2 values('11071', 'ABC', 12, null); insert into t2 values('11081', 'ABC', 11, null); insert into t2 values('11091', 'ABC', 11, null); commit; declare cursor c1 is select * from t1 where t1_id in(select t1_id from (select t1_id from t1 where t1_col3 = 'AC' order by t1_id) where rownum <= 5) for update; cursor c2 is select * from t2 where t2_id in(select t2_id from (select t2_id from t2 where t2_col3 = 12 order by t2_id) where rownum <= 5) for update; begin for rec_c1 in c1 loop ??? end loop; end; / The result must look like: T1_ID T1_COL2 T1_COL3 T2_ID ---------- -------------------- ---------- ----- 4 4 - col2 AC 11001 5 5 - col2 AC 11021 6 6 - col2 AC 11022 7 7 - col2 AC 11023 8 8 - col2 AC 11024 T2_ID T2_COL2 T2_COL3 T1_ID ----- ---------- ---------- ---------- 11001 ABC 12 4 11021 ABC 12 5 11022 ABC 12 6 11023 ABC 12 7 11024 ABC 12 8
With the help of Bencol :-)
DECLARE CURSOR c1 IS SELECT a.t1_id, b.t2_id FROM t1 a CROSS JOIN t2 b WHERE (a.t1_id, b.t2_id) IN (SELECT t1.t1_id, t2.t2_id FROM (SELECT t1_id , ROW_NUMBER () OVER (ORDER BY t1_id) t1_rn FROM t1 WHERE t1_col3 = 'AC') t1 JOIN (SELECT t2_id , ROW_NUMBER () OVER (ORDER BY t1_id) t2_rn FROM t2 WHERE t2_col3 = 12) t2 ON t1.t1_rn = t2.t2_rn WHERE t1.t1_rn <= 5) FOR UPDATE; BEGIN FOR rec_c1 IN c1 LOOP UPDATE t1 SET t2_id = rec_c1.t2_id WHERE t1_id = rec_c1.t1_id; UPDATE t2 SET t1_id = rec_c1.t1_id WHERE t2_id = rec_c1.t2_id; END LOOP; END; /
Kind regards.
Al -
Main table with two tables of children as part of the ADF
Hello
I'm trying to implement single master with two tables in detail using oracle adf framework of Jdev 11.1.1.4.0. I am able to only master / details using the link display but unable to reach the details i.e., nested block child master with nested blocks.
I created query view object based on the master and two poll objects of the base seen as details. Then, I created two master of first child link and another link for master of the second child. Even in this case in my data controls I see two different components which is incorrect.
Please let me know how to create a data control for an example below:
Fruit [MASTER]
-Details of Fruits such as the table of the adf
-Apples [FIRST CHILD]
-Details of the apples as adf table
-Orange [SECOND CHILD]
-Details of the Oranges as adf table
Kind regards
Amar.You need two viewLinks
Fruit-> apples
Fruit-> OrangesThen, in the data model, you choose the entry of fruit that has:
Fruit
|---> ApplesYou stand on the fruit and you shuttle Oranges to be below left to right.
If you use the HR schema by default, you will see this type of relationship for employees:
https://blogs.Oracle.com/Shay/entry/master_with_two_details_on_the -
Two tables with different values of basic on an analysis filter
Hi guys,.
Let assume that I have an analysis with columns: group_id and sales.
On this basis I would like to create two tables: table1 where group_id = 1 and table2 where group_id = 2.
OBIEE is able to do?
Kind regards
SlaviHi Slavi,
You can do it in a single analysis, but you have to have the column with group_id twice.
Bring, group_id_1, group_id_2 (same column), sale
Now in table 1.
bring group_id_1, sales
Then in the selection steps for group_id_1-> select members-> Action choose keep only-> choose the value of the filter 1
This will filter the table 1 with group_id 1
In table2 group_id_2 porter, sales
Then do the same step for group_id_2 with the value 2.
You now have two reports with different filter in the same report.
If you want you can keep the same name column for the two columns group_id, I just kept group_id_1, group_id_2 for easy reference.
-
By comparing the two tables for the integrity of the data
Hi all
I need to compare two tables for the integrity of the data through the SQL query.If you need to compare all the columns of t1 to t2:
(SELECT * FROM t1 MINUS SELECT * FROM t2) UNION ALL (SELECT * FROM t2 MINUS SELECT * FROM t1);
Kind regards
Ankit Rouault
http://theoraclelog.blogspot.in -
How to find the data in two tables are the same?
Hi people,
Suppose we have table emp01, have 10 records and create another emp02 as table
create the table emp02 in select * from emp01;
now both the table has the same data.
How to find a 'data' in the two tables are the same?Hello
SELECT * FROM emp01 MINUS SELECT * FROM emp02 UNION SELECT * FROM emp02 MINUS SELECT * FROM emp01
You can also compare resultset hash to select * in emp01 and select * from emp02 by using dbms_sqlhash.
Best regards
Nikolai -
Great way to add more than two tables on the data sources
Hello world
I would like to confirm everything that follows before doing so on my interface.
I work with an interface that is suppoused to pass data from some of the oracle tables in a DB X to an oracle table in a DB Y.
The target data store got a foreign key, that is why I have to download two tables on the area of thesources. Is this right? Should I tell the two tables sort? I mean those procurement.
I know this may seem a stupid question, but I like teo do things and to understand what I do in the future I can improve! If you can recommend me some additional reading on this I would really aopreciate your help and your advice.
Do not hesitate to contact me if additional information is required.
Best regards.
JaisonIf the form of files your multiple source tables are a unique entry in the table target, then they will certainly be linked. You can drag columns from a source model to another model of source to generate a join in the designer criteria.
-
BUG? Statement of BRIDGE to compare two tables
Hello
I tried to compare two tables different dbs and remembered a post on applications to Connectin Cross
http://barrymcgillin.blogspot.com/2010/11/cross-connection-queries.html
I expect to get the differences between the ARB table in my current schema and the table alias temparb arb in the other db. Yet it seems that in this case only the table in my current schema is read.BRIDGE temparb AS "EB05 01" (SELECT * FROM arb) (SELECT * FROM temparb MINUS SELECT * FROM arb ) UNION ALL (SELECT * FROM arb MINUS SELECT * FROM temparb );
I materialize at the table BRIDGE with
and select the value that I know to be only in the remote schemaBRIDGE temparb AS "EB05 01" (SELECT * FROM arb)
Both times I get no results. I even tried to use aliases on the table, same result. Tested in EA3 3.0 and 3.1.SELECT id FROM temparb WHERE id = 2562; SELECT id FROM arb WHERE id = 2562;
Has anyone tried this before?
Concerning
MarcusHi Marcus,
Have you tried without the quotes around the name of connection?
I have a named connection
system_local
which I run the following commanddrop table testbridge_remote;
drop table testdbrige;
create table testbridge (col1 int);
insert into testbridge values (1);
insert into testbridge values (2);
insert into testbridge values (3);
commit;I have a named connection
Name of the connection with space
I performed the following in thedrop table testdbrige;
create table testbridge (col1 int);
insert into testbridge values (4);
insert into testbridge values (5);
insert into testbridge values (3);
commit;Then I can execute the following statement in the connection of system_local/worksheet
BRIDGE testbridge_remote as the name of connection with Space(select * from testbridge)
+ (SELECT * FROM testbridge_remote +)
LESS
SELECT * from testbridge
+)+
UNION ALL
+ (SELECT * FROM testbridge +)
LESS
SELECT * from testbridge_remote
+);+It works well.
Returns the rows in the remote table not in the local table and lines in the local table, not the remote table.Kind regards
Dermot
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