regular exp

Similar Questions

• Reg: Regular Exp - help

  Hi Experts,

  I need help to use the regular Expression-

  WITH t AS)

  SELECT ' 1234 Angel Villa, House 420 | Detroit | WE | 700129' double txt

  )

  ----------------

  SELECT

  txt,

  SUBSTR (txt, InStr(txt,'||') + 2, (INSTR(txt,'|',1,3)-INSTR(txt,'||')-2)) val1,

  REGEXP_REPLACE (txt '([^ ||] *||) (.*)', '\2') val2

  T;

  I want to extract the text entry "Detroit" - going between the two. (begins - with that) and a. (ends - with that).

  txt - 1234 Angel Villa, House 420 | Detroit | WE | 700129

  val1 - Detroit

  val2 | Detroit | WE | 700129

  My regex is not appropriate somewhere. Please provide any suspicion in this regard (and not the exact solution - want to try)

  The backreference is very interesting but am very bad at writing regular expressions. Help much appreciated.

  Thank you and best regards,

  -Nordine

  (on Oracle 11.2.0.3.0 - Exadata)

  Published:

  Tried this now.

  REGEXP_REPLACE (txt '([^ ||] *||) ([^|] *) (|. *)', '\2') val2

  Output-

  ||||

  Nordine Hello B

  Yes, because you have more sign like | in this case you must use the non-greedy option for your star: *?

  I would use the REGEXP_SUBSTR.

  You must use the escape character \ and must be given to the * that you don't want to have the sign | Once again...

  It's a little hard to explain. If you want the solution tell me.

  Best regards, David

  P.S.: Because nobody didn't read you just wish that you do not want to have the right solution only just advice... And you already know the solution, so I post my solution too

  WITH t AS)

  SELECT ' 1234 Angel Villa, House 420 | Detroit | WE | 700129' double txt

  )

  ----------------

  SELECT

  txt,

  SUBSTR (txt, InStr(txt,'||') + 2, (INSTR(txt,'|',1,3)-INSTR(txt,'||')-2)) val1,

  REGEXP_REPLACE (txt '([^ ||] *||) (.*)', '\2') val2

  REGEXP_SUBSTR (txt '(\|) {2} ((.| ^(\|)) *?) (\|)', 1, 1, NULL, 2) LIKE REGEXP_RESULT --> Chris227 Correction

  T;

  Where:

  (Results): take this sign | but don't interpret as the OR operator.

  (\|) {2}: take the sign. twice

  .           : Take any character

  . *: Take among these characters, as you can

  .*?         : Take one of these characters, not the longest chain you will find (NON-greedy option:?)

  (.*?)       : Consider backreference in parentheses. REGEXP_SUBSTR last option is 2, because we want only the name of the city without sign.

  Last (-|)   : The name of the city must be accompanied by a sign.

  I hope it helps.

  The SQL above has been fixed-> reason: Chris227 noticed a mistake. Thanks Chris277!

• Regular exp support

  Hello

  I want to search using regexp_like for field values that start with REC_AE or REC_

  Field of table values

  'REC_AE_TMPL_GEN '.

  'REC_TMPL_GEN '.

  I tried SELECT * FROM MODEL WHERE REGEXP_LIKE (category, ' ^ REC_(AE|??)) STAT ') but it does not work.

  Help, please

  Try this: ^ REC_ (AE_)? STAT

• declare the variable

  I started warning after running this code.
  He says that this line variable has no type declaration.
  What should I do? This is the code-->

  I suggest you break it down and focus on the creation of the table of the lines before trying to move on as follows

  var myText:String = myText.text
  var myTextArr = myText.toString().split(/[\r\n]/g)
  trace (myTextArr.Length) / / should give you a count of all rows...

  / [\r\n]/g - is a regular exp that looks like for each newline character in the string that was created programmatically using \r to represent the newline

  You can also try variations of the rational expression until you get the number of rows, that you expect.

  / [\r\n]{1,2}/g - resembles a minimum of 1 and a maximum of 2 line breaks

  As a beginner, you have a hard work in front of you, I know it can get frustrating but trial and error is the search of google and way only for examples. Sample analysis weblogs out there he wrote too much already, a lot of developers is the willingness to help but little do not have the time to write the code for you. I recommend you read about regular Expressions too that they are an essential part of any directory of programmers

• deletion of records with data from junk e-mail

  Hi all
  
  I have UNWANTED data in columns like. E¿¿¿.¿¿¿.@,nulls,special charecters,
  
  in delete statement wat should we indicate where clause?
  
  one you suggest no regular exp... to remove all data other than valid numbers or charectrs of a to Z...

  The problem then is white space, which will not be replaced. So just take the Karthick_Arp solution and add trim():

  length(trim(regexp_replace(col_name,'[[:alnum:]]',null))) > 0
  

  Published by: tk-7381344, November 18, 2008 07:48

• A doubt on REG EXP

  Hi friends,
  
  Please specify the doubt in Reg Exp.
  
  Table EMP a sequel EMP_NAMEs:
  
  ============
  Anand
  Bala_G
  Chitra
  David_C
  Elango
  Faye
  ============
  
  We have a set of characters as "abcdefghijklmnopqrstuvwxyz0123456789".
  
  Now we must find EMP_NAMES County, whose characters (any) are not in the list of characters in the list above. In this example, the result should be 2. for example, "Bala_D" and "David_C. The query should be like:
  
  Declare
  v_string varchar2 (50): = "abcdefghijklmnopqrstuvwxyz0123456789";
  v_count number (6);
  Begin
  Select count (*)
  in v_count
  WCP
  where regexp_like (emp_name, v_string);
  
  dbms_output.put_line (v_count);
  
  end;
  
  ========================
  
  Thanks in advance!

  Hello

  Welcome to the forum!

  To use REGEXP_LIKE, you could say:

  WHERE     REGEXP_LIKE ( emp_name
                , '[^abcdefghijklmnopqrstuvwxyz0123456789]'
                )
  

  However, it will be faster not not to use regular expressions:

  WHERE   LTRIM ( emp_name
             , 'abcdefghijklmnopqrstuvwxyz0123456789'
             )          IS NOT NULL
  

  Published by: Frank Kulash on 10 October 2012 16:18
  Removed the extra single quote, after DAMorgan, below.

• the simple regular expression problem

  Hello
  
  I need assistance with regular expressions. I have a situation when I need to get data from one table to the other and I think that my problem can be solved using REG EXP, but I don't know how to use them properly.
  
  
  I need to separate fileld varchar2 which is basically number/number in 2 separate number fields
  

   
  
  
  CREATE TABLE tst (CODE VARCHAR2(10)); 
  
  INSERT INTO tst VALUES('10/15'); 
  INSERT INTO tst VALUES('13/12'); 
  INSERT INTO tst VALUES('30'); 
  INSERT INTO tst VALUES('15'); 
  
  CREATE TABLE tst2 (po NUMBER, co NUMBER); 

  I need to get the code in the co and po columns. I think the result should look something like this, but:
  

   
  
  INSERT INTO tst2 
  SELECT regexp_substr(CODE 'something here to get the number before /') AS po, 
         regexpr_substr(CODE 'something here to get number after') AS co 
  FROM tst;   

  Any help appreciated

  Agree with the above,

  However, if you really want to know how to do with regular expressions you can do it like this...

  SQL> select regexp_substr('10/15','[^/]+',1,1) from dual;
  
  RE
  --
  10
  
  SQL> select regexp_substr('10/15','[^/]+',1,2) from dual;
  
  RE
  --
  15
  

• One for the era: how to get this output using REGULAR EXPRESSIONS?

  How to get the bottom of output using REGULAR EXPRESSIONS?

  SQL> ed
  Wrote file afiedt.buf
  
    1* CREATE TABLE cus___addresses    (full_address                   VARCHAR2(200 BYTE))
  SQL> /
  
  Table created.
  
  SQL> PROMPT Address Format is: House #/Housename,  street,  City, Zip Code, COUNTRY
  House #/Housename,  street,  City, Zip Code, COUNTRY
  SQL> INSERT INTO cus___addresses VALUES('1, 3rd street, Lansing, MI 49001, USA');
  
  1 row created.
  
  SQL> INSERT INTO cus___addresses VALUES('3B, fifth street, Clinton, OK 74103, USA');
  
  1 row created.
  
  SQL> INSERT INTO cus___addresses VALUES('Rose Villa, Stanton Grove, Murray, TN 37183, USA');
  
  1 row created.
  
  SQL> SELECT * FROM cus___addresses;
  
  FULL_ADDRESS
  ----------------------------------------------------------------------------------------------------
  1, 3rd street, Lansing, MI 49001, USA
  3B, fifth street, Clinton, OK 74103, USA
  Rose Villa, Stanton Grove, Murray, TN 37183, USA
  
  SQL> The REG EXP query shouLd output the ZIP codes: i.e. 49001, 74103, 37183 in 3 rows.

  Published by: user12240205 on June 18, 2012 03:19

  /* Formatted on 2012/06/18 17:25 (Formatter Plus v4.8.8) */
  SELECT REGEXP_SUBSTR ((REGEXP_SUBSTR (full_address, '[^,]+', 1, 4)), '[[:digit:]]+') RESULT
    FROM cus___addresses
  

• Regular expression to allow only numeric characters or spaces in the num field such

  Hi people
  
  Am Newbie Apex using 4.0.1 / Vista / Oracle XE and am trying to create a level validation element on a phone number field
  
  I want any combination of numbers and valid spaces with only the obvious condition that the field cannot be completely spaces.
  
  Can anyone help to suggest how to do because I'm really bad with something so simple that I have no exp prev reg expressions.
  
  Thank you, as always
  Peter

  Hello
  It's quite strange, I just tried your entry (without apostrophes) and it passed. Do you have you copied my reg exp (a ^ $ included) and pasted into the Expression of Validation 2 field validation with regular Expression of type? We must really work.

  Jirka

• How exp a database of the user affected?

  I know that the system user and its password and there is another regular user, it's the name test, if I know it's password, I can exp test like the following:
  c:\ > exp test/testpw file=c:\\test.dmp
  
  but I don't know it's password. and I want to test user exp, how do?
  
  Thank you!

  exp system/pass@test owner = (test) = c:\ss file

• slower than the utility exp expdp!

  Hello
  
  I need to compare utilities vs exp expdp and get hours for schemas in my application... I started today with a small diagram which is 1.5 GB. With the help of export utility that it took 3 minutes and 51 seconds to export it. but using expdp it takes 6 minutes and 16 seconds to make the export! Expdp is supposed to be faster, but in my case, I see the export do much better. Can anyone help to look into this.
  
  To export the I used after a command:
  
  log statistics exp_ = $1_$ 3.log exp $1 / $1 file = exp_$ $1_ 3.DMP = none direct owner = y = $1 for regular export
  and
  Directory of $1 / $1 = dir1 dumpfile = exp_ expdp $1_$ 3.DMP logfile = exp_$ $1_ 3.log = $1 patterns for data pump...
  
  I have passes three arguments and the second argument is schematic size small/big etc which, as well as the schema name is $1 and a number random i.e. $3 are used in the above commands.
  
  Can someone help me determine why the utility expdp is slower for my tests?
  
  
  Thank you
  Cedric

  Cedric,

  Usually his good idea set PARALLELS the number of CPU options, you have on the server. Because the largest number (number of CPUS) can also advarsely affect performance as well. Don't forget time CPU also dealt with by other procedures and processes more you spawan can serilaize their execution resulting in a decrease in performance. So from 2 or 4 will be a good idea.

  Concerning

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