Regular expression breaks script

Similar Questions

• Divide a CSV with a regular Expression

  I'm working on a script that will read the CMYK values from a CSV file and add the nuances of the Swatches palette. I can easily split the CSV entering a comma (.split(",");), but I can't seem to get a regular expression to separate by commas and new lines.
  
  Here is the code snippet I have right now is not working:
  
  

  var fileIn = new File("/Users/brianp/Desktop/AVL-PMS-TEMP.csv");
  fileIn.open();
  var csvIn = fileIn.read();
  fileIn.close();
  
  var regEx = "/,|\\n/";
  csvRecords = csvIn.split(regEx);  
  

  I am barking the wrong tree here?

  I could change the CSV advance to find all line breaks and replace them with commas, but it looks more elegant to adapt my code for the CSV file is delivered.

  Thanks in advance!

  csvRecords = csvIn.split(/[,\n\r]/);

  This is the shortcut. To preset the regex, to leave out the quotation marks:

  var regEx = / | \n/ ;

  Better to add the CR (\r) as well.

  Use the classes of characters [...] If you can instead of alternatives (... |...), they are more effective (allegedly).

  Peter

• a regular expression question

  I have a large body of text that I am breaking into individual words (as part of an experimental project of indexing).

  I can break the text into a list in a paragraph break for each word space (a simple find and replace).

  But I want proper nouns to stay intact.

  So I'll try to write a script of the regular expression that finds all occurrences of two contiguous words that begin in a capital letter, then replace the space between the two words with an underscore.

  Sigmund Freud becomes Sigmund_Freud.

  Does anyone know how I would write this script?

  Thank you!!!

  You don't need a script, you can do it in the interface:

  Search: (\u[-\w]+)\x{20}(?=\u[-\w]+)

  Change: $1_

  \u[-\w]+ is the abbreviation of "letter followed capital one or more of the characters dash/word"; This is the first name.

  \x{20} refers to the space.

  followed by an another \u[-\w]+, the family name. This one is in an advanced search, so the whole expression paraphrases that "find a word that begins with a capital letter followed by a space if it is followed by another word beginning with a letter from the uc.

  Peter

• Build a regular expression for data series of Arduino.

  All,

  I have a few Arduinos Council integrated into a test configuration that I can't save the data of.  I now need to be able to see my data in real-time as it comes on the serial port.  I found a VI that seems like it should work, my problem is that I can't get a regular expression to work.

  The VI is not mine, but if I can get this working, I can easily put it in my VI.

  Here's my Arduino code; This is the timestamp, followed four data points, with delimiters tab. It prints on the serial port as

  190876 762314 814437 1108235 1091719

    Serial.print(sTime);
    //Serial.print(", ");
    Serial.print("\t");   
  
    data = getdata(dataRead);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead1);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead2);
    data = data>>4;
    Serial.print(data);
    //Serial.print(", ");
    Serial.print("\t");  
  
    data = getdata(dataRead3);
    data = data>>4;
    Serial.println(data);
  

  I think it is especially a problem with regular expression.  Any advice or pointers would be great.

  I wish there was a place where you just have to copy and paste my thong in and get a regular expression.

  Do not use bytes to the port!

  Take advantage of the termination character you have.  Activate it on the series set up and set it to the newline character.

  Now the VISA Read will wait until she has the entire line (or timeout if it does not).  Then you can analyze your data out there.

  I think the problem with your code, it's that you're looking for a backslash n.   Not a line break.  Turn it on the style of display of this constant and you will see it is fixed for normal display and backslash is no bar display.

• How to capture multiple line String using regular expressions?

  Hello

  I have a simple program like this:

  

  What I want to accomplish is to capture everything between > start and > to end with a single regular expression matching node. It seems that the definition of multiples? true or False does not help.

  I'm using LabVIEW 2012.

  If it is impossible to capture using a single node, that's fine. But I want to assure you that I can make full use of this node without combining several others.

  Thank you!

  > start([\w\s]*) > end

  A point matches any character except line break characters.  You have two of them.

  

• Regular Expressions do not work

  With the help of sensors 4.X, VMS2.2

  It seems that the normal regualar expressions are not accepted as valid by CiscoWorks. Example:

  If I wanted to match for "Red Duck", but the number of spaces between each letter had to be 0-5 I would use spaces:

  [R] {0-5} e [] {0-5} [d] {0-5} D {0-5} [] u] {0-5} [c] {0-5} k [] {0-5}

  That the expression would be: R e d D uc k, Red D u c k and similar.

  Why they are not allowed in String.TCP?

  SO the question is, WHERE can find a list of regular expressions ACCEPTED, that works with sensors 4.X. I found a list that works with 3.X sensors... it did not work at all. Here, any help would be great.

  Eric

  Duck of red in google returns as red + duck in Google. Space will be replaced by a plus (+) sign or % 20 as it goes over HTTP (the browser for this).

  The regular expression must be (including breaks):

  [Rr] [+] * [Ee] [+] * [JJ] [+] * [JJ] [+] * [Uu] [+] * [Cc] [+] * [Kk]

  You can't repeat a pattern of three characters like [%] 20.

• Oracle regular expressions - splits the string into words for

  Hello

  Nice day!

  My requirement is to split the string into words.

  So I need to identify the new line character and the semicolon (;), comma and space like terminator for string entry.

  Please note that I am currently embedded blank and the comma as separator, as shown below.

  Select regexp_substr('test)
  TO
  string in words, "([^, [: blanc:]] +) (', 1, 1) double;"

  How to integrate the semicolons and line break characters in regular expression Oracle?

  Please notify.

  Thanks and greetings

  Sree

  This has nothing to do with REGEXP. Is SQL * more parser does not not a semicolon at the end of the line:

  SQL > select ' testto, mm\;
  ERROR:
  ORA-01756: city not properly finished chain

  SQL >

  Just break the chain:

  SQL > select regexp_substr ('testto, mm\;' |) '
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<= regexp_count('testto,mm\;'="" ||="">
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;' |') STRINGIN
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  Or modify SQL * more the character of endpoints:

  SQL > set sqlterm.
  SQL > select regexp_substr ('testto, mm\;)
  2 string into words
  3 \w+',1,level ',') of double
  4. connect by level<=>
  5 string in words
  6      ','\w+')
  7.

  REGEXP_SUBSTR ('TESTTO, MM\;) STRINGINTOWO
  --------------------------------------
  Testto
  mm
  string
  in
  Words

  SQL >

  SY.

• REGULAR EXPRESSION - names of Split.

  Hello guys,.

  I have a question about regular expressions. Here are some names:

  WITH T AS 
  (
  SELECT 'Bill CLINTON' as name FROM dual UNION ALL
  SELECT 'Christiano RONALDO' FROM dual UNION ALL
  SELECT 'Barack Hussein OBAMA' FROM dual UNION ALL
  SELECT 'JUAN JOSE Miguel Ange' FROM dual UNION ALL
  SELECT 'Miguel Ange JUAN JOSE' FROM dual UNION ALL
  SELECT 'RONALDO Christiano' FROM dual
  ) 
  SELECT name
    FROM t;
  

  I want to break this chain. I want something like that

  RESULT:
  Bill           CLINTON
  Christiano     RONALDO
  Barack Hussein OBAMA
  Miguel Ange    JUAN JOSE
  Miguel Ange    JUAN JOSE
  Christiano     RONALDO 
  

  Is this possible? Any idea?

  Thank you guys

  This works with your data, but as Frank said, much more unusually still exists:

  SQL> WITH T AS
    2  (
    3  SELECT 'Bill CLINTON' as name FROM dual UNION ALL
    4  SELECT 'Christiano RONALDO' FROM dual UNION ALL
    5  SELECT 'Barack Hussein OBAMA' FROM dual UNION ALL
    6  SELECT 'JUAN JOSE Miguel Ange' FROM dual UNION ALL
    7  SELECT 'Miguel Ange JUAN JOSE' FROM dual UNION ALL
    8  SELECT 'RONALDO Christiano' FROM dual UNION ALL
    9  --
   10  SELECT 'M''BONGO Jesus' FROM dual UNION ALL
   11  SELECT 'Jesus M''BONGO' FROM dual UNION ALL
   12  SELECT 'Jean-Baptiste POQUELIN MOLIERE MANY OTHER NAMES' FROM dual UNION ALL
   13  SELECT 'Jean Michel JARRE' FROM dual UNION ALL
   14  SELECT 'JARRE HEAD Jean Michel' FROM dual
   15  )
   16  SELECT rtrim(regexp_substr(name, '([[:upper:]'']{2,}[ -]*)+')) as last_name
   17       , rtrim(regexp_substr(name, '([[:upper:]][[:lower:]]+[ -]*)+')) as first_name
   18  FROM t;
  
  LAST_NAME                                                                        FIRST_NAME
  -------------------------------------------------------------------------------- --------------------------------------------------------------------------------
  CLINTON                                                                          Bill
  RONALDO                                                                          Christiano
  OBAMA                                                                            Barack Hussein
  JUAN JOSE                                                                        Miguel Ange
  JUAN JOSE                                                                        Miguel Ange
  RONALDO                                                                          Christiano
  M'BONGO                                                                          Jesus
  M'BONGO                                                                          Jesus
  POQUELIN MOLIERE MANY OTHER NAMES                                                Jean-Baptiste
  JARRE                                                                            Jean Michel
  JARRE HEAD                                                                       Jean Michel
  
  11 rows selected.
  

• Find the words (wild cards) using regular expressions

  I'm testing to see if the words are present for revision 1 of a drawing of the cartridge.

  The script search the digit 1 followed by a date, a title, and 4 sets of initials.

  The number 1 is static, (date, title and original are the cards that they are different for each design).

  I use regular expressions to match the words.

  The regular expression highlighted in blue is the number 1 and the date.

  Him remains highlighted in orange does not match the title and initials.

  If anyone can help with the regular expression that is most appreciated.

  Once I got that work will add the form fields for the initials, noting only the console at this point for the tests.

  numWords = this.getPageNumWords (0);

  number of words on the page

  loop through the words on the page

  for (var j = 0; j < numWords-1; j ++)

  {/ / get the pair of words to test}

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (0, j + 1); test words

  Check if 1 26.05.16 THE STRENGTHENING REVISED MM SB AE GM word string is present

  If (ckWords.match(/ ^ 1\s [0-9] {1,2}.)) [0-9] {1,2}. [0-9] {2} \s\w+(\s+\w+){1,7}/))

  {

  Console.println (ckWords);

  }

  }

  You can use something like this:

  ckWords = this.getPageNthWord (0, j) + ' ' + this.getPageNthWord (j, 0, + 1) + ' ' + this.getPageNthWord (0, + 2 j) + ' ' + this.getPageNthWord (0, j + 3) + ' ' + this.getPageNthWord (0, j + 4) + ' ' + this.getPageNthWord (0, j + 5) + ' ' + this.getPageNthWord (0, j + 6);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 7);

  If (! ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} \.\d {2} \s\w+ (?:-s + \w +) {1.8} \s([A-Z]{2})\s([A-Z]{2})-s ([A - Z] {2}) \s([A-Z]{2})$ /)) ckWords + ckWords + "" + this.getPageNthWord (0, j + 8);

  If (ckWords.match (/ ^ 1\s\d {1,2} \.\d {1,2} {2} \s\w+ \.\d (?:-s + \w +) 1.8 ([A - Z] {2}) \s([A-Z]{2})\s([A-Z]{2})\s {} \s([A-Z]{2})$ /))

  {

  ...

• The regular expression problem

  Dear friends,

  In my script I have some sections that test the contents of an edit field before it is processed further.

  Perfectly things like the following:

  var re_Def = /#[A-Za-z][A-Za-z0-9_]+/;          // valid variable name ?
  items = ["#correct", "notcorrect", "#This_is4", "#thisIs", "@something", "#ALLOK", "", ];
  // search    0            -1          -1!!        -1!!          -1        -1!!     -1      <--- incorrect method
  // test    true         false         true        true        false       true    false    <--- correct method
  for (var j = 0; j < items.length; j++) {
    var item = items[j];
    alert ("'" + item + "' ==> " +  item.search(re_Def) + "\n" + re_Def.test(item));
  }
  var re_Def = /(\[ROW +\d+\]|\[COL +\d+\]|\[CELL +\d+, +\d+\]|Left *\(\d*\)|Right *\(\d*\)|Above *\(\d*\)|Below *\(\d*\))/;
  items = ["[ROW 17]", "[Row n]", "[ROW n]", "[CELL 3, 9]", "[CELL 3 9]", "Abbove()", "Right(3)"];
  // result  true        false      false         true         false        false         true    
  for (var j = 0; j < items.length; j++) {
    alert ("'" + items[j] + "' ==> " +  re_Def.test(items[j]));
  }
  

  But what follows always returns false, independly of the content of the string element:

  var re_Def = /{[EFJ]\d*}|{I}/;    // valid format def?
  var item = "{E27}";
  var result = re_Def.test(item);
  alert (result);                   // false !!
  

  RegEx buddy told me, that
  -l' REGULAR expression is correct
  -the result must be true, not false

  -The verbose definition of the RegEx is:
  Match is the following regular expression (attempting the next alternative only if this one fails) "{\d* [EYF]}."
  Match the character "{" literally "{}".
  Match a single character present in the list "J" "[EYF]."
  Match a single digit 0. 9 paper"\d*»
  Between zero and unlimited times, as many times as possible, giving as needed (greedy) «*»
  Match the character "}" literally "}".
  Or match number 2 below (the entire match attempt fails if it cannot match) regular expression "{i}".
  Match the characters "{i}" literally "{i}".

  Typo unrecognized? Test the faulty method?

  Results are fake, as soon as I use the list of characters []] - but look at the first block of code: there are also lists of character they are treated properly.

  The braces in the regular expression must be escaped to be taken literally:

  var re_Def = /\{[EFJ]\d*\}/;
  

  Kind regards

  JoH

• Regular Expressions of Drivng me crazy!

  Oracle Version 11 GR 2

  Scripts of test data

  CREATE TABLE REGEX_TEST

  (ID NUMBER 4,

  VARCHAR2 (50) COMMENTS

  );

  Insert into REGEX_TEST (ID, COMMENTS) values (1, "< Little Red Riding Hood > #title");

  Insert into REGEX_TEST (ID, COMMENTS) values (2, "#title < Little Red Riding Hood > #publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (3, ' #title < Little Red Riding Hood > #publisher < Penguin > #pages < 30 > ");

  Congratulations to Frank Kulash to provide the following SQL to clean the field of comments only properly marked the text in the field

  Properly tagged text is defined as

  Start by #.

  then nameOfHashTag

  then < valueOfHashTag >

  The number or name of hashtags is variable and is not known at design time

  The Frank provided SQL is (with a slight mod)

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >

  
  

  FIRST QUESTION: I understand the [^ #. * <] * component - search for zero or more occurrences of anything that is not a # tracking of zero or more characters, then a < and I understand the () sets a capturing group, but I don't understand how it works - 1 is probably a reference to the Group?

  Now, I add a few more - lines to see how he treats badly marked text that is

  void <>

  text that is not marked

  text is not enclosed by sharp hooks

  Insert into REGEX_TEST (ID, COMMENTS) values ('4, #title <>");

  Insert into REGEX_TEST (ID, COMMENTS) values (5, "#title <>#publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (6, "#title < Little Red Riding Hood > text that isn't marked < Penguin > #publisher");

  Insert into REGEX_TEST (ID, COMMENTS) values (7, "#title oops I forgot #publisher < Penguin > rafters").

  
  

  
  

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title <>#title <>#title <>#publisher < penguin >
  #title <>#publisher < penguin >#title < little Red Riding Hood > text that is not signposted #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title oops I forgot the #publisher < Penguin > rafters#title oops I forgot the #publisher < Penguin > rafters

  SECOND QUESTION: Is there any way I can specify that the <>cannot be empty - I played a bit with the +? but impossible to get what I want.  Similarly, the latter (without text no sharp hooks)-I guess this would be impossible because you don't know if it was wong, until you have met the # next date you would be somehow to follow back and ignore the whole group.

  I learned two things in this

  1. regular expressions are extremely powerful

  2. but they will drive you crazy?

  Once again thanks a lot for the help

  BTW - I managed to do what I had to do it using a lot of PL/SQL code, but not very fast!

  Hello

  So, you want only the substrings that are well-formed attribute/value pairs (attribute or value may be missing).  You want to ignore anything in the comments that is not part of a well-formed pair.

  It is not very difficult to get a single well-formed pair.  The problem is that there is no good way to say 'everything that is not part of a well-formed pair '.  One solution is to extract from each pair trained well on a separate line and then re - combine them into a single string by id, like this:

  WITH split_data AS

  (

  SELECT id

  comments

  REGEXP_SUBSTR (comments,

  , '#'      ||  -sign #.

  '[^<]+'  || ="" --="" 1="" or="" more="" of="" any="" characters="" except="">

  '<'      || ="" --=""><>

  '[^>]+'  ||  -1 or several characters any except >

  '>'          -- > sign

  1

  LEVEL

  ) AS well_formed_pair

  LEVEL AS pair_num

  OF regex_test

  ([LEVEL CONNECTION <= regexp_count="" (comments,=""> <> <[^>] + > ')

  AND PRIOR id = id

  AND PRIOR SYS_GUID () IS NOT NULL

  )

  SELECT id

  commented THAT the original

  LISTAGG (well_formed_pair) WITHIN GROUP (ORDER BY pair_num)

  THAT cleaned

  OF split_data

  GROUP BY id, comments

  ORDER BY id

  ;

  The 2nd argument of REGEXP_SUBSTR above is actually the same as the 2nd argument of REGEXP_COUNT.  I wrote one of them in a more detailed form, hoping to make it clear what happens if has been done.  You can write an expression so be it.

  The result is just what you asked:

  ID CLEANED ORIGINAL
  --- ---------------------------------------- ---------------------------------
  1 #title #title

  2 #title#publisher #title#pu
      blisher

  3 #title#publisher #title#pu
      #pages<30> blisher#pages<30>

  4 #title<>

  5 #title<>#publisher #publisher

  6 #title #title#pu text
  is not marked #publisher blisher

  7 #title oops I forgot that the rafters whoops # #title forgotten angle br
  Editor ackets #publisher

• I need help you rename a file using regular expressions in Bridge.

  Hello

  I work at a University, and we are working through files for our theses and Dissertations. We were renamed to make them more coherent. I wonder if there is a regular expression that could help in this process?

  Examples come from current file names;

  • THESIS H343G 1981
  • Thesis of 1981 g996e
  • THESIS-1981-A543G

  I just need to change the actual file names. how they are formatted.

  Where appropriate on the thesis.

  Hyphens (-) in all white space.

  First letter, last letter is lower case on appeal no (H343g)

  If the list above should look like;

  • Thesis-1981-H343g
  • Thesis-1981-G996e
  • Thesis-1981-A543g

  I've seen people do some pretty cool things with regular expressions! Any help would be greatly appreciated. Thank you!

  You would be better to use a script to do this as an example because I don't think it would be possible in the new name of bridge.

  Using ExtendScript Toolkit or a text editor to copy the code in any event and save it to sub Filename.jsx

  This must be recorded in the appropriate folder. It is located by going to preferences in Bridge, select Startup Scripts, this will open the folder where the script should be saved.

  Once this is done close and restart Bridge.

  Usage: Goto the Tools Menu and select Rename PDF files

  Be sure to only test the code with some files copied to a separate first folder to make sure it's what you want.

  The script will make all PDF files in the selected folder.

  #target bridge
  if( BridgeTalk.appName == "bridge" ) {
  renamePDFs = MenuElement.create("command", "Rename PDFs", "at the end of Tools");
  }
  renamePDFs.onSelect = function () {
  app.document.deselectAll();
  var thumbs = app.document.getSelection("pdf");
  for( var z in thumbs){
  var Name = decodeURI(thumbs[z].spec.name);
  var parts = Name.toLowerCase().replace(/\s/g,'-').match(/(.*)(-)(.*)(-)(.*)(\.pdf)/);
  var NewName = parts[1].replace(/^[a-z]/, function(s){ return s.toUpperCase() });
  NewName += parts[2]+parts[3]+parts[4]+parts[5].toUpperCase().replace(/[A-Z]$/, function(s){ return s.toLowerCase() });
  NewName += parts[6];
  thumbs[z].spec.rename(NewName);
      }
  };
  

• AFExactMatch and regular Expressions

  Hello

  I'm working on something similar to this http://forums.adobe.com/message/4215772#4215772.

  My first shot at it.  Found it useful messages of try67 and George.  I'm almost there and now, I'm stumped.

  My Custom Format Script is the following:

  Custom Format script for the text field

  If (event.value) event.value += '% ';

  My typing a custom Script is the following:

  Custom keystroke script

  DigOnlyKS();

  My custom calculation script is the following:

  If (event.value == "") event.value = 0;

  My Javascript Document is:

  function DigOnlyKS() {}

  Get everything that is currently in the field

  var val = AFMergeChange (event);

  Refuse entry if other thing that the figures

  Event.RC = AFExactMatch (/ \d* /, val);

  Event.RC = AFExactMatch (/^100\.0| [1-9] {1,2}\.\d{1}|0\.\d{1}$/, val);

  }

  Valid entries must be: 100.0, 1.0 to 99.9, and 0.1 to 0.9.

  The regular Expression seems to work on the Regex testers online.

  However, I can't enter anything in the field with the foregoing.

  If replace my Regex with the link above - ^ \d+\. ? \d{0,2}$ - I can enter data in the field.

  However, if I remove the? the - ^\d+\.\d{0,2}$ - regex to require (I think) the decimal places, I can't enter anything in the field.

  Clearly, Miss something.

  Thank you.

  Regular expression is not appropriate for a typo script until the value has been committed, and even in this case, it may be too restrictive (for example, does not allow for ".") 9 »).

  The way I would be inclined to implement would be to put the strike and Validate Format (not calculate) scripts to call the following functions, respectively.

  // Custom Keystroke script calls this
  function percent_ks() {
  
      AFNumber_Keystroke(1, 1, 0, 0, "", false);
  
  }
  
  // Custom Format script call this
  function percent_fmt() {
  
      AFNumber_Format(1, 1, 0, 0, "", false);
      if (event.value) event.value += "%";
  
  }
  
  // Custom Validate script calls this
  function percent_val() {
  
      if (event.value === "") event.value = 0;
  
      // Only allow numbers from 0 to 100
      if (+event.value >= 0 && +event.value <= 100) {
          // round to nearest tenth
          event.value = util.printf("%.1f", event.value);
      } else {
          event.rc = false;
          app.alert("Your error message goes here.", 3);
      }
  
  }
  

  It lets you enter values outside the valid range, but the validation script takes care of it. It also allows more than one digit to the right of the decimal, but the validation script it rounds up to the tenth closest. Make sense?

  Edit: correction of fault

• Regular expressions in the field of Validation does not.

  I really hope someone can help me.  I'm quite familiar with regular expressions, but for some reason, I can't it to work.

  Environment: Windows XP

  Adobe Acrobat version 8.12

  Scenario:

  In a text field of the form, the user enters a full path.

  This is the code that runs when the user leaves the field:

  / * Test alternatives

  var validChars = / ^ \w [:\\]$/
  var validChars = / ^ \w :\\$/

  var validChars = / ^ [A - Z] [a - z] [0-9] [:\\_]$/

  */

  
  var validChars = / ^ [A-Za-z0-9 :\\_]$/

  If (event.value! = "")
  {
  If ((event.value) validChars.test is false)
  {
  App.Alert ("Invalid character.  Only alphanumeric, colon, underscore, backslask and spaces are valid characters. ») ;
  Event.RC = false;
  }
  }

  The characters allowed in the path are: alphanumeric, underscore, colon, backslash (\), and space.

  I tried all the expressions above with c:\aoa_apps and they all fail: alert the invalid character appears.

  I've added alerts to print the event.value and that seems to be ok.

  I tried all of them with c:aoa_apps and they still fail.  Finally, I tried caoa_apps and they still aren't.

  I checked each of the expressions in a small validator of expression that I have and they seem to be ok.

  I'm cross-eyed looking for a reason why it's a failure.   So, apparently, that I do something stupid, again, I'm new to scripting Adobe Acrobat.  But for the life of me, I can't.

  Can anyone spot the problem?

  Any help is greatly appreciated.

  caerial.

  How you set up your regexp, only the first character is tested. Try

  place a * before the $.

• regular expressions in ActionScript?

  I've been watching the Adobe programming Action Script (pdf) publication and it

  Specifies the ECMA-262 3rd edition specification. But the specification do not seem

  specify exactly what type of version and the regular expression engine is used.

  Is - this POSIX or PERL compatible regular expressions (or both)?

  I have read and used the classic O'Reilly Mastering Regular Expressions text

  and regular expressions encoded in javascript/php/etc. (regular expressions anywhere

  can be used, Apache configuration file, other server configuration files, etc. etc. etc.)

  There is a difference in the type of engine used, while the performance is

  concerned, as well as the range of syntax is valid to a particular implementation.

  Thank you

  JK

  http://www.regular-expressions.info/JavaScript.html