a regular expression question

Similar Questions

• the regular expression question

  I have a table that have the string with the code and the code of description.each and the description is separated by a comma in the platform_desc column and have to compare code platform_desc to get the expected results.
  If there is no match with the code column .we don't have get the entire string. Please see the bottom of the sample data and expected results

  CREATE TABLE Z_TEST1
  (
  code VARCHAR2 (1000 BYTE),
  PLATFORM_DESC VARCHAR2 (1000 BYTE)
  )
  /

  Insert into z_test1 (code PLATFORM_DESC) values ('A', "AEROSTAR");
  Insert into z_test1 (code PLATFORM_DESC) values ('B', "EXPLORER");
  Insert into z_test1 (code PLATFORM_DESC) values (' a ',' CROWN VIC/GRAND MARQUIS ');
  Insert into z_test1 (code PLATFORM_DESC) values ('B','B (EXPLORER)');
  Insert into z_test1 (code PLATFORM_DESC) values ('A', "A (FORD), MA (MERCURY)");
  Insert into z_test1 (code PLATFORM_DESC) values ('B', 'B (BRONCO II)');
  Insert into z_test1 (code PLATFORM_DESC) values ('MA', 'MY (MERCURY)');
  Insert into z_test1 (code, PLATFORM_DESC) values ('MA', ' CROWN VIC/GRAND MARQUIS');
  Insert into z_test1 (code PLATFORM_DESC) values ('A','A (Aero STAR)');
  Insert into z_test1 (code PLATFORM_DESC) values ('MB', 'B (TEMPO), MB (TOPAZ)');
  Insert into z_test1 (code PLATFORM_DESC) values ('A','A (FORD)');
  Insert into z_test1 (code PLATFORM_DESC) values ('MA', ' A (FORD), MA (MERCURY), BC (SEDAN)');
  Insert into z_test1 (code PLATFORM_DESC) values ('B', 'B (TEMPO), MB (TOPAZ), AB (TOYOTA)');
  commit;

  
  Thanks in advance

  Expected data
  
  AN AEROSTAR
  B EXPLORER
  A CROWN VIC/GRAND MARQUIS
  B B (EXPLORER)
  AT A (FORD)
  B B (BRONCO II)
  OA OA (MERCURY)
  MY CROWN VIC/GRAND MARQUIS
  AT A (AERO STAR)
  MO MO (TOPAZ)
  AT A (FORD)
  OA OA (MERCURY)
  B B (TEMPO)

  Hello

  Here's a way

  SELECT code

  REGEXP_REPLACE (platform_desc

  , '(.*, )?' || -anything up to COMMA-SPACE (optional)

  ' (' || -\2 consists of...

  code |

  ' [^,]*' ||     -space, then 0 or more non-virgules

  ')'         || -end \2

  '.*'

  , '\2'

  ) AS out_desc

  OF z_test1

  ;

  Thanks for posting the CREATE TABLE and INSERT statements; It's very useful!

• Regular Expression search and replace question - please help!

  I was wondering if someone could help me I have a lot of paper with notes like this: [1], but I need them to look like in this ^[1].

  I don't know what to put in the section find [[\d]*] , but I need help with what to put in the field replace to make < sup > numbers]

  In fact, your regular expression is false. What you need is the following:

  (\[\d+\])

  The field replace must contain this:

  ^$1

• Allow specific characters - Regular Expression

  Hello everyone

  I am new to the regular expression and I have a very simple question. I use the function "read from the text file" to load a file delimited by tabs with 3 columns in my VI. Then, the string is converted to table and I use the values.

  Nevertheless, I would like to develop a "filter" that allows only digits (0-9), colon, comma , and point to strings.

  Using the function "matches regular expression", I tried a regular expression like this:

  [^ 0-9] | [^\]. [|^:]| [^,]

  But it does not work.

  Could someone help me with this problem?

  Thank you

  Dan07

  Use search and replace with regular Expression String selected.

  

• Can I do regular expressions or Boolean logic in the search?

  Can I do regular expressions or Boolean logic in the search? (Windows + F) Suppose I want to search pdf files or text files. I can go * .txt | * .pdf?

  I searched for about an hour for a simple answer to this and this is the closest, I came, but it still not answering the question.

  Can I use expressions simple boolian in instant search and if yes what are.

  I think that AND and WOULDN'T cover 90% of what I want.

  I want to search for emails for things such as [Minutes AND project x]

  Currently, this property returns all the messeges with minutes and all messages with project x.
  Since I have minutes of many projects, and many emails with project x not the minutes that returns are many.   I would use a simple AND to get the intersection.

  If and expression exist, I have found no reference to it.

  According to me, the back had these expressions in the search function.

  Thank you

• regular expression for the xml tags

  Dear smart people of the labview world.

  I have a question about how to match the names of xml text elements.

  The image that I have some xml, for example:

  Peter

  13

  and I want to match all of the names of elements, that is to say: no, son, grandson, age, regardless of any attribute have these items. There is a regular expression, I can loop, that can do this? (Something like "\<.+\> ". "") It is no good because it matches the entire xml string.) I'd really only two different expressions, one for the match start elements, e.g. and one for the correspondence of the elements, for example.

  Thanks for your help in advance!

  Paul.

  The site Of regular Expressions will be very convenient.

  They have some good tutorials on regexp with a demo of the XML tags:

  Here is a small excerpt:

  The regular expression <\i\c*\s*>matches an opening of the XML without the attributes tag corresponds to a closing tag. <\i\c*(\s+\i\c*\s*=\s*("[^"]*"|'[^']*'))*\s*>corresponds to an opening with a number any attributes. Put all together, <(\i\c*(\s+\i\c*\s*=\s*("[^"]*"|'[^']*'))*| i\c*)\s*="">corresponds to an opening with attributes or a closing tag.  (source)

  If you want advanced XML analysis I suggest JKI XML toolkit.

  Tone

• Regular Expressions do not work

  With the help of sensors 4.X, VMS2.2

  It seems that the normal regualar expressions are not accepted as valid by CiscoWorks. Example:

  If I wanted to match for "Red Duck", but the number of spaces between each letter had to be 0-5 I would use spaces:

  [R] {0-5} e [] {0-5} [d] {0-5} D {0-5} [] u] {0-5} [c] {0-5} k [] {0-5}

  That the expression would be: R e d D uc k, Red D u c k and similar.

  Why they are not allowed in String.TCP?

  SO the question is, WHERE can find a list of regular expressions ACCEPTED, that works with sensors 4.X. I found a list that works with 3.X sensors... it did not work at all. Here, any help would be great.

  Eric

  Duck of red in google returns as red + duck in Google. Space will be replaced by a plus (+) sign or % 20 as it goes over HTTP (the browser for this).

  The regular expression must be (including breaks):

  [Rr] [+] * [Ee] [+] * [JJ] [+] * [JJ] [+] * [Uu] [+] * [Cc] [+] * [Kk]

  You can't repeat a pattern of three characters like [%] 20.

• How can I the date and time using regular expressions

  Hi all

  I have depolyed filtering the log agent. While setting properties, I would like to recover the file that is generated at the present time, but along the way, I am unable to define, what regular expression that I provide retireves date and time specific file...

  Leave with kindness, men know is it possible to do?

  Thanks in advance.

  Shiva

  This seems to be the same question I can't add a timestamp in logfilter, so I'll answer in this thread. Please check the two wires as "Answered" when the issue has been resolved.

  Kind regards

  Brian Wheeldon

• REGULAR EXPRESSION - names of Split.

  Hello guys,.

  I have a question about regular expressions. Here are some names:

  WITH T AS 
  (
  SELECT 'Bill CLINTON' as name FROM dual UNION ALL
  SELECT 'Christiano RONALDO' FROM dual UNION ALL
  SELECT 'Barack Hussein OBAMA' FROM dual UNION ALL
  SELECT 'JUAN JOSE Miguel Ange' FROM dual UNION ALL
  SELECT 'Miguel Ange JUAN JOSE' FROM dual UNION ALL
  SELECT 'RONALDO Christiano' FROM dual
  ) 
  SELECT name
    FROM t;
  

  I want to break this chain. I want something like that

  RESULT:
  Bill           CLINTON
  Christiano     RONALDO
  Barack Hussein OBAMA
  Miguel Ange    JUAN JOSE
  Miguel Ange    JUAN JOSE
  Christiano     RONALDO 
  

  Is this possible? Any idea?

  Thank you guys

  This works with your data, but as Frank said, much more unusually still exists:

  SQL> WITH T AS
    2  (
    3  SELECT 'Bill CLINTON' as name FROM dual UNION ALL
    4  SELECT 'Christiano RONALDO' FROM dual UNION ALL
    5  SELECT 'Barack Hussein OBAMA' FROM dual UNION ALL
    6  SELECT 'JUAN JOSE Miguel Ange' FROM dual UNION ALL
    7  SELECT 'Miguel Ange JUAN JOSE' FROM dual UNION ALL
    8  SELECT 'RONALDO Christiano' FROM dual UNION ALL
    9  --
   10  SELECT 'M''BONGO Jesus' FROM dual UNION ALL
   11  SELECT 'Jesus M''BONGO' FROM dual UNION ALL
   12  SELECT 'Jean-Baptiste POQUELIN MOLIERE MANY OTHER NAMES' FROM dual UNION ALL
   13  SELECT 'Jean Michel JARRE' FROM dual UNION ALL
   14  SELECT 'JARRE HEAD Jean Michel' FROM dual
   15  )
   16  SELECT rtrim(regexp_substr(name, '([[:upper:]'']{2,}[ -]*)+')) as last_name
   17       , rtrim(regexp_substr(name, '([[:upper:]][[:lower:]]+[ -]*)+')) as first_name
   18  FROM t;
  
  LAST_NAME                                                                        FIRST_NAME
  -------------------------------------------------------------------------------- --------------------------------------------------------------------------------
  CLINTON                                                                          Bill
  RONALDO                                                                          Christiano
  OBAMA                                                                            Barack Hussein
  JUAN JOSE                                                                        Miguel Ange
  JUAN JOSE                                                                        Miguel Ange
  RONALDO                                                                          Christiano
  M'BONGO                                                                          Jesus
  M'BONGO                                                                          Jesus
  POQUELIN MOLIERE MANY OTHER NAMES                                                Jean-Baptiste
  JARRE                                                                            Jean Michel
  JARRE HEAD                                                                       Jean Michel
  
  11 rows selected.
  

• regexp_substr: a regular expression for the separate comma operator of witn of string literals IN

  The following regular expression separates simple values separated by commas (SELECT regexp_substr (: pCsv,'[^,] +', 1, level) FROM DUAL CONNECT BY regexp_substr (: pCsv, ' [^,] +', 1, level) IS NOT NULL); Exampple: 300100033146068, 300100033146071, 300100033146079 returns 300100033146068 300100033146071 300100033146079

  This works very well if we use the regex with SQL IN operator select * from mytable where t.mycolumn IN (SELECT regexp_substr (: pCsv,'[^,] +', 1, level) FROM DUAL CONNECT BY regexp_substr (: pCsv, ' [^,] +', 1, level) IS NOT NULL);

  But this query does not work if the comma-separated value is a single literal string 'one', 'two', 'three '.

  Thanks for your reply. my request was mainly on regexp_substr.  Need to request was simple: any table with a column of varchar type can be used. Next time I'll give you an example.

  All ways working answer for my question is is SELECT regexp_substr (: pCsv,'[^, "] +', 1, level) FROM DUAL CONNECT BY regexp_substr (: pCsv, ' [^,"] +', 1, level) IS NOT NULL

• Validation using regular expressions or oracle fn

  Hello

  I want to apply validation to a column. I'm trying to see if I can use the regexp_replace function to find a boss and see if I can replace it to a better format. Can someone help me with these rules?

  1. only the characters a - z, A - Z, 0-9, ', - is allowed. If there are no other characters, then these characters must be removed.

  2. name should not begin with a symbol.

  3. If there is any symbol permitted in the name, (for example the hyphen) then the hyphen should be preceded and followed by a space.

  I would like to know if the above can be obtained by regular expressions or any other function will be useful to achieve the same.

  
  Thank you very much

  Cherkaoui

  HI, Charan,

  Whenever you have a problem, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) of all the tables involved, so that people who want to help you can recreate the problem and test their ideas.

  Also post the exact results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.  Post in this case, maybe 5 or 10 strings, and what you would like to see (a string corrected, or a 'yes' / 'No' flag saying if this string follows rules.)

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: Re: 2. How can I ask a question on the forums?

  2784427 wrote:

  Hello

  I want to apply validation to a column. I'm trying to see if I can use the regexp_replace function to find a boss and see if I can replace it to a better format. Can someone help me with these rules?

  1. only the characters a - z, A - Z, 0-9, ', - is allowed. If there are no other characters, then these characters must be removed.

  2. name should not begin with a symbol.

  3. If there is any symbol permitted in the name, (for example the hyphen) then the hyphen should be preceded and followed by a space.

  I would like to know if the above can be obtained by regular expressions or any other function will be useful to achieve the same.

  Thank you very much

  Cherkaoui

  Sorry, we don't know what you want to do.

  1 seems to mean you want to change the given string so that it follows the rules.  (What exactly are special characters?  Are there only 2 special characters: single quotation mark and hyphen?)

  2 seems to tell us that you want to check if it meets the rules

  3. can be a

  I'll assume that you want to modify the string so that the returned value corresponds to rules.  This means that if the given string violates, 2 symbols will be removed from the beginning of the string, and if it violates 3, then spaces will be added.

  I don't think that there is a way to do this with a regular expression.

  You can make each with a separate REGEXP_REPLACE corrections, and make all in the same query by one nesting inside each other, like this:

  SELECT REGEXP_REPLACE (REGEXP_REPLACE (REGEXP_REPLACE (: str)))

  , "[^ a-zA-Z0-9 cm-]"

  )

  , '^[''-]+'

  )

  , ' *([''-]) *'

  , ' \1 '

  ) AS new_str

  OF the double

  ;

  of course, I can't test it, until post you some sample data and the exact results you want from these data.

  Here, the inner REGEXP_REPLACE rule 1 applies.  It deletes all characters except a to z small letters, capital letters A to Z, numbers, spaces, single quotes and hyphens.

  Rule 2 applies the REGEXP_REPLACE middle.  It removes the single quotes and hyphens that appear at the beginning of the string.

  The external REGEXP_REPLACE rule 3.  It guarantees that each single quotation mark or a hyphen is preceded and followed by a space.  If there is already a space (or several spaces) before and/or after the special symbol, they are replaced by a single space.  If this isn't what you want, it can be fixed, but it will make the expression even messier.

  You might consider to write a user-defined function to normalize strings.  In a function procedure, you can apply the rules one after the other. you need not nesting complicated like that.  Of course, a user-defined function will be slower, but maybe it's not a problem.

  Still, the above query converts the string so that the production rules.

  If you just want to check whether a string conforms to the rules, you can compare the original string to the output of the above expression.  If they are identical, then the string is in accordance with the rules.

• How get us a word in the regular expression

  Hi all

  I am new to regular expressions, I did some tests in Google, but not clearly how to reach the scenario below

  SELECT *
  FROM Icehead tih, head fh
  WHERE  tih.head_id = fh.head_id         
  AND    UPPER (tih.head) LIKE UPPER ('%WANT%') 
  

  The query above, we check a keyword like "WANT."

  -Along with the 'FAULT', we must move to another keyword like 'SHELL '.

  -Have you used or condition operator to above query as shown below

  SELECT *
  FROM Icehead tih, head fh
  WHERE  tih.head_id = fh.head_id 
  and UPPER (tih.head) LIKE UPPER ('%WANTS%') or UPPER (tih.head) LIKE UPPER ('%SHELL%')
  

  -Instead of use 'or' want to use the regular operator, in the future if any other keyword want to use, then we can send this word using dynamically in the process, could help me on this.

  Kind regards

  Sruthitamiri

  Sruthi Tamiri wrote:

  Thanks for your suggestion, I have % in a regular expression, sorry for the same.

  One last point after patten 'i' used what I indicate here, can you explain even.

  It is a match parameter to specify the corresponding case. Please see the documentation for the basic questions like this.

• Regular Expressions of Drivng me crazy!

  Oracle Version 11 GR 2

  Scripts of test data

  CREATE TABLE REGEX_TEST

  (ID NUMBER 4,

  VARCHAR2 (50) COMMENTS

  );

  Insert into REGEX_TEST (ID, COMMENTS) values (1, "< Little Red Riding Hood > #title");

  Insert into REGEX_TEST (ID, COMMENTS) values (2, "#title < Little Red Riding Hood > #publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (3, ' #title < Little Red Riding Hood > #publisher < Penguin > #pages < 30 > ");

  Congratulations to Frank Kulash to provide the following SQL to clean the field of comments only properly marked the text in the field

  Properly tagged text is defined as

  Start by #.

  then nameOfHashTag

  then < valueOfHashTag >

  The number or name of hashtags is variable and is not known at design time

  The Frank provided SQL is (with a slight mod)

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >

  
  

  FIRST QUESTION: I understand the [^ #. * <] * component - search for zero or more occurrences of anything that is not a # tracking of zero or more characters, then a < and I understand the () sets a capturing group, but I don't understand how it works - 1 is probably a reference to the Group?

  Now, I add a few more - lines to see how he treats badly marked text that is

  void <>

  text that is not marked

  text is not enclosed by sharp hooks

  Insert into REGEX_TEST (ID, COMMENTS) values ('4, #title <>");

  Insert into REGEX_TEST (ID, COMMENTS) values (5, "#title <>#publisher < Penguin >");

  Insert into REGEX_TEST (ID, COMMENTS) values (6, "#title < Little Red Riding Hood > text that isn't marked < Penguin > #publisher");

  Insert into REGEX_TEST (ID, COMMENTS) values (7, "#title oops I forgot #publisher < Penguin > rafters").

  
  

  
  

  Original, SELECT comments

  REGEXP_REPLACE (comments

  , '(^|>)[^#.*<]*'

  "\1") that cleaned

  of REGEX_TEST;

  Source language

  
  CLEANED#title < little Red Riding Hood >#title < little Red Riding Hood >#title < little Red Riding Hood > #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title < little Red Riding Hood > #publisher < Penguin > #pages < 30 >#title <>#title <>#title <>#publisher < penguin >
  #title <>#publisher < penguin >#title < little Red Riding Hood > text that is not signposted #publisher < Penguin >
  #title < little Red Riding Hood > #publisher < Penguin >#title oops I forgot the #publisher < Penguin > rafters#title oops I forgot the #publisher < Penguin > rafters

  SECOND QUESTION: Is there any way I can specify that the <>cannot be empty - I played a bit with the +? but impossible to get what I want.  Similarly, the latter (without text no sharp hooks)-I guess this would be impossible because you don't know if it was wong, until you have met the # next date you would be somehow to follow back and ignore the whole group.

  I learned two things in this

  1. regular expressions are extremely powerful

  2. but they will drive you crazy?

  Once again thanks a lot for the help

  BTW - I managed to do what I had to do it using a lot of PL/SQL code, but not very fast!

  Hello

  So, you want only the substrings that are well-formed attribute/value pairs (attribute or value may be missing).  You want to ignore anything in the comments that is not part of a well-formed pair.

  It is not very difficult to get a single well-formed pair.  The problem is that there is no good way to say 'everything that is not part of a well-formed pair '.  One solution is to extract from each pair trained well on a separate line and then re - combine them into a single string by id, like this:

  WITH split_data AS

  (

  SELECT id

  comments

  REGEXP_SUBSTR (comments,

  , '#'      ||  -sign #.

  '[^<]+'  || ="" --="" 1="" or="" more="" of="" any="" characters="" except="">

  '<'      || ="" --=""><>

  '[^>]+'  ||  -1 or several characters any except >

  '>'          -- > sign

  1

  LEVEL

  ) AS well_formed_pair

  LEVEL AS pair_num

  OF regex_test

  ([LEVEL CONNECTION <= regexp_count="" (comments,=""> <> <[^>] + > ')

  AND PRIOR id = id

  AND PRIOR SYS_GUID () IS NOT NULL

  )

  SELECT id

  commented THAT the original

  LISTAGG (well_formed_pair) WITHIN GROUP (ORDER BY pair_num)

  THAT cleaned

  OF split_data

  GROUP BY id, comments

  ORDER BY id

  ;

  The 2nd argument of REGEXP_SUBSTR above is actually the same as the 2nd argument of REGEXP_COUNT.  I wrote one of them in a more detailed form, hoping to make it clear what happens if has been done.  You can write an expression so be it.

  The result is just what you asked:

  ID CLEANED ORIGINAL
  --- ---------------------------------------- ---------------------------------
  1 #title #title

  2 #title#publisher #title#pu
      blisher

  3 #title#publisher #title#pu
      #pages<30> blisher#pages<30>

  4 #title<>

  5 #title<>#publisher #publisher

  6 #title #title#pu text
  is not marked #publisher blisher

  7 #title oops I forgot that the rafters whoops # #title forgotten angle br
  Editor ackets #publisher

• pattern by using regular expressions match

  I'm playing (and wrong) with regular expressions

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + > ') twice;

  give < PSN > - I understand that

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + >, 1.2 ') twice;

  give < 231 > - I understand that

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' < [[: alnum:]] + >, 1.3 ') twice;

  give < ABc > which confused me until I realized that < 3 25 > has not been matched, because it has a space inside

  so I changed it to

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' <. * + > ', 1.3) twice;

  who gave a syntax error, so I changed it again to

  Select regexp_substr (1 < PSN > / # < 231 > # < 3 25 3 > / < ABc > ',' <. * + > ') twice;

  that works, but gives < PSN > / # < 231 > # < 3 25 3 > / < ABc >

  I guess because the. * corresponds to anyting that all but the last closure >

  The question I have is how can I retrieve the text of mounting bracket included (even if it has multiple spaces)?

  Hello

  9c5dfde3-EAAE-45A7-80a1-bba8a71c826c wrote:

  Thanks for that - is there a way to return all 4 surrounded by extracts of <> without resorting to PL/SQL?

  Of course;

  REGEXP_REPLACE (str

  , '(^|>)[^<>

  , '\1'

  )

  Returns a copy of str with all outside rafters removed, for example

  <231><3 25="">

  .  It doesn't matter how many pairs of sharp hooks - there is.

• regular expression format?

  My question hopefully get me flamed, but I have to ask. When adding regular expressions newspaper Pattern Match in a configuration property is as the regular expected perl or java as expression format?
  
  for example, in a box, I entered \bStack_Trace\b/. simply the meaning match any pattern bordered by Stack_Trace?
  
  do I need... / / game characters or make just hack away and hyperic will add the rest?
  or
  do I need to get stuff like this myString.matches("\bStack_Trace\b")
  
  Thanks in advance,
  
  Deeboh

  Sure you can't get flamed for something not well documented nor frequent ;)
  It's just a small wrapper around java.util.pattern:
  http://svn.Hyperic.org/branches/HQ_3_0/src/org/Hyperic/HQ/product/StringMatcher.Java?root=Hyperic+HQ&view=markup

  We should probably add a main() method here for easy test, but you can test log_track from the command line like so:

  ./JRE/bin/Java-Dplugins.include=system - Dlog debug = - Dlog_track.debug = true.
  -jar pdk/lib/hq-product.jar t 'File server file' m - one track log.
  -End = log/test.log '-Dservice.log_track.pattern=\bStack_Trace\b'

  Then another term:
  echo "this is a Stack_Trace for deeboh" > log/test.log (will be)
  echo "this is a HayStack_Trace for dougm" > log/test.log (will not match)