Remove all duplicate table rows
How can I remove all duplicate rows from a tableremove from
It will remove if there are 2 rows then recent will be deleted
where rowid in)
Select max (rowid)
Of
where
Group
having count (*) > 1
)
If 3 or more so that one line will be deleted
You can run the above query re until you found 0 deleted rows.
If there are duplicate of a line 10 rows, you must run 9 times.
There is no single lines deleted in this query.
Tags: Database
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How can I remove all lines with only first line n.
IE if I Ant table with a trial field
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Hello guys,.
I want to know how to find all duplicate of a set of data records, in my application a duplicate is a combination of two columns, I do not want to group them, I want to know all the records duplicates
example of
CREATE TABLE EMPLOYER
(
ID NUMBER (12).
SSN VARCHAR2 (BYTE 9),
WGE NUMBER (10,2).
ERR_flg VARCHAR2 (1 BYTE)
)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (1,222222222,2532)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (2,111111111,2352)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (3,555555555,232)
INSERT INTO EMPLOYER(ID,SSN,WGE) VALUES (4,555555555,232)
3RD AND 4TH RECORDS ARE DUPLICATED... I WANT TO SHOW THEM IN MY QUERY AND UPDATE THE ERR_FLG TO 1
Thank youHello
Here's a way to get the results of a query without grouping:
WITH got_cnt AS ( SELECT id, ssn, wge , COUNT (*) OVER ( PARTITION BY ssn , wge ) AS cnt FROM employer ) SELECT id, ssn, wge FROM got_cnt WHERE cnt > 1 ;
Almost all of the functions of aggregation (such as COUNT) have analytical equivalents, which can produce the same results without collapsing the data in one row per group.
The PARTITION BY an analytical function of clause is the clause GROUP BY of an aggregate query.However, the update, what is wrong with grouping?
You can use something like the query above as a subquery in an UPDATE statement, but you will get the same results more simply with GROUP BY:UPDATE employer SET err_flg = '1' WHERE (ssn, wge) IN ( SELECT ssn, wge FROM employer GROUP BY ssn, wge HAVING COUNT (*) > 1 ) ;
Published by: Frank Kulash, 24 May 2010 15:00
Additional UPDATE... GROUP BY example
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