Replace bundle bundle by name

Similar Questions

• Stupid mistake with Bundle by name

  I recently spent too much time to research an error in the code "that used to work.  So I asked a student to look over my shoulder while I explained what was supposed to happen.  The bug is illustrated in this code snippet:

  

  I do a simple package by name, using a predefined TypeDef to define the cluster.  What I expected to get are indicated on the left, and I have actually is shown to the right.  The code looks the same, but the result is very different!

  My student asked innocently if I saw, in fact, the default value of my TypeDef (answer - Yes).  He then asked if I had connected the TypeDef to the terminal of output "by mistake."  This turns out to be almost right - what I did was to wire the flag, not the Terminal output, but by mistake, to the input Terminal.

  Note the two beige rectangles on the right edge of the boot by name.  The rightmost output, the more to the left is the entrance (this is where the wire to TypeDef comes in).  What I carelessly did was drag a wire from the indicator "far enough" to establish a connection, but, in fact, I dragged too far for that its entry into the entry box.  Here's big plans to correct and bad sons with highlight - it is not easy to see, but the highlighting on the wrong wire extends into the beige rectangle to the left.  If you bring your pointer in very carefully at the junction, you can sometimes see a point of strain on the edge of the function of the bundle, but I couldn't catch him.

     

  Needless to say that this behavior, the ability to 'evil' a bundle by name function wire, was quite unexpected (by me)-I spent most of my time, suspecting of subtle errors in my code and logic, not the errors of cabling!

  You can bet I checked the other places where the beam by a name appears in my code.  I'm posting here in the hope that others do not fall into the same trap.

  Schor (embarrassed) Bob

  Sorry to beat a dead horse, but I wanted some close this topic and comment on some of the useful responses.  A revised version of the extract is also included below.

  • Oligarlicky and tst are correct - I must have inadvertently 'fixed' the original extract before posting, as the code snippet below show fact error (I tested this time!).
  
  
  • TST is also correct that having the Option "Enable automatic wire routing" is enabled (the default behavior) would prevent this problem, with the result the obviously involuntary wireframe diagram of Test 3.  I always disable this Option when I am configuring LabVIEW, I like to control the placement of wire.
  
  
  • Many sons of "misplaced" (or incorrect) seem to be "taken" by the VI Analyzer, so I 'analyzed' this VI.  When I read his conclusions, I said "Oh, he missed the error!  But I was wrong - included an annotation of unused Code that says "service"Bundle by name"has none of its outputs one cable and therefore performs so no useful operation.»  Consider removing this function from your schema. "It was not really until I've created version 'Activate the automatic routing of the wires' reproduced by 3 tests that I realized he was talking (somewhat loosely) on my thread wrong.
  
  
  • One of my colleagues said I should stop wiring "in Hebrew" (creation of my son from right to left) - which could also prevent this error, but I prefer the "Ambidextrous" style of wiring, which means I'm leaving of whatever connection I happen to be nearby and the driver to the everywhere where it should go.

  I hope that I can remember these lessons six months from now...

  Bob Schor

  

• Find and replace function in file names?

  Is it possible to do a find and replace in the names of files, rather than the office or similar?  I have a large list of names of files that all have a problem with them I want to replace, but I don't want to pass by and do each manually!  A better way to do it?

  Rob

  Hello exoticdisease,

  Thanks for posting on the Microsoft answers Forum.

  Select the files in Windows Explorer, press and hold Shift and right click on them. Choose copy from the menu in the path. Paste the list in any editor you prefer. You get the full path for each file, but a simple find/replace will clean up if necessary.

  I don't know if it of what you're looking for or not.

  If please reply and let us know if this solves your problem or if you need further assistance.

  Marilyn
  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• replace white with _ is ok, can (a, o) umlaute replaced also in file names

  Hi all

  I use RoboHelp 8 to import Word documents and generate a WebHelp output.

  When you import the document Word all spaces are automatically replaced

  with the underscore _, is it also possible to reclace automatically umlaute a, o?

  If it is not possible to automatically replace, is this possible

  do it with search - replace (the name of the file, not the title of the topic!)

  Thanks in advance

  Andreas

  Hi Andreas.

  Your options are either replacing the umlaute in the Word file before you import it it (which maybe too many problems) or by changing the properties of the topic within RoboHelp. If you rename topics in RoboHelp, you'll be fine. It is only if the topics are changed outside of RoboHelp you will encounter problems.

• C309A replacement warranty - change of name

  Under an extended Staples warranty, my C309A Photosmart AIO has been replaced due to a jam ADF damage the sensor.  The original machine was shown on the router wireless as the HOST = HP5A814A.   The replacement comes as the HOST = HPD5C23E.  This laptop (wireless) (Vista home premium) has the HP5A814A (printer & fax) showing offline.  The replacement printer then comes as a "web services printer", but I can't seem to recognize the fax.  The HP Control Center says "disconnected".   I have to remove all the entries of printer/fax (C309A), uninstall the Panel & reinstall?

  Thank you.

  Do something fool-proof, and someone will build a better fool (Anon - cited by J. D. Falk)

  You have to define their brand new. It is never as simple as swapping in an identical printer without a configuration...

  Best regards
  ERICO

• Replace VMHostID by host name

  I run the following command:

  Get-VMHost | Get-VirtualPortGroup | Select the name, VirtualSwitch, VirtualSwitchName, VMHostId, VLanId | Export-Csv "PathHere".

  That returns all the information I want, but it puts the VMHostId instead of the host name:

  VMHostId	Name	VirtualSwitch	VirtualSwitchName	VLanId
  HostSystem-home-97975	Service console	vSwitch0	vSwitch0	0

  I don't see Parent or any other similar option under the selection from the Get-VirtualPortGroup. What is the right way to get the actual name of the host instead of the VMHostId?

  The Tee-Object cmdlet is your friend in these cases

  Get-VMHost  | ForEach-Object -Process {
    Tee-Object -InputObject $_ -Variable Temp | Get-VirtualPortGroup |
    Select @{N="VMHost";E={$Temp.Name}},Name,VirtualSwitch,VirtualSwitchName,VLanId}
  

• Scan of the Bundle chain by name

  I would like to take the output of "channel Scan and feed in a bundle by name.» There is no existing group so I wonder if I can use a constant of Cluster for the cluster of the entry. If so how the cluster constant is defined.

  My goal is to read strings ini file sections, split names and boundaries and put them in a cluster or array of clusters that can be stored as inhabitants of TestStand or FileGlobals.

  Thank you

  JVH

  jvh75021 wrote:

  There is no existing group so I wonder if I can use a constant of Cluster for the cluster of the entry. If so how the cluster constant is defined.

  There is something very common to do during initialization - group things upwards into a cluster and carry it around to use throughout the program, in sub - vi, etc.. I am happy that you are not only throw all in local or global sections!

  Yep, you will use just a constant Cluster across the first time it was packaged. Take this constant initial cluster, simply create your cluster of output known > constant. So to answer your question, the constant of cluster is defined by the known output.

  However, if this cluster ever changes during development and it will be , you are going to change every single cluster within sub - vi and an initial constant... or... you'll accompany Ben to advise and do a TypeDef!

• Group by name and not only bundle

  Hi all

  I just got myself used to clusters, son and shift registers instead to use local variables

  I have a simple question that may seem too simple!

  I use a lot of berries and want to use bundle/unbundle by name rather than just bundle/unbundle for obvious reasons.

  But since I was constantly using to initialize arrays, it has no name and so cannot use the bundle by name.

  Is there a way to get around this? (I know nothing!)

  Beginning and end of code attached images.

  Right click on any one of the constants (in) and select 'Visible-> Label', by assigning a label, you can change the name of the element in the cluster.

  Tone

• When I transfer mail, if I click a recipient and hit return, the name of the recipient is replaced by another name in the address book.

  When I transfer the mail on ICC, if I click a recipient and hit back, the recipient's name is replaced by a different name in the address book.

  It's bug and the bug fixers are working on it as soon as possible.

  The error only occurs if you use the key "TAB" or "Enter".
  So if you physically use the mouse to select recipients, and then click on in the other field, etc. - do not use TAB or Enter, then the fault does not occur.
  As an alternative, I highly recommend that you use the following method in the selection of contacts in new e-mail messages or in the transmission of emails.

  In a new message of Scripture
  Use the "Contacts sidebar". See the image below.
  If you do not see, then activate.
  'View' > "Contacts Sidebar" or toggle the view using the f9 key
  Select the address book
  Select the contacts
  Click on the button 'TO Addto' or one of the other options.

• Remove or replace the name of the network (Vista, wired to the router)

  I have 4 computers on my network home (a new laptop and Windows 7 desktop computer and an older laptop and desktop Vista, which are replaced - laptops are wireless).  I had a LOT of problem with printer sharing, especially after a reboot printer goes offline, and I can't find any way to get them back another remove printers and reinstalling (disappointment, disappointment, disappointment) online.  And then I started having problems with one of the Vista (cables to the router) computers access the computer Windows 7 new, also wired to the router.

  Then I will begin first with the last problem.  Trying to get the old wired Office Access/recognize the new desktop windows 7 Wired, I ended up resetting my fairly new Linksys router e2500 to its factory setting - and in the process gained a new network name.  I finally understood how to get the laptops wireless to recognize the new network (should be easy, but it wasn't), but the old wired Vista insists on the use of the former name of network, one that appears in the network and sharing Center implementation.  The other funny thing is that even though she seems to be using the former name of network, I put on Jack autour with her so I don't have Internet access on my old Vista computer.

  I guess that because it is trendy, it seems not to worry about the network name, but it's bothering me because it's not fair.  However, I can't find any way to delete the old name of network.  I spent the day on that and am still confused.  Baffled because it is working and baffled because I can change the name.  I also get a lot of mistakes "Windows cannot access \\myWindows7computername" when I double click on the name displayed in the network folder of Windows Explorer (probably more serious problem).  In any case, I want to address what should be first the problem of easire.

  I discovered enabled network, public folder sharing, which transforms file on the computer discovery and Vista network, sharing the printer and sharing active files (but only on the printer and all the other things of file not checked), and sharing files public computer to Windows 7 (the one with the printers connected to it) - and passwords disabled on both (all computers).

  So my first question is how to make the network name on the Vista desktop wired old deleted/changed/replaced for the new name of the current network.  Why it does not insist in using the former name of network that no longer exists.

  Ron in round rock

  Sorry about that, but I got my answer from another forum, a Linksys Forum - and I will talk about a few things in case other people have this problem/question.

  To remove the network name that appears on the Network Center and sharing, click on the link to customize to the right of the network type - and on the next screen, click on merge or delete network locations, you will / should be able to remove (don't know what fusion done or means) the network with the wrong name, EXCEPT that you can't remove it If it is being used (which is / was the problem I had).  When I unplugged the cable between the computer and the router, I was able to remove the network location (the one with the old name of network), I tried to get rid of.

  Now for the confession.  All this has nothing to do with the name of the network - and most of the things in my original post is just smoke also.  I was going down the wrong path.  It turns out that with computers connected to a router, there is only one network involved and you can call it anything you like and it will work.  There is no selection of a network involved as in the case of a wireless network.

  Network with wired computers name is determined lby network name "you enter" on the screen to customize network settings, the screen you get when you click Customize on the screen of the Network Center and sharing - and you can type in anything you want here.  I'd so go through all this.  I simply had to re - enter the network name on the screen to customize network settings, that is simply a name that you can use for your own reference.

  Ron in round rock

• A Script to find and replace the layer names

  Is there scripts to find and replace the names of layers?

  There is an excellent script available for Photoshop that allows you not only to replace words in layer names, but also insert words as prefixes, Suffixes and sequential numbers.

  The version of the illustrator of this script allows only sequential numbering: it does not offer search and replace words.

  Ideally, it would be great if there were something that could find multiple and replaces in a go:

  (for example

  You have layers like this car, the dog, the bat

  You enter: because (Option1), dog (Option2), Bat (Option3)

  Your layers become then: option 1, option 2, Option3).

  )

  Big_SmiLe, which is a very good start! Step 1 of learning how to Script is indeed, by adjusting an existing simple script to make things more complicated. (And usually then "break something", which is also a necessary part of the process.)

  You are right your comment, it comes to repetitive things. For one or two different articles that wouldn't be a problem, but in the longer lists you are soon lost.

  As usual to work with lists of search - replace is to build a table:

  var layernames = [
  [ 'FHairBowlBoy *Hair', 'Hairboy1' ],
  [ 'FHairCurlyafroBoy *Hair', 'Hairboy2' ],
  [ 'FHairSpikyBoy *Hair', 'Hairboy3' ],
  ];
  

  The general idea is to loop through all the names, check if the current layer name is "layernames [i] [0]" (the left column) and if so, rename it "layernames [i] [1]" (the right column). If you know how to write a loop in Javascript, then you can implement this immediately.

  However...

  A more advanced method to do this didn't need even loop on all layernames - instead you can immediately 'get' the correct name by layer! It's magic! Almost!

  The trick is to use a Javascript object rather than a table. JavaScript objects are nothing special; "Layers" of Illustrator are an array of objects, and each object 'sex' has a 'name' property, which you can read and set the value. What I do here, is to create a new object, where the part 'name' is the name of the original layer and its value is the name of the new layer. All you need to check each layer is if there is a "object.originalLayerName" property and if so, assign its value to this layer name.

  It looks a bit like the table above, except that (1) you use {.} instead of [..] to create an object and (2) you add pairs "name: value" instead of 'value' only (in fact, the 'name' of a value in a table is simply her number).

  So here's what it looks like:

  // JavaScript Document
  var doc = app.activeDocument;
  // name indexed object
  var layernames = {
   'FHairBowlBoy *Hair':'Hairboy1',
   'FHairCurlyafroBoy *Hair':'Hairboy2',
   'FHairSpikyBoy *Hair':'Hairboy3'
  };
  // loop through all layers
  for (var i = 0; i < doc.layers.length; i++)
  {
   //Set up Variable to access layer name
   var currentLayer = app.activeDocument.layers[i];
   if (layernames[currentLayer.name])
   {
    currentLayer.name = layernames[currentLayer.name];
   }
  }
  

  Enjoy!

• Insert into the cluster by string name

  Hello

  I am writing a Labview program to query .NET database management system and get the connected device (like USB CDC) listed with Port of corresponding Com, VID, PID, manufacturer of SN name ect...

  I got to the point where I get the channels I need and want to organize them in a cluster table.

  Here is my code, I wanted a better way to replace section circle of the code.

  Basically, I can get programmatically the cluster name, but when the cluster wads, I can't figure out a way to do it programmatically inside the while loop: a loop on the number of items in the cluster and by placing values in the right place.

  

  Is it possible to do?

  Thank you very much

  Amine

  Altenbach says:

  If the cluster contains exactly three elements of the chain (nothing else!) and they are classified as in the node of your 'bundle by name", all you have to do is on the"table of cluster"output size 3 and it wire in a table build node (upper entrance wired to your array of cluster and botton imput cable to the new cluster) Wired output by the right side of the image).

  Here is a simplified illustration which simply sets the value of the label. (top image). Because the labels are defined at compile time, all you need is perhaps to get the names of once at the beginning of the program, and then use a range of simple string instead.

  Another possibility would be to use the reference to the element to set the value inside the loop, and then get the final cluster value later (at the bottom of the image).

  (There are some simplified examples. All you need is to replace the code that gets your new string instead.)

  

• Group by name graph

  Hello guys =)

  I have a def of Type that contains a cluster. Inside the cluster, there are 4 LEDs Boolean and three numerical indicators. Now I want to add a graphic. Then I drag a chart in the cluster inside type FED. I see all the places where I use my def model to date. BUT. I use offer grouped by name a few places. This list is not updated with the chart. I use the help (CTRL + H), and I see that the thread contains all Boolean leds, digital indicators and a dynamic chart. I try to extend the bundle by name in either sense, and I try to remove it and add a new. Now matter what I do I can not figure in the list of name bundle.

  Do I did wrong?

  Thanks for any help

  Kind regards

  Even

  P.S! I finish work now so I don't have time to attach pictures, but if you need I can do it tomorrow.

  Hi emyh,

  You must give a name to your constant chart. Update inside your typedef.

  Mike

• How to get the name of a class private data controls?

  How can I get the names of the controls within a class private data?

  I use the framework of the actor and try to create a tha method will be executed when run the actor. This method should an o list all names of control inside the data class to find the initial value within a configuration file (config.ini file), the key to the configuration file will be the name of the control.

  Thank you.

  You already do the substitution method just because you write for the bundle by name.  And then how are you going to respond to all types of data might be the key.  You do more difficult things that it takes to really very few benefits.

• Remove the quotation marks the names of channel

  First of all - I'm new to tiara and VB so please forgive my ignorance!

  I have a large data set containing several groups with the same names (or almost) in each group. For reasons not worth going in channel names have quoation marks around them, while others do not.

  I'm trying to remove the quoation marks to standardize all channel names in groups, to do hoped to browse channels renaming groups as the case

  I think it should work: -.

  For

  i = 1 to GROUPCOUNT

  Call GROUPDEFAULTSET (i)

  CN (""ChannelName"" "") = "ChannelName".

  Next

  ChannelName, where is the name that I am trying to replace, but I get the following error:-expected ')'

  Can someone point out where I'm wrong?

  (Note: I also tried to use triple quotes ('' ' ChannelName' ' "), but I get this error instead - CN (" "ChannelName" "" "): = ChannelName Close support" ") ("expected for the index fields)

  Bonus points - how to get the loop jump over all groups where the channel that I'm already referencing isn't quotes in it, rather than giving me an error that the channel can not be found?

  Thank you very much in advance for any help!

  Dan

  Hello Dan,.

  You use the old syntax of script to manipulate the data. Please find below the current way to replace the double quotes with a underscote:

  Dim iLoopG, iLoopC, oGroup, oGroupChns m²
  
  m² = Chr (34) "character".
  Set oGroup = Data.Root.ChannelGroups
  iLoopG = 1 to oGroup.Count
  
    Set oGroupChns = oGroup (iLoopG). Channels
  
    iLoopC = 1 to oGroupChns.Count
  
      ' msgbox oGroupChns (iLoopC). Name
  
      oGroupChns (iLoopC). Name = Replace (oGroupChns (iLoopC). Name, m², '_')
  
    next
  
  next
  
  

  Greetings

  Walter