Request for between two dates.

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• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• get all the date of end of months between two dates

  Hi all, I'll try to find together the date of end of months between two dates.
  I have the following data in a table
  
  WITH AS's Data1
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, "TEST2" lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, "TEST3" lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, "TEST4" lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, "TEST5" lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, "TEST6" lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual
  
  )
  
  I would like to write an application that gives you all the end date for months between two dates
  for example, if you give the date 9/1/4 and 5/6/9, the output should be
  

  DT          LNAME
  -------------------
  4/30/2009   TEST

  IF I give you the dates 01/04/09 AND 01/06/09, THEN output should be

  DT          LNAME
  -------------------
  4/30/2009   TEST
  5/31/2009   TEST7

  as you can see, I want all the end dates of months between two dates by giving the output.
  
  If I give you 06/05/09 and 05/06/09, and then does so no output because there is no end of month between these two dates.
  Similarly, if I give you 30/04/09 and 30/04/09 then output should be 30/04/09 because it is an end of month date
  
  anyone can help to write a query. Thank you very much

  Jin
  Not sure if you need subquery, analytical functions for this.
  According to me, which should solve your purpose.

  WITH data1 AS
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, 'TEST2' lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, 'TEST3' lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, 'TEST4' lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, 'TEST5' lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, 'TEST6' lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual 
  
  )
  select distinct last_day(dt) dt,lname
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
  

  also, i have another request. how would i do this without using the data i provided. lets say,
   i tell you, give me alll the months end between two dates using dual in the from clause of a query.
  how would you do this in a query or pl/sql? thanks again
  

  Can be like that

  with data1 as(
  select &start_date+level-1 dt from dual
  connect by level <= &end_date-&start_date+1)
  select distinct last_day(dt)
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
   order by last_day(dt)
  

  See you soon!
  Bobin

  Published by: Buga added query for updated the need

• MaxL Script to clear the data between two dates

  Hi all

  I need advice to clear the data between two dates, I have three dimensions in my sketch, 'eno', 'hiredate' and the 'actualamount '.

  Now I need to erase the data between the date range, up to now, I have this script,

  Fix ("HireDate", "Eno")

  Difficulty (@relative ("00:00:00",0),@relative("eno",0)) 2015-07-15 "))

  CLEARDATA "sal."

  endfix

  ENDFIX

  These scripts only clears on a specific day, but I tried to write the script to clear between two dates, I surfed on a few sites, but no clear answers, finaanly came here, kindly help in this regard.

  Thanks in advance.

  Have you not tried the format of "startdate":"enddate" for example "August":"September."

  See you soon

  John

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• Number of Saturdays between two dates

  Hello

  How can I get number of Saturdays between two dates, including the two dates?

  for example number of Saturdays between 09/05/2014 and 10/05/2014 is five

  Help, please

  I use oracle 10g

  SQL> with t
    2  as
    3  (
    4  select to_date('05/09/2014 ', 'dd/mm/yyyy') from_dt
    5       , to_date('05/10/2014 ', 'dd/mm/yyyy') to_dt
    6    from dual
    7  )
    8   select to_char(from_dt + (level-1), 'fmDay') day_
    9        , count(*) cnt
   10     from t
   11  connect
   12       by level <= to_dt - from_dt + 1
   13    group
   14       by to_char(from_dt + (level-1), 'fmDay');
  
  DAY_             CNT
  --------- ----------
  Saturday           5
  Thursday           4
  Tuesday            4
  Friday             5
  Wednesday          4
  Monday             4
  Sunday             5
  
  7 rows selected.
  
  SQL>
  

• Months between two dates

  Hello

  I have two dates. start date and end date.

  I want to extract months between two dates

  months should be as

  JAN

  FEB

  MAR

  for example.

  Start - 1-jan-2014

  date of end - 31 - dec - 2014

  How can I do this?

  Thanks and greetings

  CORINE

  You should always use the function MONTHS_BETWEEN...

  for example

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5. Select to_char (add_months (start_date, rownum-1), 'My') by month
  6 t
  7 * connect by rownum<=>
  SQL > /.

  LUN
  ---
  Jan
  Feb
  Mar
  Apr
  May
  Jun
  Jul
  Aug
  Ms
  Oct
  Nov
  Dec

  12 selected lines.

  And if you want that they display, separated by commas...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5 Select listagg (to_char (add_months (start_date, rownum-1), 'My'), ',') group by month (order by rownum)
  6 t
  7 * connect by rownum<=>
  SQL > /.

  MONTH
  -----------------------------------------------------------------------------------------------------------------
  Jan, Feb, Mar, Apr, may, June, July, August, Sept, Oct, Nov, Dec

• Number of occurrences of a day between two dates

  Hello

  I have a requirement in my code to count the number of times per day occurs between two dates. So, for example if

  start date = January 1, 2014

  end date = March 31, 2014

  The number of times that happens day 1 is three times. That's why I want the result to be 3. My three input parameters are the number of the day, start and end dates. I know that this can be done by parsing through the days and incrementing a counter of sorts, but can it be done without any loop etc?

  Looking for options of

  Thank you

  Birdy

  SELECT COUNT (TO_CHAR (DAYS, 'DD')) IN)

  SELECT DAYS START_DATE + LEVEL 1

  FROM T1

  CONNECT BY LEVEL<=>

  WHERE TO_CHAR (DAYS, 'DD') ='&01';

  Post edited by: Parth272025

• How to find days between two dates in days

  Hi, I want to get the days between two dates, expressed in days, how can I do this?  For example, I date i.e. 1 October 10, 2013 (Thursday) and 2 as October 13, 2013 (Sunday).  How can I get a production of:

  Thursday, Friday, Saturday and Sunday, which are the days between Oct. 10-13, 2013.  I hope you understand my point.  Thank you

  You can try something like this

  CURSOR LOAD_PROF is

  SELECT load_prof1, v_time_profile_day

  OF load_profile_test

  WHERE profile_day IN (select TO_CHAR(:day1+level-1,'Day')

  of the double

  connect by level<>

  );

  Kind regards

  S Pax

• Number of weeks between two dates that are in the same or different year

  Hello

  How to calculate the number of weeks between two dates?

  for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014
  

  
  

  Thanks in advance.

  lukx
  

  Hello

  Looks like your date range is incorrect.

  Please try the below.

  SQL >-front right

  SQL > select D2 - D1 "days."

  2 round ((D2-D1)/7.0) "weeks."

  3 round (Months_between (d1, d2), 0) 'months '.

  (select 4

  5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

  6 from two

  (7) date_range;

  Elapsed days weeks months

  ------------ --------- ---------

  46         7         1

• Calculate the (age) years between two dates

  Nice day!

  I have not been able to find an answer, that I was able to use in the archives or online and would be very grateful for the help.  I'm working with Adobe Acrobat Pro XI (not LiveCycle) and I have very little experience with programming (for the most part, copy / paste).

  I need to create a text box that calculates the number of years between two dates entered, i.e. the age when the date of birth and death are given.  Also, would be nice if she was a Virgin until the two were provided.  Anyone would be able to give me the code I need to put in the custom calculation script?

  Once again, any help would be much appreciated!  Thank you and have a wonderful day!

  For the fields for Date of birth DOB and DOD for the Date of death and age in complete years both by using a'd-mmm-yyyy' date format you can use a custom calculation to the JavaScript for the field of age as:

  function GetField (cName) {}
  get the field with error trapping object;
  oField var = this.getField (cName);
  test error;
  if(oField == null) app.alert ("error during the" + cName, 1, 0);
  Returns the field object;
  return oField;
  } / / end GetField function;

  function {Scand (cFormat, cString)
  using date string format convert object date;
  convert string to date using format;
  Kai var = util.scand (cFormat, cString);
  the value null is an error of conversion;
  if(oDate == null) app.alert ("Conversion error" cString "by using the format" + cFormat, 1, 0);
  date of return;
  Return to oDate;
  } / / end Scand function;

  clear the value of the field;

  Event.Value ="";
  get data dob and dod;
  var oDOB = GetField ("DOB");
  Var o = GetField ("DOD");

  treat only if DOB and DOD have value and are not null;
  If (oDOB! = null & o! = null & oDOB.value! = "" & oDOD.value!) = "") {}

  convert the DOB and DOD to date objects.
  oDOB var = util.scand ("d-mmm-yyyy", oDOB.value);
  O var = util.scand ("d-mmm-yyyy", oDOD.value);

  get the difference over the years;
  var Age = oDOD.getFullYear () - oDOB.getFullYear ();

  adjust for month of previous DOD DOB;
  If (oDOD.GetMonth)< odob.getmonth())="">

  adjust the DOD before DOB date in the month of birth;

  If (oDOD.GetMonth () == oDOB.getMonth () & oDOD.getDate ())< odob.getdate())="">
  Set the value of the field;

  Event.Value = Age;
  }

• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

• Need assistance with obtaining data of users modified between two dates in IOM

  Hi all
  
  I have a 11g IOM environment where I need to write a scheduled task that needs to go out the data of users that have been modified between two dates. After the search in the forums, I've had an idea and wrote the following code for the same thing. But it doesn't seem to work. Can someone help me here please?
  
  > //initialize upper and lower attributes to two values of oracle.sql.DATE
  > Criteria1 SearchCriteria is nothing, Criteria2 = null, criteria;
  > criteria1 = new SearchCriteria ("update the", lower, SearchCriteria.Operator.GREATER_EQUAL);
  > Criteria2 = new SearchCriteria ("update the", plus top, SearchCriteria.Operator.LESS_EQUAL);
  > criteria = new SearchCriteria (Criteria1, criteria2, SearchCriteria.Operator.AND);
  > //initialize the necessary parameters, obtain a User Manager object and follow these steps
  > users = umgr.search (criteria, attrNames, settings);
  
  But this doesn't seem to work. Can someone shed light on this you? The attribute "updated on" is not available for this task? If I use a unique 'User login' attribute search criteria, this thing works and gets the user data but this does not work when I use the attribute "updated on" so made me think maybe that this attribute is not available for use via the API or something. Or maybe it's with the help of the oracle.sql.DATE is a problem here. Not sure if. So kindly help me with this.
  
  Thanks in advance,
  $id

  I suggest that create you a real attribute in your scheduled task called something like 'Last Run Timestamp'. The reason why I say this is that you can modify your search on this basis rather than manipulate the date of beginning and end of the last run. To retrieve the value, like any other attribute use this:
  >
  String lastRunTimestamp = hashMap.get ("last Run Timestamp") m:System.NET.SocketAddress.ToString ();
  >
  Format your time you are entered like this: "YYYY-MM-DD hh: mm: zzz ' in order to retrieve and format the value like this:
  >
  SimpleDateFormat time = new SimpleDateFormat ("yyyy-MM-DD hh: mm: zzz");
  recover start date, so it can be updated on the ground on the scheduled task
  Start date = new Date();

  Convert timestamp last executed so far
  Date stamp = new Date();
  timestamp = time.parse (lastRunTimestamp);
  >
  You have now your last time stamp execution that you can set your time dérirez based on.

  And finally, to return the last value of stamp on both scheduled run time, you started this task
  >
  SchedulerService task = Platform.getService (SchedulerService.class);
  Task = task.lookupScheduledTask taskEntry (getName ());
  JobParameter = taskEntry.getParameters () .get ("last Run Timestamp") jobparam;
  JobDetails job = task.getJobDetail (getName ());
  HashMap attributes = job.getAttributes ();
  String timestamp = (time.format (start));
  jobparam.setValue (timestamp);
  Attributes.put ("last Run Timestamp", jobparam);
  job.setAttributes (attributes);
  task.updateJob (job);
  >

  I hope it's useful. This is how I do all my scheduled tasks that need a timestamp.

  -Kevin

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben