run the list of declarations of a user

Similar Questions

• Fast Windows asks me to select a user from the list, but there is no user on the list to select

  Here's how stupid I am. I recently tried a problem with my control panel. I couldn't open half of the icons in the Control Panel folder for "Windows/rundll32.exe is not found" after some internet research, I tried various ways to solve this problem. To resolve this problem, I had to be the administrator. I bought the computer out of Craigslist and have no idea what happened to the previous administrator password. I disabled somehow the administrator user and all users. Essentially, when I start my computer, I gives me the splash screen windows XP telling me to "click on a user" in the list but there is no list of users. My only option is to close. I tried to hit CTRL/alt/del, which brings up a window where the user is the administrator and he asks me for the password that I have no idea what it is. I have looked through the commissioning in BIOS and Boot mode but do not know how I can bypass the first screen prompts the user of Windows XP. I locked myself out of my computer. Someone please Help! The computer came with Windows XP Professional already installed, so I don't have too much of the Windows CD.

  Hi CheddarBob,

  We recommend to start your computer in safe mode and check if you can connect to windows using the default administrator user account. To do this, try the following steps:
  a. start your computer and press the F8 key to display the advanced startup options.
  Hit and b. Select safe mode enter.
  c. connect on the default administrator user account.

  Note: You can also try to start your computer in "Last known good configuration" and check the result.

  See start the computer in safe mode

  If nothing works, then going to use Windows XP disc to continue to solve the problem.

  Visit our Microsoft answers feedback Forum and let us know what you think.

• Export the list of Shared Services Hyperion users [EPM11.1.2.2]

  Hi all

  I used to get the list of users of native directories by using the query:

  Select * from CSS_USERS;

  I watched the rest of the tables of Shared Services and could not find the 'username' of the accounts stored in the external directory. Everything I could find are users AD matching GUID. eg. msad://OBJECTGUID= \f7\70\aa\c1\fb\0f\61\4e\95\b9\e5\f8\1e\8b\23\43? USER

  Is there an easier way to get a list of users provisioned within the Hyperion?

  As a solution, I have manually draw the details of users using LCM. is there a way I could automate this?

  UPDATE *.

  -Version EPM: 11.1.2.2

  Thank you

  Kent

  Finally, I used Utility.sh to export the groups to a file called Groups.csv - it made me the list of AD users added to an indigenous group Directory.

  ---

  Reference for people EPM11.1.2.2 - utility using life cycle management

  For example.

  $ sh Utility.sh /path/Oracle/Middleware/user_projects/epmsystem1/import_export/2013-10-30__NativeDirectory_Users_Groups/Export.xml
  > Enter username - admin
  > Enter the password.

  Migration of artifacts of Foundation/Shared Services/path/Oracle/Middleware/user_projects/epmsystem1/what/2013-10-30__NativeDirectory_Users_Groups/HSS-Shared Services

  Artifact exported - users.

  Artifact exported - groups.

  Migration status - success
  $

• Run the than SP1 2012 LabVIEW VI user on Windows 2000 machines created

  The VI working on (on Windows XP) will have to be implemented on computers different 4: 3 with Windows XP SP3 and 1 with Windows 2000 SP4. This is a new program for us, so we bought LabVIEW 2012 SP1. This version of labview works on Windows XP, Vista, 7, & 8. The corresponding runtime engine runs on Windows XP, Vista, 7 &. As you can see, Windows 2000 is not listed here. I tried to build in an .exe file, but there are corresponding RTE. Is it possible for me to be able to run my VI on the Windows 2000 computer? (Of course, the upgrade of the OS would be a solution, but I would like to avoid this, if possible).

  [I've been messing around with runtimes and the most recent version that could install has TENS of LabVIEW 2009 (no SP1) on the computer running Windows 2000, if that helps at all.]

  Dennis_Knutson wrote:
  Build an exe for 2009 would require you to have a copy of LabVIEW 2009, end. I don't know if your 2012 license would even allow that and if you use some of the features, you will not be able to do the conversion down.

  If you have a license for a version of LabVIEW, you can have every (Older) version installed as well.  You need an active SSP to upgrade well!

  All the new features migrate at least 8.0 (you will get a bunch of warnings in guard and perhaps a very ugly code).

  I would try to avoid support queues (or config file functions) over the limit of 8, 6-2009.  You may see some unexpected changes and prefomace hits.

• The Task Manager XP for a user account.

  How can I Manager tasks for a user reenble? Windows XP SP3.

  DisableTaskMgr
  HKCU
   
  Default range value data type
  REG_DWORD 0 | 1 0
   
  Description
  Prevents users from start Manager (Taskmgr.exe) tasks.
   
  This entry stores the group policy setting disable the Task Manager.
  Group Policy adds this entry to the registry with a value of 1 when you
  enable the policy. If you disable the policy or not configured value
  Group Policy deletes the entry from the registry and the system behaves like
  If the value is 0.
   
  Meaning of the value
  0 (or not in registry) the policy is disabled or not configured. Users can
  Run the Task Manager.
  1 users cannot run the Task Manager. If a user tries to start the task, one Manager
  error message indicating that a policy that prohibits the display.
   
  Task Manager lets users start and stop programs; monitor the performance of
  their computers; view and monitor all programs running on their computers,
  including services system; find the executable names of programs; and change
  the priority of the process in which programs run.
   
   
   
  --
  ..
  --
  "jisgwani" wrote in message news: 3d72d3a7-f6f1-4a4b-a940-7ab5b49a2756...
  > How can I reenble Manager of the tasks for a user? Windows XP SP3.
  >
   
   

• How to add a custom menu in the menu system, as the list of Blackberry contacts

  I would like to add a custom menu tinto menu system, such as the list of Blackberry contacts, when users enter in contact list and select the custom menu, it will open my client and send a few s parametertin my application as the contact name, telephone number, please tell me how and what version of the OS can do this.

  It's still not clear to me what you want to achieve.

  You can use http://www.blackberry.com/developers/docs/6.0.0api/net/rim/blackberry/api/menuitem/ApplicationMenuIt... to add a menu item to some system applications, for example the address book. you get a context object, in a BlackberryContact, you can process or use the address book.

  Your second post seems to allude to http://www.blackberry.com/developers/docs/6.0.0api/net/rim/blackberry/api/messagelist/ApplicationInd... , it is used to place small flags with or without the number, such as that used for unread e-mail messages.

• Display list items based on another element of the list

  Hi all

  I want to display the list item based on another element of the list, but his does not work.

  This is my code:

  
  

  / * WHEN-NEW-FORM-INSTANCE * /-his work.
  DECLARE

  rg_district recordgroup;

  rg_name VARCHAR2 (40): = "district";

  vtemp NUMBER;

  BEGIN

  rg_district: = FIND_GROUP (rg_name);

  IF ID_NULL (rg_district)

  THEN

  rg_district: =.

  CREATE_GROUP_FROM_QUERY (rg_name,

  'select dist, dist district_mas.

  );

  vtemp: = POPULATE_GROUP (rg_district);

  POPULATE_LIST ('BLOCK3.) Of RIDING ", rg_name);

  END IF;

  END;

  * / CHANGED AFTER a - list * /-does not work. Cannot complete the list based on the list

  DECLARE

  rg_branch recordgroup;

  rg_name1 VARCHAR2 (1000): = "branch";

  vtemp NUMBER;

  BEGIN

  rg_branch: = FIND_GROUP (rg_name1);

  IF this is ID_NULL (rg_branch)

  THEN

  DELETE_GROUP (rg_name1);

  rg_branch: =.

  CREATE_GROUP_FROM_QUERY

  ("rg_branch",

  "SELECT FROM dist_branch WHERE district IN branch (DIST DISTRICT_MAS WHERE DISTRICT = SELECT').

  || : BLOCK3. DISTRICT OF

  );

  vtemp: = POPULATE_GROUP (rg_branch);

  POPULATE_LIST ('BLOCK3.) Branch of THE ', rg_branch);

  END IF;

  END;

  Table:
  

  CREATE TABLE DISTRICT_MAS

  (

  DIST VARCHAR2 (100 CHAR)

  );

  CREATE TABLE DIST_BRANCH

  (

  NEIGHBORHOOD VARCHAR2 (100 CHAR),

  DIRECTORATE GENERAL OF THE VARCHAR2 (100 CHAR)

  );

  Values:

  insert into district_mas values ('chennai');

  insert into district_mas values ('coimbatore');
  
  insert into dist_branch values ('chennai', 'chennai_north');

  insert into dist_branch values ('coimbatore', 'Podanur');

  
  

  Concerning

  Nassik M

  I tested the code below when the list has changed

  
  

  DECLARE

  rg_branch recordgroup;

  rg_name1 VARCHAR2 (1000): = "branch";

  vtemp NUMBER;

  QT VARCHAR2 (10): = "';

  BEGIN

  rg_branch: = FIND_GROUP (rg_name1);

  IF this is ID_NULL (rg_branch)

  THEN

  DELETE_GROUP (rg_name1);

  END IF;

  rg_branch: =.

  CREATE_GROUP_FROM_QUERY

  (rg_name1,

  'SELECT branch, branch OF THE DISTRICT WHERE the dist_branch =' | QT | : BLOCK3. DISTRICT OF | QT);

  vtemp: = POPULATE_GROUP (rg_branch);

  POPULATE_LIST ('BLOCK3.) Branch of THE ', rg_branch);

  END;

  Hope it's work...

  Hamid

• Exact match on the top of the list

  Hi all
  
  I have a list as ArrayList < user > where class user contains some fields such as firstname, lastname, and userID.
  Given a string of so-called search "searchString", I need to sort the list in a way that fits RIGHT in the list ON the fields firstname, lastname or userID comes on top and then the other. All entries already satisfied the criteria of partial matching. Just need to get exact matches on top of the list
  
  Example: If an ArrayList < user > contains {{' hominder', 'kumar', 'lpppp'}, {"leethom", "chuu', 'lpppx'}, {'thomas', 'dorothy', 'lxoxp'}, {'paul', 'meyer', 'thomyg'}, {"hom","jones","lwppp"}, {"susana","men","phpfa"}}
  where {'ajay', 'kumar', 'lpppp'} is firstname, lastname and userID of the user, respectively.
  
  {In this case if searchString = "hom", I should get {"hom", "jones", "lwppp"} and {"susana", "men", "phpfa"}} at the top of the list because they are exact matches. Kindly let me know in an effective way of TIME to do this because my site traffic is good and most of them are managers. Any help is very appreciated.

  Simply remove it and then insert it in the front. A LinkedList would be much more effective at this.

• Who runs the CRS demons

  Hello
  
  
  Can someone tell me who runs the following processes in root or user oracle Cluster ready Services?
  
  (1) crsd
  ocssd 2)
  evmd 3)
  (4) evmlogger (process)
  oprocd 5)
  
  Thank you
  Isabelle

  I do not: it's just that you have 2 separate products.

• Only local users appear in the list of connection

  I installed recently to El Capitan on an iMac and have problems with the users network connection settings. The server is running the Mavericks with OS X Server 3

  The first problem is the login screen. If the value to the list only displays the users created locally on the iMac. It doesn't even have the option 'other '.  If I change to display the username and password I can connect to the network no problem accounts, but this is not what I want.

  File Vault is not lit. The parameters are almost all by default. It's one clean and installation other than the connection to the server and allowing the connection of the network user, I made no changes before my first attempt.

  Since then, I created other local and users made changes to the connection options for the test but nothing else.

  The profile on the Server Manager is configured to display the 'other' and a list of users on the network (I changed a couple of times for the test settings, but nothing changes).

  It may be unrelated, but I found that the other changes in the Profile Manager appear to have no effect. For example, I did one of the users of the network, a mobile account, but he is not ready you as mobile on the iMac.

  Can someone give me tips on where to find the next?

  Is there a reason that you use Server3?

• User names found using the command run "control userpasswords2" do not match my user accounts

  Hello, on the #4 computer, when I use the command run, I get a list of 4 users. A, B, C, and comments.
  When I look in Control Panel I see 4 users, A, C, D and comments.
  When I go to C\:Users I see B, C, D and comments.
  I have problems with this computer #4, I get access denied, check the spelling, error code 8007005 0 x.
  All of these accounts should not match in computer #4?

  On my 3 other computers that can network with each other the results of the run command, results of the Panel control and C:\User results all correspond to A, C, D and are same as seen in Control Panel of the computer #4 comments.

  I think that the problem lies in computer #4 and is linked to the user names/accounts do not match. 4 computers user accounts all corresponding in Control Panel, so no problems.

  Don't you think that this problem of networking is related to incompatibility I describe? How can I fix this?   Gift of TIA

  Hello, on the #4 computer, when I use the command run, I get a list of 4 users. A, B, C, and comments.
  When I look in Control Panel I see 4 users, A, C, D and comments.
  When I go to C\:Users I see B, C, D and comments.
  I have problems with this computer #4, I get access denied, check the spelling, error code 8007005 0 x.
  All of these accounts should not match in computer #4?

  On my 3 other computers that can network with each other the results of the run command, results of the Panel control and C:\User results all correspond to A, C, D and are same as seen in Control Panel of the computer #4 comments.

  I think that the problem lies in computer #4 and is linked to the user names/accounts do not match. 4 computers user accounts all corresponding in Control Panel, so no problems.

  Don't you think that this problem of networking is related to incompatibility I describe? How can I fix this?   Gift of TIA

  I finally thought to it. They wore all the user names that came when I ran the command "control userpasswords2". As I said in my original post, user names in all the names of the Panel user control over all matching computers. The only conflict I've had was in the list of user names in the list found when I ran "control userpasswords2". I went to highlight the 'B' account after that I ran the command, you click Properties and changed his name to 'A'. This solved my access denied problem once and for all. Apparently he does not have all of the accounts in the control panel.

  Don

• Wireless hacked; Impossible to remove unwanted users from the list

  I had a wireless network that I used with my laptop. I deleted information wireless network of my laptop (win7) and resumed contact with a cable. I think the network has been hacked because there are about 12 other user names in the list of connection and there should be the name of my computer.

  I have no idea how a wireless router can be hacked, but I know that it can be. I don't know how else these other names could have ended up on top of my list of connection. How can I remove them?

  Also, is there a way to determine if one of these users still have access to my computers, although I have deleted the wireless network?

  Thanks for any help.

  The 12 names of that refer you to are probably wireless networks in your neighborhood.

  To confirm, display all networks the by opening a window run (Windows key + R), type cmd /k netsh wlan show networks mode = bssid (note the six spaces) and press ENTER, or, for a more complete view type cmd /k netsh wlan show all.

• How to make Windows 7 see the list of the user on the login screen, not just the last logged-on user

  I am running Windows 7 Professional 64 - bit and have two user accounts on my computer. Problem is that the login screen shows only the last logged user and one "other users" button which allows you to manually enter the username. Is it possible to return to the display of a list of all users instead?

  Jon

  OK... I found how to fix this problem. I know it's a few years since this topic (and most of the people moved to windows 8) but for those who are still Windows 7 who are tired to type the user name, whenever you log in, here is how to display the icons of the user:

  WARNING: This patch is not a hack. I do not use any third party software. I am simply change a security setting in the windows system. The longest part is to find the file. As much as I would like to say that this will fix all computers, I can't guarantee that this will be the solution for your system. This fixed my problem because my just setting should be disabled. That being said, let's move.

  As an admin (must be in an account that has administrator privileges) click the Start button and in the search at the bottom of the opening bar, the type of menu "Edit Group Policy" and press on enter. When the local Group Policy Editor window appears, click on the following arrows in the left column to expand the lists to find the file to change...

  > Computer configuration

  > Windows settings

  > Security settings

  > Local policies

  Security options<-Click on="" this="" file="" name="" or="" icon="" (the="" arrow="" icon="" won't="" do="">

  In the right menu appears a bunch of system settings, find the one that we called "Interactive logon: do not display last user name" This is the setting which will no doubt say "Enabled" beside him. Right-click on the file and select 'Properties', then disable the setting. Restart your computer and you should be good to go!

• the list of users to Weblogic

  Hello

  Can someone please help me get all weblogic users using the SQL query? Is this possible? I want to do a LOV ADF based on these users form. Can someone help me please in this matter

  By default users are stored in the built-in LDAP server and you can then recover using JMX

  List users and groups in Weblogic using JMX | Middleware wonders!

  If you have an authenticator of database you must then run the corresponding sql query according to the scheme of the DB

  I hope this helps!

  Faisal

• How to define an attribute of the declarative component with the list of options

  12.1.3 jdev

  I'm trying to define a declarative component UOM. It has a text box with a selectOneChoice of the optional codes for this type of unit of MEASURE.

  I have uomType as one of the attributes of my unit of MEASURE. It may be of WEIGHT, VOLUME, LENGTH, etc. Is it possible to provide a list of the channels supported for my uomType? So, when the user uses this component, they can select a type they want in the list, instead of typing in themselves.

  	< afc:attribute >
  	< afc:attribute - name > uomType < / afc:attribute - name >
  	< afc:attribute - class > java.lang.String < / afc:attribute - class >
  	< afc: required > true < / afc: required >
  	< / afc:attribute >

  Thank you.

  Hello

  Unfortunately the lists are not an option with the declarative elements

  Frank