Scene 1, Layer 'as', image1, 24 1050 line: cannot assign a value without reference.

Similar Questions

• Scene 1, Layer 'Actions', image1, line 27 1084: syntax error: expected rightbrace before _01_010.

  I need help with this code please!

  Stop_btn.addEventListener (MouseEvent.CLICK, fl_ClickToPauseVideo_3);

  function fl_ClickToPauseVideo_3(event:MouseEvent):void

  {

  Assets/01_01_010.Fla.pause ();

  }

  Play_Btn.addEventListener (MouseEvent.CLICK, fl_ClickToPlayVideo_3);

  function fl_ClickToPlayVideo_3(event:MouseEvent):void

  {

  Assets/01_01_010.fla. Play();

  }

  Restart_btn.addEventListener (MouseEvent.CLICK, fl_ClickToPauseVideo);

  function fl_ClickToPauseVideo(event:MouseEvent):void

  {

  Assets/01_01_010.fla. Seek (0);

  }

  Tranz_Btn.addEventListener (MouseEvent.CLICK, fl_ClickToPosition_3);

  var fl_TF_3:TextField;

  var fl_TextToDisplay_3:String = "FEMA mission is to support our citizens and first responders to ensure that as long as nation, we work together to build, maintain, and improve our ability to prepare, protect, respond, to recover from and mitigate all risks.»

  FEMA mitigation efforts may reduce risks associated with the events of potential dangers are underway. This course focuses on the operations of FEMA risk mitigation joint offices, which are established after a disaster declaration to focus on mitigation of the effects of future risks of the State affected by the disaster. « ;

  function fl_ClickToPosition_3(event:MouseEvent):void

  {

  fl_TF_3 = new TextField();

  fl_TF_3.AutoSize = TextFieldAutoSize.LEFT;

  fl_TF_3.background = true;

  fl_TF_3.border = true;

  fl_TF_3.x = 200;

  fl_TF_3.y = 100;

  fl_TF_3.text = fl_TextToDisplay_3;

  addChild (fl_TF_3);

  }

  each line with a slash has a problem.

  1. all paths/filenames must be enclosed in quotes.

  2. I don't see any reason, you need to reference a fla in actionscript

  3. you could certainly not apply actionscript as play (), pause () and seek() methods to a fla.

  Bottomline: you have almost certainly incorrect references to what appears to be an instance of the flvplayback component.

• Scene 1, Layer 'actions', image1, line 1084: Syntax error: expecting identifier before plusassign.

  butt.addEventListener (MouseEvent.MOUSE_UP, makeMC);     var mc1:MovieClip = new MYMC();     function makeMC (event: MouseEvent): void {if (clipAdded) {/ / same as if (clipAdded is true) removeChildAt (numChildren - 1);}}  Last added} addChild (mc1);   clipAdded = true; MC1.x = & = 100; MC1.y = 300; MC1. Play(); clipAdded = true; } removeChildAt (numChildren - 1); }} var clipAdded:Boolean = false;     / * child feature (mc1) {clipAdded = true ;} * /}

  Your code is a mess... anyway, it contains the following may be where the problem lies...

  MC1.x = & = 100;

  It is or = or +=, but it cannot be both

• Symbol "LoseMessage", "Reset_btn", image1, 15 1061 line: call to a method may be undefined

  Hi I have a game set in place, when exhaust you your life it takes you to a screen to lose (symbol), on this screen, I have a button called Reset Game.

  The name of the button is 'Reset_btn '.

  The button instance's "resetbtn".

  I have the code in the symbol, and I get this error:

  Symbol "LoseMessage", "Reset_btn", image1, 15 1061 line: call to a method may be undefined for addEventListener through a reference with static type class.

  Here is my code:

  The button Reset code
  resetbtn.addEventListener (MouseEvent.CLICK, Reset_btn);
  function Reset_btn(event:Event):void
  {
  gotoAndStop (1);
  }

  
  I gave my button and the instance name and a name for the button, why am I still get this error, can anyone help?

  Casey

  As I mentioned in my last response, this isn't how you assign an instance name to an object.  Delete what you have done for this button in the library.  Select the button on the stage inside the movieclip and in the Panel properties assign it as the instance name where it say .

• Line arguments command of VI without generating EXE

  I am following this guide: Go of Arguments from the command line to an executable of LabVIEW

  I want to pass arguments from command line in Windows in LabVIEW without having to build my project into an EXE.  I just want a VI that prepares to run when open.

  It's my LabVIEW code:

  

  However when I call my VI by using the command line, I don't see my arguments-user:

  "C:\Program NIUninstaller Instruments\LabVIEW 2009\LabVIEW.exe" "C:\Desktop\LabVIEW Code\test.vi" - test arg1 arg2

  The call above gives only "LabVIEW" as the first command line argument.  I don't see 'test', 'arg1' or 'arg2' in the array of command line Arguments.

  Hmmm... It's disappointing. I just tried with LV 8.5 and it is fine with that also.

  I've been running these sub XP SP3.

  I guess that you have closed completely Labview before running the command line?

  

  

• Assign a value of zero for no. selected lines

  Try to find a way to assign a value to null if my account has no line.
  
  What I have right now is:

  CREATE OR REPLACE FUNCTION count_deductions (empno IN emp.empno%TYPE)
  RETURN NUMBER
  IS
    ded_count      NUMBER(2);
  BEGIN
    SELECT count(deduction_amount)
    INTO   ded_count
    FROM   emp_deductions
    WHERE  fk_empno = empno;
  EXCEPTION 
    WHEN NO_DATA_FOUND THEN
      ded_count :=0;
    RETURN ded_count;
  END;
  /

  Have tried different ways but I still get the message:
  SQL > select * from show_deduction_v where empno = 7169;
  
  no selected line
  
  Instead of the zero value by filling in the field.

  Ok. So the problem is that the view returns no rows. It has nothing to do with the service. The function returns 0 if there is no such thing as the EMPNO spent. The problem is that there is no line in the EMP with a 7169 EMPNO. This means that the function is never called.

  Why do you want the view to return a row for an EMPNO that does not exist? Is there a table somewhere in the database where a 7169 EMPNO is? If so, your vision may outer join to that table.

  Justin

• Convert multiple lines in a single value separated by commas

  Is is possible to convert multiple lines in a single value by concatenating the value of each line in OBIEE. I think that IO had seem a blog related to this by I'm not able to find him. Essentially, here's what I would do:
  Number of customer location
  101
  101 NY
  101 PA
  102 TX
  102 CA
  
  This is to convert
  101. HE, NY, PA
  102 TX, CA
  
  Can you get it someone please let me know if this is possible and how to operate it.
  
  Thanks in advance for the help.

  You can do this by creating a DB function,

  Visit this link
  Re: Display of the horizontal values

  Thank you
  Vino

• Follow-up - how can I order lines based on a value from column to HFR

  As discussed in my question on queries Top, I have a column that I ordered highest to lowest on a report.
  
  I have now, thanks to mballo, have a column of row (still hidden) as well as the column that contains the values. I have 25 rows. My use of the Rank ([M, 1:25].ifNN(-1), descending) provides values but no order.
  
  How can I get the lines sorted by the values in a particular column, then the first line has the highest value and the rest in descending order?
  
  J

  In the property sheet of grid, there is an option "comes out" about 1/2 at the bottom of the page. Once activated it will bring up a window that allows you to apply the sorting. You can take specific lines or all the rows and then apply that based on a column. Or vice versa.

• Two lines with the same value (in a single pass) but a different value (in another pass)...

  Hello
  I have the following table:
  create the table pp_status (ppid number (10), ppdescr varchar2 (20),)
  (1) number, varchar2 (4)) bordered;
  The ppid is the primary key.
  
  where: the ppid Gets the values of a sequence, status may have values (0, 1, 2) and bordered of... years.
  Thus, some values of line may be as follows:
  insert into pp_status values(1,'XX',0,'2009');
  insert into pp_status values(2,'XXY',0,'2010');
  insert into pp_status values(3,'XXT',1,'2009');
  .....
  
  Now, I want to impose a business rule in which declaratively:
  If and only if both lines have values of shell (as in row 1, 3 in the example above lines) but different data values in the neck of status (and specifically the values 0 and 1 (not 2), as in the lines of the sample 1 and 3) then the second row (that is, the third row in the whole of the sample) is permitted , otherwise not. For example, the following lines:
  insert into pp_status values(3,'XXT',2,'2009'); {because of the whole first line was inserted}
  insert into pp_status values(3,'XXT',0,'2009'); {because of the whole first line was inserted}
  
  should not be allowed...
  
  Is it possible to achieve without writing code... I mean the declaratively.
  
  Note: I use DB10g v.2
  
  Thank you
  SIM

  SIM,

  It's an interesting challenge, which requires two unique indexes to solve declaratively:

  SQL> create table pp_status(ppid number(10),ppdescr varchar2(20),
    2  status number(1) check (status in (0,1,2)),firstyear varchar2(4));
  
  Tabel is aangemaakt.
  
  SQL> create unique index ui1 on pp_status (firstyear,decode(status,2,0,status))
    2  /
  
  Index is aangemaakt.
  
  SQL> create unique index ui2 on pp_status (firstyear,decode(status,2,1,status))
    2  /
  
  Index is aangemaakt.
  
  SQL> insert into pp_status values(1,'XX',0,'2009');
  
  1 rij is aangemaakt.
  
  SQL> insert into pp_status values(2,'XXY',0,'2010');
  
  1 rij is aangemaakt.
  
  SQL> commit
    2  /
  
  Commit is voltooid.
  
  SQL> insert into pp_status values(3,'XXT',2,'2009');
  insert into pp_status values(3,'XXT',2,'2009')
  *
  FOUT in regel 1:
  .ORA-00001: Schending van UNIQUE-beperking (RWIJK.UI1).
  
  SQL> insert into pp_status values(3,'XXT',0,'2009');
  insert into pp_status values(3,'XXT',0,'2009')
  *
  FOUT in regel 1:
  .ORA-00001: Schending van UNIQUE-beperking (RWIJK.UI1).
  
  SQL> insert into pp_status values(3,'XXT',1,'2009');
  
  1 rij is aangemaakt.
  

  Kind regards
  Rob.

  PS: why the hell proclaim the year varchar2 (4) instead of number 4?

• State of color lines based on a value in the same row

  I would like to color report lines based on a value in the same row.
  
  For bolting with the table 'EMP ':
  
  I would like job = MANAGER and Red work = CLERK to be green etc etc.
  
  The other example I found was the possibility of a single color either the nail or the default color.
  
  I'm looking for a way to do multiple colors.

  Hello

  In the model line, you can use #1 #, 2 # #, etc. to indicate where a field in the report should be released. It doesn't have to be clear - that is to say, you can use it in style tags if you wish.

  So take a query such as:

  SELECT EMPNO,
  ENAME,
  DEPTNO,
  DECODE(DEPTNO, 10, 'green', 20, 'red', 30, 'cyan', 'white') BG_COLOUR
  FROM EMP
  

  You get the column 1 = empno, 2 = ename, 3 = deptno and 4 = bg_colour. In the model line, you can then do:

  Before defining lines (implements the table):

  <table>
  <tr><td>ID</td><td>Name</td><td>Dept</td></tr>
  

  After setting (farm table) lines:

  </table>
  

  Model 1 (used for all lines) line:

  <tr style="background-color:#4#;"><td>#1#</td><td>#2#</td><td>#3#</td></tr>
  

  Then, for each row, the color that has been calculated by using the DECODE function is used in the style tag for color the background of the whole line.

  How to determine the colors, it's you. I used DECODE here, but you can use a field on the DEPT table to hold and use it in your SQL statement.

  Andy

• Why photoshop create new shape layer whenever I draw a line?

  Hi guys

  I try to draw a bunch of lines, but Im having a problem. I start with a blank page, then I create a new layer. There are, I have the line tool and draw a line under this layer. That layer because that immediately a layer of "shape". Then I draw another line, and rather than stay on the layer, it makes a new layer of 'shape' and mask the previous layer. This continues and and for each line, it makes a new layer and previous mask. Why he continue to create new layers? I want that all the lines stay on the same layer.

  Thanks for your help

  Alex

  As c.p you said "almost."  Choose 'Combine shapes' in this dialog box, Options bar.

  

• Scene 1 layer Actions 1120: access of the window using the undefined property!

  I'm really new to Flash and I use the current CC of Flash to create a banner with the evolution of the images and a button that target changes for each slide.

  I'm in a HTML Canvas and everything seems to work okay in test Ctrl + entry with the button goes to different pages.

  5 errors occur when I export to SWF Movie

  Scene1, layer, frame 1 line 4 column 2 1120: access of undefined property window.

  Scene1, actions layer, frame 40 line 4 column 2 1120: access of undefined property window.

  Go looking around, it seems to be the button actions that I used code snippets for.

  Actions: Frame1

  this.buttonOne.addEventListener ("click", fl_ClickToGoToWebPage);

  function fl_ClickToGoToWebPage() {}

  window.open ("http://www.fireflybbq.eu/#!") ("product/prd1/2832376001/kansas-sweet-%26-smoky-bbq-rub", "_blank");

  }

  Actions: Frame 40

  this.buttonTwo.addEventListener ("click", fl_ClickToGoToWebPage_2);

  function fl_ClickToGoToWebPage_2() {}

  window.open ("http://www.fireflybbq.eu/#!") ("rub / c1faw", "_blank");

  }

  Im not sure what is wrong with the code as it runs in the test, but not in the export any help would be appreciated

  This should work for a publication of html5, but not for a swf file

  to a swf file, you must use actionscript, not javascript window.open is the javascript code.

  Use the externalinterface class call javascript in html file swf or navigateToURL incorporation

• Intro, layer 'AS3 hand', frame 2, line 14 1119: access to property may be undefined, click on by

  The last line of code (found on frame 2) below reproduces this error, why?  Yes, frame 2 has the button on the stage with the name of the instance 'normalScreenClickHandler '.

  function normalScreenClickHandler(e:MouseEvent):void
  {
  gotoAndPlay (5);
  }
  normalScreenButton.addEventListener (MouseEvent.click, normalScreenClickHandler);

  Kind regards

  Ron

  Use CLICK... case questions

• Get rid of BarChart legend and create a horizontal line to a specific value

  Hey,.
  I work with barregraphes.
  1st screen: I want to disable the legend of my Barchart.
  http://imgur.com/wMo6Tfv, DRiNA9C
  Second screen: I want to create a line in my Barchart on a specific value 700 as seen on the screen.
  http://imgur.com/wMo6Tfv, DRiNA9C #1
  Is this Possible? Also: what object to set the ID to change the color bar. I tried
  
  Chart histogram;
  barchart.setId ("Chart");
  
  CSS:
  #barchart
  {
  -fx-background-color: red;
  }
  But it did not work. Thank you!

  No, you do not miss anything. I had a temporary brain freeze. You can add nodes directly to an arbitrary region.

  If this makes it a little harder. You need to add the line to the container in which your chart is maintained, and of course this means that you understand the coordinates of the line relative to this container. To simplify a bit, axis has a scale property of conversion of units of the axis to display units, and also according to the docs of css, the table has a child with the css class "table-horizontal-zero line." So one possible strategy is to enter this line and figure the change in the coordinates needed him. There is still work to do to find the correct coordinates relative to the container, and if you want it to run with things move (for example, when the user resizes the window), you need to do a lot of link.

  This seems to work:

  import java.util.Arrays;
  import java.util.List;
  
  import javafx.application.Application;
  import javafx.beans.binding.DoubleBinding;
  import javafx.beans.property.DoubleProperty;
  import javafx.beans.property.SimpleDoubleProperty;
  import javafx.event.ActionEvent;
  import javafx.event.EventHandler;
  import javafx.scene.Node;
  import javafx.scene.Scene;
  import javafx.scene.chart.CategoryAxis;
  import javafx.scene.chart.LineChart;
  import javafx.scene.chart.NumberAxis;
  import javafx.scene.chart.XYChart;
  import javafx.scene.control.Button;
  import javafx.scene.layout.AnchorPane;
  import javafx.scene.layout.BorderPane;
  import javafx.scene.layout.Region;
  import javafx.scene.shape.Line;
  import javafx.stage.Stage;
  import javafx.util.StringConverter;
  
  public class LineChartSample extends Application {
  
    @Override
    public void start(Stage stage) {
      stage.setTitle("Line Chart Sample");
      final CategoryAxis xAxis = new CategoryAxis();
      final NumberAxis yAxis = new NumberAxis();
      yAxis.setTickLabelFormatter(new StringConverter() {
  
        @Override
        public Number fromString(String string) {
          return Double.parseDouble(string);
        }
  
        @Override
        public String toString(Number value) {
          return String.format("%2.2f", value);
        }
  
      });
      xAxis.setLabel("Month");
  
      final LineChart lineChart = new LineChart(
          xAxis, yAxis);
  
      lineChart.setTitle("Stock Monitoring, 2010");
      lineChart.setAnimated(false);
  
      final XYChart.Series series = new XYChart.Series<>();
      series.setName("My portfolio");
  
      final List> data = Arrays.asList(
  
      new XYChart.Data("Jan", 23),
          new XYChart.Data("Feb", 14),
          new XYChart.Data("Mar", 15),
          new XYChart.Data("Apr", 24),
          new XYChart.Data("May", 34),
          new XYChart.Data("Jun", 36),
          new XYChart.Data("Jul", 22),
          new XYChart.Data("Aug", 45),
          new XYChart.Data("Sep", 43),
          new XYChart.Data("Oct", 17),
          new XYChart.Data("Nov", 29),
          new XYChart.Data("Dec", 25));
  
      series.getData().addAll(data);
  
      final AnchorPane chartContainer = new AnchorPane();
      AnchorPane.setTopAnchor(lineChart, 0.0);
      AnchorPane.setBottomAnchor(lineChart, 0.0);
      AnchorPane.setLeftAnchor(lineChart, 0.0);
      AnchorPane.setRightAnchor(lineChart, 0.0);
      chartContainer.getChildren().add(lineChart);
  
      Button button = new Button("Show line");
      button.setOnAction(new EventHandler() {
  
        @Override
        public void handle(ActionEvent event) {
  
          final double lineLevel = 35;
  
          final Region chartRegion = (Region) lineChart
              .lookup(".chart-plot-background");
  
          final Line zeroLine = (Line) lineChart
              .lookup(".chart-horizontal-zero-line");
  
          final DoubleProperty startX = new SimpleDoubleProperty(0);
          final DoubleProperty endX = new SimpleDoubleProperty(0);
          final DoubleProperty y = new SimpleDoubleProperty(0);
  
          startX.bind(new DoubleBinding() {
            {
              super.bind(chartRegion.boundsInParentProperty());
            }
  
            @Override
            protected double computeValue() {
              double x = chartRegion.getBoundsInParent().getMinX();
              for (Node n = zeroLine.getParent().getParent(); n != chartContainer && n.getParent() != null; n = n.getParent()) {
                x += n.getBoundsInParent().getMinX();
              }
              return x;
            }
          });
  
          endX.bind(new DoubleBinding() {
            {
              super.bind(chartRegion.boundsInParentProperty());
            }
  
            @Override
            protected double computeValue() {
              double x = chartRegion.getBoundsInParent().getMaxX();
              for (Node n = zeroLine.getParent().getParent(); n != chartContainer && n.getParent() != null; n = n.getParent()) {
                x += n.getBoundsInParent().getMinX();
              }
              return x;
            }
          });
  
          y.bind(new DoubleBinding() {
            {
              super.bind(chartRegion.boundsInParentProperty(),
                  yAxis.scaleProperty(), zeroLine.startYProperty());
            }
  
            @Override
            protected double computeValue() {
              double y = zeroLine.getStartY() + lineLevel * yAxis.getScale();
              for (Node n = zeroLine.getParent().getParent(); n != chartContainer && n.getParent() != null; n = n.getParent()) {
                y += n.getBoundsInParent().getMinY();
              }
              return y;
            }
          });
  
          Line line = new Line();
          line.startXProperty().bind(startX);
          line.endXProperty().bind(endX);
          line.startYProperty().bind(y);
          line.endYProperty().bind(y);
  
          chartContainer.getChildren().add(line);
        }
  
      });
  
      BorderPane root = new BorderPane();
      root.setCenter(chartContainer);
      root.setTop(button);
  
      Scene scene = new Scene(root, 800, 600);
      lineChart.getData().add(series);
  
      stage.setScene(scene);
      stage.show();
  
    }
  
    public static void main(String[] args) {
      launch(args);
    }
  }
  

• HP Deskjet 1050 J410 cannot print in black and white

  Hey everybody,

  My HP Deskjet 1050 J410 on 64-bit Windows 7 is unable to print in black and white, even after selecting the option to do so. There is no error message, and the diagnostic tool on the HP site can not solve this problem too.

  Your help is appreciated.

  Hello world

  Follow the steps described in the following document below.

  Troubleshooting print quality problems