See questions based on SQL.

Similar Questions

• When users who are working with an Application based on SQL (accounting), application suddenly closes!

  When users working with an Application based on SQL (accounting), application closes without prompting.

  We have virtual server Hyper-v with SQL server 2008 sp1 - other departments report no problem just for accounting

  They can't really work...

  Thank you

  Hadad

  These MS Answers forums are intended for the home rather than the it professional user. I suggest therefore that repost you your question in the forums MS Technet here:

  http://social.technet.microsoft.com/Forums/en-us/categories/ .

  (I'm sorry, but I can't move this thread for you because the two forums are working on separate platforms)

• Firefox does not open or does not (see/questions/964132)

  was Ok until recently

  Please include more information, such as your operating system (Windows?) and the version, more exactly what is happening when you try to start Firefox. The information provided in a recent Firefox crash report, if any, can also help. See Firefox plant - troubleshoot and prevent assistance fixing crashes under help in setting this crash and post any crash report IDs recently (they start with bp - )

  The title of your question, says "Firefox does not open or does not (see/questions/964132)" I have reviewed this issue and it was launched by another user of Firefox. /questions/964132? page = 2 # 477049 answer has a number of suggestions if Firefox does not start. Which have you tried?

  To see other possible solutions

  • Troubleshoot and diagnose problems in Firefox
  • http://KB.mozillazine.org/Browser_will_not_start_up
  • / issues/958850 Firefox does not open after a reboot

  Note: A "clean and reinstall" was one of the suggestions/issues/964132. This means remove the Firefox application and then files by reinstalling Firefox since a new download, as explained at the stage of "Reinstall Firefox" in troubleshoot and diagnose problems in Firefox. So that allows you to start Firefox, but if the problem comes back after the computer restarts, you should make another "clean reinstall" and then resolve your plugins by disabling all, as suggested by the troubleshoot and diagnose problems of Firefox article.

• total run time based on sql id?

  Hello

  I wrote under query to find out the total run time sql and total executions happened based on sql id for each date. Can you get it someone please let me know if the output below is correct?

  SQL> SELECT
    trunc(begin_interval_time, 'DD'),
    ROUND(sum(elapsed_time_delta)/1000000) "Total Execution Time (sec)",
    ROUND(sum(executions_delta)) "Total Execution"
    FROM dba_hist_sqlstat a
    JOIN dba_hist_snapshot b
    ON a.snap_id = b.snap_id
    WHERE sql_id        = '8acg09uq48jzk'
    AND executions_delta>0
    GROUP BY trunc(begin_interval_time, 'DD')
    ORDER by trunc(begin_interval_time, 'DD') DESC;
  
  
  TRUNC(BEG Total Execution Time (sec) Total Execution
  --------- -------------------------- ---------------
  01-AUG-14                        160          122078
  31-JUL-14                       9309         1822147
  30-JUL-14                       6667         1845014
  29-JUL-14                       6196         1873091
  28-JUL-14                     277268         1517005
  27-JUL-14                      78546          794048
  26-JUL-14                       1359         1166650
  25-JUL-14                       7665         1826915
  24-JUL-14                       6786         1907862
  23-JUL-14                       8132         2019695
  22-JUL-14                       6611         1948861
  
  
  TRUNC(BEG Total Execution Time (sec) Total Execution
  --------- -------------------------- ---------------
  21-JUL-14                       7980         2948449
  20-JUL-14                       3226         3554316
  19-JUL-14                       3405         3222148
  18-JUL-14                      10179         2478602
  17-JUL-14                       7950         1972643
  16-JUL-14                       8465         2054012
  15-JUL-14                       8483         2248688
  14-JUL-14                       8644         2243460
  13-JUL-14                        942         1478516
  12-JUL-14                        985         1075398
  
  
  

  Generate AWR report during the period of interest and you will get more information.

  Apart from that, what problem you ar trying to solve. Please explain that

  You can also use the following, because you are looking for particular sql

  awrsqrpt. SQL > for individual ssql

  awrsqrpti. SQL > for sql on a particular instance... (useful in case of CARS)

  Kind regards

  Harman

• Best practical Question - update the query (see object) based on the drop-down list selection

  I have a question about the most efficient way to perform the following task:

  I create a page that contains several DVT components to display data based on specific requests.  Top of page I am hoping to have a drop down menu (selectOneChoice) that contains dates different and based on what the user selects (i.e. 2010, 2011, 2012, 2013, etc.), this will update the query in the view object of some (i.s. WHERE Date = '2011', or WHERE Date = 2013"), and then you view the appropriate data in the DVT.  What is the best way to do this - from a point of view bean managed / page, as well as the View object?  Advice/documentation would be appreciated.

  Thank you!

  When you drag the vo executeWithParams one another that will create links for operations such as 'executeWithParams2', 'executeWithParams3 '. On the method that you use to update a view by calling the executeWithParams operation, you call the other operations too.

  Timo

• 2 newbie question on Oracle SQL Developer

  Hello world
  
  I just started using SQL Developer (1.5.1), the question can seem easier (can not find FAQ...), any help will be appreciated.
  
  1. How can I turn on result of the query grid, not clear?
  2. How can I see the retail package compile error message in SQL Developer?
  
  
  Thank you!
  
  Lei

  Hello

  In fact, you can look at it SQL Dev demo.
  1. run the query using F9 or CTRL + ENTER.
  2 If you look on the underside of the SQL Dev, there is a dockable panel (Log - compiler tab) that shows you the warning message, error, etc.

  Kind regards

  Buntoro

• See questions about the Satellite A205-S5859

  I would like to know the following:

  1. is there a problem with the speakers of this first use. The volume deteriorates. You will need to set to 100.

  2. can I put the car in a dedicated video video?

  3. What is the maximum memory for this model? Where is the memory chip?

  One of my friends has a laptop A200. It s not A205 but very similar. The A205 is designed for the American market and the A200 to the European market.

  So finally, I can give you some suggestions on the issue:

  (1) any volume questions are not known for me everything works ok.

  (2) No, upgrading the graphics card is definitely not possible

  (3) I guess you'll find this info in the user manual. Did you check that?
  But I think that there is a possibility for an upgrade to 4 GB of RAM. But I do not recommend upgrading the RAM to 4 GB due to the limitation of the 32-bit operating system. All the 32-bit OS s can manage 3.2 GB RAM max.
  Finally, the position of the slots memory; I think that it s at the bottom of the unit.

  See you soon

• LabVIEW basics - Cahnging Boolean State question based on the input signal

  Hi all

  I would like the State to change the Boolean indicator based on a simulated sine wave signal. I have partially managed to do this but need help to develop it.

  See the attached vi. At the present time changes Boolean false to true when the value of the signal is greater than 8 or lower than-8.

  The focus I need is:

  Once the signal passes more than 8 (and the Boolean value becomes true), I hope it becomes false again to a value of 9, but only after the peak value was passed or when the signal is down.

  Similarly on the negative side of the graph, I want the Boolean value to become reality at 8-under, stay true until after the peak value was passed and then back to false when the value is greater than-9.

  Any suggeastions?

  Thank you

  While Crossrulz responded, I had a little look.

  Don't let me spoil your pleasure with the VI attached. Have a go yourself.

• Journal inisght - question content pack SQL

  Hello

  Seems to me a mistake with happy pack SQL Log Insight.

  Environment - Log Insight 2.5 (problem also on version 2.01), Windows Journal Insight client version 2.5, MS SQL 2008R2 and Server Windows 2012

  in the log file, I came across this article:

  2015-01-12 16:51:25.407580 0 x 00001414 < error > FLogCollector:1357 | Specification of missing or invalid directories.

  2015-01-12 16:51:25.407580 0 x 00001414 < error > FLogCollector:207 | Invalid parameters were obtained for the channel "MSSQL." Channel < filelog | MSSQL > will remain inactive until this as correctly configured.

  I have configured the MSSQL entry in the file liagent.ini as:

  [filelog |] MSSQL]

  Directory = Microsoft SQL Server\MSSQL10_50.MSSQLSERVER\MSSQL\Log

  Charset = UTF-16

  Am I missing something here, because it is according to the instructions on the market place?

  I can see data are sent to the insight Journal, only it isn't linked :-(SQL

  any help is very appreciated

  Thank you

  Harold

  There is a typing error in the list, it must be small d for directory.

• Question on query SQL Tuning

  We have made from a 9i database to an 11 g database.  The defined query works perfectly under 9i (about 1 second) but takes 60 to 70 seconds back to 11g.  The strange thing is that it has an outer query and a subquery.  If I remove the where clause of the outer query, it runs in less than a second.  Here's the query...

  SELECT the period, biweek_start, biweek_end, pay_period_complete, worker_count

  FROM (SELECT to_char (en.start_date, ' dd/mm/yyyy') |) « à » ||

  TO_CHAR (en.start_date + 13, ' dd/mm/yyyy') period.

  en.start_date biweek_start,

  en.start_date + biweek_end 13,

  Decode (sign (sysdate - en.start_date - 13),

  -1,

  'Ongoing',

  Pay_period_complete 'Done'),

  ta_mssauth_pkg.actual_endorser (en.start_date, '33811') worker_count

  FROM (select worker_id,

  default_endorser resolved_endorser,

  effective_date,

  correspondents

  of endorse_delegate_history_v

  where default_endorser = '33811'

  Union

  Select worker_id,

  temporary_delegate resolved_endorser,

  effective_date,

  correspondents

  of endorse_delegate_history_v

  where temporary_delegate = '33811'

  and temporary_delegate is not null),

  endorse_activity_v en

  WHERE en.worker_id = de.worker_id

  AND en.endorse_status = n

  AND en.start_date < = de.expiration_date

  AND en.start_date + 13 > = de.effective_date

  GROUP BY en.start_date)

  WHERE worker_count > 0;

  The function that is used in the inner query to generate the worker_counts is quite complex.  But it works subsecond if you run manually.  And it works very well when you run the query without the "where worker_count > 0" part.

  So the where clause of the outer query seems to be the cause of the problem - it is based on a function which should have calculated a value FIRST, and then the outer query must run depending on the result of the inner query.  Here are the plans to explain to the two different versions:

  BAD REQUEST - 60 to 70 seconds

  Object owner name cardinality bytes cost object description
  SELECT STATEMENT, GOAL = 41 1 617 ALL_ROWS
  HASH GROUP BY 41 1 617
  NESTED LOOPS
  616 1 41 NESTED LOOPS
  VIEW CA17062 58 186 4464
  58 186 5392 SINGLE FATE
  UNION-ALL
  TABLE ACCESS BY INDEX ROWID TAS_AUTH ENDORSE_DELEGATE_HISTORY_TBL 42 139 4170
  INDEX RANGE SCAN TAS_AUTH ENDORSE_DELEGATE_HIST_DEF_IDX 3 139
  TABLE ACCESS BY INDEX ROWID TAS_AUTH 14 47 1222 ENDORSE_DELEGATE_HISTORY_TBL
  INDEX RANGE SCAN 3 47 ENDORSE_DELEGATE_HIST_TEMP_IDX TAS_AUTH
  INDEX RANGE SCAN TAS_AUTH 2 1 TA_SCLENDORSE_PK

  TABLE ACCESS BY INDEX ROWID 3 1 17 ENDORSE_ACTIVITY_TBL TAS_AUTH

  GOOD QUESTION < 1 second

  Object owner name cardinality bytes cost object description
  SELECT STATEMENT, GOAL = 1025 25 617 ALL_ROWS
  HASH GROUP BY 1025 25 617
  NESTED LOOPS
  616 25 1025 NESTED LOOPS
  VIEW CA17062 58 186 4464
  58 186 5392 SINGLE FATE
  UNION-ALL
  TABLE ACCESS BY INDEX ROWID TAS_AUTH ENDORSE_DELEGATE_HISTORY_TBL 42 139 4170
  INDEX RANGE SCAN TAS_AUTH ENDORSE_DELEGATE_HIST_DEF_IDX 3 139
  TABLE ACCESS BY INDEX ROWID TAS_AUTH 14 47 1222 ENDORSE_DELEGATE_HISTORY_TBL
  INDEX RANGE SCAN 3 47 ENDORSE_DELEGATE_HIST_TEMP_IDX TAS_AUTH
  INDEX RANGE SCAN TAS_AUTH 2 1 TA_SCLENDORSE_PK
  TABLE ACCESS BY INDEX ROWID 3 1 17 ENDORSE_ACTIVITY_TBL TAS_AUTH

  If these expleain plans look almost identical to me - can someone tell me why having where clause of the outer query is originally so wrong and how I can solve this problem?  I tried using the NO_MERGE and PUSH_SUBQ - tips but nothing of what I did so wrong not better requested.

  Thanks in advance!

  Cory

  You can also try taking advantage of the scalar subquery caching by changing

  ta_mssauth_pkg.actual_endorser (en.start_date, '33811') worker_count

  TO

  worker_count (select ta_mssauth_pkg.actual_endorser (en.start_date, '33811') of double)

  Which could cache the results for recent start dates, massively reducing the number of calls.

  I think the NO_PUSH_PRED is a better approach, because the cache is less reliable to eliminate duplicate calls - it can cache the value, it could have thrown the corresponding value in the cache already, there is no guarantee of behavior and values the more en.start_date the request to meet the less reliable the caching will be.

• question on the sql statement

  Hi expert,
  
  I have after sql statement, the function 'hiroc_get_delta_amount1' and 'hiroc_get_delta_amount2' are used separately in select and where subparagraph. These two functions are exactly the same, except that there is a log insert inside statement. for the 'hiroc_get_delta_amount1' function, newspapers are supposed to write the newspaper of table1, while for the function "hiroc_get_delta_amount2", newspapers are supposed to write the newspaper of table2. After you run this sql, I got the data loaded in the table2 newspaper, however, no data is loaded into newspaper table1.
  
  could you please tell me why there is no data in table2 journal for function
  
  1. sql statement;
  
  Select
  pp.policy_premium_pk,
  pp.policy_fk,
  pp.policy_term_fk,
  pp.risk_fk,
  pp.coverage_fk,
  pp.transaction_log_fk,
  pp.coverage_component_code,
  hiroc_rpt_user.hiroc_get_delta_amount1 (pp.policy_fk, pp.policy_term_fk, pp.risk_fk, pp.coverage_fk, pp.transaction_log_fk, pp.coverage_component_code),
  pp.rate_period_from_date
  PRODBKUPDW_MART.rmv_policy_premium pp
  where pp.rate_period_type_code = 'TERM_COVG. '
  and pp.coverage_component_code <>'NETPREM '.
  and hiroc_rpt_user.hiroc_get_delta_amount2 (pp.policy_fk, pp.policy_term_fk, pp.risk_fk, pp.coverage_fk, pp.transaction_log_fk, pp.coverage_component_code). = 0
  Pp.policy_premium_pk group,
  pp.policy_premium_pk,
  pp.policy_fk,
  pp.policy_term_fk,
  pp.risk_fk,
  pp.coverage_fk,
  pp.transaction_log_fk,
  pp.coverage_component_code,
  pp.rate_period_from_date;
  
  2. Insert the statement used for two functions of journal:
  
  (1) function "hiroc_get_delta_amount1".
  
  insert into HIROC_RPT_USER. Values of LOG_TEST1 (v_start, sysdate,
  p_policy_fk, p_policy_term_history_fk, p_risk_fk, p_coverage_fk, p_transaction_log_fk, p_comp_code);
  COMMIT;
  
  
  (2) function "HIROC_GET_DELTA_AMOUNT_1".
  
  insert into HIROC_RPT_USER. Values of LOG_ZB_TEST_1 (v_start, sysdate,
  p_policy_fk, p_policy_term_history_fk, p_risk_fk, p_coverage_fk, p_transaction_log_fk, p_comp_code);
  COMMIT;

  WRONG FORUM!

  Welcome to the forum!

  Unfortunately, you have posted on the SQL Developer forum which, as the title of the forum is NOT for questions of SQL and PL/SQL.

  Please mark this thread ANSWERED and transfer your question in the forum SQL and PL/SQL
  SQL and PL/SQL

  When repost you your question, you must provide the DDL for the two functions, not only a query in them. And unless these functions use the pragma AUTONOMOUS_TRANSACTION and VALIDATION and then inserts into a table 'log' what they do will be not permanent anyway.

  You will also need to provide the number of rows that the SELECT query returns since if no line is activated, the first function cannot even be called.

  Where this question: why are you recording of information in the context of a still SELECT query? What goal are you trying to achieve this returns the loss of performance you pay?

• Cannot see the developer plus sql or sql table

  I created a folder in the application designer. Then I built the table. I can close the file and then find it in the application designer. But if I go to sql plus and sql developer, I do not see it. Am I missing a step?

  You can probably see all the tables of the sysadm because someone else give you good grant for objects of this existing on sysadm.
  For the purpose of new or modified (drop + create) you should:
  1. log in as sysadm and run

  grant select on new_table_name to your_own_user;
  

  2. connect with your own user and run

  create synonym new_table_name for sysadm.new_table_name;
  

  Then you will be able to query this table without using schema name alias.
  Some admin also have a ddl trigger to make it automatically.
  You can also work with a role and a public synonym if more than one user needs access to the objects of sysadm.

  Nicolas.

• Question based on LEAD with view.

  HII friends,
  
  I use a view in which I used the LEAD feature and I am faced with the question with the first record.
  
  That's my opinion
  
  DROP VIEW APPS. VW_TBL_TEST_1;
  
  CREATE OR REPLACE STRENGTH SEEN APPS. () VW_TBL_TEST_1
  OHR,
  EFFECTIVE_START_DATE,
  EFFECTIVE_END_DATE,
  PREVIOUS_COE,
  PREVIOUS_SDO,
  PREVIOUS_PID,
  PREVIOUS_BAND,
  PREVIOUS_LOCATION,
  PREVIOUS_COUNTRY,
  PREVIOUS_DESIGNATION,
  PREVIOUS_BUSINESS_FUNCTION,
  RUN_DATE,
  PRODUCT_LEVEL1,
  PRODUCT_LEVEL2
  )
  AS
  SELECT THE OFFICE OF THE HIGH REPRESENTATIVE,
  NVL)
  LEAD (EFFECTIVE_END_DATE)
  COURSES (ORDER OF THE OHR, EFFECTIVE_START_DATE DESC)
  + 1,
  EFFECTIVE_START_DATE
  )
  EFFECTIVE_START_DATE,
  effective_end_date,
  previous_coe,
  OF XX_WORK_HIS;
  
  and the output from this point of view of an employee is
  
  OHR EFFECTIVE_START_DATE EFFECTIVE_END_DATE PREVIOUS_COE
  103021253 1 May 10 - AC1
  103021253 15 April 10-30 April 10 company s America
  103021253 23 March 10-14 April 10 company s America
  103021253 1 May 09-22 March 10 business s America
  103021253 5 March 09-30 April 09 company s America
  103021253 10 February 09 - 4 March 09 company s America
  103021253 1 January 09 - 9 February 09 company s America
  103021253 13 August 08-31 December 08 Creditek
  103021253 1 January 08-12 August 08 Creditek LLC
  103021253 13 April 07-31 December 07
  103021253 1-sep-06-12 April 07
  103021253 12 August 06-31 AUG 06
  103021253 8 August 06-11 August 06
  103021253 26 October 10 - 7 August 06
  
  You can check in the last line of the effective Start date is 26 October 10 which is wrong, why it's I don't know.
  
  If I run this directly from the query instead of view, I'm getting the correct record.
  Query-
  
  SELECT THE OFFICE OF THE HIGH REPRESENTATIVE,
  NVL)
  LEAD (EFFECTIVE_END_DATE)
  COURSES (ORDER OF THE OHR, EFFECTIVE_START_DATE DESC)
  + 1,
  EFFECTIVE_START_DATE
  )
  EFFECTIVE_START_DATE,
  effective_end_date,
  previous_coe,
  OF XX_WORK_HIS
  where OHR = '103021253';
  
  Correct record
  OHR EFFECTIVE_START_DATE EFFECTIVE_END_DATE PREVIOUS_COE
  103021253 1 May 10 - AC1
  103021253 15 April 10-30 April 10 company s America
  103021253 23 March 10-14 April 10 company s America
  103021253 1 May 09-22 March 10 business s America
  103021253 5 March 09-30 April 09 company s America
  103021253 10 February 09 - 4 March 09 company s America
  103021253 1 January 09 - 9 February 09 company s America
  103021253 13 August 08-31 December 08 Creditek
  103021253 1 January 08-12 August 08 Creditek LLC
  103021253 13 April 07-31 December 07
  103021253 1-sep-06-12 April 07
  103021253 12 August 06-31 AUG 06
  103021253 8 August 06-11 August 06
  103021253 7 July 03-7 August 06
  
  Check the last row, EFFECTIVE_START_DATE its 7 July 03, which is the correct record.
  
  I don't get if I use same condition in view why I get a bad record in last place.
  
  Please suggest.
  
  Thank you
  Bachan.

  My problem is solved, but can you tell me what is the problem with the query I used and what happens with COMPARTMENTALIZED BY

  See the documentation for the PARTITION BY clause:
  http://download.Oracle.com/docs/CD/B19306_01/server.102/b14200/functions001.htm#i1000371

  ... and a previous thread dealing with the same problem you encountered: {: identifier of the thread = 1044458}
  (Note that the position of Solomon and the link to AskTom)

• question about pl/sql script

  Hi all
  I need to manage other tables that will contain as follows:
  whenever the user query it will be an insert in this table called mng_rishui_session that contain
  track:
  NUM of user's session id,
  Date and time of execution of the request,
  type of query
  every 15 minutes, I need to delete the data of the user of some the various tables according to the type of the query.
  the tables that contain the data:
  mng_rishui_session / / DESC
  session_id_num NOT NULL VARCHAR2 (30)
  type_query not null number (2)
  date of time_query
  I want to write a pl/sql script like this:

   
  declare cursor c1 as 
  select session_id_num,type_query 
  from mng_rishui_session 
  where time_query (/*here i need to do the condition that 15 minutes has passed from the time query 
   i don't know how to do this */
  begin 
  for e in c1 loop 
  
  case e.type_query 
  when 1 
  delete query1_table where session_id_num :=e.session_id_num;
  when 3 
  delete query3_table where session_id_num :=e.session_id_num;
  end
  end loop;
  end;

  issues related to the:
  1. how to check if 15 minutes where the past
  2. it is good to do with loop for writing valid deletion in the loop
  or do I have to do it another way to write this.
  Thanks in advance
  Naama

  Hi, Naama,

  Naama wrote:
  ... now my script looks like this:
  mng_session. SQL

  
  declare cursor c1 as
  select session_id_num,type_query
  from mng_rishui_session
  where  (sysdate - t_query) * 24 * 60 >= 15;  
  
  begin
  for e in c1 loop
  case e.type_query
  when 1 then
  delete query1_table where session_id_num = e.session_id_num;
  when 3 then
  delete query3_table where session_id_num  =e.session_id_num;
  end case;
  end loop;
  end;
  

  first of all, I want to know where I'm going to do the validation, if I need to do.

  In the PL/SQL code (so we won't do it in case of error) but after the LOOP is finished.
  In other words, assuming you are using a LOOP. It will be much more effective if you just do a DELETE statement on each table. Think about it: If your mng_rishui_session has 1,000 rows where t_query (or time_query, if the column is always so called) is fortunate to have one of the type_queries you want at least 15 minutes, and 100 of these lines, then you must fetch the 1,000 rows (if not all of the table) , and separate 100 DELETE queries. It is more effective to extract 100 lines (assuming that there is an index composed of type_query and t_query) and to only 2 DELETE statements. See below.

  Second:
  I run this script through linux system, in order to head to sleep.
  My problem is that I am trying to append the output of script;
  but it won't let me

  People on this site will try to help you. Why not try to help them do it?
  Do not say "he won't let me": show all that you know the problem. What exactly have you tried? That's happened? If you got an error, display the full error message, including the line number. If you got the wrong results, describe what happened.

  My goal is:

  a script running the sql scripy called:
  CS-mng-session:

  #!bin/bash
  sqlplus user/passwd@dbname @mng_session /*mng_session is the script were i declare the cursor etc.*/
  in the command line i want to write :
  (sleep 600; sh cs-mng-session)& 
  

  the problem is that if I do not exit. He recorded in sql and the script does not return to the command line.
  How do I overcome this problem?

  Make an EXIT.

  Try something like this:

  DECLARE
       cutoff_date     DATE     := SYSDATE - (15 / (24 * 60));
  BEGIN
       DELETE     query1_table
       WHERE     session_id_num  IN (
                           SELECT  session_id_num
                           FROM     mng_rishui_session
                           WHERE     type_query     = 1
                           AND     t_query          <= cutoff_date
                         );
  
       DELETE     query3_table
       WHERE     session_id_num  IN (
                           SELECT  session_id_num
                           FROM     mng_rishui_session
                           WHERE     type_query     = 3
                           AND     t_query          <= cutoff_date
                         );
  
       COMMIT;          -- If desired
  END;
  /
  
  EXIT;
  

  Is there a reason why query1_table should be different from query3_table? Why can't you have just a query_table, with a column of type_query?

  What happens if there is an error? You won't want to know? You must add an EXCEPTION section to write the details about the error in a log table and someone send an email on this subject.

  Published by: Frank Kulash, August 31, 2010 09:07
  Added / issue;

• Pretty simple Question of PHP/SQL

  I made a page where the user connects to something, but I want to keep having the same password as their user name. What is the best way to do it? Can I do it through dreamweaver or SQL? I guess an IF statement with the kill conditioon or something along those lines will work, I really don't want the values with the user name and password for repeated added to my database at all.
  
  Thanks for the help, sorry, it's Aussie a newbie question: P

  Geschenk wrote:
  > you can simply compare the field values submitted username & password using
  > an IF-ELSE statement, and if the password is username, tell him
  > something ;-) What s your server, PHP, ASP, CF model?

  It says PHP in the subject line, PHP is.

  If {($_POST)}
  {If ($_POST ['username'] == {$_POST ['password']})}
  $error = '

  You cannot use your username as password

  ';
  }
  else {}
  Insert here the code of behavior insert record server
  }
  }

  In the form itself:

  --
  Adobe Community Expert David Powers
  Author, "Foundation PHP for Dreamweaver 8" (friends of ED)
  Author, "PHP Solutions" (friends of ED)
  http://foundationphp.com/