selection of image based on exif time difference between images

Similar Questions

• How do the time difference between two dates?

  Hi all
  
  I use this query to get the time difference between two dates.
  
  Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;
  
  but do not get the correct result.
  
  Thank you

  Left KEY... Left Padding of tanks.

• "There is a time difference between the client and the server"

  Unit 4.0.3

  Everything worked very well, and all of a sudden, I'm not able to connect to the server unit using any domain account. When I enter the domain/name username/password, I get this error message:

  ************************************************

  The system is unable to log on due to the following error:

  There is a time difference between the client and the server.

  Try again or contact your system administrator.

  **************************************************

  I can use the same domain account (unityinstall) and the journal in other machines. I can connect the machine to the unit using a local account. There is no time difference between the DC server and unity.

  Need help,

  Thank you

  Partha

  Log on to your LOCAL computer using an account that has privileges

  At the command prompt, type the following:

  NET TIME ancien_mot_passe/set

  Found this on the MS site:

  Cannot open a session if the Date and time are not synchronized

  http://support.Microsoft.com/default.aspx?scid=kb;en-us;232386&product=Win2000

• Calculation of the time differences between several lines

  Hello
  
  I have a table as below:
  
  EVENT ID DATE
  1. start 05/03/2012-13:00
  1. stop the 15:00 05/04/2012
  1. start 09:00 05/07/2012
  1 stop on 05/09/2012 10:00
  Start 2 08/06/2012-08:00
  2 stop on 08/07/2012 10:00
  
  I would like to calculate the duration (in hours ideally) between 'Start' and 'Stop' for each ID, so having a set of lines:
  
  ID TimeSpan
  ---------------------
  1 75
  26 2
  
  I would appreciate any idea how to solve this, ideally as a SQL solution or maybe a function.
  
  Thank you very much!
  Tom

  The difference between two dates is a number, where 1 = 1 day. Multiply by 24 to get hours.

  Use the LAG, as stated above, to compare the date prior to the current date.

  create table T(TID, EVENT, TDATE) as select
  1, 'start', TO_DATE('03/05/2012 13:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'Stop',  TO_DATE('04/05/2012 15:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'start', TO_DATE('07/05/2012 09:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  1, 'Stop',  TO_DATE('09/05/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  2, 'start', TO_DATE('06/08/2012 08:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
  2, 'Stop',  TO_DATE('07/08/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL;
  
  select tid, round(sum(hours)) hours from (
    select case
      when EVENT = 'Stop' then 24*(TDATE - LAG(TDATE) over(partition by TID order by TDATE))
      else 0 end hours,
    TID from T
  )
  group by tid;
  
  TID HOURS
  --- -----
    1    75
    2    26
  

• time difference between dates

  I managed to present the session for the start date variable: CAST (VALUEOF (s_sd) AS DATE)
  and for the end date: CAST (VALUEOF (s_ed) AS DATE)
  
  How can I show the number of days of interval between them?

  Create an another session variable to calculate the difference between the dates.

  Select DATEDIFF (DD, "MM DD YYYY","MM DD YYYY") FROM DUAL;

  Hope that the question is answered.

  Update of the Post:

  The function datediff above would only work in SQL Server, if you use the oracle database, use the code below:

  SELECT SYSDATE - TO_DATE('20081205','YYYYMMDD') datediff FROM DUAL;

  Note: You can replace the sysdate with your custom date, but do not forget to mention the data format of date after the mention of the date of your custom.

  Thank you
  -Laurence.

• Time difference between extraction in bulk and standard fetch?

  Hello world

  I have performed below block in the SCOTT schema for the gap between the standard extraction and extraction block. I read that extraction is more standard fast recovery. How ever the results were opposed as shown below.

  Resut

  ------------

  PL/SQL procedure successfully completed.

  the extraction time is 114

  the time required for extraction bulk is 136

  Block I ran

  ------------------------

  declare

  type owner_name_t is table of the all_objects.object_name%type;

  owner_c owner_name_t;

  object_name_c owner_name_t;

  number of l_start;

  number of l_end;

  cursor c1 is

  Select the owner, object_name object;

  Start

  l_start: = dbms_utility.get_time;

  I'm in c1

  loop

  null;

  end loop;

  l_end: = dbms_utility.get_time;

  dbms_output.put_line (' the extraction time is ' |) (l_end-l_start)) ;

  l_start: = dbms_utility.get_time;

  -car me in c1

  Open c1;

  loop

  When exit c1% notfound;

  collect the fetch c1 into loose in owner_c, object_name_c;

  end loop;

  Close c1;

  l_end: = dbms_utility.get_time;

  dbms_output.put_line (' bulk is the time needed to extract ' |) (l_end-l_start)) ;

  end;

  Can someone suggest as to why it happened?

  Thanks and greetings

  580988 wrote:

  Hello world

  I have performed below block in the SCOTT schema for the gap between the standard extraction and extraction block. I read that extraction is more standard fast recovery. How ever the results were opposed as shown below.

  Can someone suggest as to why it happened?

  Thanks and greetings

  Well I run your code using Oracle 12 c and based on your query in your cursor may be the first time that it will be a little different but then I noticed your code and I wonder... WHY you BULK COLLECT within the loop?

  That's the whole point of the bulk to pick you up.  Get you ONCE... in 'bulk '.

  Here is your code changed on my db and my result set

  SET SERVEROUTPUT ON
  
  DECLARE
  
     TYPE owner_name_t IS TABLE OF all_objects.object_name%TYPE;
  
     owner_c         owner_name_t;
     object_name_c   owner_name_t;
     l_start         NUMBER;
     l_end           NUMBER;
  
     CURSOR c1 IS
        SELECT owner
              ,object_name
          FROM all_objects;
  
  BEGIN
  
     l_start := DBMS_UTILITY.GET_TIME;
  
     FOR I IN c1 LOOP
        NULL;
     END LOOP;
  
     l_end := DBMS_UTILITY.GET_TIME;
  
     DBMS_OUTPUT.PUT_LINE ('The time required for fetch is ' || TO_CHAR(l_end - l_start)));
  
     l_start := DBMS_UTILITY.GET_TIME;
  
     OPEN c1;
  
     --LOOP
        --EXIT WHEN c1%NOTFOUND;
  
     DBMS_OUTPUT.PUT_LINE('Fetching bulk collect');
  
     FETCH c1
      BULK COLLECT
      INTO owner_c, object_name_c;
  
     --END LOOP;
  
     CLOSE c1;
  
     l_end := DBMS_UTILITY.GET_TIME;
  
     DBMS_OUTPUT.PUT_LINE ('The time required for bulk fetch is ' || TO_CHAR((l_end - l_start)));
  
  END;
  /
  

  Result set

  

• How to set the time difference between each data when using keithley 2400 scanning

  Hello friends,

  I use scanning Keithley vi the extent of SCANNING and acquire vi. I want to measure the voltage for each step and a pause between each two data, so I need a delay between each I step.

  I'm a starter to use Labview, thank you very much for your answers.

  Perry

  As Dennis says, if you use the built-in scan function, you will need to consult the manual. See Section 10-16 (this is page 10 of article 16, only paragraphs not but 10, 16) for the manual Keithley 2400.

  The Keithley 24xx series has a speed of measurement in units called PLC (Power Line Cycles). The default speed is 1PLC, which means a measure is taken with each cycle of line 1 power supply or 1/60th of a second (16.67ms). 24XX can range from 0.01 PLC (all 0.16ms) 10 PLC (all 166.6ms). The faster you measure, the less accuracy you get.

  To programmatically set this value, the command is

  ENSe:CURRent:NPLCycles

  ENSe:VOLTage:NPLCycles

  Depending on what you are sensing and where is the number of controllers from 0.01 to 10.

  Another factor that will determine the time between data points is the cycle SDM. These are more complicated, look at your Keithley manual for more information. Look at article 6 and article 11 for more information.

  Note:

  PLC times are based on a cycle of 60 Hz US.

• There is the time difference between I phone and Apple Watch

  Ythe time on my I phone is correct, but on my Apple Watch is not

  You have sync it and paired? in the same time zone?

• Measure the time difference between a digital output and an analog input that responded to the questionnaire

  Hallo,

  I use the following system:

  • OR PXI-1044 with controller NI PXI-8109
  
  
  • OR PXI-2564 switch module to turn on the monitor of my test device
  
  
  • Data acquisition multifunction NI PXI-6259 to measure the signal that responded to the questionnaire jump

  The two cards are the same - PXI trigger bus. For both, PXI-2564 and PXI-6259 I use DAQmx to set the reading and writing of the channels.

  Now, I want to measure the time between the digital output, my unit turns and the analog input, which measures the response of my system.

  I can't do work by myself, please help me!

  I thank Ludwig.

  Hi Ludwig,.

  If you can't give us any VI we have difficulties with to help you.

  Because I Donat knowledge how your program is mounted it is not easy to know where you should enter signals.

  Here's a question similar to yours:

  http://forums.NI.com/T5/LabVIEW/best-way-to-measure-time/TD-p/178704

  and 2 external links:

  http://www.ehow.com/how_8698983_measure-time-LabVIEW.html

  http://objectmix.com/LabVIEW/385152-how-can-i-use-LabVIEW-measure-time-between-analog-pulses.html

• calculate the time difference between several lines

  Hello

  I have a table as below:

  create table select TEST_CASETBL (ID, CASE_NUM, CASE_STATUS, CASE_SUB_STATUS, LAST_UPD_DTTM)

  112, 123-456', 'open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' hh24:mi:ss' of dd/mm/yyyy) of the DUAL union all select them

  315, 123-456', 'open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of the DUAL union all select

  651, 123-456', 'open', 'Work', TO_DATE (August 20, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') from DUAL;

  I would like to calculate the duration total (days ideally) to CASE_SUB_STATUS, so have a set of lines:

  CASE_NUM of work waiting on admin waiting on customer

  -------------------------------------------------------------------------------------------------------------------------------------------------------

  123-456 70days 6 hours

  Here is the explanation of the pattern:

  ex: for everyday business computing (timestamp timestamp of ID:651 - ID:219) +(timestamp of ID:315-timestamp of ID:114) + (ID:112 stamp - current_time) = 11 days + 21 days 22hrs 23hrs 36 days 9 hours

  still waiting on admin

  (ID:219 timestamp - timestamp of ID:315) + (ID:113 timestamp - timestamp of ID:112)

  still waiting on the client

  (ID:114 timestamp - timestamp of ID:113)

  I would appreciate any idea how to solve this, ideally as an SQL

  Thank you

  Should he not?...

  with test_casetbl (id, case_num, case_status, case_sub_status, last_upd_dttm) as)

  Select 112, 123-456', 'Open', 'Work', TO_DATE (11 March 2015 13:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 113, 123-456', 'Open', 'pending on the admin', TO_DATE (10 January 2015 15:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 114, 123-456', 'Open', 'client expectation', TO_DATE (10 July 2015 09:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 315, 123-456', 'Open', 'Work', TO_DATE (September 15, 2015 10:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 219, 123-456', 'Open', 'pending on the admin', TO_DATE (January 9, 2015 08:00 ',' dd/mm/yyyy hh24:mi:ss') of all the DOUBLE union

  Select 651, 123-456', 'Open', 'Work', TO_DATE (August 20, 2015 10:00 ',' the hh24: mi: ss' dd/mm/yyyy) double

  ),

  t like)

  Select case_num,

  case_sub_status,

  (last_upd_dttm, 1, sysdate) ahead of diff last_upd_dttm (partition by order of last_upd_dttm case_num).

  of test_casetbl

  )

  Select case_num,

  trunc (a) | "day (s). TO_CHAR (date ' 1-1-1' + a, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "work."

  trunc (b) | "day (s). TO_CHAR (day 1-1-1' + b, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") 'Waiting on admin',

  trunc (c) | "day (s). TO_CHAR (day 1-1-1' + c, "fmhh24" 'mi' minute (s) "ss" second (s) hour (s)"") "waiting on customer."

  t

  pivot)

  Sum (diff)

  for case_sub_status in)

  'Work' is.

  B "waiting on admin',

  C "customer expectation."

  )

  )

  CASE_NUM	Working	Waiting on admin	Waiting on customer
  123-456	63 day (s) 22 hour (s) (s) 50 minute 49 second (s)	19 day (s) on 20 (s) hour 0 minute 0 second (s)	27 day (s) on 4 hour (s) 0 minute 0 second (s)

• Is there an easy way to calculate the time difference?

  I am trying to find a way to calculate the time difference between

  here at a certain time

  var settime:Number = 02:35

  and

  now would be getDate();

  I tried something rediculus, but it does not work when I entered a date less than 24 hours, is there a class out there who can just this kind of things

  or y at - it something on the internet that could tell me the difference between different time

  Thank you

  My attempt

  var date: Date = new Date();

  Set timer to what would I like to call the function
  var lastcallH:Number = 22;
  var lastcallM:Number = 50;
  var lastcallS:Number = 0;

  Set up of the 24-hour clock
  var tHour:Number = 24;
  var tMinute:Number = 60;
  var tSecond:Number = 60;

  Get the current time
  var cHour:Number = date.getHours ();
  var cMinutes:Number = date.getMinutes ();
  var cSeconds:Number = date.getSeconds ();

  Set the first variable
  var fH:Number;
  var fM:Number;
  var fS: Number;

  A second set of Variable
  var sH: number;
  var sM:Number;
  var sS:Number;

  Final conversion for the Timer
  var finalMil:Number;

  Time variables that will need to be converted

  If (lastcallH < Thur)
  {
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);
  }
  ElseIf (cMinutes > 0 | cSeconds > 0) {}
  ++ Choir;
  ++ cMinutes;
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }
  else {}
  fH = chorus - Thur;
  fM = cMinutes - tMinute;
  fS = cSeconds - tSecond.
  }

  sH = fH + lastcallH;
  sM = fM + lastcallM;
  sS = fS + lastcallM;

  If (< 0 sH: sM < 0 | sS < 0)
  {
  sH = sH * (-1);
  sM = sM * (-1);
  sS = sS * (-1);
  }
  finalMil = (sH * 60) + (sM * 60) + (sM * 60);

  Allows you to implement a timer
  var yahooTime:Timer = new Timer (finalMil, repeat);
  var repeat: Number = 1;

  yahooTime.start ();

  yahooTime.addEventListener (TimerEvent.TIMER, displayCall);

  function displayCall(event:TimerEvent):void
  {
  trace ("well let's success");
  }

  your first trace() statement is almost certainly not what you want.

  dtDate2 is 08/08/2009

  and it's probably not what you want.  Flash months are zero-based.  That is to say, January corresponding to month 0 and December is the month 11.

• Calculation of time difference

  Hi Experts,
  
  I had separate columns for the date and time and have an obligation to calculate the time difference between them.
  
  Examples of data as below.
  
  _ Date ordered Date classified at the time as time released
  27/04/2010 06:36 04/27/2010 08:21:55
  27/04/2010 06:36 04/27/2010 07:07:29
  27/04/2010 06:36 04/27/2010 07:07:29
  27/04/2010 06:36 04/27/2010 07:07:29
  27/04/2010 06:36 04/27/2010 07:07:29
  
  How to calculate the time difference between ordered and distributed in minutes?
  
  Published by: Sweta on April 27, 2010 04:34

  This gives a shot:

  SELECT  SOH_ORDER_NO
  ,       (
                  (SOH_DATE_RELEASED + TO_NUMBER(TO_CHAR(SOH_TIME_RELEASED,'SSSSS'))/(60*60*24))
          -       (SOH_DATE_CREATED + TO_NUMBER(TO_CHAR(SOH_TIME_CREATED,'SSSSS'))/(60*60*24))
          )*24*60 AS DIFF_IN_MINUTES
  FROM    SALES_ORDER
  

  You should really think about change this data model if you can.

• Convert time difference in seconds in hours, minutes, and seconds

  Hi all
  
  I used the following logic to calculate the time difference between 2 passes of time for all the individual lines.
  
  (floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24) |) ':' || MOD (Floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24 * 60), 60) |': ' | MOD (Floor ((TIME_ACTIONED-TIME_ALLOCATED) * 24 * 60 * 60), 60))
  
  The user asked a column that displays the SUM of all the differences in time between the report.
  
  Any help much appreciated!
  
  
  Thank you
  Sweta

  Simply the sum of time_actioned - time_allocated, then do the same calculation you make on this sum.

  John

• By selecting the difference between two images

  Hello

  I have two photos exactly the same thing that I took using a tripod, studio lighting and general conditions. However, in the second photo, I inserted a subject - in this case a sculpture complex. Photoshop can merge these two images together AND choose so the difference between the two images - in this case the sculpture complex?
  
  

  Basically, I need to select the sculpture and do not want to spend time manually selecting due to its complexity. I need to separate the background and the sculpture for editing on their own layers.

  Thank you

  Stephen-CS3

  You posted this in the two forums, its been answered in the mac forum.

• My nail of the thumb in bridge always have evidence the adjustments I make to RAW files. Now, for the first time they have not. However when I select the images adjusted and open them in CS6 adjustments are there. I restarted the bridge and PS, and I rest

  My nail of the thumb in bridge always have evidence the adjustments I make to RAW files. Now, for the first time they have not. However when I select the images adjusted and open them in CS6 adjustments are there. I restarted bridge and PS, and I restarted the computer (Mac). Still the same problem.

  I thank assani, but it wasn't the answer. The problem was, I finally understood, that the "option for generation of quality and preview thumbnails" wasn't on "high quality" as it usually is. I have no idea how this happened as I never change this option.

  Thanks a lot for your help.

  Mitchel Gray