time difference between dates

I managed to present the session for the start date variable: CAST (VALUEOF (s_sd) AS DATE)
and for the end date: CAST (VALUEOF (s_ed) AS DATE)

How can I show the number of days of interval between them?

Create an another session variable to calculate the difference between the dates.

Select DATEDIFF (DD, "MM DD YYYY","MM DD YYYY") FROM DUAL;

Hope that the question is answered.

Update of the Post:

The function datediff above would only work in SQL Server, if you use the oracle database, use the code below:

SELECT SYSDATE - TO_DATE('20081205','YYYYMMDD') datediff FROM DUAL;

Note: You can replace the sysdate with your custom date, but do not forget to mention the data format of date after the mention of the date of your custom.

Thank you
-Laurence.

Tags: Business Intelligence

Similar Questions

How do the time difference between two dates?
Hi all

I use this query to get the time difference between two dates.

Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;

but do not get the correct result.

Thank you
Left KEY... Left Padding of tanks.

"There is a time difference between the client and the server"

Unit 4.0.3

Everything worked very well, and all of a sudden, I'm not able to connect to the server unit using any domain account. When I enter the domain/name username/password, I get this error message:

************************************************

The system is unable to log on due to the following error:

There is a time difference between the client and the server.

Try again or contact your system administrator.

**************************************************

I can use the same domain account (unityinstall) and the journal in other machines. I can connect the machine to the unit using a local account. There is no time difference between the DC server and unity.

Need help,

Thank you

Partha

Log on to your LOCAL computer using an account that has privileges

At the command prompt, type the following:

NET TIME ancien_mot_passe/set

Found this on the MS site:

Cannot open a session if the Date and time are not synchronized

http://support.Microsoft.com/default.aspx?scid=kb;en-us;232386&product=Win2000

code succcessive to genereate difference between dates in a table

First create and insert statements;

create table schedule(iloan_code number , schedule_date date);

insert into schedule values(1001, to_date('01-jun-2012'));
insert into schedule values(1001, to_date('01-jul-2012'));
insert into schedule values(1001, to_date('01-aug-2012'));
insert into schedule values(1001, to_date('01-sep-2012'));
insert into schedule values(1001, to_date('01-oct-2012'));
commit;

The output of the table of the ANNEX should be now like this:

ILOAN_CODE     SCHEDULE_DATE
1001              01-JUN-12
1001              01-JUL-12
1001              01-AUG-12
1001              01-SEP-12
1001              01-OCT-12

We want an additional column by name as well as the existing columns DAYS that would be the difference between dates.

First line should be the difference between sysdate as well as the date of June 1, 2012 and successive lines must be the difference between successive calendar date

For example in the second row the DAYS column should represent the difference between 1 July 2012 and 1 June 2012 and so on for the following ranks too.

We need get the result by a SELECT statement

The output of the table in the ANNEX must be something like that.

iloan_code      schedule_date     days     Logic which we need 
1001     1-Jun-12     22     sysdate-1st June 2012
1001     1-Jul-12     30     difference between 1st July 2012 and 1st June 2012
1001     1-Aug-12     31     difference between 1st aug 2012  and 1st July 2012
1001     1-Sep-12     31     difference between 1st sep  2012 and 1st aug  2012
1001     1-Oct-12     30     difference between 1st oct 2012 and 1st sep 2012

Please notify;

Hello

You can change the Hoek solution like this:

SELECT    iloan_code
,             schedule_date
,             schedule_date - LAG ( schedule_date
                            , 1
                     , TRUNC (SYSDATE)
                     ) OVER (ORDER BY schedule_date)     AS days_between
FROM      schedule
ORDER BY  schedule_date
;

If all schedule_dates will be after SYSDATE, then you need not the CASE expression to test if it is.
The argument optional 3rd to LAG is a return value in case there is no previous line.

Sri says:
... The output of the table in the ANNEX must be something like that.

iloan_code      schedule_date     days     Logic which we need
1001     30-Jun-12     07     sysdate-30June 2012
1001     1-Jul-12     30     difference between 1st July 2012 and 30 June 2012 ...

The difference between 30 June 2012 and July 1, 2012 is not only 1 day?

How to set the time difference between each data when using keithley 2400 scanning

Hello friends,

I use scanning Keithley vi the extent of SCANNING and acquire vi. I want to measure the voltage for each step and a pause between each two data, so I need a delay between each I step.

I'm a starter to use Labview, thank you very much for your answers.

Perry

As Dennis says, if you use the built-in scan function, you will need to consult the manual. See Section 10-16 (this is page 10 of article 16, only paragraphs not but 10, 16) for the manual Keithley 2400.

The Keithley 24xx series has a speed of measurement in units called PLC (Power Line Cycles). The default speed is 1PLC, which means a measure is taken with each cycle of line 1 power supply or 1/60th of a second (16.67ms). 24XX can range from 0.01 PLC (all 0.16ms) 10 PLC (all 166.6ms). The faster you measure, the less accuracy you get.

To programmatically set this value, the command is

ENSe:CURRent:NPLCycles

ENSe:VOLTage:NPLCycles

Depending on what you are sensing and where is the number of controllers from 0.01 to 10.

Another factor that will determine the time between data points is the cycle SDM. These are more complicated, look at your Keithley manual for more information. Look at article 6 and article 11 for more information.

Note:

PLC times are based on a cycle of 60 Hz US.

Second difference between dates GMT?

Hello

I need to get the second difference between a date later GMT and current date of GMT.

My code looks like this:
```
Calendar futureDate = Calendar.getInstance(TimeZone.getTimeZone("GMT"));futureDate.set(Calendar.YEAR, 2009);futureDate.set(Calendar.MONTH, 11);futureDate.set(Calendar.DATE, 12)futureDate.set(Calendar.HOUR, 10)futureDate.set(Calendar.MINUTE, 43)futureDate.set(Calendar.SECOND, 18);

int secs = (futureDate.getTime().getTime() - System.currentTimeMillis()) / 1000;
```
This code gives me 12 hours too many seconds. I'm I have GMT + 7 time zone. DateTime, the value source Blackberry.

When I debug, and print the futureDate, it shows me my timezone instead of GMT.

Another weird thing. If I subtract the TimeZone.getDefault () .getRawOffset () in my calculation of seconds, the seconds are then 7 hours in advance. Where are these 5 hours from extra?

Thank you.

Sorry, just a little chip, I don't have the time to carefully review your problem (maybe do later) but two things:

(1) System.currentTimeMillis () returns the time UTC. I think that CMJ is incorrect when he says that it returns local time.

(2) GMT is NOT necessarily UTC time on the device. GMT in London at the present time is UTC to 1, because we (I'm in the United Kingdom) use Daylight Saving. If you want to discover the real hour GMT, on the device or the Simulator, set time GMT from Casablanca.

I need to check these, do not have the time, but here are some other thoughts on the top of my head.

(a) timezone "GMT" is, in fact, Casablanca GMT, i.e. not affected by Daylight Saving.

(b) Note When you specify the time of the calendar, there are two forms of time:
TIME - what you used, can be morning or afternoon

HOUR_OF_DAY - which I think is what you should use.

So change your code to use HOUR_OF_DAY, and I suspect that this could work. But as noted, just off the top of my head...

Difference between Date of invoice and Date GL accounting Date Oracle AP
Hello

I have a question that might help a lot of people too late.
I tried to run these queries
Select aia. INVOICE_ID
of AP_INVOICES_ALL aia, aida AP_INVOICE_DISTRIBUTIONS_ALL
where aia. INVOICE_ID = aida. INVOICE_ID
and aia. INVOICE_DATE <>aida. ACCOUNTING_DATE

Select aia. INVOICE_ID
of AP_INVOICES_ALL aia, aida AP_INVOICE_DISTRIBUTIONS_ALL
where aia. INVOICE_ID = aida. INVOICE_ID
and aia.GL_DATE <>aida. ACCOUNTING_DATE

I see that there are a lot of results for these queries, where the Date of the invoice is not equal to the posting date and of the GL_Date of an invoice does not match the posting date in the distribution table.
So, what is the difference between these dates.
And if I had to take the date of posting of the invoice of the document, the date on which I have to take for these invoices in AP

Thank you
Bob
Hello

Date of GL:

The date used to determine the right time of accounting for the transactions of your invoice and payment of GL. You assign a GL Date on your invoice during invoice entry
and your payments during the creation of payment.

Date of invoice:

The invoice date that you assign to an invoice, you enter in Payables. Accounts payable uses this date to calculate the invoice due date, the terms of payment of the invoice. The invoice date may be the date of the invoice, or it can be another date that you specify.

Posting date:

The GL Date for distributions of the invoice. If you do not enter a value here or enter a value for GL Date when you submit Payables Open Interface Import, accounts payable will allocate a GL Date based on the GL Date set in the region of the invoice of the Payables Options window.

Kind regards
Rahul

Difference between Date hh: mm
Hello

I'm having the following table, I want the difference between time in hh & another exit as hh: mm with rounded seconds.

CREATE TABLE 'ITIP. "" TOTO ".
("N1" VARCHAR2 (100),)
"T1D" THAT DAY.
'T2D' DAY
)

Insert into FOO (n1, t1d and T2D)
values ('TT', to_date (25 June 2012 10:46:56 ',' dd-mm-yyyy hh24:mi:ss'), to_date (25 June 2012 10:51:53 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('TT', to_date (25 June 2012 10:51:53 ',' dd-mm-yyyy hh24:mi:ss'), to_date (25 June 2012 10:51:57 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('TT', to_date (25 June 2012 10:32:06 ',' dd-mm-yyyy hh24:mi:ss'), to_date (25 June 2012 10:43:09 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('TT', to_date (25 June 2012 10:43:09 ',' dd-mm-yyyy hh24:mi:ss'), to_date (25 June 2012 10:53:09 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('UU', to_date (25 June 2012 10:46:56 ',' dd-mm-yyyy hh24:mi:ss'), to_date (June 25, 2012 21:44:39 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('UU', to_date (27 June 2012 10:51:53 ',' dd-mm-yyyy hh24:mi:ss'), to_date (June 27, 2012 11:46:10 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('UU', to_date (28 June 2012 10:32:06 ',' dd-mm-yyyy hh24:mi:ss'), to_date (28 June 2012 18:45:32 ',' dd-mm-yyyy hh24:mi:ss'));))
Insert into FOO (n1, t1d and T2D)
values ('UU', to_date (June 29, 2012 14:22:13 ',' dd-mm-yyyy hh24:mi:ss'), to_date (June 29, 2012 17:24:20 ',' dd-mm-yyyy hh24:mi:ss'));))
commit;

What is the result when we substract two dates?, as I want the difference between time in hh & another exit as hh: mm with rounded seconds.

Please suggest a query for the same thing.

Thank you
Hello

user12009546 wrote:
... What is the result when we substract two dates?

This is the number of days between these two dates. You can convert than an INTERVAL, which is more like what you want, using NUMTODSINTERVAL:
```
NUMTODSINTERVAL ( dt2 - dt1
                , 'DAY'
                )
```
If you don't want that all the information, you can use SUBSTR or regular expressions to get only the part you want.

I would also like the difference between the time in hh & another exit as hh: mm with rounded seconds.

Please suggest a query for the same thing.

If the difference will always be between 0 and 24 hours, then you can do something like diff_c below:
```
SELECT       dt1
,       dt2
,       NUMTODSINTERVAL ( dt2 - dt1
                   , 'DAY'
                 )          AS diff_i
,       TO_CHAR ( ROUND ( TRUNC (SYSDATE) + (dt2 - dt1)
                       , 'MI'
                 )
            , 'HH24:MI'
            )               AS diff_c
FROM      toto
;
```
Output:
```
DT1                 DT2                 DIFF_I                         DIFF_
------------------- ------------------- ------------------------------ -----
25-06-2012 10:46:56 25-06-2012 10:51:53 +000000000 00:04:57.000000000  00:05
25-06-2012 10:51:53 25-06-2012 10:51:57 +000000000 00:00:04.000000000  00:00
25-06-2012 10:32:06 25-06-2012 10:43:09 +000000000 00:11:03.000000000  00:11
25-06-2012 10:43:09 25-06-2012 10:53:09 +000000000 00:10:00.000000000  00:10
25-06-2012 10:46:56 25-06-2012 21:44:39 +000000000 10:57:42.999999999  10:58
27-06-2012 10:51:53 27-06-2012 11:46:10 +000000000 00:54:17.000000000  00:54
28-06-2012 10:32:06 28-06-2012 18:45:32 +000000000 08:13:26.000000000  08:13
29-06-2012 14:22:13 29-06-2012 17:24:20 +000000000 03:02:07.000000000  03:02
```

Calculation of the time differences between several lines

Hello

I have a table as below:

EVENT ID DATE
1. start 05/03/2012-13:00
1. stop the 15:00 05/04/2012
1. start 09:00 05/07/2012
1 stop on 05/09/2012 10:00
Start 2 08/06/2012-08:00
2 stop on 08/07/2012 10:00

I would like to calculate the duration (in hours ideally) between 'Start' and 'Stop' for each ID, so having a set of lines:

ID TimeSpan
---------------------
1 75
26 2

I would appreciate any idea how to solve this, ideally as a SQL solution or maybe a function.

Thank you very much!
Tom

The difference between two dates is a number, where 1 = 1 day. Multiply by 24 to get hours.

Use the LAG, as stated above, to compare the date prior to the current date.

create table T(TID, EVENT, TDATE) as select
1, 'start', TO_DATE('03/05/2012 13:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'Stop',  TO_DATE('04/05/2012 15:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'start', TO_DATE('07/05/2012 09:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
1, 'Stop',  TO_DATE('09/05/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
2, 'start', TO_DATE('06/08/2012 08:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL union all select
2, 'Stop',  TO_DATE('07/08/2012 10:00:00', 'dd/mm/yyyy hh24:mi:ss') from DUAL;

select tid, round(sum(hours)) hours from (
  select case
    when EVENT = 'Stop' then 24*(TDATE - LAG(TDATE) over(partition by TID order by TDATE))
    else 0 end hours,
  TID from T
)
group by tid;

TID HOURS
--- -----
  1    75
  2    26

selection of image based on exif time difference between images

Hello
I am a user of LR5. In a sequence of new pictures to import, I have a few Images that are taken with a time difference of less than 10 seconds. These images are part of a sequence for the stacking of pano. I want to select these images (or the value of a brand like a colored flag) with a single command. Is there a way to implement a script for LR or a way to do this?
All advice welcome.
thx a lot.
kkd

In the library, try 'Battery Auto capture time'

Measure the time difference between a digital output and an analog input that responded to the questionnaire

Hallo,

I use the following system:
- OR PXI-1044 with controller NI PXI-8109
- OR PXI-2564 switch module to turn on the monitor of my test device
- Data acquisition multifunction NI PXI-6259 to measure the signal that responded to the questionnaire jump
The two cards are the same - PXI trigger bus. For both, PXI-2564 and PXI-6259 I use DAQmx to set the reading and writing of the channels.

Now, I want to measure the time between the digital output, my unit turns and the analog input, which measures the response of my system.

I can't do work by myself, please help me!

I thank Ludwig.

Hi Ludwig,.

If you can't give us any VI we have difficulties with to help you.

Because I Donat knowledge how your program is mounted it is not easy to know where you should enter signals.

Here's a question similar to yours:

http://forums.NI.com/T5/LabVIEW/best-way-to-measure-time/TD-p/178704

and 2 external links:

http://www.ehow.com/how_8698983_measure-time-LabVIEW.html

http://objectmix.com/LabVIEW/385152-how-can-i-use-LabVIEW-measure-time-between-analog-pulses.html

To return the rows when there is a certain difference between dates

Hello.

I have a table called

#president #.
pres_name
BIRTH_DATE

and

#winner #.
name
year_elected

I wish I had all the presidents returned, who where under the age of 50 years when they elected.
year_elected is only a 4-digit number; 1924 etc. While birth_date is 2001-01-01 etc.

I have no idea how to make this work, ive tried substr and one things and a lot of other weird (prob wrong).

select distinct p.pres_name, substr(p.birth_date, 0, 4), w.year_elected
from president p, winner w
where p.pres_name = w.name

I did this witch query will show me all the presidents and their dates for the election and the date of birth. Now I just want something that returns only the guys where there is a difference in value 49 (?) between birth_date and year_elected

Johan

Edited by: user10248089 02-Oct-2008 00:42

Based on information from Dave on presidents being elected the first Tuesday of November...

SQL> with president as (select 'Bob' as pres_name, to_date('1/7/1934','DD/MM/YYYY') as birth_date from dual union all
  2                     select 'Fred', to_date('13/5/1950','DD/MM/YYYY') from dual union all
  3                     select 'Jim', to_date('21/12/1960','DD/MM/YYYY') from dual)
  4      ,winner    as (select 'Bob' as name, '1979' as year_elected from dual union all
  5                     select 'Fred', '2005' from dual union all
  6                     select 'Jim', '2000' from dual)
  7  --
  8  select p.pres_name, p.birth_date, w.year_elected
  9        ,trunc(months_between(next_day(to_date('01/11/'||w.year_elected,'DD/MM/YYYY'),'TUE'),birth_date)/12) as age
 10  from president p join winner w on (p.pres_name = w.name)
 11  /

PRES BIRTH_DAT YEAR        AGE
---- --------- ---- ----------
Bob  01-JUL-34 1979         45
Fred 13-MAY-50 2005         55
Jim  21-DEC-60 2000         39

SQL>

And the WHERE clause can be applied based on the same calculation as described in the age column

Time difference between extraction in bulk and standard fetch?

Hello world
I have performed below block in the SCOTT schema for the gap between the standard extraction and extraction block. I read that extraction is more standard fast recovery. How ever the results were opposed as shown below.
Resut
------------
PL/SQL procedure successfully completed.
the extraction time is 114
the time required for extraction bulk is 136
Block I ran
------------------------
declare
type owner_name_t is table of the all_objects.object_name%type;
owner_c owner_name_t;
object_name_c owner_name_t;
number of l_start;
number of l_end;
cursor c1 is
Select the owner, object_name object;
Start
l_start: = dbms_utility.get_time;
I'm in c1
loop
null;
end loop;
l_end: = dbms_utility.get_time;
dbms_output.put_line (' the extraction time is ' |) (l_end-l_start)) ;
l_start: = dbms_utility.get_time;
-car me in c1
Open c1;
loop
When exit c1% notfound;
collect the fetch c1 into loose in owner_c, object_name_c;
end loop;
Close c1;
l_end: = dbms_utility.get_time;
dbms_output.put_line (' bulk is the time needed to extract ' |) (l_end-l_start)) ;
end;
Can someone suggest as to why it happened?
Thanks and greetings

580988 wrote:

Hello world

I have performed below block in the SCOTT schema for the gap between the standard extraction and extraction block. I read that extraction is more standard fast recovery. How ever the results were opposed as shown below.

Can someone suggest as to why it happened?

Thanks and greetings

Well I run your code using Oracle 12 c and based on your query in your cursor may be the first time that it will be a little different but then I noticed your code and I wonder... WHY you BULK COLLECT within the loop?

That's the whole point of the bulk to pick you up. Get you ONCE... in 'bulk '.

Here is your code changed on my db and my result set
```
SET SERVEROUTPUT ON

DECLARE

   TYPE owner_name_t IS TABLE OF all_objects.object_name%TYPE;

   owner_c         owner_name_t;
   object_name_c   owner_name_t;
   l_start         NUMBER;
   l_end           NUMBER;

   CURSOR c1 IS
      SELECT owner
            ,object_name
        FROM all_objects;

BEGIN

   l_start := DBMS_UTILITY.GET_TIME;

   FOR I IN c1 LOOP
      NULL;
   END LOOP;

   l_end := DBMS_UTILITY.GET_TIME;

   DBMS_OUTPUT.PUT_LINE ('The time required for fetch is ' || TO_CHAR(l_end - l_start)));

   l_start := DBMS_UTILITY.GET_TIME;

   OPEN c1;

   --LOOP
      --EXIT WHEN c1%NOTFOUND;

   DBMS_OUTPUT.PUT_LINE('Fetching bulk collect');

   FETCH c1
    BULK COLLECT
    INTO owner_c, object_name_c;

   --END LOOP;

   CLOSE c1;

   l_end := DBMS_UTILITY.GET_TIME;

   DBMS_OUTPUT.PUT_LINE ('The time required for bulk fetch is ' || TO_CHAR((l_end - l_start)));

END;
/
```
Result set

Difference between dates

11.2.0.4
not just a simple less question.
Having a job of populating a table, table has several fields, 1 field is a date stamp
create table t1
(date of col1,
lotsofcols varchar2 (100))
Work is essentially a
Insert into t1 (sysdate, 'somedata');
Work can run hundreds of times per minute, I need to know when something happens when labour has not filled the table within a certain time, the time is different during the day, but if I get it working for a minute away its fine. I only need to run hourly check. So I want to select in the table all records during the preceding hour, then select the next inserted row, fewer dates and check whether it was more than a minute. I can tell you that in a few ways, but the main SQL is what Im in trouble with. I don't have a sequence number of the table.
drop table t1;
create table t1
(date of col1,
col2 varchar2 (10));
-run 4 times this
Insert into t1
values (sysdate, 'abc');
-run once to get a tape with a gap of 10 minutes
Insert into t1
values (sysdate + (10 / 24 / 60), 'abc')
commit;
-all records in the last hour
Select *.
from t1
where col1 > (sysdate - (24 / 60))
COL1 COL2
------------------- ----------
30/01/2015-10:46:07 abc
30/01/2015-10:46:08 abc
30/01/2015-10:46:10 abc
30/01/2015-10:46:12 abc
30/01/2015-10:56:16 abc
I want to select col1 4th row rank 5 col1, rank 3 rank col1 col1 4 etc, if the gap is greater than 60 seconds, then return - something, maybe an additional column of an instruction box

Select *.

from (select col1

col2

lag (col1) on prev_col1 (order by col1)

, numtodsinterval (col1 - gal (col1) (col1 order), 'DAY') diff

from t1

)

where diff > numtodsinterval (1, 'MINUTE')

Differences between Data Pump and always by inheritance, import and export

Hi all
I work as a junior in my organization dba and I saw that my organization still uses legacy import and export utility instead of Oracle Data Pump.
I want to convence my manager to change the existing deal with Oracle Data Pump, I have a meeting with them to keep my points and convence them for Oracle utility pump data.
I have a week very convencing power but I won't miss to discover myself, I can't work myself and really a need with differences of strength against import and export, it would be really appreciated if someone can put strong points against Oracle Data pump on legacy import and export.
Thank you
Cabbage

Hello

a other people have already said the main advantage of datapump is performance - it is not just a little more fast exp/imp it is massively faster (especially when combined with parallel).

It is also more flexible (once much more) - it will even create users with exports level schema which imp can't do for you (and it is very annoying that he could never).

It is reusable

It has an api plsql

It supports all types of objects and new features (exp is not - and that alone is probably reason to spend)

There even a 'legacy' at 11.2 mode where most of your old exp parameter file will still work with him - just change exp expdp and impdp print.

The main obstacle to the transition to datapump seems to be all "what do you mean I have to create a directory so that it works", well who and where is my dumpfile why can't it be on my local machine. These are minor things to go well beyond.

I suggest do you some sort of demo with real data of one of your large databases - do a full exp and a full expdp with parallel and show them the runtimes for them to compare...

See you soon,.

Rich

time difference between dates

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