SQL to get the Monday of each week of IW in one year!

Similar Questions

• get the length of each string in a column

  Hi all

  Is there a way to get the length of each string in a column:

  for example:

  If the table contains lines like below:

  Select 'test test1 test31' col1 of double

  Union of all the

  Select 'sectest1 sectest234' double col1

  The output should be as below:

  col1

  ------------

  4 5 6

  8 10

  That is to say get the count of each separated from the chain of space in a column. Is this possible using regexpr_substr?

  Thanks in advance.

  Roy.

  Try the below

  SELECT LISTAGG(val1,' ') IN ONE GROUP)

  New_val ORDER BY lvl)

  Of

  (SELECT LENGTH (REGEXP_SUBSTR (col1,'[^] +', 1, LEVEL)) val1,)

  RN,

  LEVEL lvl

  Of

  (SELECT col1,

  ROWNUM rn

  Of

  (SELECT 'test test1 test31' col1 OF double)

  UNION ALL

  SELECT 'sectest1 sectest234' double col1

  )

  )

  CONNECT BY LEVEL<= regexp_count(col1,'="">

  AND PRIOR rn = rn

  AND PRIOR DBMS_RANDOM. VALUE IS NOT NULL

  )

  GROUP BY rn;

  OUTPUT:-

  =======

  col1

  ----

  4 5 6

  8 10

  Thank you

  Ann

• Get the Parent for each record in the child

  Dear Experts,

  I have a table that contains the parent and child information. I need to make a request to get the parents of each book of the child table. I tried to write the query but does not get the expected results. Please help me.

  Table: relationship

  Parent of the child

  102 101

  103 102

  104 103

  106 105

  107 106

  109 108

  110 109

  Output:

  Expected child

  102 101

  103 102; 101

  104 103, 102, 101

  106 105

  107 106; 105

  109 108

  110 109

  Thank you very much

  Hello

  MU * 443499 * TR wrote:

  Dear Experts,

  I have a table that contains the parent and child information. I need to make a request to get the parents of each book of the child table. I tried to write the query but does not get the expected results. Please help me.

  Table: relationship

  Parent of the child

  102 101

  103 102

  104 103

  106 105

  107 106

  109 108

  110 109

  Output:

  Expected child

  102 101

  103 102; 101

  104 103, 102, 101

  106 105

  107 106; 105

  109 108

  110 109

  Thank you very much

  Why do you want to

  Expected child

  -----  ---------------

  110 109

  Instead of

  Expected child

  -----  ---------------

  110 109; 108

  ?

  You may want something like this:

  CONNECT_BY_ROOT SELECT AS children

  SYS_CONNECT_BY_PATH (parent, ';')  AS expected_output

  FROM table_x

  WHERE CONNECT_BY_ISLEAF = 1

  CONNECT BY child = parent PRIOR

  ;

  If you would care to post CREATE TABLE and INSERT statements for your sample data, and then I could test this.

• How get the text of each paragraph when a textStyleRange is made of texts to multiple paragraphs

  Hello

  Always on my account findText. The result is sometimes as a textStyleRange which contains the texts of multiple paragraphs. What is the best (and easy) way to get the text of each paragraph individually?

  Example: The result of an italic findText with the following extract gives me "saectur quatur? " " Ipsapidunte our" as a unique textStyleRange (correct) but I want to get the text of each paragraph.

  Is there a way to force the findText in the paragraphs and not those of them and if not, how to cut the textStyleRange in 2 texts?

  -----------------------

  Our Ipsapidunte and eumquosame derepre id ulparch iliquae offic tem faccusd aecaborrum, sequi aut doloreperi quaectem eatem faces very quam, con nullaccus repratur molorio enis modi sumquibus nostemquam and volorum facidunti nonseditati re a dolut dolorest ab idipitem saectur quatur?

  Our Ipsapidunte and eumquosame derepre id ulparch iliquae offic tem faccusd aecaborrum, sequi aut doloreperi quaectem eatem faces very quam, con nullaccus nostemquam repratur molorio enis modi sumquibus and re volorum facidunti nonseditati a saectur dolut dolorest ab idipitem quatur?

  There are two solutions:

  (1) you could be formatted every paragraph with formatting marks that you know doesn't exist anywhere else. In this way, each textStyleRange is guaranteed to end at the end of the paragraph.

  (2) you can access the entire first paragraph: myTextStyleRange.paragraphs [0]. I have not tested, but no doubt it works. You could also do a loop: paraLength = myTextStyleRange.paragraphs.length; for (i = 0; i< paralength;="" i++);="" mypara="myTextStyleRange.paragraphs[i];}">

• multiple-join: get the value of each participant

  In the multiple join, the studio and independent do not allow to define the inside interactive activity can be suspended. Is there another way to put it can be suspended?
  
  If the instance has 5 copies and each is sent to different participants, how to get the value of each user?
  
  Quantity of copies to wait to release the default value is 0. What it means?

  Forget not the only multiple makes copies. The main forum is a copy, it remains as it was before the Multiple. And the join does not know how to merge magically all the data of each copy in the main forum. It takes that code as well in the join. Otherwise, your main instance will remain intact.

  If I understand your example, you're not updating the values of the instance variables of your main instance, only copies.

  If you want to get a number that corresponds to the sum of all values sent by all participants in the Multiple, you must make the amount inside the join:

  This.var2 = this.var2 + copy.var1;
  (don't forget to initialize var2 in the primary instance)

  In this way, whenever a copy arrives at the join, var2 is added the value typed in the participant of this particular copy.

  I hope that helps!

• Get the number of month, week and day between 2 dates

  Hi all
  
  Is it possible to display the number of months, weeks and days between 2 dates? by using only the SQL or PL/SQL...
  
  Entry:
  Date: October 1, 2010
  Date: October 19, 2010
  
  I want output like below (assuming starts the week from Monday to Sunday in oracle).
  
  October 1, 2010-(since it's in the middle of the week)
  October 2, 2010-(since it's in the middle of the week)
  October 3, 2010-(since it's in the middle of the week)
  40. (4 Oct-10 Oct falls into the 40th week of the year)
  41. (11 Oct-17 Oct falls into the 41st week of the year)
  October 18, 2010-(since it's in the middle of the week)
  October 19, 2010-(since it's in the middle of the week)
  
  
  Note: If there is a month between the date, the number of the month should be displayed.
  End of the month, the remaining date included with a full week, then the week of the year number should
  displayed. After posting the week, remaining dates should be displayed as it is...
  
  
  Appreciate your help...
  
  
  
  Thank you.
  Fox.

  You mean something like this...

  SQL> ed
  Wrote file afiedt.buf
  
    1  WITH t AS (select date '2010-09-27' as fdate, date '2010-11-21' as tdate from dual)
    2  --
    3  -- END OF TEST DATA
    4  --
    5  select dt2
    6  from (
    7        select dt,
    8               case when days_of_mn = days_in_month then 'Whole: '||to_char(dt,'Month')
    9                    when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   10               else to_char(dt, 'DD-fmMonth-YYYY')
   11               end as dt2
   12              ,row_number() over (partition by
   13                 case when days_of_mn = days_in_month then to_char(dt,'Month')
   14                                  when days_of_wk = 7 then 'Week: '||to_char(dt,'fmWW')
   15                 else to_char(dt, 'DD-fmMonth-YYYY')
   16                 end order by dt) as rn
   17        from (
   18              select dt, wk, mn, days_in_month
   19                    ,count(*) over (partition by wk) as days_of_wk
   20                    ,count(*) over (partition by mn) as days_of_mn
   21              from (
   22                    select fdate+rownum-1 as dt
   23                          ,to_number(to_char(fdate+rownum-1,'fmWW')) as wk
   24                          ,to_number(to_char(fdate+rownum-1,'fmMM')) as mn
   25                          ,to_number(to_char(last_day(fdate+rownum-1),'fmDD')) as days_in_month
   26                    from t
   27                          connect by rownum <= tdate-fdate+1
   28                   )
   29             )
   30        ) x
   31  where rn = 1
   32* order by dt
  SQL> /
  
  DT2
  -----------------
  27-September-2010
  28-September-2010
  29-September-2010
  30-September-2010
  Whole: October
  Week: 44
  Week: 45
  Week: 46
  19-November-2010
  20-November-2010
  21-November-2010
  
  11 rows selected.
  
  SQL>
  

• SQL Server, get the event ID 10016 hourly

  Hi guys,.

  We get the error message below on our SQL with OS WS2012 server every hour.

  "The application-specific permission settings do not grant permission to local Activation for the application server COM with the CLSID.

  {FDC3723D-1588-4BA3-92D4-42C430735D7D}

  and APPID

  {83B33982-693D-4824-B42E-7196AE61BB05}

  the user NT SERVICE\SQLAgent$ IBSQL2012 SID (S-1-5-80-485265429-2350460967-4062759752-2586802043-2488535659) from address LocalHost (using LRPC) running in the container of the application unavailable SID (not available). This security permission can be modified using the Component Services administrative tool. »

  I have been through a few threats and read it from another post on the internet, but under Component Services, tab of the particular service related to this message (based on its APPID) I see that SYSTEM is already added and it has the Launch Local and local Activation permissions granted to the security.

  Why are we always get that number, because instead of local authorities, we should give remote "..." from LocalHost (using LRPC) address... » ?

  All thoughts

  MCG

  Ask the question in the SQL Server forums:
  http://social.msdn.Microsoft.com/forums/SQLServer/en-us/home?category=SQLServer

• subquery to get the results on each side of the result of the query

  I need to get the part numbers that are 2 above and 2 below the room number of the authenticated user. I know well enough the enclosed code would not work, but it's the idea of what I want to do. The upper part of the query gives me the number of the person that is authenticated to the room, and then I need to retrieve all the room numbers that fall between 2 on each side of him. In other words, if the user is in room 110, I need all the people in the room 108, 109, 111, 112 (and Prépliez 110). Yet I am not skilled enough to get this correct query. It's MySQL, if that makes a difference.

  Select the user ID, fname, lname, dorm, room
  of p1 psr_subjects join psr_subjects on p1.dorm = p2.dorm p2

  where p1.username = something
  and p2.room <> p1.room
  and p2.room between p1.room 2 and p1.room - 2

• SQL to get the average timestamp between 2 stamps

  I know similar question has been asked several times in several forums. Most of them deals with the recovery of interval or a difference between the timestamps in figures (hours, minutes,...) or by using PL/SQL or custom functions.

  Without using PL or custom functions, but just a sql, which is the most effective way of the timestamp of calculation which is in between 2 timestamps?

  ALTER session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS ";

  Select
  TO_DATE ('2013-12-05 04:30:20 ',' YYYY-MM-DD HH24:MI:SS') start_date,
  TO_DATE ('2013-12-06 15:00:30 ',' YYYY-MM-DD HH24:MI:SS') end_date.
  "avg_date
  Double;

  Thank you

  Srinivas - y.

  in-house dates (and tiemstamps) are just number, then you can simply add half the difference between the dates of the start_date:

  Select to_date ('2013-12-05 04:30:20 ',' YYYY-MM-DD HH24:MI:SS') start_date

  , to_date ('2013-12-06 15:00:30 ',' YYYY-MM-DD HH24:MI:SS') end_date

  , to_date ('2013-12-05 04:30:20 ',' YYYY-MM-DD HH24:MI:SS')

  + ((to_date ('2013-12-06 15:00:30 ',' YYYY-MM-JJ HH24:MI:SS')-to_date ('2013-12-05 04:30:20 ',' YYYY-MM-DD HH24:MI:SS')) / 2) date_in_the_middle))

  of the double

  START_DATE END_DATE DATE_IN_THE_MIDDLE

  ------------------- ------------------- -------------------

  2013-12-05 04:30:20-2013-12-06 15:00:30 2013-12-05 21:45:25

• On startup, I get the messages that applications have stopped working. One of them is (2nd message) IE3SH application has stopped working. How can I fix it?

  Start-up applications to receive messages from windows that have stopped working. One of them is IE3SH application has stopped working. How can I fix it?

  Hi 9gonz9,

  Welcome to the Microsoft Answers site!

  You get this error message when you start the desktop computer?

  You can check if the complete startup items are checked in the msconfig utility.

  1. open System Configuration by clicking Start , clicking Control Panel, clicking system and security, clicking Administrative Tools, and then double-click the System Configuration.

  If you are prompted for an administrator password or a confirmation, type the password or provide confirmation.

  2. click the Startup tab and check if all the items are archived there.

  You can also run a bag of security for your computer and check if this solves the problem.

  http://www.Microsoft.com/Security_Essentials/

  If the problem persists, turn the computer in clean boot and check if all the background program is causing this error message. To help resolve the error and other messages, you can start Windows Vista by using a minimal set of drivers and startup programs. This type of boot is known as a "clean boot". A clean boot helps eliminate software conflicts.

  The steps to perform a clean boot are given below:

  1 log on to the computer using an account with administrator rights

  2. click on start, type msconfig.exe in the start search box and press ENTER to start the System Configuration utility.

  If you are prompted for an administrator password or for confirmation, type your password, or click on continue

  3. on the general tab, click Selective startup, and then clear the check box load startup items. (The check box use the file Boot is not available.)

  4. on the Services tab, click to select the skin all the Microsoft services check box, and then click Disable all

  Note: Following this step lets services Microsoft continue to run. These services include networking, Plug-and-Play, record of events, error reporting, and other services. If you disable these services, you can permanently delete all restore points. Do not do this if you want to use with existing restore points system restore utility

  Once you start the office see if you get the error message. If not then follow the divide and conquer method mentioned in the article below to know which program is causing the problem.

  For more information about the clean boot, follow the below given link:

  How to troubleshoot a problem by performing a clean boot in Windows Vista or in Windows 7

  http://support.Microsoft.com/kb/929135

  When you are finished troubleshooting, follow these steps to reset the computer to start as usual:

  1. click on start, type msconfig.exe in the start search box and press ENTER.

  If you are prompted for an administrator password or for confirmation, type your password, or click on continue.

  2. on the general tab, click the Normal startup option, and then click OK.

  3. When you are prompted to restart the computer, click on restart

  Hope this information is useful.

  Amrita M

  Microsoft Answers Support Engineer
  Visit our Microsoft answers feedback Forum and let us know what you think.

• How can I get the circular cursor return cloning, it changed from one day to the next day at a type of line of sight...

  HI: I use 14 items, were to deal with a large number of RAW files... shut down last night, started once again today and the tool "clone stamp", I can't get the circular cursor in diameter I want, it only gives me the type of the cross... I changed anything myself... need the circle again!

  brucet32720494 wrote:

  HI: I use 14 items, were to deal with a large number of RAW files... shut down last night, started once again today and the tool "clone stamp", I can't get the circular cursor in diameter I want, it only gives me the type of the cross... I changed anything myself... need the circle again!

  Make sure that the ALT key is not stuck

  Go in Edition > Preferences > display and cursors. Other sliders: Standard is the default value.

  To change the size of the cursor, use the support according to the letter P on your keyboard. ] increase [decrease.

• get the time for each transaction

  Hi Master,

  Someone asked me a question.

  I have a pl/sql block with multiple DML operations. How do you know how much time took each DML operation (not on a single table, tables different operations are underway in my pl/sql block)?  Like this

  Update statement

  INSERT statement

  Remove the statement

  I replied like that... Use dbms_utility.get_time... If each statement how long it takes... We can easily find...!  Once, he said... no I want to use predefined packages. DBA does not accept.

  How can I fix this... Masters?

  Please advise... !!!

  Concerning

  AR

  
  

  DBA will no longer accept pkgs installation... !!

  Create an account of RTO and defend his position to not use standard Oracle supplied packages, take the DBA.

  Therefore, these packages should already be installed.

  (Some essential element of the information seems to be missing).

  Since no valid rationale was given for this crazy requirement (IMHO), the correct solution may possibly be: replace your DBA.

  (I'd love to hear from experienced 'why' people, this requirement would be valid.)

  MK

• How can I get the name of each field

  When in a form with fields to fill in Acrobat Pro ms, I can click form prepare, then more, then set field calculation order...

  A dialog box appears stating "calculated fields.

  How can I get a list of all THE fields to fill?

  roricka

  The complete list is available in the field list in the bottom right of the window in form view prepare.

• Get the date of each month in the last year

  Hi all

  I need to find the last date of the month for the year.

  Example:

  I used to spend the date or such year 2012 or 01-01-2012(DD-MM-YYYY)

  SQL query should return the last date of the month as

  31/01/2012

  28/02/2012

  31/03/2012

  30/04/2012

  .

  .

  .

  .

  .

  12/31/2012

  For more top the requirement that I wrote the SQL code following

  select rownum as row_count,
  case when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Jan_month,
  case when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as Feb_month,
  case when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as mar_month,
  case when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as apr_month,
  case when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as may_month,
  case when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jun_month,
  case when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jul_month,
  case when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as aug_month,
  case when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as sep_month,
  case when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as oct_month,
  case when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as nov_month,
  case when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as dec_month
  
  
  from dual connect by level <= 12 order by rownum;
  
  
  
  
  

  Result

  Jan_Month

  Feb_Month

  Mar_Month

  Apr_Month

  may_month

  jun_month

  jul_month

  aug_month

  sep_month

  oct_month

  nov_month

  dec_month

  1

  31/01/2014

  2

  28/02/2014

  3

  31/03/2014

  4

  30/04/2014

  5

  31/05/2014

  6

  30/06/2014

  7

  31/07/2014

  8

  31/08/2014

  9

  30/09/2014

  10

  31/10/2014

  11

  30/11/2014

  12

  12/31/2012

  Except the result:

  am result except as single line such as

  Jan_Month	Feb_Month	Mar_Month	Apr_Month	may_month	jun_month	jul_month	aug_month	sep_month	oct_month	nov_month	dec_month
  31/01/2012	28/02/2012	31/03/2012	30/04/2012	31/05/2012	30/06/2012	31/07/2012	31/08/2012	30/09/2012	10/31/2012	30/11/2012	12/31/2012

  Kindly give me suggestion to archive more high result.

  Thanks and greetings

  Saami

  I agree with Marcus Pivot is the way to go on this subject... But on the other hand you almost solved yourself... it was just a max function for your results:

  ---------

  select
  max(case  when rownum=1 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Jan_month,
  max(case  when rownum=2 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as Feb_month,
  max(case  when rownum=3 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as mar_month,
  max(case  when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as apr_month,
  max(case  when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as may_month,
  max(case  when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jun_month,
  max(case  when rownum=7 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as jul_month,
  max(case  when rownum=8 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as aug_month,
  max(case  when rownum=9 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as sep_month,
  max(case  when rownum=10 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as oct_month,
  max(case  when rownum=11 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as nov_month,
  max(case  when rownum=12 then last_day(to_date(add_months(trunc(to_date('01-01-2012','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end) as dec_month
  from dual connect by level <= 12 order by rownum;
  

  AND to avoid hard-coding, you can also modify your query in the form:

  select
  max(case  when rownum=1 then last_day(to_date(to_char(rownum),'MM')) end) as Jan_month,
  max(case  when rownum=2 then last_day(to_date(to_char(rownum),'MM')) end) as Feb_month,
  max(case  when rownum=3 then last_day(to_date(to_char(rownum),'MM')) end) as mar_month,
  max(case  when rownum=4 then last_day(to_date(to_char(rownum),'MM')) end) as apr_month,
  max(case  when rownum=5 then last_day(to_date(to_char(rownum),'MM')) end) as may_month,
  max(case  when rownum=6 then last_day(to_date(to_char(rownum),'MM')) end) as jun_month,
  max(case  when rownum=7 then last_day(to_date(to_char(rownum),'MM')) end) as jul_month,
  max(case  when rownum=8 then last_day(to_date(to_char(rownum),'MM')) end) as aug_month,
  max(case  when rownum=9 then last_day(to_date(to_char(rownum),'MM')) end) as sep_month,
  max(case  when rownum=10 then last_day(to_date(to_char(rownum),'MM')) end) as oct_month,
  max(case  when rownum=11 then last_day(to_date(to_char(rownum),'MM')) end) as nov_month,
  max(case  when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month
  from dual connect by level <= 12 order by rownum;
  

  Easy way: (without login)

  SELECT LAST_DAY (TO_DATE (ROWNUM, 'MM')) AS Jan_month,
         LAST_DAY (TO_DATE (ROWNUM + 1, 'MM')) AS Feb_month,
         LAST_DAY (TO_DATE (ROWNUM + 2, 'MM')) AS Mar_month,
         LAST_DAY (TO_DATE (ROWNUM + 3, 'MM')) AS Apr_month,
         LAST_DAY (TO_DATE (ROWNUM + 4, 'MM')) AS May_month,
         LAST_DAY (TO_DATE (ROWNUM + 5, 'MM')) AS Jun_month,
         LAST_DAY (TO_DATE (ROWNUM + 6, 'MM')) AS Jul_month,
         LAST_DAY (TO_DATE (ROWNUM + 7, 'MM')) AS Aug_month,
         LAST_DAY (TO_DATE (ROWNUM + 8, 'MM')) AS Sep_month,
         LAST_DAY (TO_DATE (ROWNUM + 9, 'MM')) AS Oct_month,
         LAST_DAY (TO_DATE (ROWNUM + 10, 'MM')) AS Nov_month,
         LAST_DAY (TO_DATE (ROWNUM + 11, 'MM')) AS Dec_month
    FROM DUAL
  

  See you soon,.

  Manik.

• How to get the date - 7 days (week)

  Hi all
  
  I am beginner in Java and JSP
  
  I'm JSP search form (VO) where I need to set a default value for the start_date - 7 days
  
  OK I get this display today date but how to get that displays a date-7 days?
  
  
  < %
  DateFormat df = new SimpleDateFormat ("JJ. MM.yyyy");
  Date date = new Date();
  String default = 'StartDate =' + df.format (new Date());
  % >
  
  ID
  Thank you

  Simple approach if you're not worried about leap years: -.

  Date todayMinus7 = new Date(System.currentTimeMillis() - 7 * 24 * 60 * 60 * 1000);
  

  Alternatively take a look at the GregorianCalendar class and the add() method.