String to date in AS3

Similar Questions

• In the VI library OR: extract, control of the channel numbers are loaded automatically every time that the VI is open with "count to five: a 2 three 4.0 five." Whence this string of data?

  Even after the removal of the string "count to five: a 2 3 4.» 5."since the control of the chain and its replacement by another string, the original string returns after that the VI has been saved then reopened. Whence this string of data? I have attached a copy of the library feature. In my application, I was able to work around the problem by replacing the chain with a constant string control. But I'm still curious to know what is happening.

  Thank you
  Chuck

  Chuck,

  Chain drive was scheduled by default with the string you see.  To change it, enter the new string, right-click on the control and select

  Operations on the data > default font of the current value

  Now, save your vi.

• How to read a combination of strings and data data file

  Hello

  I'm having the combination of strings and datas to read a data file. I'm reading the file name, the time constants and comments in four indicators separate string (lines for comments varies for different files). And read the data in a 2D array. How can I do this? Y at - it a function that can serch of special characters in the spreadsheet file, so I can locate exactly where I should start reading the specific data. Here's how the data file is displayed. Thank you very much.

  Best,

  Richard

  filename.dat
  14:59 12/31/2009
  --------------------------------------------------
  Sample = 2451
  Frequency = 300, time of waiting = 2500
  Temperature = 20
  --------------------------------------------------
  a few comments
  a few comments
  a few comments
  a few comments
  a few comments
  --------------------------------------------------

  7.0000E + 2 1.5810E - 5
  7.0050E + 2 1.5400E - 5
  7.0100E + 2 1.5500E - 5
  7.0150E + 2 1.5180E - 5

  ....

  Here's a (big) hint.

  

  I would like to give you an excerpt, but I've not updated this machine yet.  It's a pretty boring delimiter, if you know what's good for you, you start to use commas, tabs or simple spaces (my order of preference).  It is far too easy start add or remove spaces and then you need to use more complex methods to obtain data from worksheet.

• A string of data Java Tuxedo server sending thai lang but salt is?

  A string of data Java Tuxedo server sending thai lang but salt is?

  I am java code, read data in oracle 11 and send data to the salt

  but the thai lang data?

  I do. Thank you Todd bit in posting

  I do not know is a correct.

  I started java envelopment

  Export JAVA_TOOL_OPTIONS = ""-Dfile.encoding = UTF8 ' "

  Tuxedo Java Server can send data LANGUAGE THAI to the success of the customer.

• Get string of data Variables

  Hello

  I'm post and retrieve data to an ASP page on a site.

  The data returned using the following function:

  var dataS3:String;
  function handleComplete3(event:Event):void
  {
       var loader3:URLLoader = URLLoader(event.target);
       dataS3 = loader3.data;
       trace(dataS3); 
  }
  
  

  The trace (showing the received data) looks like: score1 = 0.5244005132792953 & score2 =-0.27105341041929653

  How can I get these 2 partitions (score1 and score2), which seem to be part of a string of data, into separate variables that I can then later use as numeric values in frames (round/add/subtract/multiply/divide their)? Is there a way to analyze the 2 variables for use in mathematics from frame later? Would I declare var DataS3 differently or keep it as a string, and then somehow convert the string back to separate the numbers or integers?

  Any help appreciated.

  In general, you use objects, you can run a loop on this. You can also type cast that you do only when you must instead create a variable to use.

  Your example rewritten using a table and casting can be:

  function handleComplete3(event:Event):void

  {

  do a bunch of var = value pairs

  var urlVars:Array = String (event.target.data).split("&");)

  S5

  trace (String(urlVars[0]). Split ("=") [1]); a string of draws

  S6

  trace (String(urlVars[1]). Split ("=") [1]); a string of draws

  Now you want to conversion, just convert online numbers instead of again assign vars

  S7

  trace (Math.Round (Number (String(urlVars[0]). ((Split ("=") [1]) * 1000) / 1000); number of prints

  S8

  trace (Math.Round (Number (String(urlVars[1]). ((Split ("=") [1]) * 1000) / 1000); number of prints

  }

  The fundamental point is that you can use the data that you receive directly and unless it is in a feature called very intensively you can just multiple operations at the same time without saving changes out of additional variables.

  You are allowed to Garland and types of melting as you go. For example I have to split the string by one & ampersand into a temporary array, I did it for easier reading. To print your S7 I would have done this one line of code:

  function handleComplete3(event:Event):void

  {

  traces of your S7

  trace (Number (Math.Round (Number (String (String (Event.Target.Data). Split ("&") [0]). Split("=") [1]) * 1000) / 1000));

  }

  There is no difference between the S7 printing. You assigned a bunch of variables and set up one by one. I sank anonymously their Garland style without attributing all the variables working directly on the data. I just wanted to point the daisy chaining power of ActionScript. You can convert things as you go and condense the code and dynamic variable usage a bit.

• String to date Conversion inside XSLT

  Hi all
  
  I want to convert a string of (Eg: 2009-12-06 00:00:00) to a type of format date yyyy-mm-dd Vice versa.
  
  I managed to convert the Date to a string
  
  < element name = "input" type = "date" / > (schema)
  
  < element name = "result" type = "string" / > (schema)
  
  
  < ns1:SIDtoCRMProcessResponse >
  < ns1:result >
  < xsl: value-of select = "xp20:format - dateTime (/ ns1:SIDtoCRMProcessRequest / ns1:input,)" [M01] / [D01] / [Y0001] [H01]: [m01]: [s01] ")" / > "
  < / ns1:result >
  < / ns1:SIDtoCRMProcessResponse >
  
  
  but when try to String in Date
  
  < element name = "input" type = "string" / > (schema)
  
  < element name = "result" type = "date" / > (schema)
  
  < ns1:CRMToSIDProcessResponse >
  < ns1:result >
  < xsl: value - of select = "xp20:format - dateTime(/ns1:CRMToSIDProcessRequest/ns1:input,"[Y0001]-[M01]-[D01]")" / > "
  < / ns1:result >
  < / ns1:CRMToSIDProcessResponse >
  
  his failure
  
  I think the format dateTime function expects the entry date. Can someone kindly help me how to convert String to Date inside a xsl without using the external java function.
  Thank you

  you could use some dirty concatination to build the format yourself.

  not going to win the beauty contest but

• Formatting string to date in BPEL

  Y at - it a way to format a string to date in BPEL value.
  
  I would date a string and I need to push this date value in Oracle data to a field that is of data type Date. I don't see no function in BPEL, which is allowing me to do.
  
  For example my entry of BPEL is ' 01/01/2010' and I need to convert this string in the variable of type date and assign one of the fields in one of the tables in the Oracle database.
  
  I use xp20:format - dateTime function, but it is also to give me the time that I am not able to introduce into the database of the field is specified as the date.
  
  I'm doing this conversion in the allocation and transformation process.
  
  Thank you
  Arun-
  
  Published by: user626948 on August 28, 2008 22:40

  I guess you are trying to insert in the database through the database adapter. The DB adapter always represents a database as XML dateTime date. The default format to create a dateTime is YYYY-MM-DD' you hh. To create a dateTime valid object to be inserted into your database with the given substring you would end up with an expression such as:

  XP20:format-DateTime(Concat(Substring('01/01/2010',7,4),'-',SUBSTRING('01/01/2010',1,2),'-',SUBSTRING('01/01/2010',4,2),'T00:00:00'))

  assuming that 1 January 2010 is in MM/DD/YYYY format. In the expression builder you will probably replace the 1 January 2010 "with a reference to a variable that contains the date value.

  Kind regards
  André Jochems

• AppleScript set the string to date and add 30 minutes

  I am filling 2 boxes of time on a website in Safari, using Applescript from buttons selected by the user.

  My current Applescript is:

  Value dialog box to display the dialog box buttons ' when did your first departure case? {"07:30, ' 08:00, ' 08:30" "" "}

  definition of the first button returned of the result

  inputByName ("time 1", 0, start)

  the value of test for '07:30 ' - assuming that the user has selected '07:30 ' in the dialog box

  Test date - do not know how to assign 07:30 as an hour

  Finishing to test set + (30 * minutes)

  inputByName ("2", 0, finishing)

  The error return is number 'Invalid date and time date 07:30 < < script > >.' -30720

  Any help would be greatly appreciated!

  Thank you

  s

  You must use a complete date in the date/time of your machine settings.  A simple way is to simply get the current date (which returns a full date object) and manipulate that, for example:

  tell (current date)
    set its time to (7 * hours) + (30 * minutes)
    set someDate to it
  end tell
  return time string of someDate
  

• How to convert a string of data to a table 1 d

  Dear all,

  I wonder if someone can help me.

  In the attached Elf, I have my program (in labview 8.6) who read the updates and the data of temperature for the time.

  I want to use temperature update in a calculation.  How can I get the new temperature I think it's in a format string and convert it into table 1 d?

  I tried, but the number I got the temperature wasn't the same temperature, which is shonw in the section of the program data.

  Could someone help me please?

  Kind regards

  You do not read the temperature, you read a binary file. You seem to be assuming that the string format, but do you really know? Nobody here can say since you do not have the file, if it is you need to use one of the functions of conversion of the string. And please, get rid of the local data variable. You're already usin shift registers. Do the same with the data from the file.

• Make XY graph from the string with date and time data

  1 all sorry for my English.

  I have files with data. In this array of strings, I have 2 columns with date and time. I want to show these data to the XY Chart with time and date on some of the DBL and X on Y.

  I tried to do it by myself, but cannot add to time on X axis.

  Hi olderon,

  you date string is something like "30.01.2014" but looking for "%d//%m %y. Spot the problem?

• Avoid writing empty lines or remove the empty string between data lines

  Hello

  I have this problem...  I write as a 4 x 4 witch table comes from a graph of intensity in a file. But when I write, regardless of the method that I use out it somehow unusable when I try to read more later.

  Right now I got change for a 1 x 16 table witch I later convert back to 4 x 4 again shown in the graph of the intensity.

  The problem is that I have empty lines between the data I want to remove to display correctly.

  Maybe to be clear in my explanation I will post screenshots of how I write and how I like to read...

  

  Can someone help me?

  Thank you!

  Antonio

  Why do you use a loop to create a string to write to the file? In LabVIEW 8.x writing on a spreadsheet file is polymorphic, so you can select the instance of 'Double' and simply connect your table 2D directly to it, without a loop or anything like that. On playback, even select the instance 'Double' for your return values exactly as you wrote them.

• Compare the string to date?

  Hello everyone, I have a date recorded in this format string ' 25/05/2011' and I want to compare this string with the current date. I am able to do so if I divided the Date to a String [] string, but it's using a coding hard to compare dates, which does not work if I use: String CurDate = dateFormat.formatLocal (System.currentTimeMillis ()); Because the format is not always as DD/MM/YYYY, depending on the settings of the user's phone. I'm sure that there is a better way to compare two dates, could someone ' a please advise me on this matter. Please note that I have saved in this format DD/MM/YYYY Date String. Thanks in advance.

  create a calendar, to day/month/year and check if it's the day same long http://www.blackberry.com/developers/docs/6.0.0api/net/rim/device/api/util/DateTimeUtilities.html#is... )

• Date string between Dates

  Hello.  I came up with a method that seems to work fine.  Just thought it might be a more effective way to determine if a date string (must be from a string) is located between 2 other dates (of string).

  TimeZone clientZone = TimeZone.getDefault();
  
          String dateToCompare="2012-10-03";
          String dateBegin="2012-10-01";
          String dateEnd="2012-10-07";
  
          Date date1= new Date(HttpDateParser.parse(dateToCompare));
          Date date2= new Date(HttpDateParser.parse(dateBegin));
          Date date3= new Date(HttpDateParser.parse(dateEnd));
  
          Calendar calToCompare = Calendar.getInstance(clientZone);
          Calendar calBegin = Calendar.getInstance(clientZone);
          Calendar calEnd = Calendar.getInstance(clientZone);
  
          calToCompare.setTime(date1);
          calBegin.setTime(date2);
          calEnd.setTime(date3);
  
          if(calToCompare.after(calBegin) && calToCompare.before(calEnd)) {
              Dialog.alert("date is between");
          }
          else {
              Dialog.alert("date is NOT between");
          }
  

  Is there a better way to do this?  Thank you.

  Date date1 = new Date (HttpDateParser.parse (dateToCompare));
  Date2 = new Date (HttpDateParser.parse (dateBegin));
  Date date3 = new Date (HttpDateParser.parse (dateEnd));

  long compareDateLong = date1.getTime ();

  long beginDateLong = date2.getTime ();

  long endTimeLong = date3.getTime ();

  If (beginDateLong < comparedatelong="" )="" &&="" (="" endtimelong=""> compareDateLong) {}

  Dialog.Alert ("date is between");
  }
  else {}
  Dialog.Alert ("date is NOT between the two");
  }

• How to parse a string to date

  Hello

  I have the string as Wednessday, June 13, 2009 | 12 AM GMT, I want to analyze and convert data type Date. I did the same on J2SE, but class SimpleDateFormat does not parse method in RIM API.

  Please suggest.

  Thank you

  RJ

  If you are looking for an answer on how to do it in Java, you're the best post your question in the Java development forums.

• String to date

  Hi all

  I know there are countless questions about this but I have a problem of slgiht - I'm trying to convert a string in the format YYYY-MM-DD hh: mm:. SCOTT Z

  I am currently splitting the string in the corresponding of the int and then pass them in a calendar using the calendar.set (Calendar.MINUTE) etc. However, if the date and time has passed are that:

  11-05-2010 hour: 11 51 05 it seems lost 20 minutes from time when I call Calendar.getTime ();

  Someone at - it a better way to manage which takes into account the time zone or know why this causes a problem has.

  Hi Zidane,

  can you try it.

  private DateField _dateofBirth;
  DateFormat _dateFormat = DateFormat.getInstance(DateFormat.DATE_DEFAULT);
  _dateofBirth = new DateField("DOB", _datetime,_dateFormat,DateField.DATE);