sum when separate

Hello

I have table

ID | cost

1. 100

2. 200

2. 200

3. 500

4. 500

5. 800

6. 100

6. 100

6. 100

and I need sum (cost) where id is distinct, NO GROUP!

I need to get

all costs

2200

(1 id) 100 + (id 2) 200 + (id 3)500 + (id 4)500+ (id 5)800+ (id 6) 100= 100 + 200 + 500 + 500 + 800 + 100 = 2200

Thanks for help

Select

Sum (Max (cost)) cost

from your_table

Group by id

Tags: Database

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    LO 59611

    SAP 2685

    SPA 95

    I changed above query returns the results online wise.

    Question:-how to add a total of column below sql. (I can reach to above sql by cumulative Group)

    SELECT

    SUM (CASE WHERE THE VALUE LIKE '% LO %' THEN 1 0) OTHERWISE END "LO."

    SUM (CASE WHERE THE VALUE AS THE ' %') THEN 1 OTHER END 0 'LA',)

    SUM (CASE WHERE THE VALUE AS "SAP %') THEN 1 OTHER 0 END 'SAP',)

    SUM (CASE WHERE THE VALUE LIKE ' % SPA %') THEN 1 ANOTHER END 'SPA' 0)

    OF LOGTD

    WHEN TRUNC (DATE_AGS) = TRUNC (SYSDATE)-1

    AND LOG_STATUS = 'P '.

    AND VALUE IS NOT NULL

    output

    THE SAP LO SPA

    62140 59611 2685 95

    2.

    SELECT ERR_SRC_SYSTEM, COUNT (VALUE)

    (SELECT DISTINCT VALUE,

    (IN THE CASE WHERE THE VALUE LIKE '% LO %' THEN 'LO'

    WHAT VALUE LIKE ' % THE % ' THEN 'THE

    WHAT VALUE LIKE '% SAP %' THEN 'SAP '.

    WHAT VALUE AS 'SPA %' THEN 'SPA' OTHER 'OTHER '.

    ERR_SRC_SYSTEM END)

    OF LOGTD

    WHEN TRUNC (DATEAGS) = TRUNC (SYSDATE)-1

    AND LOG_STATUS = 'E '.

    AND VALUE IS NOT NULL)

    ERR_SRC_SYSTEM GROUP

    ORDER BY 1;

    ERR_SRC_SYSTEM, COUNT (VALUE)

    THE 174

    LO 3

    63 SPA

    Question:-how to display columns for bottom case distinct values and the State (I can reach to above sql by cumulative Group)

    Expected:

    THE SPA SAP LO

    174-3-63-0

    I tried something below, but it didn't work because it lead to a distinct value for the column name

    SELECT

    SUM (SEPARATE CASE WHEN TRANSACTION_SID LIKE '% LO %' THEN 1 0) OTHERWISE END "LO."

    SUM (DISTINCT CASES WHERE TRANSACTION_SID LIKE ' % THE %') THEN 1 OTHER END 0 'LA',)

    SUM (DISTINCT CASES WHERE TRANSACTION_SID LIKE ' % SAP %') THEN 1 OTHER 0 END 'SAP',)

    SUM (separate BOX WHEN TRANSACTION_SID LIKE '% SPA %' THEN 1 ELSE 0 END) "SPA".

    OF OD_LG_TRANSACTION_LOG

    WHEN TRUNC (CREATED_DATE) = TRUNC (SYSDATE)-1

    AND LOG_STATUS = 'E '.

    AND TRANSACTION_SID IS NOT NULL

    Kind regards

    Veera

    It's a shame that we didn't give examples of input data to go with your question. Therefore, it is difficult to answer. Saying that, here are my attempts to answer your questions:

    (1) to add columns, you do: col1 and col2 +... + colN. This applies, even if those columns are functions - for example. (Col1) FN + fn (col2) +... + fn (colN).

    (2) maybe you're after something like ' count (distinct cases where trasnaction_sid ' % THE %' as the end value)?

    For example I think you're after, based on a small sample of the dataset:

    with sample_data as (select 1 col1, 'abc' col2 from dual union all
                         select 2 col1, 'bcd' col2 from dual union all
                         select 3 col1, 'abc' col2 from dual union all
                         select 4 col1, 'efg' col2 from dual union all
                         select 5 col1, 'abc' col2 from dual union all
                         select 6 col1, 'hij' col2 from dual union all
                         select 7 col1, 'bcd' col2 from dual union all
                         select 8 col1, 'dfg' col2 from dual union all
                         select 9 col1, 'cde' col2 from dual)
    select count(distinct case when col2 like '%b%' then col2 end) b,
           count(distinct case when col2 like '%d%' then col2 end) d,
           count(distinct case when col2 like '%l%' then col2 end) l
    from   sample_data;
    
             B          D          L
    ---------- ---------- ----------
             2          3          0
    
  • When count sum ID number total &lt; 300

    Afternoon Folks,

    I was wondering if someone could help me with a query of code?

    I'm counting the number of Packs of Service where the total payment of the amount for each separate sp_id is less than 300 pounds and also more than 300 pounds.

    This is the code I have so far:

    Select the specialty
    count (distinct sp_id) "Service Packs",
    Sum (payment_total) "Total paid £»,
    round (sum (payment_total) / count (distinct sp_id), 0) 'average spend by MS.
    of a3_fact_sms_service_inv
    where specialized ("podiatry", "Podiatry")
    and service_date between '01 Jan 11' and 31 Dec 11'
    Specialty group

    This is the table that I want it to look

    SPECIALTY Service Packs Total paid £ average spend by SP * < 300 * > 300 *.
    Podiatry 129 25682,26 199 * 107 * 22 *.
    Podiatry 622 206651,08 332 * 403 * 219 *.

    I'm currently running application 10 g

    Concerning
    Farming :)

    First of all, ' 01 Jan 11' is not a date, but rather a string. Use literals date (or at least to_date):

    with t as (
               select  specialty,
                       sp_id,
                       sum(payment_total) sp_id_total
                 from  a3_fact_sms_service_inv
                 where specialty in ('Chiropody','Podiatry')
                   and service_date between date '2011-01-01' and date '2011-12-31'
                 group by specialty,
                          sp_id
              )
    select  specialty,
            count(sp_id) "Service Packs",
            sum(sp_id_total) "Total Paid £",
            round(sum(sp_id_total) / count(sp_id)) "Average Spend per SP",
            count(case when sp_id_total < 300 then 1 end) "Service Packs Less £300",
            count(case when sp_id_total = 300 then 1 end) "Service Packs Equal £300",
            count(case when sp_id_total > 300 then 1 end) "Service Packs Greater £300"
      from  t
      group by specialty
    /
    

    SY.

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