Table in different ranges of sort number

Similar Questions

• 'For' loop with a different number of iterations. Second, the auto-indexation of the tables with different sizes is done. It can affect the performance of the Vi?

  Hello

  I have a loop 'for' which can take different number of iterations according to the number of measures that the user wants to do.

  Inside this loop, I'm auto-indexation four different 1 d arrays. This means that the size of the tables will be different in the different phases of the execution of the program (the size will equal the number of measures).

  My question is: the auto-indexation of the tables with different sizes will affect the performance of the program? I think it slows down my Vi...

  Thank you very much.

  My first thought is that the compiler to the LabVIEW actually removes the Matlab node because the outputs are not used.  Once you son upward, LabVIEW must then call Matlab and wait for it to run.  I know from experience, the call of Matlab to run the script is SLOW.  I also recommend to do the math in native LabVIEW.

• Search range of the number to other folders

  Hi all

  I want to know the records which are in the range of other records in the table as:

  with t as 
  (select 1 ID, 405 Address, 3 Num from dual
  union all
  select 2 ID, 399 Address, 10 Num from dual)
  select * from t 
  

  If I'm on ID = 1 and I want the number of records in the table with the range of logic (405,406,407,408) is the research (Address [405] + num [3]) and output should be 2nd

  because its already use 405,406,407,408 (logical is 399 + 10, so between 399 to 409).

  Same deal if I select Id = 2, then he should be back record id = 1.

  Please help me...

  Thank you

  Xandot

  Brute force, be simplified:

  with t as

  (select 1 ID, address 405, 3 double Num

  Union of all the

  Select option 2 IDS, address 399, line 10 of the double

  Union of all the

  Select ID, address 406 3, 1 double Num

  Union of all the

  Select ID, address 400 4, 1 double Num

  Union of all the

  Select ID, 400 address 5, 6 double Num

  )

  Select

  *

  t, (select address has, address + num n t where id = 1) a

  where id! = 1

  and (address

  between a.a

  and a.n

  or address + num

  between a.a

  and a.n

  or AA

  between the address

  and address + num

  or a.n

  between the address

  and address + num

  )

  ID; ADDRESS; NB; A; N

  "2";" 399. " "" 10. " "" 405 "; "408"

  "3";" 406. " » 1 » ; "" 405 "; "408"

  "5";" 400. " » 6 » ; "" 405 "; "408"

• Article 059 (filter how-to ADF related tables by date range) in JDeveloper 12 c (12.1.3)

  Hello.

  I try to implement a solution to article 059 (filter how-to ADF related tables by date range) in JDeveloper (12.1.3) 12 c but hothing happen when I start this example.

  Could someone advise me what to do to make this example work properly on JDeveloper 12 c?

  I made the example work again. The problem is that you can't somehow store new attribute values in the card more. If you store the values for the filter to a different place, it works again.

  Please read the complete solution in my blog https://tompeez.wordpress.com/2015/04/11/how-to-filter-adf-bound-tables-by-date-range-jdeveloper-12-1-x/

  You can download the workspace of GitHub. The link is provided at the end of the blog.

  Timo

• How to acquire of various AI channels simultaneously with a different range for each of them?

  How to acquire of various AI channels simultaneously with a different range for each of them?

  In LabView, I found some examples but in C it is not seem to be any.

  Or you can add channels one by one with individual instructions: the follwing code compilation and runs without error on vitual DAQ hardware:

  ERR = DAQmxCreateTask ("", &taskH); ")
  
  ERR = DAQmxCreateAIVoltageChan (taskH, ' Dev1/ai0', 'AI0', DAQmx_Val_Cfg_Default,-5,0, 5.0, DAQmx_Val_Volts, "");
  
  ERR = DAQmxCreateAIVoltageChan (taskH, ' Dev1/ai1', 'AI1', DAQmx_Val_Cfg_Default,-10,0, 10.0, DAQmx_Val_Volts, "");
  
  DAQmxStartTask (taskH);
  
  ERR = DAQmxReadAnalogF64 (taskH, 5, 10.0, DAQmx_Val_GroupByChannel, val, 10, & read, 0);
  
  DAQmxClearTask (taskH);
  
  

• scroll bar for both tables of different size

  Hello world

  I am applying for thermocouples. Application is working otherwise fine, but I can't make two tables of different size scrolls with a scroll bar. I've attached a picture to make it a little easier to understand. In the photo you can see that there are two tables. Superior is 1 d including channel names. Below is a table with time and the measured temperatures. Vertical scrolling works very well that only the lower table must be the object of a scroll. But if I want to scroll horizontally, I also need to scroll the top table so that the channel names and measured temperatures would correspond. This is the problem that I have not been able to solve. The lower table can 'constantly' update (vertically) because the measure may be underway. I tried to use nodes property tables below top table of controls (IndexValues). I found many many solutions that work with the same dimension tables, but I couldn't manage so that they work with my application. Anyone have any ideas? I use LV 8.6

  Thank you

  Mika

  Also consider using a Table, where the built-in column heading allows to scroll the data, and it is the only control header & data.

• Sort the table of Foundtext and respective Page number

  Hi all

  I'm a novice scripter. It is also my first Indesign script. Please help anyone for my first script. Here is my requirement.

  I want to generate a text style applied to particular character with belonging "number of Page. Also, I need to sort the text found in alphabetical order with the belonging itself page number. I have generated just the text and the page number for membership by writing the following code.

  myDoc var = app.activeDocument;
  var myDocPath = app.activeDocument.filePath;
  var myDocName = app.activeDocument.name;

  app.findTextPreferences = null;
  app.findTextPreferences.appliedCharacterStyle = myDoc.characterStyles.item ("Test");
  var myText = myDoc.findText ();
  var myPageNumber = new Array;
  var myFoundText = new Array;
  var myFoundTextSort = new Array;

  for (var i = 0; i < myText.length; i ++)
  {
  myFoundText.push (myText [i] .silence);
  }

  for (j = 0; j < myText.length; j ++)
  {
  var r = getPageFor(myText[j].characters[0]);
  myPageNumber.push (r.name);
  }

  var inc = 0;
  var myLogFile = new File (myDocPath.fsName + "/ Text_Report_" + app.activeDocument.name.split(".")) ([0] + ".log");
  If (myLogFile.open ("w", defined, undefined))
  {
  if(myFoundText.Length!=0)
  {
  for (var k = 0; k < myFoundText.length; k ++)
  {
  SERIALNO = k + 1;
  myLogFile.writeln ("" + serialno + ".")  ' + myFoundText [k] + "-Page" + myPageNumber [k]);
  }
  }
  }

  myLogFile.close ();
  myDoc.close ();

  function getPageFor (element)
  {
  While (!) (element instanceof Page) | element instanceof request))
  If (element instanceof character)
  item = element.parentTextFrames [0] .parent;
  on the other
  item = element.parent;
  If (element instanceof Page)
  Returns the element;
  Returns a null value.
  }

  Please help anyone. Thanks in advance

  Well, you're almost there. The current problem is in your push instruction. Array.push (...) peut push more than a single element in the table, but it will do so in single shoot; This is why you do not get the composite objects back, but each has pushed point on its own place.

  So either use the method of Kasyan and create a composite object

  PAGEText.push ({pageNumber: 5, text: "this is some text 5 '});

  either way, in a table:

  MYFoundText.push ([MYResults [i] .silence, r.name]);

  Whatever it is, you have to adjust your sort code for what you choose.

• How to display the information in the employee table based on the salary in different ranges.

  I have a table that is used with the details of the employee. I want that employees on the basis of the order of the salary range for the list. For eg., list of employees that are there, I first list salary range 1000-3000 and 3000-5000, then 5000-10000. How to write sql queries to solve this problem? your answers are appreciated.

  something like that

  select t.*,
        case
          when sal between 1000 and  3000 then 1
          when sal between 3000 and  5000 then 2
          when sal between 5000 and 10000 then 3
          else 99
        end range
    from scott.emp t
    order by range, 1, 2;
  

• Filter for table data, the range of data obtained and defined 2D

  I produce data of an ultrasonic sensor at 1 K Hz, and there is a lot of data (data points range of 0 to 10). However, in some cases when I know that the data should be about 7 (for example) I get outliers (about 9 and 10). Is it possible to define a filter for data in the defined range.

  I averaged the data to get an average value, and outliers are distorting. In the worst case, my outliers are 30 to 40% of the data generated. I created a filter to sort the data and, taken from the lowest value. I stop the loop when data reaches a value greater then 9. But this seems to take a long time (because the loop checks for each data point and there are 1000s of them).

  Is there a better way to filter data and define a predefined table range to collect?

  I enclose my filter.vi... and a set of samples of my previous data. The ranges of data of 10-8 and would like to have the range 7.5 to 8.5 to consider. The sensor records tension here and the problem can be solved by installing a different type of sensor, but if a filter in LabView can due it, the sensor that we use now is absolute.

  I am in kind of emergency, my design in unfinished because of this problem, if someone can find some time to share some suggestions, I will be grateful.

  Thanks in advance.

  See attachment.  I have incorporated the data you've posted in the vi.  It doesn't seem like any data were less than 8.7 or so, so I modified the scope so it would be a few points on average.  Some games were completely out of reach while the average came back like NaN (not a number) due to a division by zero.

• How to find how many times, how many numbers in a range of numbers (number of lines and columns) has been repeated (numbers 3.6.2)

  Hello

  I have a range of numbers from B2 - B11 until the G2 - G11. For example:

  31	7	28	10	4	17
  20	13	44	2	1	39
  32	45	39	4	10	25
  26	38	27	43	12	3
  42	35	37	1	34	21
  13	39	11	14	5	37
  21	33	34	4	13	10
  31	14	1	24	35	3
  20	2	24	27	22	30
  10	34	36	32	3	27

  I would like to know who among these numbers have occurred and how many times. For example (just to have as an example): number 10 repetitions 5 times, number 13 repeated 3 times, 24 repetitions 9 times.

  Repeats = duplicates.

  I want to know all the repetitive number and how many times they repeat.

  Is there some kind of formula I can use to get there. It would be good to have the sorted result. For example:

  32 repeats 10 times

  24 repeat 9 times

  6 reps 8 times

  5 repeat 7 times

  22. repeat 6 times

  10 repeats 5 times and so on.

  Hello

  Problem of three steps:

  1. Determine the distinct values
  2. Count the number of times each appears in the table
  3. Sort by value or frequency (or both).

  The first step is easily handled by copy separate Automator Service, a Service of Automator, written by SGIII. A link to the file in post June 21 of the SG in this thread: Re: Analyzing column (maybe not the correct wording)

  After downloading and installing the service, select the cells containing the numbers, call the service, and then select the first regular (ie. non-header) cell to a new table and the dough.

  (The following assumes the new table has a header row, no column header, and you have selected - click - cell A2 before pasting.)

  You will get a list of distinct numbers in a single column (A2 - A34, of your sample and support of note).

  To count the numbers:

  In this example, the existing table is named 'Table 1'

  Enter the following formula in B2 the new table, and then fill up to the last line of the column B:

  = COUNTIF (Table 1::B:G, A)

  Results should be as shown:

  

  Sort the results on column (value) or B (frequency)

  Two types (A, then B) will be put in order of frequency, with values appear the same number of times sorted by value within this group.

  Kind regards

  Barry

• after image restore, backup partition table is different

  Hello

  He is a 2012 Macbook mid Pro with El Capitan and Bootcamp.

  After repeated with Bootcamp (Windows 10 Pro) problems I started using Image of Terabyte for Linux in order to safeguard this Macbook. Forums terabyte that people know that the Image of Linux (such as Image for Windows) is able to create a reliable backup, but also to restore - restore an entire disk image or restoring individual partitions.

  I followed their instructions precisely and activated the two options "restore first Beach" and "TPG hidden OS" (as one terabyte official, Member of the forum wrote) when restoring a partition.

  Unfortunately, it did not work! Bootcamp was no longer visible in the start screen or wasn't visible, but not start.

  What I found was that I had to keep the two options (see above) with DISABILITIES.

  Then I could restore some partition images - and 10 Windows in Bootcamp is bootable.

  Well, it was the long introduction.  I'm sorry.

  Now my question is:

  Is this something that has changed my partition table?

  Before restoring an Image for backup of Linux for the first time, I had this partition table:

  localhost: ~ root # fdisk/dev/disk0

  Disk: geometry / dev/disk0: 60801/255/63 [976773168 sectors]

  Signature: 0xAA55

  From end

  #: cyl hd s - cyl hd s id [Start - size]

  ------------------------------------------------------------------------

  1: EA 1023 254 63 - 1023 254 63 [1-409639]

  2: AF 1023 254 63 - 1023 254 63 [409640-857906448] HFS +.

  3: AB 1023 254 63 - 1023 254 63 Boot Darwin [858316088-1269536]

  * 04:07 1023 254 63-1023 254 63 [859586560-117186560] HPFS/QNX / TO THE

  BUT:

  After failed attempts to restore and work finally restore my partition table operation is different:

  Fdisk/dev/disk0

  Disk: geometry / dev/disk0: 60801/255/63 [976773168 sectors]

  Signature: 0xAA55

  From end

  #: cyl hd s - cyl hd s id [Start - size]

  ------------------------------------------------------------------------

  1: EA 0 0 2 - 1023 255 63 [1-409639]

  2: AF 25 102 15 - 1023 255 63 [409640-857906448] HFS +.

  3: AB 1023 0 57 - 1023 255 63 Boot Darwin [858316088-1269536]

  * 04:07 1023 199 8-1023 255 63 [859586560-117186560] HPFS/QNX / TO THE

  Everything seems to work fine, but I wonder if the different appearance of the partition table can be a problem?

  For example, compare:

  1: EA 1023 254 63 - 1023 254 63]

  3 o

  409639]

  TO

  1: EA 0 0 2 - 1023 255 [63 3 o 409639]

  It's the output of 'diskutil list ':

  localhost: ~ root # diskutil list

  / dev/disk0 (internal, physical):

  #: NAME SIZE TYPE IDENTIFIER

  0: GUID_partition_scheme * GB 500,1 disk0

  1: disk0s1 EFI EFI 209.7 MB

  2: Apple_HFS Macintosh HD 439,2 GB disk0s2

  3: disk0s3 Apple_Boot Recovery 650.0 MB HD

  4: Microsoft database BOOTCAMP 60.0 GB disk0s4

  And the output of 'TPG - r - vv show/dev/disk0':

  See the TPG: / dev/disk0: mediasize = 500107862016; SectorSize = 512; blocks = 976773168

  See the TPG: / dev/disk0: MBR suspicious to sector 0

  See the TPG: / dev/disk0: Pri GPT to sector 1

  See the TPG: / dev/disk0: GPT Sec at sector 976773167

  start index size summary

  0 1 MBR

  1 1 Pri GPT header

  2 32 table GPT Pri

  34 6

  40 409600 1 part TPG - C12A7328-F81F-11D2-BA4B-00A0C93EC93B

  409640 857906448 2 part TPG - 48465300-0000-11AA-AA11-00306543ECAC

  858316088 1269536 3 part TPG - 426F6F74-0000-11AA-AA11-00306543ECAC

  859585624 936

  859586560 117186560 4 part TPG - EBD0A0A2-B9E5-4433-87C0-68B6B72699C7

  976773120 15

  976773135 32 table dry GPT

  976773167 1 dry GPT header

  Out of 'gdisk/dev/disk0:

  localhost: ~ root # gdisk/dev/disk0

  GPT fdisk (gdisk) version 1.0.1

  WARNING: Open with shared lock devices will not have their

  table partition automatically reloaded!

  Scanning partition table:

  MBR: hybrid

  BSD: absent

  APM: absent

  TPG: present

  Found a valid GPT with hybrid MBR; using GPT.

  Command (? for help): p

  Disk/dev/disk0: 976773168 sectors, GiB 465.8

  Logical sector size: 512 bytes

  Identifier (GUID) of disc: 38A2E667-6E00-4C0F-BD78-C95979E3CFAE

  Partition table contains up to 128 entries

  First usable sector is 34, last usable area is 976773134

  The partitions will be aligned with the boundaries of sector 8

  Space is free total 957 sectors (478,5 KiB)

  Starting number (sector) end (sector), Code name of size

  409639 40 1 MiB EF00 EFI 200.0

  2 409640 858316087 409.1 giB AF00 Macintosh HD

  3 858316088 859585623 619.9 MiB AB00 Recovery HD

  4 859586560 976773119 55.9 giB 0700 BOOTCAMP

  Any ideas?

  Another question:

  Is it possible to save the table to partition like that?

  DD if = / dev/sda of = gptandmbr bs = 512 count = 34

  Thank you very much

  NEUMAC

  In Fdisk, the CHS numbers are arbitrary on modern disks. They are the time of BIOS and old disks with CHS geometry. Puts BCA from Mac 0-1023 (1024 cylinders), 0-255 (256 heads) and 0-63 (64 sectors). Modern disks far exceed those numbers and would drain them. Must match what is the triplet of start/end/size and it fits in GPT and MBR. You can put arbitrary 0,0,0 for CHS and you will see all issues on GPT disks.

  Please do not use TBIL to restore W10 to circa 1970-80 disks.

• Table of different columns

  Hello

  In the attached VI, I am currently getting all tables appears in the same columns. I'm showing every passage in the VI attached to show different columns in the string table.

  Any help will be appreciated.

  Thank you

  hiNi.

  I allocate an array of strings to the final size, then replace the data as you go. Here's the quick rewrite (LabVIEW 8.5).

  (I don't understand your use of the structure of sequence variable, local and while loops. The first two are not necessary and the curls should be FOR loops, because you know the number of iterations in advance.

  (Note also that you must work with chains for the final table. A digital painting is filled with zeros for undersized lines or columns. An empty string for the missing elements seems most appropriate).

• Container for several tables of different length

  Hey,.

  I'm doing an algorithm for labelling component connected in LabVIEW.  I came across the problem that I need some sort of data structure that I can't create.  I hope that I've missed something and someone can report this to me.

  What I'm looking for is a container that can contain lists of lists of 2 values.  Basically, I have several labels.  Each label will have a list of coordinates in.  The closest I came to this creation is a 2D cluster table.  Then, the cluster contains the coordinates X and Y.  The problem is that each list is not the same size, and for a table of 2D in labVIEW, all rows/columns must have the same length.

  In summary, I'm looking for a way to store multiple lists of coordinates.  The lists will all be of different lengths, and I don't know how many lists there will be.

  Is it possible to do this?

  If not, does anyone know an easier way than that looking for a 2D for concentrations table all?  At the back of my mind, I want to say that there may be a Vision VI of OR who can do this, but I can't find a.

  Thanks for your help,

  Dominic Walker

  A way to manage several arrays of different lengths (but all the same type of data) is to put the berries in a queue.  Each element in the queue must be a table, but they can be of different lengths.  To get to all the tables, you use the preview queue feature.  It returns an array of clusters with each table queue in a separate group (if I remember correctly).   Perhaps an array of clusters of berries would work for you.  I just checked that this allows arrays of different lengths.  You can also place a control of the chain with the label of the cluster if it is appropriate.

  Lynn

• moving partioned tables to different areas of storage in oracle 11g.

  Dear all,
  I need to move the table partitioned to a different tablespace. I moved all the partitions individually, as well as the index.
  However I have a problem now, when I check the user_tables or dba_tables view, I see correspomding tablespaces null in the table of the column tablespace_name.
  
  How do I see the name of the tablespace in these views.

  Even thouh Sb gave you the right answer, I just show you below to copy / paste screen 11.2.0.1 sqlplus:

  test1@ORCL> create table t (x number)
    2    partition by list (x)
    3    (partition p1 values (10),
    4    partition p2 values (20));
  
  Table created.
  
  test1@ORCL> select table_name,tablespace_name from user_tables;
  
  TABLE_NAME                     TABLESPACE_NAME
  ------------------------------ ------------------------------
  T
  
  1 row selected.
  ---Means tablespace_name.user_tables is always null for partition table(s).
  ---Ok, then how do I see the tablespace name?
  test1@ORCL> select table_name, partition_name,tablespace_name
    2  from user_tab_partitions
    3  where table_name = 'T';
  
  TABLE_NAME                     PARTITION_NAME                 TABLESPACE_NAME
  ------------------------------ ------------------------------ ------------------------------
  T                              P1                             USERS
  T                              P2                             USERS
  
  2 rows selected.
  
  test1@ORCL> ALTER TABLE T MOVE PARTITION P1 TABLESPACE EXAMPLE;
  
  Table altered.
  
  test1@ORCL> select table_name, partition_name,tablespace_name
    2  from user_tab_partitions
    3  where table_name = 'T';
  
  TABLE_NAME                     PARTITION_NAME                 TABLESPACE_NAME
  ------------------------------ ------------------------------ ------------------------------
  T                              P1                             EXAMPLE
  T                              P2                             USERS
  
  2 rows selected.
  
  test1@ORCL> select table_name,tablespace_name from user_tables;
  
  TABLE_NAME                     TABLESPACE_NAME
  ------------------------------ ------------------------------
  T
  
  1 row selected.
  

  Just for your information please.

  Concerning
  Girish Sharma

• Little change in the table and little range between 2 numeric values

  Hi all

  I am a student in Electromechanics in Belgium and I do a simulation of an explosion with 48 leds for my final project.

  In the attachment, you can see the program that I have already written. I think that this can be done more easily, but I don't know how.

  I cut out 48 leds in 2 tables, with each table 24 LED.

  If you see the program you will understand actually the best way to do this is to shift bits, but I don't think it can be done in LabVIEW?

  But, the program works, so this isn't the real problem.

  Now, I have to add a new function to the program, which allows you to add a range of leds.

  So if you want to test 10 led 18 led, you can choose the "from... to..." menu and complete the range of leds.

  Also, if you want to send a linear explosion with a fork, it must be possible to leave the early explosion to run 10 and end on 18.

  I thought to do a function like this:

  1111 1111 1111 1110 0000 0000 (10)

  0000 0011 1111 1111 1111 1111 (18 reverse)

  0000 0011 1111 1110 0000 0000 (the LED range I want)

  but I do not know how...

  Can someone please help me with this, it's keep me busy for days

  I don't ask you to do the program for me, because I know it's complicated, but some advise to help me further with this.

  Thank you!

  I forgot the attachment