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Similar Questions

I need an event to repeat the 1st Thursday of each month; the only option I have is every 8th 6 or each day.

I wish I had a repetitive on the first event and the third Thursday of each month. I can't make it a monthly event repeated the same day of the week.

Also, I get an overlay on my Yahoo screen that says I must be disconnected or closed another page and I need to connect when I did this. Is this a problem of Yahoo?

For your repeat again, I guess that's your Yahoo calendar? This isn't a matter of Firefox, I suggest you try to communicate with yahoo.

For the other questions, try the following:
Upgrade to Firefox 15. Then, Firefox Refresh - reset the parameters and modules

Select the last record of each month

Hello
to select the last docnumber and qty of every month
Structure
Name Null? Type
------------------------------- -------- ----
PRODUCTCODE NUMBER
NUMBER NUMBER
DATE OF PLANFORMONTH
NUMBER OF CLEXPECTEDQTY
NUMBER OF CLCONFIRMQTY
NUMBER OF CLFGBUFFERQTY
NUMBER OF CLTOTPRINTBUFFER
in this select query if I take the sum he required all records where, as I want the last record of each month
SELECT productcode docnumber MAX (Number), planformonth, SUM (clexpectedqty) clexpectedqty (planformonth) MAX.
SUM (clconfirmqty) clconfirmqty, SUM (clfgbufferqty) clfgbufferqty, cltotprintbuffer OF FGSALESPLAN of the SUM (cltotprintbuffer)
GROUP BY productcode, (planformonth)
Sandy

Hello

Thanks its working now the code is written as below:

SELECT * FROM

(SELECT

e.*,

ROW_NUMBER() OVER (partition by PRODUCTCODE by DOCNUMBER DESC order) r

Of

E FGSALESPLAN)

WHERE r = 1 AND

entryvalid = 'Y '.

order by Number

Sandy

Find the 2nd Sunday of each month in a report

Hello
I have the data of EMP_Name and Join_Date. I have to build a dashboard report where
1. In the dashboard, there is a command prompt. If I select a year and a month then, the report is expected to show that the data of the respective month.
2. This report will show the employees who joined the company only after the 2nd Sunday of each month until the end of the month.
Inputs/suggestions, how to build it?
Thanks in advance.

You have a question, Yes... a SQL query... OBIEE do not mean SQL but LSQL, your query will be not really usable like this...

You're right, it seems that when the first day of the month is a Saturday he jump 1 week...

The correct formula for the 3rd Friday is:

TIMESTAMPADD (SQL_TSI_DAY, (14 + 6-CASE WHEN DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE)) = 7 THEN 0 END ELSE DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))), TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))

If instead of CURRENT_DATE you want to use your own column date just to replace in the formula and it works.

How to find the first Sunday and the second Saturday of each month

Hi all
How to find the first Sunday and the second Saturday of each month
Thank you
Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

994122 wrote:

Hello

I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

Do you have a procedure?

Should you output only for the months you passed in the parameter?

The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

PROCEDURE two_dates)

p_date IN DATE

p_first_sunday DATE

p_second_saturday DATE

)

IS

BEGIN

p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

END two_dates;

Or you describe what you need.

How to get the second Monday of each month in a given date range?

In Oracle forms, how to get the second Monday of each month in a given date range?
I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?
WITH month_range AS
(
SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month
, TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month
OF the double
)
SELECT NEXT_DAY (6 + ADD_MONTHS (first_month
, LEVEL - 1
)
, 'MONDAY '.
) AS second_monday
OF month_range
CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)
;
Thanks in advance.

Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

END AS second_day

FROM (SELECT SYSDATE startdate,

SYSDATE + 300 enddate

THE DOUBLE)

CONNECT BY LEVEL<=>

for the 25th day of each month in Date function
Dear all,

I want to want to get the 25th day of each month
as.
Select sysdate from dua.

Concerning
```
SQL> select trunc(sysdate,'MM')+24 "Day" from dual;

Day
---------
25-MAY-13
```

How to get the date for the first Monday of each month

Dear members,

How to get the date for the first Monday of each month.

I wrote the following code

SELECT decode (to_char (trunc (sysdate + 30, 'MM'), 'DAY'), 'MONDAY', trunc (sysdate + 30, 'MM'), NEXT_DAY (trunc (sysdate + 30, 'MM'), "LUN")) FROM DUAL

But he looks at complex bith.

Abhishek

Published by: 9999999 on 8 March 2013 04:30

Use the IW format - it will make independent NLS solution. And all you need is truncated 7^th day of each month using IW:

select  sysdate current_date,
        trunc(trunc(sysdate,'mm') + 6,'iw') first_monday_the_month
  from  dual
/

CURRENT_D FIRST_MON
--------- ---------
08-MAR-13 04-MAR-13

SQL>

Here is the list of the first Monday of the month of this year:

with t as(
          select  add_months(date '2013-1-1',level-1) dt
            from  dual
            connect by level <= 12
         )
select  dt first_of_the_month,
        trunc(dt + 6,'iw') first_monday_the_month
  from  t
/

FIRST_OF_ FIRST_MON
--------- ---------
01-JAN-13 07-JAN-13
01-FEB-13 04-FEB-13
01-MAR-13 04-MAR-13
01-APR-13 01-APR-13
01-MAY-13 06-MAY-13
01-JUN-13 03-JUN-13
01-JUL-13 01-JUL-13
01-AUG-13 05-AUG-13
01-SEP-13 02-SEP-13
01-OCT-13 07-OCT-13
01-NOV-13 04-NOV-13

FIRST_OF_ FIRST_MON
--------- ---------
01-DEC-13 02-DEC-13

12 rows selected.

SQL>

SY.

to calculate the days of sheets each month

Hi all
I need a query which can get leaves from an employee of days each month.
Example:
1.
If an employee has leave of date_start = 15 January 2014 ', date_end = 30 January 2014 "which is in the same month, then it will be"
Duration = 15-30 + 1 = 16 days
Total_days_in_jan = 31 days
Calculation of salary leave will be amount = (: base +: housing) * (: duration) / (Total_days_in_jan)
= (1000 + 2000) * 16/31
' 2. If his two month date_start = 15 January 2014 ', date_end = 10 February 2014.
I wrote code that works perfect below
If to_char(:date_start,'mm') = to_char(:date_end,'mm') then
v_mon_days: = TO_CHAR (last_day (TO_DATE(:date_start,'DD-MON-YYYY')), 'DD');
v_tot: = (nvl(:BASIC1,0) + nvl (:FUJ_LIVING,0)) *(:Duration_)/v_mon_days;
elsif to_char(:date_start,'mm') <>to_char(:date_end,'mm') then
v_mon_days_st_dt: = TO_CHAR (last_day(:date_start), 'DD');
v_mon_days_en_dt: = TO_CHAR (last_day(:date_end), 'DD');
v_lv_days_st_dt: = last_day(:date_start) -: date_start + 1;
v_lv_days_en_dt: =: date_end - trunc(:date_end,'mm') + 1;
v_tot_st_dt: = (nvl(:BASIC1,0) + nvl(:FUJ_LIVING,0)) * (v_lv_days_st_dt) / v_mon_days_st_dt;
v_tot_en_dt: = (nvl(:BASIC1,0) + nvl(:FUJ_LIVING,0)) * (v_lv_days_en_dt) / v_mon_days_en_dt;
v_tot: = nvl(v_tot_st_dt,0) + nvl(v_tot_en_dt,0);
end if;
Return round (v_tot);
3. If the 3 months off, say date_start = 24-may-2014 date_end = July 2, 2014.
I need some help here... what happens if the 4 month also leave...
Please suggest.
Kind regards
Afzal.

Hi Roger, Etbin

Thanks for your replies.

I found the solution on the month to display between two dates.

To calculate that I used the loop as below

declare

ST DATE: =: date_start;--TO_DATE('24-MAY-2014','DD-MON-YYYY');

ED DATE: =: date_end;--TO_DATE('02-JUL-2014','DD-MON-YYYY');

number of v_t_amount;

CURSOR C1 IS

SELECT more GRAND (ST, ADD_MONTHS (TRUNC (st, 'MONTH'), (LEVEL - 1))) dt.

LESS (ed,

LAST_DAY (ADD_MONTHS (TRUNC (st, 'MONTH'), (LEVEL - 1)))

) ld

OF THE DOUBLE

CONNECT BY LEVEL<>

MONTHS_BETWEEN (TRUNC (ed, 'MONTH'), TRUNC (st, 'MONTH'))

+ 1

ORDER BY 1;

V_AMOUNT NUMBER: = 0;

V_T_AMOUNT NUMBER: = 0;

NUMBER OF V_DAYS;

BEGIN

FOR I IN C1 LOOP

V_AMOUNT: = (nvl(:SALARY_DIFF,0) + nvl(:SPECIAL_ALLOWANCE,0) + nvl(:CF_OTHERS,0)

+ NVL(:Computer,0) + nvl(:PHONE_ALLOW,0) + nvl(:WORK_NATURAL,0)

(+ nvl(:TRANSPORTATION,0) * (i.1d - i.dt + 1) / TO_CHAR (LAST_DAY (i.1d), 'dd'));

V_T_AMOUNT: = V_AMOUNT;

end loop;

end if;

dbms_output.put_line (v_t_amount);

end;

repeat_interval in DBMS_SCHEDULER.create_job - for the 2nd day of each month

Hi all

I want to clarify in the repeat_interval the Scheduler for this task must be run on the second of each month at 20:00.
I've been racking my brains out but nothings coming out.

Any suggestions?

You probably want a range like this:

FREQ=MONTHLY;BYMONTHDAY=2;BYHOUR=20;BYMINUTE=0;BYSECOND=0;

You can use the DBMS_SCHEDULER. EVALUATE_CALENDAR_STRING function to test, as follows:

SQL > DECLARE
  2  start_date        TIMESTAMP;
  3  return_date_after TIMESTAMP;
  4  next_run_date     TIMESTAMP;
  5  BEGIN
  6  start_date :=
  7    to_timestamp_tz('01-JAN-2003 10:00:00','DD-MON-YYYY HH24:MI:SS');
  8  return_date_after := start_date;
  9  FOR i IN 1..5 LOOP
 10    DBMS_SCHEDULER.EVALUATE_CALENDAR_STRING(
 11      'FREQ=MONTHLY;BYMONTHDAY=2;BYHOUR=20;BYMINUTE=0;BYSECOND=0;',
 12      start_date, return_date_after, next_run_date);
 13  DBMS_OUTPUT.PUT_LINE('next_run_date: ' || next_run_date);
 14  return_date_after := next_run_date;
 15  END LOOP;
 16  END;
 17  /
next_run_date: 01/02/2003 08:00:00.000000 PM
next_run_date: 02/02/2003 08:00:00.000000 PM
next_run_date: 03/02/2003 08:00:00.000000 PM
next_run_date: 04/02/2003 08:00:00.000000 PM
next_run_date: 05/02/2003 08:00:00.000000 PM

use to insert the last day of each month
Hi, I wrote this code but it did not insert the 20 December and it is January 1, and next time running is 31 January... I would like to work to make this insert every last day of each month...
```
begin
  sys.dbms_job.submit(job => :job,
                      what => 'INSERT INTO hisrtu 
                                        SELECT rtunum, linked, dbchkd, chaqty, dbvald, ctrltr, meaadj, qtyrtu, month, year, entity, rtunam 
                                        FROM qtyrtu;',
                      next_date => to_date('31-10-2010 01:00:03', 'dd-mm-yyyy hh24:mi:ss'),
                      interval => 'SYSDATE +30');
  commit;
end;
/
```
I don't know if it's because I assigned the date 31-10... In November it's just but December has not...

Best regards, hope you can help me.

I use oracle 9i
Hello

If you want the job to run at 02:00 the last day of the next month, then the desired argument is:
```
interval => 'ADD_MONTHS (TRUNC (SYSDATE, ''MONTH''), 2) - (22 / 24)'
```
In other words, if she finishes running at 02:30 on 31 January, then
TRUNC (SYSDATE, 'MONTH') will be at 00:00:00 January 1
ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), 1) will be March 1st at 00:00:00
ADD_MONTHS (TRUNC (SYSDATE, 'MONTH'), - 1) (22 / 24) will be 22 hours earlier, i.e. 02:00 on the last day of February.

logandro wrote:
I don't know if it's because I assigned the date 31-10... In November it's just but December has not...

Do you mean this line?

next_date-online to_date (October 31, 2010 01:00:03 ',' dd-mm-yyyy hh24:mi:ss'),

I don't think that's a problem. The next_date specifies only when it work baptisms. I guess he ran on October 31; you said it was running well on 30 November, 30 days after that. Something has to happen after November 30.

Note that the interval argument is relative when the task completes. If a task takes 30 minutes to run, then
```
interval => 'SYSDATE +30'
```
means that, if it turns to
01:00:03 October 31, then it will run again about
01:30:03 November 30, around
02:00:03 on December 30.
02:30:03 January 29 and so on. If your business does that for a few seconds, it won't matter much.

If you decide to use LAST_DAY, don't forget not that the hours-minutes-seconds referring LAST_DAY are the same as those of his argument.

How can I program a list of Interfaces that will run on the last Sunday of each month...

Hi can someone help me to achieve this scenario...
Thanks in advance...

Hello

Make the scenario for each interface and expand when the script option is planning.

Scheduling---> option execution---> select month (day of week)---> monthly date = last & Sunday and schedule accordingly.

Let me know

Thank you

Nomination for the third Wednesday of each month

How can I set up my monthly calendar to an event that occurs every third Wednesday of the month? Thank you.

Hello
- You use windows calendar or any other program?
If sa is the Windows Calendar, then it is not possible to do.

http://Windows.Microsoft.com/en-us/Windows-Vista/customize-Windows-Calendar

Diana

Microsoft Answers Support Engineer

Calendar: How make you an appointment to repeat the same day (no date) of each month

Hello

I use the calendar in Windows RT.

How to make an appointment to repeat, for example, the second Tuesday of each month?

Hi Matt,

Thanks for posting the question on Microsoft Community.

According to the description, it looks like you want to make an appointment in a calendar application.

I have these steps that should help you to solve the problem.

Try these steps and check:

a. open the Calendar application.

b. Select the date to which you want to schedule the appointment.

c. type view more.

d. press the dropdown under what frequency and select on a monthly basis.

e. tap save change which is at the top right of the screen.

I hope this helps. If you have questions more related to Windows, feel free to post here at Microsoft Community.

Query to find data of each month
Hello

I have 2 tables.

(1) Order_tb

Name Null? Type
----------------------------------------- -------- ----------------------------

ORDERID NOT NULL NUMBER
NUMBER OF CUSTOMERID
ORDERDATE DATE

(2) Order_d

Name Null? Type
----------------------------------------- -------- ----------------------------

ORDERID NUMBER
PRODUCTID NOT NULL NUMBER
PRODUCTNAME VARCHAR2 (20)
NUMBER OF SELLINGPRICE

I need to find the total find the selling price for each month of the year 2012 (orderdate) total.

I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.

Thank you

Published by: RSD on February 28, 2013 09:18
Hello

RSD wrote:
I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.

The WHERE clause below, is what limits the results for 2012.
```
SELECT       TRUNC (t.orderdate, 'MONTH')     AS month
,       SUM (d.sellingprice)          AS total_sellingprice
FROM       order_tb  t
JOIN       order_d   d  ON  d.orderid  = t.orderid
WHERE       t.orderdate  >= DATE '2012-01-01'
AND       t.orderdate  <  DATE '2013-01-01'
GROUP BY  TRUNC (t.orderdate, 'MONTH')
ORDER BY  TRUNC (t.orderdate, 'MONTH')
;
```
I hope that answers your question.
If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
Simplify the problem. For example, pretend you're only interested in the first 3 or 4 months of 2012; We will find a solution tht can easily be adapted for 12 (or any other number) of motnhs.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}

the 50 GB renews each month

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