the components of the price setting

OK my requirement is as follows,
I have elements that consist of components.
the price of the item is the sum of the parts.

what users would like to now is for the components to be adjusted so that the sum of the parts (the cost) is an integer value.
which is equal to the value rounded of the components summation of costs.

Here's a little querry that shows what I mean.

with t as
(
Select item_number 1, 'A' component, component_price 3.12 Union double
Select 1, 'B', 3.45 double Union
Select 1, 'C', 12.12 double Union
Select 1, had ', 7.12 double Union
Select option 2, 'X', 7.05 double Union
Select 2, 'Y', the double union 5.62
Select 3, 'Z', 52.03 double Union
Select 3, 'AA', 8.94 double Union
Select 3, 'BB', double 2.45)
Select item_number, component, component_price,.
-a total price of article
Sum (component_price) on item_price (item_number partition),
-total rounded
rounded_item_price Round (Sum (component_price) on (item_number score)),
-the difference between the two
Round (Sum (component_price) more (item_number partition))-sum (component_price) on the difference (item_number partition).
-number of items in the item
Count (Component) on the components (item_number partition)

t;

is there an easy way to adjust the items in each element of the training?
or what I need to do something similar to the use of the type clause and just add or subtract a few cents until I get it?
with t1 as (
            select 1 item_number, 'A' component, 3.12 component_price from dual union
            select 1,'B',3.45 from dual union
            select 1,'C',12.12 from dual union
            select 1,'D',7.12 from dual union
            select 2,'X',7.05 from dual union
            select 2,'Y',5.62 from dual union
            select 3,'Z',52.03 from dual union
            select 3,'AA',8.94 from dual union
            select 3,'BB',2.45 from dual
           ),
     t2 as (
            select  item_number,
                    component,
                    component_price,
                    -- total price of the item
                    sum(component_price) over (partition by item_number) item_price,
                    -- rounded total
                    round(sum(component_price) over (partition by item_number)) rounded_item_price,
                    -- difference between the two
                    round(sum(component_price) over (partition by item_number)) - sum(component_price) over (partition by item_number) difference,
                    -- number of components in the item
                    count(component) over (partition by item_number) components,
                    count(component) over (partition by item_number order by component) rnum
              from  t1
           )
select  t2.*,
        case sign(difference)
          when -1 then -least(round(-difference / components,2),-difference - round(-difference / components,2) * (rnum - 1))
          else least(round(difference / components,2),difference - round(difference / components,2) * (rnum - 1))
        end adjustment
  from  t2
/

ITEM_NUMBER CO COMPONENT_PRICE ITEM_PRICE ROUNDED_ITEM_PRICE DIFFERENCE COMPONENTS       RNUM ADJUSTMENT
----------- -- --------------- ---------- ------------------ ---------- ---------- ---------- ----------
          1 A             3.12      25.81                 26        .19          4          1        .05
          1 B             3.45      25.81                 26        .19          4          2        .05
          1 C            12.12      25.81                 26        .19          4          3        .05
          1 D             7.12      25.81                 26        .19          4          4        .04
          2 X             7.05      12.67                 13        .33          2          1        .17
          2 Y             5.62      12.67                 13        .33          2          2        .16
          3 AA            8.94      63.42                 63       -.42          3          1       -.14
          3 BB            2.45      63.42                 63       -.42          3          2       -.14
          3 Z            52.03      63.42                 63       -.42          3          3       -.14

9 rows selected.

SQL>  

SY.

Published by: Solomon Yakobson, February 12, 2010 11:48

Tags: Database

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    Gopinath Ramasamy

    Published by: Guillet Ramasamy on 6 December 2012 17:41

  • Can someone tell me where I can find the price to icloud by car

    I just spent 15 minutes looking for this site for the price of the icloud drive. No luck.
    Can someone tell me the URL of the icloud drive price list please? Or is it one of those things where, "If you have to ask, you cannot afford it."

    ICloud Drive is itself is free, but if you want more than 5 GB of space in there, you will have to pay for it.

    (145117)

  • Where can I find the price of the app, and why they are hidden?

    Why are they not those openly displayed apps prices? You need to click on 'Recover' to see the price? Seems a little shady. What is the price for Word Streak With Friends (paid version)? Thank you.

    (I'll fix my phone soon but wanted to learn about this first; could switch to Android that iTunes is not very user-friendly.) "This is an example.)

    1. the applications themselves are free. Some features in them requires a purchase.

    2. see #1.

    3. $5,99 in the USA.

    (145055)

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