the Max version data
Helloneed your help in obtaining data from max version and I have two 10g (10.2.0.4) and 11 GR 2
DB version: 10g and 11 g 2
Table:
=========
user_charachters
==========
user_id number
u_version number
charachters number
user_id and u_version has indexes and table has about million rows and growing ===========
user_id version characters
2345 1 25
2345 2 30
456789 1 78
33333 1 45
33333 2 67
33333 3 23
user_id version characters
2345 2 30
456789 1 78
33333 3 23
select a.*
from user_charachters a
where a.user_id || a.version = (select b.user_id|| max(b.version)
from user_charachters b
where b.user_id = a.user_id
group by b.user_id); Published by: nydba on August 1, 2011 10:57
with user_characters as (
select 2345 user_id,1 version,25 characters from dual union all
select 2345,2,30 from dual union all
select 456789,1,78 from dual union all
select 33333,1,45 from dual union all
select 33333,2,67 from dual union all
select 33333,3,23 from dual
)
-- end of on-the-fly data sample
select user_id,
max(version) version,
max(characters) keep(dense_rank last order by version) characters
from user_characters
group by user_id
/
USER_ID VERSION CHARACTERS
---------- ---------- ----------
2345 2 30
33333 3 23
456789 1 78
SQL>
SY.
Tags: Database
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If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
Explain, using specific examples, how you get these results from these data.
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----------
create the table max_test
(
'PROJECT' VARCHAR2 (50 BYTE),
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VARCHAR2 (5 BYTE) 'VERSION',
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--------------
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