time order date by am pm
Please help me get the results below. My order of requirement by date am day then MP
Select d)
SELECT TO_CHAR)
To_date (' August 15, 2009, 16:30 ')
(' DD/month/YYYY, hh: mi: ss AM')
(' YYYY-MM-DD hh: mi: ss AM') d
OF THE DOUBLE
Union of all the
SELECT TO_CHAR)
To_date (' August 15, 2009, 05:30 ')
(' DD/month/YYYY, hh: mi: ss AM')
(' YYYY-MM-DD hh: mi: ss AM') d
OF THE DOUBLE
Union of all the
SELECT TO_CHAR)
To_date (August 15, 2009, 18:30 ')
(' DD/month/YYYY, hh: mi: ss AM')
(' YYYY-MM-DD hh: mi: ss AM') d
OF THE DOUBLE
Union of all the
SELECT TO_CHAR)
To_date (August 15, 2009, 19:30 ')
(' DD/month/YYYY, hh: mi: ss AM')
(' YYYY-MM-DD hh: mi: ss AM') d
The DOUBLE) order by d.
I get after the output of the query above in the below.
Actual output
--------------------------
15/08/2009-16:30
15/08/2009 05:30
15/08/2009-18:30
15/08/2009-19:30
How to modify the above query to get the below output. Basically I need to order by h and then h
expected results
--------------------------
15/08/2009 05:30
15/08/2009-16:30
15/08/2009-18:30
15/08/2009-19:30
Select TO_CHAR(d,'DD-MM-YYYY HH:MI:ss AM') in the d
from (SELECT TO_DATE('15/August/2009,4:30:00 PM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union d all the)
SELECT TO_DATE('15/August/2009,5:30:00 AM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union all the
SELECT TO_DATE('15/August/2009,6:30:00 PM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union all the
SELECT TO_DATE('15/August/2009,7:30:00 pM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL
)
order by to_date(d,'DD/MM/YYYY HH:MI:ss AM')
D |
---|
15/08/2009 05:30 |
15/08/2009-16:30 |
15/08/2009-18:30 |
15/08/2009-19:30 |
Concerning
Etbin
Tags: Database
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