time order date by am pm

Please help me get the results below. My order of requirement by date am day then MP

Select d)

SELECT TO_CHAR)

To_date (' August 15, 2009, 16:30 ')

(' DD/month/YYYY, hh: mi: ss AM')

(' YYYY-MM-DD hh: mi: ss AM') d

OF THE DOUBLE

Union of all the

SELECT TO_CHAR)

To_date (' August 15, 2009, 05:30 ')

(' DD/month/YYYY, hh: mi: ss AM')

(' YYYY-MM-DD hh: mi: ss AM') d

OF THE DOUBLE

Union of all the

SELECT TO_CHAR)

To_date (August 15, 2009, 18:30 ')

(' DD/month/YYYY, hh: mi: ss AM')

(' YYYY-MM-DD hh: mi: ss AM') d

OF THE DOUBLE

Union of all the

SELECT TO_CHAR)

To_date (August 15, 2009, 19:30 ')

(' DD/month/YYYY, hh: mi: ss AM')

(' YYYY-MM-DD hh: mi: ss AM') d

The DOUBLE) order by d.

I get after the output of the query above in the below.

Actual output

--------------------------

15/08/2009-16:30

15/08/2009 05:30

15/08/2009-18:30

15/08/2009-19:30

How to modify the above query to get the below output. Basically I need to order by h and then h

expected results

--------------------------

15/08/2009 05:30

15/08/2009-16:30

15/08/2009-18:30

15/08/2009-19:30

Select TO_CHAR(d,'DD-MM-YYYY HH:MI:ss AM') in the d

from (SELECT TO_DATE('15/August/2009,4:30:00 PM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union d all the)

SELECT TO_DATE('15/August/2009,5:30:00 AM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union all the

SELECT TO_DATE('15/August/2009,6:30:00 PM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL Union all the

SELECT TO_DATE('15/August/2009,7:30:00 pM','DD/Month/YYYY,HH:MI:ss AM') FROM DUAL

)

order by to_date(d,'DD/MM/YYYY HH:MI:ss AM')

D
15/08/2009 05:30
15/08/2009-16:30
15/08/2009-18:30
15/08/2009-19:30

Concerning

Etbin

Tags: Database

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