totalizer of time-elapsed time

Similar Questions

• Time elapsed between 2 points

  Hello

  I'm trying to measure the time between 2 datapoints.
  During the data acquisition begins the time must be saved and when the signal reaches 90% of it is max.
  These 2 times then extracts itself and then you have the elapsed time.
  But I'm not sure how to proceed... I thought with dishes sequences.

  You capture a signal at all times?  What is your sampling rate?

  What you need to do first to get the signal.  You can find the maximum value with Array Max & Min function.  Calculate your 90% (0.9 * Max).  Search the data until your get the 90% or greater.  Download this issue of sampling.  Your time is so number of samples at the helm of the 90% divided by the sampling rate (samples per second).

• Elapsed time

  Hi guys, I use the elapsed time to set an expectation and to have, at the same time, the ability to stop waiting.

  The problem is that if for example I put on hold for 1 minute the first time everything works fine, but when I repeat the same operation (my VI is a state machine so I can put it in an idle state) something goes wrong... I tried to debug but I am sure that the problem is the elapsed time for two reasons: the first is that I have replaced it with wait function (ms) and it works correctly whenever I want, the second is that I put a flag on the time elapsed (s) and the first time, I see that he County/wait of 0 to 1 sec while the second time in automatic mode it goes to 5,46 without any account Countdown.

  I hope you can help me because it makes me crazy.

  Hello

  I joined again the VI version 2012

  I've also attached the snapshot and the snippet where you can not open the VI

  Best regards

  TuiTui

• Elapsed time on graph does not match indicator sound

  Hello

  I created a vi that displays three waveforms on a graph whose axis x shows the time elapsed since the vi was launched. The data is written to an excel spreadsheet. Everything works as expected with the exception that column of time in my file does not match the time that is displayed on the x-axis of my table. The time in my file only shows increments of 0.1 second, with the same sample for every ten samples, so that the time on the graph increases in increments of 0.001 (accuracy I had put in) and is unique for each data point in amplitude. I have attached my output file for reference. The column 'X' is both.

  I am collecting data at 100 Hz and 10 samples of reading both using the continuous sampling mode. Without my loop for the values of x, I get a sample of time on every ten - what I understand why, given my sampling rate; with it, I get this same sample for all ten samples (again, I think I understand why, but foolishly hoped that might solve the problem). What I don't understand is why the time on my table is incrementing differently time data, I wrote to my folder, since both are from the same source. Anyone would be able to help me understand that, if I can try to solve my problem?

  I have also included my vi. I use USB 6229 OEM.

  This is because you write 10 copies of t0 to the worksheet

  Try this little maodification and see if that helps

  

• Problems of time elapsed VI

  Hello friends OR,.

  I'm having a problem with my "time up" vi where he would not count toward the top.

  I'm using labview 8.0

  Here's what I'm trying to do in case I do wrong here...

  I'm trying to reset my table of default values after a certain period of time elapsed. I tried to use a node to invoke to do this, but for some reason, that didn't work. So I just put in a case structure and just put 0 constants for the indicators after my time target was reached, but now my time would not count upward...

  Help, please!

  It's really hard to figure out exactly what you want... but I tried to give it a shot. Once, again follow what RavensFan proposed (in addition they won the super bowl)... your architecture suggests that you do the tuturials online (admittedly, I tried not to alter your style/logic...but as suggested there are many improvements that can be made here.)

• Elapsed time in flat sequence Frames

  I enclose a VI file simplified what I'm trying to do. Ideally, this program starts when "OK" is pressed and cross frames (or steps) to the time indicated as wait times. The program would then reset. It will be meant to time the experimental stages, possibly with release of equipment parameters. I wish I could have a direct timer for each step backwards (ideally) or to give elapsed time. I tried different variations, but nothing seems to give me a direct timer as I'm looking.

  This timer is not entirely necessary, it would be good to know where experience is the place to experience 50 hours that makes us turn.

  I am very new to LabVIEW, please excuse that requires the simplicity of the solution that it likely.

  As a simple state machine, it is trivial. See if the attached VI may give you some ideas.

  Note that since this is a state machine...

  • It can be stopped at any time. If you allow only stop in the slow case, don't wire in other cases.
  • No local variable!
  • No loops inside loops!
  • No sequence!
  • A unique array of clusters setting information specific to the State in one place. Nothing distributed across multiple locations.
  • All States timer reuse the same code, just with two values different (State and duration).
  • For more complex scenarios, you can add more flavors State.
  • Note that I use the output of waiting for the tick ms. (you can also use the number of cycles, but who would need a separate waiting)
  • Simple, scalable, and extensible code. Just add items to the enum and add corresponding cases.
  • modify if needed.

• Elapsed time [new]

  Can Hi anyone help me on this please...

  Comments and suggestions are welcome.

  Kind regards

  NORWEGIAN KRONER

  

  Altenbach says:

  I still don't understand why you need two timers. You can remove the timer B and simply compare the elapsed time of A with B time goal and light the LED if the elapsed time is higher.

  I meant like that.

• Recording time elapsed for a change in status of the Boolean button

  Hello

  I'm new to Labview and tries to implement a simple program. I want to find the elapsed time in seconds when a key value is faithful to a false button has changed. I created the following VI attached for the same but the timer works only up to 50 seconds and then returns to 0. I don't know why, but I didn't click any autoreset in this express VI.

  Can someone help me?

  N

  Maverick269 wrote:

  ... but the timer works only up to 50 seconds and then returns to 0. I don't know why, but I didn't click any autoreset in this express VI.

  If you double-click the express VI, you will notice that it is configured to 50seconds. Set it to a very large number, such as + inf

  (I do not understand why you need a property value node? All wire to the terminal of control directly.)

• VI clock with the time elapsed

  Hi guys. I want to make a clock that shows me to hours and minutes. I used the elapsed time.

  Could check you if this solution is fine? Because I'm not sure if I've made mistakes.

  

  You can still use 'number of ICT.

• Model in the loop timed While the elapsed time

  Hello NOR community,

  I'm trying to use a while loop timed to run controller simulated for a mechanical system test. I need the time loop to run at an even 50 Hz to simulate the controller that will eventually drive the mechanical system. To check the speed at which the loop runs, I made a VI that gets a value from each loop clock and subtracts the value of the clock of the current iteration of the value of the clock of the previous iteration. I have eliminated all other codes this VI except for the recovery of the clock, to ensure that no problem with another code in VI. I find that the time between iterations is not constant, but it is consistent. In other words, the elapsed time can change at each loop, but it changes according to a specific model, such that the average elapsed time is equal to the value that I use for the timed loop. The loop will run faster than posed for several cycles, then slow down during a cycle even at the same time. Here are some examples:

  Running at 5 Hz: elapsed switches schedules between 0.203125 and 0,187500 seconds

  Clocked at 8 Hz: time is constantly 0.125 seconds.

  Operating at 10 Hz: elapsed switches schedules between 0,109375 and 0,093750 seconds

  By examining the differences between elapsed time and the stability of the 8 Hz setting, it seems that there is a minimum time of 0,015625 seconds (64 Hz) division. It is much worse than the 1ms accuracy claimed in documentation. This could be the cause?

  I am running Windows XP with LabVIEW version 8.5.1 and have observed this behavior on several computers with different screws

  Thank you!

  Erik

  Your problem is the function that you use to get the current time.  It's just the time of the Windows clock which has a resolution of 16 msec.

  You must use the function of number of cycles as Jarle has pointed out.

• Elapsed timer

  Hello

  I'm doing this project in motion sensor. I got to work like when it detects a movement it will turn on the Boolean value has led. I'm so now suppose to add some kind of timer which some recommended the passage of time, I tried to find but I do not know how to connect to my program. My task is to set a timer, while 10 minutes elapsed, no movement is detected, it will trigger a logic 1 (digital input) to another program. But now I'm focusing on this program I need to integrate the two to the right. So, how do I do not connect to make as how I had described. And finally I need a reset for that button after it input 1 logic (which will trigger an alarm - another program) it can be reset to zero and count down 10 minutes still. Thank you

  First of all, you keep in your original thread.

  Then take the LabVIEW tutorials.

  LabVIEW Introduction course - 3 hours
  LabVIEW Introduction course - 6 hours

  Then, read the help file for the elapsed time function.

  Finally, set up a simple VI where you can experiment with how this function works.

• different type of terminals of elapsed time of the DAQ assistant

  I connected a digital relay to one of the outputs. I have installation wizard DAQ to operate a valve with the relay. Now, I want to control the valve to drive all... .lets say 20 seconds, until I stop the program. What I need, is to change the State of each 20 seconds. I tried to use the "Out of time", but when I try to connect 'elapsed time' 'Data' on the ass of data acquisition. It reports on the different types of data. What would be the way easy and clean to use a "timer" to operate a relay on a basis of time fixed and periodic? Thanks in advance!

  I enclose a picture of my horrible test...

  I'm using Labview student 2009 edition.

  Put an is not in there also.

  

• How do I know the elapsed time

  
  

  Hello

  The difference between your option (a) and (b) is as below:

  (a) you get timestamp of the time before and after processes and subtract to find the elapsed time between the two... I will suggest you to convert time double data type before subtracting stamps...

  (b) you get "millisecond" of timer tick before and after the process count and subtract to find the elapsed time between the two... and last multiplication is 1000 to convert it to second...

  In my opinion, I'd rather (a)

  Thank you

  HS

• The display and recording time elapsed during the reading of the instrument

  I've been programming Labview for a total of two days so please bear with my inexperience. I have a 9201 module that takes a reading of the voltage and it is plotted on a graph. I click on a Boolean switch and the graph starts playback and recording data every 3 seconds. When I click on that same switch I would like to start a clock. Then once the button is clicked once again I need to stop the clock and save time. I tried to use the elapsed timer function but can not understand how to operate inside my main while loop. I don't know if I need to use a subvi or something different all together. I enclose my any project that could make the issue easier to understand. Thanks in advance for any help.

  I changed your code (personally I him would not have made it, but I don't want too many changes in your code because you are a beginner in LabVIEW!).

  -Now, there are 2 loops: 1 bow for the acquisition (looped) and 1 loop for user interface operations (while loop + event structure: it is a very powerful structure in LabVIEW and you should take a look at a few examples to understand how it works)

  -You will find a registry to offset used by loop acquisition: I explain what it is in the diagram...

  -I gave you a VI that is almost the same as 'out of time' Express VI: maybe it will be interesting to try too understand that when you get more experience in LabVIEW (you will understand 'functional global variables' and "reentrancy execution": these 2 animals are used by 'elapsed time' Express VI (but also by the VI I've included, and which is almost the same thing))

  Note that I have shown the solution to 1 of the 4 graphs: you will need to do the same for the other 3. You also need to code elapsed time saving.

  Once again, the solution I gave you is very far from perfection, but with 2 days of practice of LabVIEW, it would be too complicated to explain the different architectures and the means of communication between the loops etc...

• Timer elapsed time in seconds

  Hello

  I want to continually update the timer indicator up every second.  I don't understand why the program does not work?  Can offer you assistance to help me display timed time (in seconds).

  Thank you

  hiNi.

  PS, I know that there is a timer express VI passed, but I would like to know how to display the time elapsed without the express VI. Thank you!

  Why every second?  With each iteration of the loop?

  Since your loop runs every 100ms, you might make a counter using another register shift.  When the counter reaches 10, download your timed.

  Try these screws to see if they do what you want.