Unexpected result with select max (colmn) in anonymous block

Hello

The following query gives me 28 800 like sum (sal)
SELECT SUM(salary)
FROM employees 
    WHERE department_id =60
O/P is :  28800
But when I use the above query in anonymous block, it gives me 684400
DECLARE
 v_sum_sal NUMBER;
 department_id employees.department_id%TYPE := 60;
BEGIN
    dbms_output.put_line ('The department_id is'||department_id);
   SELECT SUM(salary)
      into v_sum_sal 
    FROM employees 
    WHERE department_id = department_id ;
   dbms_output.put_line ('The sum of sal is'||v_sum_sal);
END;
Exit instructions above gives me 684400 as output... But the grounds are 28800

You can me why the output differs block anonymous reference please

Hello

What about prefixing all your PL/SQL variables so that they do not match a column_name :

DECLARE
 v_sum_sal NUMBER;
 v_department_id employees.department_id%TYPE := 60;
BEGIN
    dbms_output.put_line ('The department_id is'||v_department_id);
   SELECT SUM(salary)
      into v_sum_sal
    FROM employees
    WHERE department_id = v_department_id ;
   dbms_output.put_line ('The sum of sal is'||v_sum_sal);
END;

Because, with the first names, where clause was equivalent to:

where 1=1

Tags: Database

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    Published by: UW (Germany) on 16.08.2012 16:48 (changed min at the maximum, but it makes only a difference when there is same ranking values)

  • GROUP BY with HAVE (MAX)

    The SELECT statement with the GROUP BY clause shows the incomplete result.

    The result of this query should display only the Group of the automaker, which shows the maximum hourly way (DFC).

    How should the clause be here?



    SELECT type, AVG (c_h) DFC

    GROUP BY type

    HAVING?


    The result is:

    TYP DFC     
    5000 MG
    Jaguar 7000
    Triumph 9000



    Thank you very much in advance for the help.

    Edited by: user3227321 14.08.2010 11:55

    You need to address as below

    having avg (c_h) = (select max (avg(c_h))
                           from tabname
                           group by typ)

    You can also use as below in your sql

    with c as
(
SELECT typ, AVG (c_h) DFC
GROUP BY typ
)
select typ,dfc
from c
where dfc = (select max(dfc)
                   from c)

    Try it!

  • Select max (length) - how to display the length of a group MAX

    Hello

    I have a table with the name of DVD and names of files on the DVD.
    I would like to know how to change this query to get another column, MAX_LENGHT, the MAXIMUM length of the name of FILE to a DVD of return
    This doesn't work request
    select DVD, FILENAME, (SELECT max(length(FILENAME)) / 2 + 4 FROM TABLE) AS MAX_LENGHT from TABLE
    DESIRED RESULT
    DVD    FILENAME     MAX LENGHT
DVD1     Alina     8
DVD1     Aidan     8
DVD1     Aiden     8
DVD1     Akira     8
DVD1     Alex     8
DVD1     Alyssa     8
DVD1     Arianna     8
DVD1     Ashley     8
DVD1     Ava     8
DVD1     Benjamin8
DVD1     Bianca     8
DVD1     Blake     8
DVD1     Brandon     8
DVD1     Brayden     8
DVD1     Brayden     8
DVD1     Brianna     8
DVD1     Brielle     8
DVD1     Brooklyn8
DVD2     Dakota     11
DVD2     Dalia     11
DVD2     Daniel     11
DVD2     Dante     11
DVD2     David     11
DVD2     Diego     11
DVD2     Dingbang11
DVD2     Dominic     11
DVD2     Dylan     11
DVD2     Chase     11
DVD2     Chloe     11
DVD2     Christopher     11
DVD2     Claire     11
DVD2     Cole     11
DVD2     Connor     11
    Thank you

    Roseline

    You can use the analytic version of the function max:

    SELECT  DVD
,       FILENAME
,       MAX(LENGTH(FILENAME)) OVER (PARTITION BY DVD) AS MAX_LENGTH
FROM    TABLE

  • HELP! : SELECT &amp; MAX

    I had a few difficulties to do a sql query.

    Table 1: Master

    2 columns: name, Contact_ID
    Name1, contact_id_1
    name 2, contact_id_2
    name 3, contact_id_3

    ...

    Table 2: details
    2 columns: Version Contact_id, address,.
    contact_id_1, address_a, 1
    contact_id_1, address_b, 2
    contact_id_2, address_c, 1
    contact_id_2, address_d, 2
    contact_id_2, address_e, 3
    contact_id_3, address_f, 1
    ......

    Question I have:

    How can I make a query showing the list of names with the address with the latest version?

    Result: I'm looking:

    Name1, address_b
    name 2, address_e
    name 3, address_f
    .......

    --------------------------

    Thank you very much for the help in advance! 
    with master as
(
  select 'name1' as name, 'contact_id_1' as contact_id from dual union all
  select 'name2' as name, 'contact_id_2' as contact_id from dual union all
  select 'name3' as name, 'contact_id_3' as contact_id from dual
),
detail as
(
  select 'contact_id_1' as contact_id, 'address_a' as address, 1 as version from dual union all
  select 'contact_id_1' as contact_id, 'address_b' as address, 2 as version from dual union all
  select 'contact_id_2' as contact_id, 'address_c' as address, 1 as version from dual union all
  select 'contact_id_2' as contact_id, 'address_d' as address, 2 as version from dual union all
  select 'contact_id_2' as contact_id, 'address_e' as address, 3 as version from dual union all
  select 'contact_id_3' as contact_id, 'address_f' as address, 1 as version from dual
)
--
-- end of test data, query is below
--
select m.name,
       d.address
from   master m,
       detail d
where  m.contact_id = d.contact_id
and    d.version = (select max(version) from detail d2 where d2.contact_id = d.contact_id)
/

NAME  ADDRESS
----- ---------
name1 address_b
name2 address_e
name3 address_f 

3 rows selected

    Published by: Cyn on December 17, 2009 16:39

  • When I subtract two numbers DBL and try to compare the result with another DBL, it fails

    I found a curious problem with subtraction and compare numbers DBL in LabVIEW (8.6). Here's how it works:

    1. subtract two numbers DBL such that the result is not incorporated. (Say, 3.2 - 3.1)

    2. compare the result with a constant/control that is on the result of the subtraction (in the example, 0.1)

    3 see the output of the comparison.

    If the result of the subtraction is an integer, the Boolean result is (as expected). If the result is not complete, the comparison fails.

    (Now, if I simply compare two floating point numbers, it works, so the issue is not with the node comparison itself, but with the data that is entered to the node). Can someone understand why this happens? It's unexpected, it's a pretty serious bug.

    It is provided with all programming languages. Numbers do not have an exact binary floating-point representation. This has been discussed endlessly. Never use the equal function with floats. You can use the function in the range and force.

  • Computer started to delay the result with a click of a button, etc. by seveal seconds.

    Have aw computer laptop Dell Inspiron 1501 XP SP3. Computer started to delay the result with a click of a button, etc. by seveal seconds.  A ran the anti-virus, malware search, keylogers search and found nothing.  The delay also occurs when you use an application such as CorelDRAW, Word, WordPerfect programs, etc.  any ideas what is happening or where to look? Thank you.

    You experience this delay all the time, or they occur from time to time?

    Could complete you the following procedure to obtain information about your current system and post here, so I can be more specific in suggestions.
    0 close the programs as open as you can before the first step.
    1 copy the following line below exactly as it appears:
    Taskpad cmd /C /V > tempo & tempo notebook
    2. press on + R
    3. paste copied line run window and press enter or click Ok.
    4 copy all the information from the Notepad window. (The list can be long, you can use + a combination to select all)
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    6. after that you can close the Notepad window.

  • Tabular with nvl (max (col), 0) + 1

    Hi all

    I have a table block, I want to generate sequence for the key item numbers primary with nvl (max (col), 0) + 1

    I wrote this in a w-n-r-i trigger:

    "LAST_RECORD;

    SELECT NVL (MAX (ALERT_ID), 0) + 1 ON: EX_ALERT_SETUP. ALERT_ID EX_ALERT_SETUP; "

    but when I enter a new record with the cursor, it also gets the '1', body I have not saved the first '1 ',.

    How to deal with this situation?

    Thank you

    ORA-01400 wrote:

    Hi all

    I have a table block, I want to generate sequence for the key item numbers primary with nvl (max (col), 0) + 1

    I wrote this in a w-n-r-i trigger:

    "LAST_RECORD;

    SELECT NVL (MAX (ALERT_ID), 0) + 1 ON: EX_ALERT_SETUP. ALERT_ID EX_ALERT_SETUP; "

    but when I enter a new record with the cursor, it also gets the '1', body I have not saved the first '1 ',.

    How to deal with this situation?

    Thank you

    If it's a bad design, simply change the trigger as before Insert at the block level. Sequences of database is suggested.

    Hope this helps

    Hamid

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