Value Alpha may change between two keyframes?

Similar Questions

• Value Alpha may change progressively faster in a Tween?

  Hello

  Flash CS5

  I have a discoloration of Alpha 21% to Alpha 1% MC in a classic tween, I need the fade to be slow and growing faster as time passes.

  How this is done?

  The MC I'm fading, is one that I have now managed to fade in my other post. Its been 5 frames each with a different png. I imagine that the makeup of the MC is not relevant, it's just a matter of how to increase the alpha fade rate, logarithmic, for example, somewhat like altering the curve of acceleration!

  Envirographics

  The only way to do it with an interpolation of the timeline is to adjust the easing in the properties panel.

  You should consider using Actionscript instead of the timeline Tween interpolation, especially if this setting is important for you to 3 seconds

• Because between two keyframes with the same position, there is movement?

  Because between two keyframes with the same position, there is movement?

  This would be due to the influence or speed?

  Quick glance:

  1. image: 'x' is 384px

  

  2 image: 'x' is 387px

  

  3. picture: 'x' is 384px

  

  Keyframes to which I refer are selected in the middle.

  

  There is a change in the balance between two key frames that are in the same position, without keyframes between them.

  FAQ: Why my layer (camera) moves backward between the keyframes value equal?

• Change the transformation between two keyframes without affecting adjacent transformations on the same timeline

  I'm creating a tree of decision/chart. I'm animate the position of a chart on the scene when the user selects Yes or no in response to a series of questions.

  I divided each movement of the diagram on the chronology of the scene in the form of labels. I staggered these transformations as keyframes on the same layer/path. The issue I'm having is when I manipulate the position of my diagram by moving on the stage, it affects the adjacent transformations. I have my separate transformations with a 1/10 of a second away because I thought that this would split the timeline, but it does not appear!

  

  While I can change the transformations manually by typing in coordinates xy it would be ten times faster to move the diagram on the stage instead and not to overwrite adjacent transformations.

  How to limit the transformation for the two points for the key frame with what I fear?

  Hello

  If you disable the automatic transition mode in the timeline panel, you can then create individual keyframes first for your late departure from the values, and then add transitions for each pair selected later. That should help you achieve what you're trying to do.

  Once you have done this, if you need to make an adjustment later without affecting the adjacent keyframe you can do this by placing the playhead on the keyframe, selecting the key image, then adjusting the property.

  HTH,

  Joe

• How to stop the unwanted movements between two keyframes?

  Hello

  I have created a few titles and am animation to move upwards and then downwards, then stops - I also applied a Gaussian blur.  3 keyframes.  1 start outside of the entire frame (so you don't see any).  2. go to a point (except it goes beyond this point) 3. Land at a point lower.

  For some reason any motion going past where I tell myself, as if there is a spring effect that happens automatically.  I don't understand.

  Please watch short video...

  Thank you!

  

  Make a right-click on the key frames and their linear value.

• How to change between two cast member

  I need exchanging two Member of the cast, for example, the cast Member 1 with Member of distribution 2.
  How what I can do ?

  first of all you need a sprite on the stage then its easy reference the sprite and then use lingo to swap the two.

  something like that

  You can put this in almost any type of script

  Sprite (1) .member = member('"xMemberName")

  You can also use lingo to identify the sprite that you want to share so that in the case, you need to adapt this sprite to a different channel, it will not be fooled

  something like this

  first of all you need two scripts now one of the sprite swapping action, if ever you put maybe a button. and another that is attached to the sprite

  the first is the ID

  something like this

  Global swapSpriteID - puts this var as a total for the entire movie he could know

  on beginSprite me

  swapSpriteID = sprite (me.spriteNum)

  end

  then in the other script that you use to change the Member of Sprite has this

  global swapSpriteID - recognizing the global var that this script can access

  on mouseUp me - could do in no way just an example

  Sprite (swapSpriteID) .member = member ("xMemberName")

  end

  hope this has helped

• When I create two keyframes at the same position between keyframes at different positions this way adds a loop. How can I get rid of the loop?

  When I create two keyframes at the same position between keyframes at different positions this way adds a loop. How can I get rid of the loop? I was just by dragging the handles on the vertex point, but I want to get rid of the loop together.

  Focus on the Bezier handles on the motion path in the Composition window. You can select the tool pen (g) and hold down the Alt/Option key to select the tool convert Vertex (it looks like a V on the side) and then fix the handle manually or click on the top of the trajectory to change it to a straight line. You can also play with spatial interpretation Keyframe.

  To avoid this, you can change the interpolation of keyframes in space to linear preferences. Most of the time I don't like straight so I keep my default value of Bézier.

• Count the number of records between two values of keys (BTREE)

  How can I count the number of keys between two values?

  I use python driver and BTREE access method.

  = >

  Ideally, what I want is a set of whole time series data (intervals may change) to a given number of points on average. The keys are timestamps and the values are the data that it takes on average. I need to count the number of records between two timestamps so that I can divide this figure by the number of points I need and data on average. What is the best way to do it?  Or should I keep the timestamp constant intervals and use the RECNO access method?

  Thank you
  (first post btw... and why is there not a lot of people at stackoverflow that answering the questions of Berkeley DB?)

  BDB is an integrated db and there no internal counters or statistics you might grap to use for this.    You will have to do it manually.

  You can create a cursor, grap the records you want, whenever you get the next card that you bump a counter.

  If you are using RECNO, you can use a slider to obtain the number of registration (DB_GET_RECNO), and if all that you data is in

  sequentail records with no missing documents, you can find the total number of take the last rec #-original rec # + 1 to get a count.

  If you pass the SQL API, you can issue a SQL query to give you a count.  Select count (*) where...

  As you enter the data anyway, so better perhaps to count records as you go along.

  Thank you

  Mike

• How do you find the average value of all the data between two points on a single channel

  I'm tring to calculate the average value of all data points in a single field between two distinct points

  I rasthaus an illustration.

  Hi smoothdurban,

  I thought you wanted to specify the area of interest with the sliders of the band.  If you rather automatically define the area of interest based on thresholds, etc., we cannot see the interactive nature of the example I sent.

  What are the criteria used to determine the start and end of the region of interest lines?

  I would be able to type this out for you if you sent a representative data set ([email protected])

  Brad Turpin

  Tiara Product Support Engineer

  National Instruments

• Take the time between two values

  Hi people,

  I have a problem and I know idea how to solve... I need help.

  The problem is I want to take the time between two values max as you can see in the chart.

  For example, in the image that I have add

  4.5 - 1 840 = 2.66

  And enter this value in the 'time between mostra '.

  It's that I want...

  But what I think is very complicated, because I don't know how to take the time correctly and does remove...

  Thank you very much

  Any solution?

  Hi jocuma,

  I tried something and hope that helps u.

  Just create two arrays of temperature and voltage. First of all, I'll get the value of the voltage when it is more of a certain value and that same index to get the value of time and store in the shift register.

  When I get the second higher than the limit value, I'll get time and subtract the previous value.

• Dynamic calculation of the number of days between two dates in a table

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  Hi BO123,

  BO123 wrote:

  Hello

  I'm working on request where I dynamically calculate the number of days between two dates in a table.

  The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

  APEX version: 5.0

  one of the way to do this by calling ajax on change of end_date.

  See the sample code given below to fetch the resulting duration and making the field read only after calculation

  Step 1: Change your page

  under CSS-> Inline, put the code below

  .row_item_disabled {
    cursor: default;
    opacity: 0.5;
    filter: alpha(opacity=50);
    pointer-events: none;
  }
  

  Step 2: Create on demand Ajax process I say CALC_DURATION

  Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call

  Declare
    p_start_date  date;
    p_end_date    date;
    p_duration number;
  Begin
    p_start_date  := to_date(apex_application.g_x01);
    p_end_date    := to_date(apex_application.g_x02);
  
     --do your calculation and assign the output to the variable p_duration
    select p_end_date - p_start_date into p_duration
      from dual;
  
    -- return calculated duration
    sys.htp.p(p_duration);
  End;
  

  Step 3: Create the javascript function

  Change your page-> the function and the declaration of the Global Variable-> put the javascript function

  You must extract the rowid in the first place, for which you want to set the time, see line 2

  assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

  See no line no 8 how set the value returned by the process of ajax at the duration column

  Replace your column to the respective column identifiers in the code below

  function f_calulate_duration(pThis) {
    var row_id  = pThis.id.substr(4);
    var start_date = $('#f06_'+row_id).val();
    apex.server.process ( "CALC_DURATION", {
    x01: start_date,x02: $(pThis).val()
  }, { success: function( pData ) {
  // set duration to duration column
  $('#f08_'+row_id).val(pData);
  // disable duration column
  $("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
  });
  }
  

  Step 4: choose the end date call the javascript function

  Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below

  onchange="javascript:f_calulate_duration(this);"
  

  
  

  hope this helps you,

  Kind regards

  Jitendra
  

• Calculate the difference in days between two Dates

  Hello

  I'm trying to understand how to calculate the difference in days between two dates using JavaScript in LiveCycle. (Minimum = JavaScript knowledge)

  Where 'Start_Date' and 'Current_Date' are the names of the two dates in the palette of the hierarchy. (the two Date/time field)

  * Current date is using the object > value > execution property > current Date/time

  I need a text or number field showing the difference in days. (Difference_in_Days)

  I noticed the following code is pretty standard among other responses:

  var

  Start_date = new Date (Start_Date);

  var

  Current_Date = new Date (Current_Date);

  var

  nAgeMilliseconds = Current_Date.getTime) - Start_date.getTime ();

  var

  nMilliSecondsPerYear = 365 * 24 * 60 * 60 * 1000 ;

  I know there is lack of code and code above are may not be not correct.

  Please notify.

  OK, that's because of the way that javascript and works of the calculate event.  The field will be filled with whatever the script resolves at the end of execution. Technically, your script does not have a value because the last thing you do is an assignment to a variable.  Change the last line as follows:

  Math.ABS ((firstDate.getTime)

  ((- secondDate.getTime (()) / (oneDay));

  (eliminate the variable assignment) and get rid of the app.alert.  Your script will "return" (have) regardless of the value of calculation from the East and which will be stored in the field.

• "Limited connection" when you configure the network between two computers XP.

  Original title: Configuration of the network connection

  Trying to establish a network connection between two home PCs., both running Windows XP Pro. Have been through the network on both PC Setup Wizard but, they still say limited, in fact no connection. I use an Ethernet cable between the two Crusader. If it is true what I'm doing wrong?

  Thanx Terry

  Old but good, networking tips from MVP Malke, MS:

  The best and simplest is to buy a wireless router. This way you get Internet connectivity both machines and the added benefit of security more between you and the Internet. Then you configure your network wireless safely, and then you configure file/printer sharing. Here is information on the implementation of a router and also in networking. It seems long, but don't be intimidated. Setting up a router and the LAN of sharing between two computers takes about 15 minutes.

  The router configuration

  Setting up a router is simple enough. Normally, you run the CD that came with the router and follow the instructions. If you're running Vista, maybe the CD that came with the router does not work; I do not know this. But you can set up the router without the CD. Note that if you have Internet cable for the connection you have just set up the router to DHCP (or there may even be a choice of cable to choose). If you have DSL Internet, you select TRP usually and enter the username and password you selected when you initially set the DSL connection. So:

  1. turn off the power to your cable modem.

  2. attach a cable (usually supplied with the router) course Ethernet cat5e Internet/WAN port of the router to the Ethernet port on the cable modem.

  3. connect the ethernet cable cat5e from the network card in your computer to one of the ports on the router. If you do not have an ethernet cable (because you were using USB), you will need to go to the store and buy a.

  4. turn on the cable modem. After that all the lights are on, turn on the router.

  To configure the router:

   

  Have a computer connected to the router with an ethernet cable. Examples given are for a Linksys router. See the manual of your router or the router mftr's Web site. for the parameters by default if you don't have a Linksys. Open a browser such as Internet Explorer or Firefox and in the address bar type:

  http://192.168.1.1 [Enter] (it is default IP address of the router, which varies from router to router then check your manual)

  This will bring you to the login screen of the router. The default username is blank and the Linksys default password is "admin" without the quotes. Enter this information. You are now in the configuration of the router utility. Your configuration utility may be slightly different from mine.

  Click the Administration link at the top of the page. Enter your new password. MAKE A NOTE SOMEWHERE THAT YOU WILL NOT LOSE. Re-enter the password to confirm it, and then click Save settings at the bottom of the page. The router will reboot and show you the box of connection again. Do not fill in the user name and put it in your new password to enter the configuration utility.

  Now, click on the link wireless at the top of the page. Change the network name (SSID) wireless by default to something, you'll recognize. I suggest that my clients not use their surname as the SSID. For example, you might want to name your network wireless network "CastleAnthrax" or similar.

  Click on save settings and when you get the prompt that your changes were successful, click the wireless security link which is just beside the Basic Wireless Settings link (where you changed your SSID). If you have a newish computer, you will be able to affect security WPA2-Personal Mode. Do this and enter a password. The password is what you enter on all computers that are allowed to connect to the wireless network. MAKE A NOTE SOMEWHERE THAT YOU WILL NOT LOSE.

  At this point, your router is set up and if the computer that you use to configure the router will normally connect wireless, disconnect the Ethernet cable and wireless of the computer should see your new network. Enter the password you created to join the network and start surfing.

  *****

  B. file/printer sharing of

  Excellent, comprehensive, but easy to understand article on sharing files/printer under Vista. Contains information about sharing printers and files, and the folders:

  http://TechNet.Microsoft.com/en-us/library/bb727037.aspx

  For XP, start by running the Network Setup Wizard the on all machines (see warning in section A below).

  Problems sharing files between computers on a network are usually caused by 1) a misconfigured firewall or a firewall neglected (including a dynamic firewall in a virtual private network); or (2) inadvertently run two firewalls such as the firewall of Windows and a third-party firewall. and/or (3) do not have accounts to the same users and passwords on all computers in the workgroup. (4) tries to create actions where the operating system does not.

  A. configure the firewall on all machines to allow traffic to local area network (LAN) as being approved. With the Windows Firewall, it means which allows file sharing / print on the Exceptions tab normally run the XP Network Setup Wizard will take care of this for these machines. The only "witch hunt", it will turn on the XPSP2 Windows Firewall. If you are not running a third-party firewall or you have an antivirus with "Internet Worm Protection" (like Norton 2006/07) which acts as a firewall, you're fine.  With a third-party firewall, I usually set up the allocation of LAN with an IP address range. E.g. would be 192.168.1.0 - 192.168.1.254. Obviously you would substitute your correct subnet. Do not run more than one firewall. DON'T STOP FIREWALLS; CONFIGURE THEM CORRECTLY.

  (B) to facilitate the Organization, put all computers in the same workgroup. This is done from the System applet in Control Panel, the computer name tab.

  C. create the counterpart of the user accounts and passwords on all machines. You do not need to be logged into the same account on all machines and assigned to each user account passwords can be different; accounts/passwords just need to exist and to match on all machines. DO NOT NEGLECT TO CREATE PASSWORDS, EVEN IF ONLY OF SIMPLE. If you want a machine to boot directly to the desktop (a particular user account) for convenience, you can do this. The instructions on this link work for XP and Vista:

  Set up Windows to automatically connect (MVP Ramesh) - http://windowsxp.mvps.org/Autologon.htm

  D. Si one or more of the computers is XP Pro or Media Center, turn off Simple file sharing (Folder Options > view tab).

  E. create share as you wish. XP Home does not share the users directory or the Program Files, but you can share folders inside those directories. A better choice is to simply use the Shared Documents folder. See the first link above for more information on Vista sharing.

  F. you have the job of file sharing (and tested by exchanging a file between machines), if you want to share a printer connected locally to one of your computers, share of this machine. Then go to the printer mftr Web site. and download the latest drivers for the correct system. Install them on the target machines. The printer must be collected during the installation procedure. If this isn't the case, install the drivers and then use the Add Printer Wizard. In some cases, printers must be installed as local printers, but it is outside this response.

• How to remove spaces between two separators

  Hi all

  How to remove the spaces between two separators, but space is required between the characters.

  I have an input as string below

  "# ABC DEF GHI # JKLMN.

  Expected string as below. Here the space between DEF GHI is required, but other spaces must remove.

  "ABC #DEF #JKLMN GHI".

  I tried with REPLACE it but it removes all spaces and this is a mistake.

  REPLACE ('ABC # DEF GHI # JKLMN', ' ')

  Please guide me. Thank you.

  For example, if the hash/pound symbol may not have a space before and after, then you need to change the regular expression to use ' * ' instead of ' + '...

  SQL > ed
  A written file afiedt.buf

  1 Select trim (regexp_replace ('ABC # DEF GHI #JKLMN',' (* # *) ',' #'))
  2 * of the double
  SQL > /.

  (REGEXP_REPLA TRIM
  -----------------
  ABC #DEF #JKLMN GHI

  Always be clear in your requirements.

  Re: 2. How can I ask a question in the forums?

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben